In the following page, with Firefox the remove button submits the form, but the add button does not.
How do I prevent the remove button from submitting the form?
function addItem() {
var v = $('form :hidden:last').attr('name');
var n = /(.*)input/.exec(v);
var newPrefix;
if (n[1].length == 0) {
newPrefix = '1';
} else {
newPrefix = parseInt(n[1]) + 1;
}
var oldElem = $('form tr:last');
var newElem = oldElem.clone(true);
var lastHidden = $('form :hidden:last');
lastHidden.val(newPrefix);
var pat = '=\"' + n[1] + 'input';
newElem.html(newElem.html().replace(new RegExp(pat, 'g'), '=\"' + newPrefix + 'input'));
newElem.appendTo('table');
$('form :hidden:last').val('');
}
function removeItem() {
var rows = $('form tr');
if (rows.length > 2) {
rows[rows.length - 1].html('');
$('form :hidden:last').val('');
} else {
alert('Cannot remove any more rows');
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<html>
<body>
<form autocomplete="off" method="post" action="">
<p>Title:<input type="text" /></p>
<button onclick="addItem(); return false;">Add Item</button>
<button onclick="removeItem(); return false;">Remove Last Item</button>
<table>
<th>Name</th>
<tr>
<td><input type="text" id="input1" name="input1" /></td>
<td><input type="hidden" id="input2" name="input2" /></td>
</tr>
</table>
<input id="submit" type="submit" name="submit" value="Submit">
</form>
</body>
</html>
You're using an HTML5 button element. Remember the reason is this button has a default behavior of submit, as stated in the W3 specification as seen here:
W3C HTML5 Button
So you need to specify its type explicitly:
<button type="button">Button</button>
in order to override the default submit type. I just want to point out the reason why this happens.
Set the type on your buttons:
<button type="button" onclick="addItem(); return false;">Add Item</button>
<button type="button" onclick="removeItem(); return false;">Remove Last Item</button>
...that'll keep them from triggering a submit action when an exception occurs in the event handler. Then, fix your removeItem() function so that it doesn't trigger an exception:
function removeItem() {
var rows = $('form tr');
if ( rows.length > 2 ) {
// change: work on filtered jQuery object
rows.filter(":last").html('');
$('form :hidden:last').val('');
} else {
alert('Cannot remove any more rows');
}
}
Note the change: your original code extracted a HTML element from the jQuery set, and then tried to call a jQuery method on it - this threw an exception, resulting in the default behavior for the button.
FWIW, there's another way you could go with this... Wire up your event handlers using jQuery, and use the preventDefault() method on jQuery's event object to cancel the default behavior up-front:
$(function() // execute once the DOM has loaded
{
// wire up Add Item button click event
$("#AddItem").click(function(event)
{
event.preventDefault(); // cancel default behavior
//... rest of add logic
});
// wire up Remove Last Item button click event
$("RemoveLastItem").click(function(event)
{
event.preventDefault(); // cancel default behavior
//... rest of remove last logic
});
});
...
<button type="button" id="AddItem" name="AddItem">Add Item</button>
<button type="button" id="RemoveLastItem" name="RemoveLastItem">Remove Last Item</button>
This technique keeps all of your logic in one place, making it easier to debug... it also allows you to implement a fall-back by changing the type on the buttons back to submit and handling the event server-side - this is known as unobtrusive JavaScript.
Sometime ago I needed something very similar... and I got it.
So what I put here is how I do the tricks to have a form able to be submitted by JavaScript without any validating and execute validation only when the user presses a button (typically a send button).
For the example I will use a minimal form, only with two fields and a submit button.
Remember what is wanted:
From JavaScript it must be able to be submitted without any checking. However, if the user presses such a button, the validation must be done and form sent only if pass the validation.
Normally all would start from something near this (I removed all extra stuff not important):
<form method="post" id="theFormID" name="theFormID" action="">
<input type="text" id="Field1" name="Field1" />
<input type="text" id="Field2" name="Field2" />
<input type="submit" value="Send" onclick="JavaScript:return Validator();" />
</form>
See how form tag has no onsubmit="..." (remember it was a condition not to have it).
The problem is that the form is always submitted, no matter if onclick returns true or false.
If I change type="submit" for type="button", it seems to work but does not. It never sends the form, but that can be done easily.
So finally I used this:
<form method="post" id="theFormID" name="theFormID" action="">
<input type="text" id="Field1" name="Field1" />
<input type="text" id="Field2" name="Field2" />
<input type="button" value="Send" onclick="JavaScript:return Validator();" />
</form>
And on function Validator, where return True; is, I also add a JavaScript submit sentence, something similar to this:
function Validator(){
// ...bla bla bla... the checks
if( ){
document.getElementById('theFormID').submit();
return(true);
}else{
return(false);
}
}
The id="" is just for JavaScript getElementById, the name="" is just for it to appear on POST data.
On such way it works as I need.
I put this just for people that need no onsubmit function on the form, but make some validation when a button is press by user.
Why I need no onsubmit on form tag? Easy, on other JavaScript parts I need to perform a submit but I do not want there to be any validation.
The reason: If user is the one that performs the submit I want and need the validation to be done, but if it is JavaScript sometimes I need to perform the submit while such validations would avoid it.
It may sounds strange, but not when thinking for example: on a Login ... with some restrictions... like not allow to be used PHP sessions and neither cookies are allowed!
So any link must be converted to such form submit, so the login data is not lost.
When no login is yet done, it must also work. So no validation must be performed on links.
But I want to present a message to the user if the user has not entered both fields, user and pass. So if one is missing, the form must not be sent! there is the problem.
See the problem: the form must not be sent when one field is empty only if the user has pressed a button, if it is a JavaScript code it must be able to be sent.
If I do the work on onsubmit on the form tag, I would need to know if it is the user or other JavaScript. Since no parameters can be passed, it is not possible directly, so some people add a variable to tell if validation must be done or not. First thing on validation function is to check that variable value, etc... Too complicated and code does not say what is really wanted.
So the solution is not to have onsubmit on the form tag. Insead put it where it really is needed, on the button.
For the other side, why put onsubmit code since conceptually I do not want onsubmit validation. I really want button validation.
Not only the code is more clear, it is where it must be. Just remember this:
- I do not want JavaScript to validate the form (that must be always done by PHP on the server side)
- I want to show to the user a message telling all fields must not be empty, that needs JavaScript (client side)
So why some people (think or tell me) it must be done on an onsumbit validation? No, conceptually I am not doing a onsumbit validating at client side. I am just doing something on a button get pressed, so why not just let that to be implemented?
Well that code and style does the trick perfectly. On any JavaScript that I need to send the form I just put:
document.getElementById('theFormID').action='./GoToThisPage.php'; // Where to go
document.getElementById('theFormID').submit(); // Send POST data and go there
And that skips validation when I do not need it. It just sends the form and loads a different page, etc.
But if the user clicks the submit button (aka type="button" not type="submit") the validation is done before letting the form be submitted and if not valid not sent.
Well hope this helps others not to try long and complicated code. Just not use onsubmit if not needed, and use onclick. But just remember to change type="submit" to type="button" and please do not forget to do the submit() by JavaScript.
I agree with Shog9, though I might instead use:
<input type = "button" onClick="addItem(); return false;" value="Add Item" />
According to w3schools, the <button> tag has different behavior on different browsers.
You can simply get the reference of your buttons using jQuery, and prevent its propagation like below:
$(document).ready(function () {
$('#BUTTON_ID').click(function(e) {
e.preventDefault();
e.stopPropagation();
e.stopImmediatePropagation();
return false;
});});
$("form").submit(function () { return false; });
that will prevent the button from submitting or you can just change the button type to "button" <input type="button"/> instead of <input type="submit"/>
Which will only work if this button isn't the only button in this form.
Suppose your HTML form has id="form_id"
<form id="form_id">
<!--your HTML code-->
</form>
Add this jQuery snippet to your code to see result,
$("#form_id").submit(function(){
return false;
});
Buttons like <button>Click to do something</button> are submit buttons.
You must add type
This is an html5 error like has been said, you can still have the button as a submit (if you want to cover both javascript and non javascript users) using it like:
<button type="submit" onclick="return false"> Register </button>
This way you will cancel the submit but still do whatever you are doing in jquery or javascript function`s and do the submit for users who dont have javascript.
Just add e.preventDefault(); in your method should prevent your page from submitting forms.
function myFunc(e){
e.preventDefault();
}
According to the MDN Web Docs
The preventDefault () method of the Event interface tells the user
agent that if the event is not explicitly processed, its default
action should not be taken into account as it would normally be. The
event continues to propagate as usual, unless one of its listeners
calls stopPropagation () or stopImmediatePropagation (), either of
which terminates the propagation.
The return false prevents the default behavior. but the return false breaks the bubbling of additional click events. This means if there are any other click bindings after this function gets called, those others do not Consider.
<button id="btnSubmit" type="button">PostData</button>
<Script> $("#btnSubmit").click(function(){
// do stuff
return false;
}); </Script>
Or simply you can put like this
<button type="submit" onclick="return false"> PostData</button>
I am sure that on FF the
removeItem
function encounter a JavaScript error, this not happend on IE
When javascript error appear the "return false" code won't run, making the page to postback
Set your button in normal way and use event.preventDefault like..
<button onclick="myFunc(e)"> Remove </button>
...
...
In function...
function myFunc(e){
e.preventDefault();
}
return false;
You can return false at the end of the function or after the function call.
Just as long as it's the last thing that happens, the form will not submit.
if you have <input />
use it
<input type="button"/>
if you have <button>btn</button>
use it
<button type="button">btn</button>
Here's a simple approach:
$('.mybutton').click(function(){
/* Perform some button action ... */
alert("I don't like it when you press my button!");
/* Then, the most important part ... */
return false;
});
I'm not able to test this right now, but I would think you could use jQuery's preventDefault method.
The following sample code show you how to prevent button click from submitting form.
You may try my sample code:
<form autocomplete="off" method="post" action="">
<p>Title:
<input type="text" />
</p>
<input type="button" onclick="addItem()" value="Add Item">
<input type="button" onclick="removeItem()" value="Remove Last Item">
<table>
<th>Name</th>
<tr>
<td>
<input type="text" id="input1" name="input1" />
</td>
<td>
<input type="hidden" id="input2" name="input2" />
</td>
</tr>
</table>
<input id="submit" type="submit" name="submit" value="Submit">
</form>
<script language="javascript">
function addItem() {
return false;
}
function removeItem() {
return false;
}
</script>
The function removeItem actually contains an error, which makes the form button do it's default behaviour (submitting the form). The javascript error console will usually give a pointer in this case.
Check out the function removeItem in the javascript part:
The line:
rows[rows.length-1].html('');
doesn't work. Try this instead:
rows.eq(rows.length-1).html('');
https://developer.mozilla.org/pt-BR/docs/Web/API/HTMLFormElement/submit_event
Do your logic on the form onsubmit event
submitter Read only
An HTMLElement object which identifies the button or other element which was invoked to trigger the form being submitted.
onsubmit="(evt) => console.log(evt)"
The event itself will bring along the caller and some usefull info.
Just use evt.preventDefault(); (default submit) evt.stopPropagation(); (submit bubbling) if the caller is a
As the title says This is the code that I tried with. The forms must appear one by one because information from previous forms determine how the next ones will look.
$(document).ready(function(){
$('#first_form').submit(function(){
$('#first_form').fadeOut('fast');
$('#second_form').fadeIn('fast');
});
});
<form action="new_patch.php" method="POST" id="first_form">
Title: <input type="text" name="patch" placeholder="Patch 4.20">
<br/>
Number of Champions: <input type="number" name="champ_number" min="1" max="99">
<br/>
<input type="submit" value="submit">
</form>
<form action="new_patch.php" method="POST" id="second_form" style="display: none;" >
<input type="text" value="text">
<input type="submit" value="submit">
<?php
$champ_number = null;
if(isset($_POST['champ_number']))
{
$champ_number = $_POST['champ_number'];
for($champ_number;$champ_number>0;$champ_number--)
{
echo "<br/>Champion ".$champ_number."<input type=\"number\" name=".$champ_number." min=\"1\" max=\"99\">";
}
}
?>
</form>
You're mixing client-side and server-side form code. Submitting the form will reload the page entirely, so from the looks of your code it will fade in the new form when the old form is submitted, but then reload the page so the old form will show again anyway.
You could either:
Let the PHP determine how the next form appears based on the submission of the first form, e.g. if (isset($_POST["First_form_submit"]) { Show second form... }
Probably better and more user-friendly: make the second form appear below once the user has filled in the relevant inputs on the first form before they've submitted
you can use:
$('#first_form').submit(function(){
$('#first_form').fadeOut(function() {
$('#second_form').fadeIn('fast');
});
return false;
});
From the jQuery documentation the syntax is fadeIn( [duration ] [, complete ] ) it accepts a duration and a onComplete callback that you can use to execute the next action when the first is completed.
I did this once too, just add a submit class to the button and make it like this:
<input type="submit" value="submit" class="submit">
Change script to a click function.
$(document).ready(function(event){
event.preventDefault();
$('.submit').click(function(){
$('#first_form').fadeOut(400);
$('#second_form').fadeIn(400);
});
});
PS, also you need to prevent submit default...otherwise it will just submit the form, see this JSfiddle
Is it possible?
I want a user to post an array full of 1-5 pieces of data.
At first there would be only one text field on show, but on clicking a 'plus' icon next to it, it would create another text field below it for more user input.
I would also want to have a delete icon next to text boxes 2-5, to remove them if necessary.
My JQuery knowledge is limited, and I can work out how to append text boxes to a list, but not to keep track of them/delete them. Ideally I would also want to pass them as an array to php, so I can easily loop through them.
<input type="text" size="15" maxlength="15" name="1"><img src="add.png" onclick="add();">
<!-- Below is hidden by default, and each one shows on click of the add image -->
<input type="text" size="15" maxlength="15" name="2"><img src="delete.png" onclick="delete(2);">
<input type="text" size="15" maxlength="15" name="3"><img src="delete.png" onclick="delete(3);">
<input type="text" size="15" maxlength="15" name="4"><img src="delete.png" onclick="delete(4);">
<input type="text" size="15" maxlength="15" name="5"><img src="delete.png" onclick="delete(5);">
jQuery clone() is very handy for this. A small example how it could be done (working example on jsfiddle)
<ul>
<li><input type="text" name="textbox[]" /></li>
</ul>
<input type="button" id="addTextbox" value="Add textbox" />
<script type="text/javascript">
$(function(){
$('#addTextbox').click(function(){
var li = $('ul li:first').clone().appendTo($('ul'));
// empty the value if something is already filled in the cloned copy
li.children('input').val('');
li.append($('<button />').click(function(){
li.remove();
// don't need to check how many there are, since it will be less than 5.
$('#addTextbox').attr('disabled',false);
}).text('Remove'));
// disable button if its the 5th that was added
if ($('ul').children().length==5){
$(this).attr('disabled',true);
}
});
});
</script>
For the server-side part, you could then do a foreach() loop through the $_POST['textbox']
As long as you give each text box a name like "my_input[]", then when the form is submitted, PHP can get the answer(s) as an array.
$_REQUEST['my_input']; would be an array of the values stored in each text box.
Source: Add and Remove items with jQuery
Add
Remove
<p><input type="text" value="1" /></p>
<script type="text/javascript">
$(function() { // when document has loaded
var i = $('input').size() + 1; // check how many input exists on the document and add 1 for the add command to work
$('a#add').click(function() { // when you click the add link
$('<p><input type="text" value="' + i + '" /></p>').appendTo('body'); // append (add) a new input to the document.
// if you have the input inside a form, change body to form in the appendTo
i++; //after the click i will be i = 3 if you click again i will be i = 4
});
$('a#remove').click(function() { // similar to the previous, when you click remove link
if(i > 1) { // if you have at least 1 input on the form
$('input:last').remove(); //remove the last input
i--; //deduct 1 from i so if i = 3, after i--, i will be i = 2
}
});
$('a.reset').click(function() {
while(i > 2) { // while you have more than 1 input on the page
$('input:last').remove(); // remove inputs
i--;
}
});
});
</script>
You will need to create DOM elements dynamically. See how it is done for example in this question. Notice that
document.createElement
is faster then using jquery's syntax like
$('<div></div>')
Using that technick, you could create inputs like
<input name="id1"/>
<input name="id2"/>
<input name="id3"/>
<input name="id4"/>
<input name="id5"/>
On submitting your form you'll get all them in your query string like
...id1=someval1&id2=someval2&...
Having that, you could process this query as you want on server side.
<form method="POST" id="myform">
<input />
Add textbox
<input type="submit" value="Submit" />
</form>
<script type="text/javascript">
$(document).ready(function(){
$('#add_textbox').click(function(){
var form=$(this).closest('form');
var count=form.find('input').length();
form.append('<div class="removable_textbox"><input />delete</div>');
$('.delete_input').click(function(){
$(this).find('.removable_textbox').remove();
return false;
});
return false;
});
$('#myform').submit(function(){
var i=1;
$(this).find('input').each(function(){
$(this).attr('name','input-'+i);
i++;
})
});
});
</script>
<?php
if(isset($_POST['input-1'])){
$input_array=$_POST;
}
?>
something like this?
I wrote a litte jQuery plugin called textbox. You can find it here: http://jsfiddle.net/mkuklis/pQyYy/2/
You can initialize it on the form element like this:
$('#form').textbox({
maxNum: 5,
values: ["test1"],
name: "textbox",
onSubmit: function(data) {
// do something with form data
}
});
the settings are optional and they indicate:
maxNum - the max number of elements rendered on the screen
values - an array of initial values (you can use this to pass initial values which for example could come from server)
name - the name of the input text field
onSubmit - onSubmit callback executed when save button is clicked. The passed data parameter holds serialized form data.
The plugin is not perfect but it could be a good start.
I want to email the value of the slider along with some things they entered into my form to my php email script. This is how the form looks that will pass data to the POST method of mailer.php:
<form method="POST" action="mailer.php">
Name:
<input type="text" name="name" size="19"><br>
<br>
E-Mail:
<input type="text" name="email" size="19"><br>
<input type="hidden" name="slider_value" size="19" value=document.getElementById('sliderValue').value><br>
<br>
<input type="submit" value="Submit" name="submit">
</form>
document.getElementById('sliderValue').value is the call I make to get the value of the slider but when I pass this to the value of my hidden input slider_value I get back "document.getElementById('sliderValue').value" in the email that is sent by my php script. How would I pass the value instead?
document.getElementById is a Javascript function. It probably won't do what you want it to unless you put it in a place where Javascript is accepted.
One way to pass the slider value is by putting the sliderValue element in the form that you are submitting.
If that is not an option, you can set the value of the slider_value element with Javascript. Either set an onsubmit attribute to the form like this:
<form method="POST" action="mailer.php"
onsubmit="this.slider_value.value = document.getElementById('sliderValue').value">
or add an event listener to do it:
var form = document.forms[0]; //this may need to be changed depending on your form
function addSliderValue() {
this.slider_value.value = document.getElementById('sliderValue').value;
}
if (form.addEventListener) { //most browsers
form.addEventListener("submit", addSliderValue, false);
} else if (form.attachEvent) { //IE
form.onsubmit = addSliderValue;
}
Bind a function to the sliders "onSlide/onChange/whatever it's called" event that will update the hidden input field with the slider value. Also set the input value to the initial slider value on slider init. That should do the trick.
<form action="page.php" method="post">
<input type="text" name="some_text" />
<input type="submit" name="some_submit" /
</form>
I want to submit this form by pressing defined keyboard button. I wonder how to do it. If it was just an <a> element it would be simple - I would just change window.location value after handling keypress event. But there is some data to send and I have no idea how to solve this.
You can create an event handler for a key press event, then submit the form using its submit() method to pass all the form data to the recipient page "page.php".
Using jQuery, this is trivial:
<form id="myForm" action="page.php" method="post">
<input type="text" name="some_text" />
<input type="submit" name="some_submit" />
</form>
<script type="text/javascript">
$('#myForm").keyDown(function(e){
if(e.which == 13) // When key pressed is "Enter" key.
$('#myForm').submit();
});
</script>
Read Javascript Madness: Keyboard Events for more information on interpreting keyboard events.
The data will be passed automatically as a result of form.submit()
Give a name to the form
<form name="myform" action="page.php" method="post">
After handling key press event do
document.myform.submit()
which will basically submit the form. If you want to add more parameters to it add those as hidden elements inside form.
For an example of key press handling, see http://dev.kanngard.net/Permalinks/ID_20050426091851.html - it submits a form if key 13 (Enter) is pressed, but can be modified to any other key.
In general: register a function to be called on KeyDown event, inside the function, check which key was pressed; if needed, submit() your form.
I'm in trouble:
function action(button) {
if ($('a.'+button+':visible').length > 0) {
if ($('a.'+button+':visible').attr('class') == button || $('a.'+button+':visible').attr('class') == 'rotate '+button) {
var adr = $('a.'+button+':visible').attr('href');
window.location = adr;
}
if ($('a.'+button+':visible').attr('class') != button) {
$('a.'+button+':visible').click();
}
}
if ($('input.'+button+':visible').length > 0) {
$('#form').submit();
}
}
Where variable 'button' is button's classname and #form is form's id. By clicking submit it works normally, but it doesn't work by keyboard event.