I'm having trouble getting JSON data sent from JavaScript to PHP. Here is my Javascript:
var noteData = {
nData: {
"postID": $postID,
"commentPar": $commentPar,
"commentValue": $commentValue
}
}
var sendData = JSON.stringify(noteData);
$.ajax({
type: "POST",
url: templateUrl+"/addnote.php",
data: sendData,
dataType : 'json',
success: function(data) {
alert(data);
console.log(sendData);
},
error: function(e) {
console.log(e.message);
console.log(noteData);
console.log(sendData);
alert("error");
}
});
Here is how I just test if the data is even being passed to PHP, it always returns back null.
<?php
$nData = json_decode($_POST['nData']);
echo json_encode($nData);
?>
What am I doing wrong?
You are sending the data as raw JSON to PHP, not as POST parameter.
There are two alternatives. The first one leaves your PHP intact:
var noteData = {
nData: {
"postID": $postID,
"commentPar": $commentPar,
"commentValue": $commentValue
}
}
var sendData = JSON.stringify(noteData);
$.ajax({
type: "POST",
url: templateUrl+"/addnote.php",
data: {
nData: sendData
},
dataType : 'json',
success: function(data) {
alert(data);
console.log(sendData);
},
error: function(e) {
console.log(e.message);
console.log(noteData);
console.log(sendData);
alert("error");
}
});
The second one modifies the PHP side alone. You need to read the input stream directly to obtain the raw data.
<?php
$nData = json_decode(file_get_contents('php://input'));
echo json_encode($nData);
This one might be slightly different depending on the server configuration. See the documentation on the input stream wrappers.
Tell your post request that you are sending json object
contentType: "application/json"
Related
As the title says, I failed to pass the data array via json ajax to php. I am using codeigniter, what did I do wrong? here is the jQuery code:
function load_page_data1(){
var data = [];
data['val'] = "solid_t1";
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/Chart_varnish/getdata',
data: data,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
}
Here is the php code:
function getdata(){
$parameter = '';
if(isset($_POST))
{
if(isset($_POST['val']))
{
$parameter = $_POST['val'];
} else
{
echo "failed!";
}
}
$this->load->model('Chart');
$this->load->helper('url');
$data1 = $this->Chart->getdata_solid($parameter);
echo json_encode($data1);
}
Final:
Guys, it turn out that the values did passed from jQuery to php, the problem is that I stupidly call the same php function twice within the javascript function, then the second time calling without posting the 'val', so that the php function error and stop.
Thank you all for your answers, at least I learn the different ways to passing data by using jQuery.
Don't make a array if it's not a array just make a object
var data = {};
data.val = "solid_t1";
// equivalent to
data ={val:"solid_t1"};
// equivalent to
data['val'] ="solid_t1";
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/Chart_varnish/getdata',
data: data,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
Update 1: if you need to send array you need to make a proper array object like below
Example :
var data=[];
item ={val:'value'};
data.push(item);
var new_data = JSON.stringify(data);
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/Chart_varnish/getdata',
data: new_data,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
For Debugging :
May be problem with your server side code .so for the testing purpose comment all the line in function just do this echo json_encode($_POST); and in your ajax success function just add console.log(output); and let me know the result.
create one json object
jsonObj = [];
create array list as per your need
item = {}
item ["val"] = "solid_t1";
push the array list in to the json.
jsonObj.push(item);
Please have a try like this. It is working in my case.
Your full code will be like
function load_page_data1(){
jsonObj = [];
item = {}
item ["val"] = "solid_t1";
jsonObj.push(item);
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/Chart_varnish/getdata',
data: jsonObj,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
}
The another way to use this is given below.
function load_page_data1(){
var jsonObj = {};
jsonObj["val"] = "solid_t1";
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/Chart_varnish/getdata',
data: jsonObj,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
}
Instead of var data = []; use var data = {}; to initialize your data. It should solve your problem.
Your data wasn't being passed as json, now it will.
Code will be:
function load_page_data1(){
var data = {};
data['val'] = "solid_t1";
$.ajax({
type: 'POST',
url: BASE_URL+'index.php/welcome/getdata',
data: data,
dataType: 'json',
success: function(output) {
alert(output);
},
error: function(request, status, error){
alert("Error: not working");
}
});
}
One more suggestion please use CI input library for post request in controller.
e.g.
$parameter = $this->input->post('val');
I am trying to get my search bar working, however I am having issues with an ajax post.
For whatever reason, none of the data is being appended to the URL. I have tried various things with no success. I am attempting to send the data to the same page (index.php).
Here is my jquery:
$(function(){
$(document).on({
click: function () {
var tables = document.getElementsByTagName("TABLE");
for (var i = tables.length-1; i >= 0; i-= 1) {
if (tables[i]) tables[i].parentNode.removeChild(tables[i]);
}
var text = $('#searchBar').val();
var postData = JSON.stringify({ searchTerm: text });
$.ajax({
type: 'POST',
url: 'index.php',
dataType: 'json',
data: postData,
success: function() {
alert("Test");
}
});
}
}, "#searchButton");
});
And here is the php which I have with index.php:
<?php
require('course.php');
if(isset($_POST['searchTerm'])) {
echo $_POST['searchTerm'];
}
?>
No matter what I try, I am unable to get anything to post. I have checked the network tab in chrome, and I'm not seeing anything that indicates it's working correctly.
Any ideas?
EDIT:
I've changed my code to this, and it seems I'm getting closer:
$(document).on({
click: function () {
$("TABLE").remove()
var text = $('#searchBar').val();
$.ajax({
type: 'GET',
url: 'index.php',
dataType: 'text',
data: { searchTerm: text },
success: function() {
alert("Test");
}
});
}
}, "#searchButton");
And:
<?php
require('course.php');
if(isset($_GET['searchTerm'])) {
echo $_GET['searchTerm'];
}
?>
Now I am getting ?searchTerm=theTextIEnter as expected, however it's still not being echoed in index.php.
Do not use JSON.stringify() to convert object to string. data passed to $.ajax must be an object and not JSON.
For whatever reason, none of the data is being appended to the URL.
You are making a POST request. POST data is sent in the request body, not in the query string component of the URL.
If you change it to a GET request (and inspect it in the correct place, i.e. the Network tab of your browser's developer tools and not the address bar for the browser) then you would see the data in the query string.
This will work for you use data: { postData } on place of data:postData and you will receive your data in $_POST['postData']
$(function(){
$(document).on({
click: function () {
var tables = document.getElementsByTagName("TABLE");
for (var i = tables.length-1; i >= 0; i-= 1) {
if (tables[i]) tables[i].parentNode.removeChild(tables[i]);
}
var text = $('#searchBar').val();
var postData = JSON.stringify({ 'searchTerm' : text });
$.ajax({
type: 'POST',
url: 'index.php',
dataType: 'json',
data: { postData },
success: function(data) {
alert(data.searchTerm);
}
});
}
}, "#searchButton");
});
In index.php
<?php
if(isset($_POST['postData'])) {
echo $_POST['postData'];
die;
}
?>
If you want to send data via the URL you have to use a GET request. To do this, change the type of the request to GET and give the object directly to the data parameter in your jQuery, and use $_GET instead of $_POST in your PHP.
Finally note that you're not returning JSON - you're returning text. If you want to return JSON, use json_encode and get the value in the parameter of the success handler function.
Try this:
$(document).on({
click: function () {
$('table').remove();
$.ajax({
type: 'GET',
url: 'index.php',
dataType: 'json',
data: { searchTerm: $('#searchBar').val() },
success: function(response) {
console.log(response.searchTerm);
}
});
}
}, "#searchButton");
<?php
require('course.php');
if(isset($_GET['searchTerm'])) {
echo json_encode(array('searchTerm' => $_GET['searchTerm']));
}
?>
Remove dataType: 'json', from your AJAX. That is all.
Your response type is not JSON, yet by setting dataType: 'json' you're implying that it is. So when no JSON is detected in the response, nothing gets sent back to the method handler. By removing dataType it allows the API to make an educated decision on what the response type is going to be, based on the data you're returning in the response. Otherwise, you can set dataType to 'text' or 'html' and it will work.
From the manual:
dataType: The type of data that you're expecting back from the server.
This is NOT the type of data you're sending/posting, it's what you're expecting back. And in your index.php file you're not sending back any JSON. This is why the success() method is not satisfying. Always set the dataType to the type of data you're expecting back in the response.
With POST Request:
Please comment below line in your code:
//var postData = JSON.stringify({ searchTerm: text });
And use below ajax code to get the post-data:
$.ajax({
type: 'POST',
url: 'index.php',
dataType: 'json',
data: { searchTerm: text },
success: function() {
alert("Test");
}
});
With GET Request:
You can convert your data to query string parameters and pass them along to the server that way.
$.ajax({
type: 'GET',
url: 'index.php?searchTerm='+text,
dataType: 'json',
success: function(response) {
alert(response);
}
});
In response, You can get the data with alert, so you may get idea about the same.
I have the following code on product.php .. can't seem to echo post variable from ajax post. Alert displays fine. Please help
JQUERY
document.getElementById("LBTest").onchange = function(){
var lbtest = $('#LBTest :selected').val();
$.ajax({
type: "POST",
url: "product.php",
data: {test: lbtest},
success: function()
{
alert("Successful");
}
});
}
PHP
if(isset($_POST['test'])){
$data = $_POST['test'];
echo $data;
}
You need to do something with the data you receive from the ajax call. For example, to put the result into a <div> called resultDiv:
success: function(data)
{
$('#resultDiv').html(data);
alert("Successful");
}
$.ajax({
type: "POST",
url: "product.php",
data: {test: lbtest},
success: function(data)
{
alert("Successful");
}
});
You need to add the data to the success function that is called. You can do this locally or reference another function meant to handle responses coming back from the server.
success: function(data)
{
console.log(data);
alert(data + " was returned from the server");
}
It is a good idea on the server side to json_encode the objects that are being returned and using error codes that can be more appropriately handled on the client.
handleResponse(data) {
var data = $.parseJSON(data);
if(data.code >= 200 || data.code < 300) {
// modify the dom, add data to a model, take over the world with your web app.
}
}
This is the jquery ajax part in which i have sent json data to the php file.
$(function () {
$('form').submit(function () {
var fields = $(this).serializeArray();
var ans_json = JSON.stringify(fields);
console.log(ans_json);
$.ajax({
url: "results.php",
type: "POST",
data: ans_json,
dataType: "json",
success: function (result) {
console.log(result);
}
});
return false;
});
});
Now i want to use this json data sent to the php page.How can i do it? I have done it this way but it returns null.
<?php
echo json_decode('ans_json');
?>
I have a set of 10 questions which need to be answered. 3 questions were answered so got the below result.This is what i got in my console.
[{"name":"answer_9","value":"a"},{"name":"answer_10","value":"a"}] quizzes.php:14
null
You don't need to decode any JSON string at server-side if you encode properly your parameters.
You can use .serialize() to do the form serialization for you, and it's ready to send.
$(function () {
$('form').submit(function () {
var serialized = $(this).serialize();
$.ajax({
url: "results.php",
type: "POST",
data: serialized,
...
});
return false;
});
});
Your parameters will be available in your $_POST as in any normal POST request. For example,
$ninth_answer = $_POST["answer_9"];
You need to decode the POST variable. Currently you're decoding just a string which even isn't valid JSON.
<?php
$json_arr = json_decode($_POST['my_json'], true);
var_dump($json_arr);
echo "First name in json is:". $json_arr[0]['name'];
?>
and edit your javascript to reflect following:
This posts my_json parameter with your json as an value. This makes it easy for PHP to recieve it using $_POST.
$.ajax({
url: "results.php",
type: "POST",
data: {"my_json": ans_json},
dataType: "json",
success: function (result) {
console.log(result);
}
});
I suggest to read a little about those things:
http://api.jquery.com/jQuery.ajax/
http://ee1.php.net/manual/en/function.json-decode.php
I am trying to send a JSON to my PHP script and for some reason is returning null in the alert message.
I've searched throughout Stack Overflow and other forums and used other people's examples but somehow I keep getting it wrong. I checked in Firebug and the request is being sent. I am very new to handling JSON queries.
Could anyone point at what I am doing wrong so that I can learn for the next time?
My JQuery Code:
var name = $('#formName').val();
var regno = $('#formRegNo').val();
var charityinfo = $('#formCharityInfo').val();
var searchimprove = $('#formSearchImprove').val();
var finantialaid = $('#formFinantialAid').val();
var contactname = $('#formContactName').val();
var contactphonenumber = $('#formContactPhoneNumber').val();
var contactfaxnumber = $('#formContactFaxNumber').val();
var contactemail = $('#formContactEmail').val();
var website = $('#formWebsite').val();
var address = $('#formAddress').val();
var postcode = $('#postCode').val();
var arrayData = {"name":name,"regno":regno,"charityinfo":charityinfo,"searchimprove":searchimprove,"finantialaid":finantialaid,"contactname":contactname,"contactphonenumber":contactphonenumber,"contactfaxnumber":contactfaxnumber,"contactemail":contactemail,"website":website,"address":address,"postcode":postcode};
console.log(name);
$.ajax({
url: "test.php",
type: "POST",
dataType: "json",
contentType: "json",
async: false,
data: arrayData,
success : function(response) {
alert(response);
},
error: function(){
alert("error");
}
}); //End AJAX
My PHP Code:
<?php
$return = $_POST;
echo json_decode($return);
?>
first, collect your form data in 1 step, serialize it as json:
var arrayData = $('#my_form_id').serialize();
If you post your data, you should post the appropriate post variable name with it. Add some more decriptive error handling:
$.ajax({
url: "/test.php",
type: "POST",
data: 'mydata = ' + arrayData,
success : function(response) {
alert(response);
},
error: function (xhr, ajaxOptions, thrownError) {
alert(thrownError);
}
});
And then on the php side pick it up:
$mydata = $_POST['mydata'];
$arrayData = json_decode($mydata);
var_dump($arrayData);
You haven't encoded the data you are sending as JSON. You are passing an object to jQuery and allowing it to encode it (as application/x-www-form-urlencoded). You need to encode your data as JSON and pass a string to data:.
json is not a content-type, application/json is.
$_POST is populated from application/x-www-form-urlencoded or multipart/form-data, it doesn't contain the raw post request. You need to use php://input to get that.
First of all you don't need to create json yourself
use JSON.stringify() function function to create JSON
or you can also use the jquery serialize() function
var arrayData=$("FORMID").serialize();
$.ajax({
url: "test.php",
type: "POST",
dataType: "json",
contentType: "json",
async: false,
data: arrayData,
.....
and decode this json serverside using json_decode() function