Form was not submitted with checkbox array - php

Although the following function has a little problem. But I can not find. Every time either checkbox is checked or not but form was not submitted!!
<input type="checkbox" name="chk_user[]" value="1" class="chk_delete" id="1" />
<input type="checkbox" name="chk_user[]" value="2" class="chk_delete" id="2" />
<input type="checkbox" name="chk_user[]" value="3" class="chk_delete" id="3" />
<input type="checkbox" name="chk_user[]" value="4" class="chk_delete" id="4" />
<script>
$("form").submit(function() {
$('.chk_delete').each(function(){
if($(this).is(':checked')){
return true;
}
});
alert("No entry was selected!");
return false;
});
</script>
Can anybody locate the problem?
The following is working, but I don't understand why. Any good logic?
$("form").submit(function(e) {
if(!$('input[type=checkbox]:checked').length) {
e.preventDefault();
alert("No entry was selected!"); }
return true; });

Give this a whirl:
$("form").submit(function(e) {
if(!$('input[type=checkbox]:checked').length) {
e.preventDefault();
alert("No entry was selected!"); }
return true; });

You are using the return true into the each loop. Using return in the each loop just mean if the loop continue (on true) or if it stop (on false).
That beign said, you script will alway roll hover a return false, preventing the form from submiting.
What you could do
If you want to keep the loop, save if it's true or false in a var!
var isChecked = false;
$('.chk_delete').each(function(){
isChecked = $(this).is(':checked')
return !isChecked;
});
return isChecked;
OR
Use your working script, I don't see what's wrong with it
$("form").submit(function(e) {
if(!$('input[type=checkbox]:checked').length) {
e.preventDefault();
alert("No entry was selected!");
}
return true;
});
$('input[type=checkbox]:checked') select every checked box. So $('input[type=checkbox]:checked').length take the length. Having ! is the same thing as !=.
Finally, !$('input[type=checkbox]:checked').length is a shotcut for $('input[type=checkbox]:checked') != 0. If true, it .preventDefault() wich prevent the form of submiting.

Related

jQuery submit form via submit button

Is it possible to submit a form by clicking a div-element as if it was submitted by the submit button?
So that this PHP works:
if(isset($_POST["share"])) { /* do something*/ }
Form:
<form id="form" action="publish.php" method="POST">
<textarea name="description" maxlength="500">Description...</textarea>
<input type="submit" name="share" value="Share" />
</form>
This does NOT post the share value, $_POST['share'].
if($(".post-form").length){
$(".post-form").click(function(event) {
$("#form").submit();
return false;
});
}
Yes this is possible by using the .submit() function. You can use it like so:
// Wait until the document has been fully loaded
$(document).ready(function() {
// Bind a click event to your element
$('div').click(function(event) {
// Submit the form
// The callback should add a hidden field with the name "share"
$('form').submit(function(eventObj) {
$('<input />').attr('type', 'hidden')
.attr('name', "share")
.attr('value', "Share")
.appendTo('form');
return true;
});
});
});
You can find more information here
Demo: jsfiddle
Set an id for submit button:
<input type="submit" name="share" value="Share" id="btn_submit" />
then you can control it in jquery like this:
$("#btn_submit").onclick(function(){
if(condition==true)
{
return true;
}
else
{
return false;
}
});

Check if check box is checked using PHP and AJAX [duplicate]

I need to check the checked property of a checkbox and perform an action based on the checked property using jQuery.
For example, if the age checkbox is checked, then I need to show a textbox to enter age, else hide the textbox.
But the following code returns false by default:
if ($('#isAgeSelected').attr('checked')) {
$("#txtAge").show();
} else {
$("#txtAge").hide();
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" id="isAgeSelected"/>
<div id="txtAge" style="display:none">
Age is selected
</div>
How do I successfully query the checked property?
How do I successfully query the checked property?
The checked property of a checkbox DOM element will give you the checked state of the element.
Given your existing code, you could therefore do this:
if(document.getElementById('isAgeSelected').checked) {
$("#txtAge").show();
} else {
$("#txtAge").hide();
}
However, there's a much prettier way to do this, using toggle:
$('#isAgeSelected').click(function() {
$("#txtAge").toggle(this.checked);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" id="isAgeSelected"/>
<div id="txtAge" style="display:none">Age is something</div>
Use jQuery's is() function:
if($("#isAgeSelected").is(':checked'))
$("#txtAge").show(); // checked
else
$("#txtAge").hide(); // unchecked
Using jQuery > 1.6
<input type="checkbox" value="1" name="checkMeOut" id="checkMeOut" checked="checked" />
// traditional attr
$('#checkMeOut').attr('checked'); // "checked"
// new property method
$('#checkMeOut').prop('checked'); // true
Using the new property method:
if($('#checkMeOut').prop('checked')) {
// something when checked
} else {
// something else when not
}
jQuery 1.6+
$('#isAgeSelected').prop('checked')
jQuery 1.5 and below
$('#isAgeSelected').attr('checked')
Any version of jQuery
// Assuming an event handler on a checkbox
if (this.checked)
All credit goes to Xian.
I am using this and this is working absolutely fine:
$("#checkkBoxId").attr("checked") ? alert("Checked") : alert("Unchecked");
Note: If the checkbox is checked it will return true otherwise undefined, so better check for the "TRUE" value.
Use:
<input type="checkbox" name="planned_checked" checked id="planned_checked"> Planned
$("#planned_checked").change(function() {
if($(this).prop('checked')) {
alert("Checked Box Selected");
} else {
alert("Checked Box deselect");
}
});
$("#planned_checked").change(function() {
if($(this).prop('checked')) {
alert("Checked Box Selected");
} else {
alert("Checked Box deselect");
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<input type="checkbox" name="planned_checked" checked id="planned_checked"> Planned
Since jQuery 1.6, the behavior of jQuery.attr() has changed and users are encouraged not to use it to retrieve an element's checked state. Instead, you should use jQuery.prop():
$("#txtAge").toggle(
$("#isAgeSelected").prop("checked") // For checked attribute it returns true/false;
// Return value changes with checkbox state
);
Two other possibilities are:
$("#txtAge").get(0).checked
$("#txtAge").is(":checked")
This worked for me:
$get("isAgeSelected ").checked == true
Where isAgeSelected is the id of the control.
Also, #karim79's answer works fine. I am not sure what I missed at the time I tested it.
Note, this is answer uses Microsoft Ajax, not jQuery
If you are using an updated version of jquery, you must go for .prop method to resolve your issue:
$('#isAgeSelected').prop('checked') will return true if checked and false if unchecked. I confirmed it and I came across this issue earlier. $('#isAgeSelected').attr('checked') and $('#isAgeSelected').is('checked') is returning undefined which is not a worthy answer for the situation. So do as given below.
if($('#isAgeSelected').prop('checked')) {
$("#txtAge").show();
} else {
$("#txtAge").hide();
}
Use:
<input type="checkbox" id="abc" value="UDB">UDB
<input type="checkbox" id="abc" value="Prasad">Prasad
$('input#abc').click(function(){
if($(this).is(':checked'))
{
var checkedOne=$(this).val()
alert(checkedOne);
// Do some other action
}
})
This can help if you want that the required action has to be done only when you check the box not at the time you remove the check.
You can try the change event of checkbox to track the :checked state change.
$("#isAgeSelected").on('change', function() {
if ($("#isAgeSelected").is(':checked'))
alert("checked");
else {
alert("unchecked");
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" id="isAgeSelected" />
<div id="txtAge" style="display:none">
Age is selected
</div>
Using the Click event handler for the checkbox property is unreliable, as the checked property can change during the execution of the event handler itself!
Ideally, you'd want to put your code into a change event handler such as it is fired every time the value of the check box is changed (independent of how it's done so).
$('#isAgeSelected').bind('change', function () {
if ($(this).is(':checked'))
$("#txtAge").show();
else
$("#txtAge").hide();
});
I ran in to the exact same issue. I have an ASP.NET checkbox
<asp:CheckBox ID="chkBox1" CssClass='cssChkBox1' runat="server" />
In the jQuery code I used the following selector to check if the checkbox was checked or not, and it seems to work like a charm.
if ($("'.cssChkBox1 input[type=checkbox]'").is(':checked'))
{ ... } else { ... }
I'm sure you can also use the ID instead of the CssClass,
if ($("'#cssChkBox1 input[type=checkbox]'").is(':checked'))
{ ... } else { ... }
I hope this helps you.
I believe you could do this:
if ($('#isAgeSelected :checked').size() > 0)
{
$("#txtAge").show();
} else {
$("#txtAge").hide();
}
I decided to post an answer on how to do that exact same thing without jQuery. Just because I'm a rebel.
var ageCheckbox = document.getElementById('isAgeSelected');
var ageInput = document.getElementById('txtAge');
// Just because of IE <333
ageCheckbox.onchange = function() {
// Check if the checkbox is checked, and show/hide the text field.
ageInput.hidden = this.checked ? false : true;
};
First you get both elements by their ID. Then you assign the checkboxe's onchange event a function that checks whether the checkbox got checked and sets the hidden property of the age text field appropriately. In that example using the ternary operator.
Here is a fiddle for you to test it.
Addendum
If cross-browser compatibility is an issue then I propose to set the CSS display property to none and inline.
elem.style.display = this.checked ? 'inline' : 'none';
Slower but cross-browser compatible.
This code will help you
$('#isAgeSelected').click(function(){
console.log(this.checked);
if(this.checked == true) {
$("#txtAge").show();
} else {
$("#txtAge").hide();
}
});
This works for me:
/* isAgeSelected being id for checkbox */
$("#isAgeSelected").click(function(){
$(this).is(':checked') ? $("#txtAge").show() : $("#txtAge").hide();
});
There are many ways to check if a checkbox is checked or not:
Way to check using jQuery
if (elem.checked)
if ($(elem).prop("checked"))
if ($(elem).is(":checked"))
if ($(elem).attr('checked'))
Check example or also document:
http://api.jquery.com/attr/
http://api.jquery.com/prop/
This is some different method to do the same thing:
$(document).ready(function (){
$('#isAgeSelected').click(function() {
// $("#txtAge").toggle(this.checked);
// Using a pure CSS selector
if ($(this.checked)) {
alert('on check 1');
};
// Using jQuery's is() method
if ($(this).is(':checked')) {
alert('on checked 2');
};
// // Using jQuery's filter() method
if ($(this).filter(':checked')) {
alert('on checked 3');
};
});
});
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<input type="checkbox" id="isAgeSelected"/>
<div id="txtAge" style="display:none">Age is something</div>
Use this:
if ($('input[name="salary_in.Basic"]:checked').length > 0)
The length is greater than zero if the checkbox is checked.
My way of doing this is:
if ( $("#checkbox:checked").length ) {
alert("checkbox is checked");
} else {
alert("checkbox is not checked");
}
$(selector).attr('checked') !== undefined
This returns true if the input is checked and false if it is not.
You can use:
if(document.getElementById('isAgeSelected').checked)
$("#txtAge").show();
else
$("#txtAge").hide();
if($("#isAgeSelected").is(':checked'))
$("#txtAge").show();
else
$("#txtAge").hide();
Both of them should work.
$(document).ready(function() {
$('#agecheckbox').click(function() {
if($(this).is(":checked"))
{
$('#agetextbox').show();
} else {
$('#agetextbox').hide();
}
});
});
1) If your HTML markup is:
<input type="checkbox" />
attr used:
$(element).attr("checked"); // Will give you undefined as initial value of checkbox is not set
If prop is used:
$(element).prop("checked"); // Will give you false whether or not initial value is set
2) If your HTML markup is:
<input type="checkbox" checked="checked" />// May be like this also checked="true"
attr used:
$(element).attr("checked") // Will return checked whether it is checked="true"
Prop used:
$(element).prop("checked") // Will return true whether checked="checked"
This example is for button.
Try the following:
<input type="button" class="check" id="checkall" value="Check All" /> <input type="button" id="remove" value="Delete" /> <br/>
<input type="checkbox" class="cb-element" value="1" /> Checkbox 1 <br/>
<input type="checkbox" class="cb-element" value="2" /> Checkbox 2 <br/>
<input type="checkbox" class="cb-element" value="3" /> Checkbox 3 <br/>
$('#remove').attr('disabled', 'disabled');
$(document).ready(function() {
$('.cb-element').click(function() {
if($(this).prop('checked'))
{
$('#remove').attr('disabled', false);
}
else
{
$('#remove').attr('disabled', true);
}
});
$('.check:button').click(function()
{
var checked = !$(this).data('checked');
$('input:checkbox').prop('checked', checked);
$(this).data('checked', checked);
if(checked == true)
{
$(this).val('Uncheck All');
$('#remove').attr('disabled', false);
}
else if(checked == false)
{
$(this).val('Check All');
$('#remove').attr('disabled', true);
}
});
});
The top answer didn't do it for me. This did though:
<script type="text/javascript">
$(document).ready(function(){
$("#li_13").click(function(){
if($("#agree").attr('checked')){
$("#saveForm").fadeIn();
}
else
{
$("#saveForm").fadeOut();
}
});
});
</script>
Basically when the element #li_13 is clicked, it checks if the element # agree (which is the checkbox) is checked by using the .attr('checked') function. If it is then fadeIn the #saveForm element, and if not fadeOut the saveForm element.
To act on a checkbox being checked or unchecked on click.
$('#customCheck1').click(function() {
if (this.checked) {
console.log('checked');
} else {
console.log('un-checked');
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type="checkbox" id="customCheck1">
EDIT: Not a nice programming expression if (boolean == true) though .checked property might return other type variables as well..
It is better to use .prop("checked") instead. It returns true and false only.
I am using this:
<input type="checkbox" id="isAgeSelected" value="1" /> <br/>
<input type="textbox" id="txtAge" />
$("#isAgeSelected").is(':checked') ? $("#txtAge").show() : $("#txtAge").hide();
Though you have proposed a JavaScript solution for your problem (displaying a textbox when a checkbox is checked), this problem could be solved just by css. With this approach, your form works for users who have disabled JavaScript.
Assuming that you have the following HTML:
<label for="show_textbox">Show Textbox</label>
<input id="show_textbox" type="checkbox" />
<input type="text" />
You can use the following CSS to achieve the desired functionality:
#show_textbox:not(:checked) + input[type=text] {display:none;}
For other scenarios, you may think of appropriate CSS selectors.
Here is a Fiddle to demonstrate this approach.

Form not submitting through outside button using Jquery

I have a form
<div id='formdiv'>
<form action='purchase.php' method="POST" id="purchaseform">
......
<input type="submit" value="Add Purchase" />
</form></div>
After user submits the form..he is first made to confirm the enteries:
$('#purchaseform').submit(function(){
$('#formdiv').hide();
$('#confirmdiv').show();
return false;
});
where the confirm div is:
<div id='confirmdiv'>
data to be confirmed....
<input type="button" value="Confirm" id = "confirmform"/>
<input type="button" value="Cancel" id = "cancelform"/>
</div>
I am trying to submit the form once user clicks on confirm button
$('#confirmform').click(function(){
$('#purchaseform').submit();
$('#formdiv').show();
$('#confirmdiv').hide();
});
But the form is not submitting...anyone knows what am i doing wrong here??
its because when you call the $('#purchaseform').submit(); it will again read your first statement which is
$('#purchaseform').submit(function(){
$('#formdiv').hide();
$('#confirmdiv').show();
return false;
});
try using a hidden input to indicate if the datas are confirmed or not. In your form put a hidden textfield
<div id='formdiv'>
<form action='purchase.php' method="POST" id="purchaseform">
<input type="submit" value="Add Purchase" />
<input type="hidden" name="isconfirm" id="isconfirm" value="0" />
</form></div>
then in your other statement put a condition before you call return false and the other functions
$('#purchaseform').submit(function(){
var confirm = $("#isconfirm").val();
if(confirm == 0) {
$('#formdiv').hide();
$('#confirmdiv').show();
return false; }
});
then change this as well
$('#confirmform').click(function(){
$("#isconfirm").val(1); //change the value to 1
$('#purchaseform').submit();
$('#formdiv').show();
$('#confirmdiv').hide();
});
It's pretty logical that it's not submitting. After all, whenever it tries to submit, it will instead go to your submit event handler, which always returns false. You have to make sure that if the submit comes from your script instead of from the button in the form, it does submit. One way to do that is like this:
var confirmed = false;
$('#purchaseform').submit(function(){
if (!confirmed)
{
$('#formdiv').hide();
$('#confirmdiv').show();
return false;
}
else
{
confirmed = false;
return true;
}
});
$('#confirmform').click(function(){
confirmed = true;
$('#purchaseform').submit();
$('#formdiv').show();
$('#confirmdiv').hide();
});
This can easily be edited to suit your needs. Another way to do this would be to instead bind the original event to the submit button instead of the actual submit event, but if you do that, you might get into trouble later on if you have a text field in the form and the user presses enter while it's selected. This would then directly submit without confirmation, whereas in the above solution it will neatly ask for a confirmation.
you want to have a confirm dialog, first i think that is better to use the jquery ui dialog plugin http://jqueryui.com/dialog/#modal-confirmation
Here is the code to use :
1- add "display:none" to your confirm dialog
<div id='confirmdiv' style="display:none">
data to be confirmed....
</div>
delete confirm event
$('#confirmform').click ....
2- init your dialog
$( "#confirmdiv" ).dialog({
resizable: false,
height:140,
modal: true,
buttons: {
"Confirm": function() {
$('#purchaseform').submit();
},
"Cancel": function() {
$( this ).dialog( "close" );
}
}
});
3- Test your code
4- thats all folks
You are overriding what happens when the form gets submitted in
$('#purchaseform').submit(function(){
$('#formdiv').hide();
$('#confirmdiv').show();
return false;
});
Instead, how about you use
$('#purchaseform').find(":submit").click(function(e){
$('#formdiv').hide();
$('#confirmdiv').show();
return false;
}
Or, of course, you can set an ID on the submit button and use that.
That's because your $('#confirmform').submit() function invoke the 1st submit function again.

Error bind click on jquery check value empty

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#btnSubmit').bind('click', function(){
var option = $('#option1').val();
if(option == ''){
alert('Answer empty');
}
return false;
});
});
</script>
...
<input type="radio" id="option1" name="option1 />
<input type="submit" name="btnSubmit" id="btnSubmit" value="submit" />
...
=> error click button submit not alert
Because the value of that radio is on (default value), look here: http://jsfiddle.net/DV9WP/
you should modify you code a bit get the value of :checked radio button and if its not checked it means the value is empty and alert the answer is empty
for example
$('#btnSubmit').bind('click', function(){
alert("");
var option = $('#option1:checked').val();
if(!option){
alert('Answer empty');
}
return false;
});
here is the working example http://jsfiddle.net/L8VY8/

jQuery broken function after added new function

What's wrong here? The alert function was working until I added this new function to it.
Is there anything I am doing wrong? It just simply doesn't fire the alert anymore.
<input value="1" type="checkbox" name="salgsvilkar" id="checkbox2" style="float:left;"
/>
{literal}
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(function() {
//checkbox
$("#scrollwrap").click(function(){
$("#scrollwrap").toggleClass('highlight');
});​
});
$(function(){
//button
$("#fullfor_btn").click(function(e){
if(!$("#checkbox2").is(':checked') == false)
{
alert("Please accept the terms of sale.");
e.preventDefault();
}
});
});
</script>
{/literal}
<button type="submit" class="submit" name="{$method}" id="fullfor_btn" title="Fullfør bestillingen nå" value=""> </button>
Instead of:
if(!$("#checkbox2").is(':checked') == false) {
why not just use the much more readable:
if($("#checkbox2").is(':checked')) {
EDIT: If your intention is for the alert to fire when the checkbox is not checked:
if(!$("#checkbox2").is(':checked')) {
Your logic is probably not what you intended, as karim79 said.
if(!$("#checkbox2").is(':checked') == false)
is identical in function to
if($("#checkbox2").is(':checked') == true)
so your alert will only trigger when the checkbox is checked.
you can put all your code in the same $(function(){ code }) in your example, you are setting the document ready twice
$(function() {
//checkbox
$("#scrollwrap").click(function(){
$("#scrollwrap").toggleClass('highlight');
});​
//button
$("#fullfor_btn").click(function(e){
if($("#checkbox2").is(':checked'))
{
alert("Please accept the terms of sale.");
e.preventDefault();
}
});
});
Works for me.
Though it seems a little odd that you'd trigger the alert when the checkbox is checked, instead of when it is not.

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