hide empty rows inside of li - php

Question

I have a li with a couple of row..I can hide row's when in db have NULL, but when have empty I don't know how can do it.
this is the code I used:
<ul id="responds">
<?
$sql = $conn->prepare("SELECT id_diagnosticon, f_diagnosticon, id_paciente, id_doctor, diagnostico, diagnostico1, diagnostico2, diagnostico3, hconsulta2, presion_art, peso FROM DIAGNOSTICON where id_paciente = $_GET[id_paciente] order by id_diagnosticon DESC");
$sql->execute();
while($row = $sql->fetch(PDO::FETCH_ASSOC)) {
echo '<li id="item_'.$row["id_diagnosticon"].'">';
echo '<div class="del_wrapper"><a href="#" class="del_button" id="del-'.$row["id_diagnosticon"].'">';
echo '<img src="../images/icon_del.gif" border="0" />';
echo '</a></div>'; echo ' Fecha de consulta : ';echo $row["f_diagnosticon"]; echo ' <br><br> ';
if (!is_null($row["diagnostico"]))
{
echo '<b>Diagnostico de consulta :</b>'; echo $row["diagnostico"]; echo '<br><br>';
}
if (!is_null($row["diagnostico1"]))
{
echo '<b>Diagnostico 2 :</b>'; echo $row["diagnostico1"]; echo '<br><br>';
}
if (!is_null($row["diagnostico2"]))
{
echo '<b>Diagnostico 3 :</b>'; echo $row["diagnostico2"]; echo '<br><br>';
}
if (!is_null($row["diagnostico3"]))
{
echo '<b>Diagnostico 4 :</b>'; echo $row["diagnostico3"]; echo '<br><br>';
}
if (!is_null($row["presion_art"]))
{
echo '<b>Presi&oacuten Arterial : </b>'; echo $row["presion_art"];
}
if (!is_null($row["peso"]))
{
echo ' | <b> Peso : </b>'; echo $row["peso"];
}
echo '<br><br>';
echo $row["hconsulta2"].'</li>';
}
?>
</ul>
so I want to hide these row in li when the data in mysql in empty....right now only hide NULL data
-

Answer 1

Use empty:
if ( ! empty($row['something']) )
{
echo $row['something'];
}

Answer 2

Another option is to handle this with the query using COALESCE:
WHERE COALESCE(SomeField,'') <> ''