PHP : Get the value of Dropdown and pass it to another dropdown - php

Question

I have a problem right now [PHP]. I have a dropdown and its loading my database for the first page, when I proceed to the next page it also have a dropdown where its also loading the my database and also I can get the value of my dropdown in the first page using an echo only.
This is the scenario:
I choose in the dropdown first page the "Letter A" and when I click the button it will proceed to the next page. The dropdown in the second page loaded the items in the database but instead of "-select-" is the first index in the dropdown I want is "Letter A" will be the first index.
This is my code in first page for drowdown:
<select name="id">
<option value="" >- select -</option>
<?php
include 'connect.php';
$q = mysql_query("select fldNetname from tblnetwork");
while ($row1 = mysql_fetch_array($q))
{
echo "<option value='".$row1[fldNetname]."'>".$row1[fldNetname]."</option>";
}
?>
</select>
and this is my code in second page for dropdown:
if ($get_ID != "")
{
echo "<br/>";
echo $get_ID;
//echo "show()";
}
else
{
echo "No Network Selected";
echo "<br/>";
//echo "hide()";
}
?>
<option value="">- select -</option>
<?php
include 'connect.php';
$q = mysql_query("select fldNetname from tblnetwork");
while ($row1 = mysql_fetch_array($q))
{
echo "<option value='".$row1[fldNetname]."'>".$row1[fldNetname]."</option>";
}
?>
</select>
Thanks in advance!

Answer 1

On your second page, you need to check whether the value is the same as the one you received from the first page:
echo "<option value='".$row1[fldNetname]."' " . (($row1[fldNetname] == $get_id)?"selected":"") . ">".$row1[fldNetname]."</option>";

Answer 2

if $get_ID, is actually your $_GET['id'] value, then just do...
while ($row1 = mysql_fetch_array($q))
{
echo "<option value='".$row1['fldNetname']."'";
if($row1['fldNetname']==$get_ID){echo "selected='selected'";}
echo ">".$row1['fldNetname']."</option>";
}
Or as one line...
while ($row1 = mysql_fetch_array($q))
{
echo "<option value='".$row1['fldNetname']."' " . (($row1['fldNetname'] == $get_ID)?"selected='selected'":"") . ">".$row1'[fldNetname']."</option>"
}

Answer 3

Have you tried?
changing (on the second page)
<option value="">- select -</option>
to
<option value="<?php echo $yourVar; ?>"><?php echo $yourVar; ?></option>
Then in the while loop, skip the value selected to prevent a duplicate choice.
Something like:
while ($row1 = mysql_fetch_array($q))
{
if($yourVar != $row1[fldNetname]){
echo "<option value='".$row1[fldNetname]."'>".$row1[fldNetname]."</option>";
}
}