PDO/MySQL fetch multiple columns with if statement - php

Question

I'm currently trying to fetch two images location from my database, how do I return both columns and if both empty then echo another image. This is what I've got so far.
How do I return both photo and photo_small so that I may echo them in a php file.
PUBLIC FUNCTION Profile_Pic($uiD) {
$sth = $this->db->prepare("SELECT photo,photo_small FROM users WHERE uiD = :id");
$sth->execute(array(':id' => $uiD));
if ($sth->rowCount() > 0) {
$data = $row['photo'];
return $data;
} else {
$data = './icons/users.png';
return $data;
}
}

Answer 1

PUBLIC FUNCTION Profile_Pic($uiD) {
$sql = "SELECT photo,photo_small FROM users WHERE uiD = ?";
$sth = $this->db->prepare($sql);
$sth->execute(array($uiD));
$data = $sth->fetch();
if (empty($data['photo'])) {
$data['photo'] = './icons/users.png';
}
if (empty($data['photo_small'])) {
$data['photo_small'] = './icons/users.png';
}
return $data;
}
if you want to replace both images if even one is absent
PUBLIC FUNCTION Profile_Pic($uiD) {
$sql = "SELECT photo,photo_small FROM users WHERE uiD = ?";
$sth = $this->db->prepare($sql);
$sth->execute(array($uiD));
$data = $sth->fetch();
if (empty($data['photo']) || empty($data['photo_small'])) {
$data['photo'] = './icons/users.png';
$data['photo_small'] = './icons/users.png';
}
return $data;
}

Answer 2

Just return all of the values you want in an array.
You can ensure that both photo and photo_small are not empty strings or NULL by using empty().
Don't forget to retrieve your row using PDOStatement::fetch().
You should not use rowCount() to determine the number of rows returned in a SELECT statement. According to the documentation for PDOStatement::rowCount():
For most databases, PDOStatement::rowCount() does not return the number of rows affected by a SELECT statement.
Try this:
$row = $sth->fetch(PDO::FETCH_ASSOC);
if ($row && !empty($row['photo']) && !empty($row['photo_small'])) {
$data = array('photo' => $row['photo'], 'photo_small' => $row['photo_small']);
return $data;
} else {
$data = array('photo' => './icons/users.png', 'photo_small' => './icons/users.png');
return $data;
}
Then when you call the function, your returned result can be used like this:
$uiD = 1;
$result = Profile_Pic($uiD);
$photo = $result['photo'];
$photo_small = $result['photo_small'];