I am using the code below in my php file to get the values from a multiple checkbox.
if(!empty($_POST['check_list'])) {
foreach($_POST['check_list'] as $check) {
update_comment_meta($check, 'consider', 1);
}
}
The problem is that this code is apparently putting in the array $_POST['check_list'] only the checked values.
My need is to perfom the function update_comment_meta also on uncheked values, by putting '0' as the third parameter instead of '1'.
For more details, I give the code generating the HTML form:
<form action="" id="primaryPostForm" method="POST">
<?php
$defaults = array(
'post_id' => $current_post);
$com= get_comments( $defaults );
foreach ($com as $co) {
if(get_comment_meta($co->comment_ID, 'consider', true)==1) {
?><input type="checkbox" name="check_list[]" value="<?php echo $co->comment_ID; ?>" checked="checked">
<?php }
else {
?><input type="checkbox" name="check_list[]" value="<?php echo $co->comment_ID; ?>" >
<?php
}}
</form>
Your usual help is always appreciated.
sending unchecked value to post is somewhat not that easy.Better solution is that you name checkbox in a way using which you can easily iterate over them in post page.
Use hidden input along with checkbox.Checkbox prioritize over hidden input.
<form>
<input type='hidden' value='0' name='check_box_con'>
<input type='checkbox' value='1' name='check_box_con'>
</form>
Now after submit, as both have same name , check_box_con will show hidden field value if unchecked , else will override and show original.
For more see
Post the checkboxes that are unchecked
Here is the solution I used ( based on PeeHaa comment):
if(!empty($_POST['check_list'])) {
foreach ($com as $co) {
if (in_array($co->comment_ID,$_POST['check_list']))
update_comment_meta($co->comment_ID, 'consider', 1);
else
update_comment_meta($co->comment_ID, 'consider', 0);
}
}
In fact POST variable works like this with checkboxes, so the simple way is to use server side language to know what are values not sent via POST.
Thank you for your time.
Related
How to read if a checkbox is checked in PHP?
If your HTML page looks like this:
<input type="checkbox" name="test" value="value1">
After submitting the form you can check it with:
isset($_POST['test'])
or
if ($_POST['test'] == 'value1') ...
Zend Framework use a nice hack on checkboxes, which you can also do yourself:
Every checkbox generated is associated with a hidden field of the same name, placed just before the checkbox, and with a value of "0". Then if your checkbox as the value "1", you'll always get the '0' or '1' value in the resulting GET or POST
<input type="hidden" name="foo" value="0" />
<input type="checkbox" name="foo" value="1">
When using checkboxes as an array:
<input type="checkbox" name="food[]" value="Orange">
<input type="checkbox" name="food[]" value="Apple">
You should use in_array():
if(in_array('Orange', $_POST['food'])){
echo 'Orange was checked!';
}
Remember to check the array is set first, such as:
if(isset($_POST['food']) && in_array(...
Let your html for your checkbox will be like
<input type="checkbox" name="check1">
Then after submitting your form you need to check like
if (isset($_POST['check1'])) {
// Checkbox is selected
} else {
// Alternate code
}
Assuming that check1 should be your checkbox name.And if your form submitting method is GET then you need to check with $_GET variables like
if (isset($_GET['check1'])) {
// Checkbox is selected
}
$check_value = isset($_POST['my_checkbox_name']) ? 1 : 0;
I've been using this trick for several years and it works perfectly without any problem for checked/unchecked checkbox status while using with PHP and Database.
HTML Code: (for Add Page)
<input name="status" type="checkbox" value="1" checked>
Hint: remove checked if you want to show it as unchecked by default
HTML Code: (for Edit Page)
<input name="status" type="checkbox" value="1"
<?php if ($row['status'] == 1) { echo "checked='checked'"; } ?>>
PHP Code: (use for Add/Edit pages)
$status = $_POST['status'];
if ($status == 1) {
$status = 1;
} else {
$status = 0;
}
Hint: There will always be empty value unless user checked it. So, we already have PHP code to catch it else keep the value to 0. Then, simply use the $status variable for database.
To check if a checkbox is checked use empty()
When the form is submitted, the checkbox will ALWAYS be set, because ALL POST variables will be sent with the form.
Check if checkbox is checked with empty as followed:
//Check if checkbox is checked
if(!empty($_POST['checkbox'])){
#Checkbox selected code
} else {
#Checkbox not selected code
}
You can check the corresponding value as being set and non-empty in either the $_POST or $_GET array depending on your form's action.
i.e.: With a POST form using a name of "test" (i.e.: <input type="checkbox" name="test"> , you'd use:
if(isset($_POST['test']) {
// The checkbox was enabled...
}
You can do it with the short if:
$check_value = isset($_POST['my_checkbox_name']) ? 1 : 0;
or with the new PHP7 Null coalescing operator
$check_value = $_POST['my_checkbox_name'] ?? 0;
Learn about isset which is a built in "function" that can be used in if statements to tell if a variable has been used or set
Example:
if(isset($_POST["testvariabel"]))
{
echo "testvariabel has been set!";
}
Well, the above examples work only when you want to INSERT a value, not useful for UPDATE different values to different columns, so here is my little trick to update:
//EMPTY ALL VALUES TO 0
$queryMU ='UPDATE '.$db->dbprefix().'settings SET menu_news = 0, menu_gallery = 0, menu_events = 0, menu_contact = 0';
$stmtMU = $db->prepare($queryMU);
$stmtMU->execute();
if(!empty($_POST['check_menus'])) {
foreach($_POST['check_menus'] as $checkU) {
try {
//UPDATE only the values checked
$queryMU ='UPDATE '.$db->dbprefix().'settings SET '.$checkU.'= 1';
$stmtMU = $db->prepare($queryMU);
$stmtMU->execute();
} catch(PDOException $e) {
$msg = 'Error: ' . $e->getMessage();}
}
}
<input type="checkbox" value="menu_news" name="check_menus[]" />
<input type="checkbox" value="menu_gallery" name="check_menus[]" />
....
The secret is just update all VALUES first (in this case to 0), and since the will only send the checked values, that means everything you get should be set to 1, so everything you get set it to 1.
Example is PHP but applies for everything.
Have fun :)
$is_checked = isset($_POST['your_checkbox_name']) &&
$_POST['your_checkbox_name'] == 'on';
Short circuit evaluation will take care so that you don't access your_checkbox_name when it was not submitted.
A minimalistic boolean check with switch position retaining
<?php
$checked = ($_POST['foo'] == ' checked');
?>
<input type="checkbox" name="foo" value=" checked"<?=$_POST['foo']?>>
<?php
if (isset($_POST['add'])) {
$nama = $_POST['name'];
$subscribe = isset($_POST['subscribe']) ? $_POST['subscribe'] : "Not Checked";
echo "Name: {$nama} <br />";
echo "Subscribe: {$subscribe}";
echo "<hr />";
}
?>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<input type="text" name="name" /> <br />
<input type="checkbox" name="subscribe" value="news" /> News <br />
<input type="submit" name="add" value="Save" />
</form>
<form>
<input type="check" id=chk1 value="1">
<input type="check" id=chk2 value="1">
<input type="check" id=chk3 value="1">
</form>
when you check on chk2 you can see values as:
<?php
foreach($_POST as $key=>$value)
{
if(isset($key))
$$key=strip_tags($value);
}
insert into table (chk1,chk2,chk3) values ('','1','');
?>
in BS3 you can put
<?php
$checked="hola";
$exenta = $datosOrdenCompra[0]['exenta'];
var_dump($datosOrdenCompra[0]['exenta']);
if(isset($datosOrdenCompra[0]['exenta']) and $datosOrdenCompra[0]['exenta'] == 1){
$checked="on";
}else{
$checked="off";
}
?>
<input type="checkbox" id="exenta" name="exenta" <?php echo $checked;?> > <span class="label-text"> Exenta</span>
Please Note the usage of isset($datosOrdenCompra[0]['exenta'])
Wordpress have the checked() function.
Reference: https://developer.wordpress.org/reference/functions/checked/
checked( mixed $checked, mixed $current = true, bool $echo = true )
Description
Compares the first two arguments and if identical marks as checked
Parameters
$checked
(mixed) (Required) One of the values to compare
$current
(mixed) (Optional) (true) The other value to compare if not just true
Default value: true
$echo
(bool) (Optional) Whether to echo or just return the string
Default value: true
Return #Return
(string) html attribute or empty string
i have fixed it into a PHP form with a checkbox
$categories = get_terms( ['taxonomy' => 'product_cat', 'hide_empty' => false] );
foreach ($categories as $categorie) {
echo "<input type="checkbox" value="$categorie->term_taxonomy_id" name="catselected[]"> $categorie->slug";
}
This way i add it to the Woocommerce tabel.
wp_set_post_terms( $product_id, $_POST['catselected'], 'product_cat' );
filter_input(INPUT_POST, 'checkbox_name', FILTER_DEFAULT, FILTER_FORCE_ARRAY)
<?php
if(isset($_POST['nameCheckbox'])){
$_SESSION['fr_nameCheckbox'] = true;
}
?>
<input type="checkbox" name="nameCheckbox"
<?php
if(isset($_SESSION['fr_nameCheckbox'])){
echo 'checked';
unset($_SESSION['fr_nameCheckbox']);
}
?>
you should give name to your input .
then which box is clicked you will receive 'on' in your choose method
Array
(
[shch] => on
[foch] => on
[ins_id] => #
[ins_start] => شروع گفتگو
[ins_time] => ما معمولاً در چند دقیقه پاسخ میدهیم
[ins_sound] => https://.../media/sounds/ding-sound-effect_2.mp3
[ins_message] => سلام % به کمک نیاز دارید؟
[clickgen] =>
)
i have two checked box in my form name with 'shch' and 'foch'
This is my form and categories comes from the database with while loop.
I want to insert the checked inputs only in to database.
How can i detect which checkbox is selected ?
<form action="account.php" method="POST">
<ul class="account-info">
<li>Category1 : <input type="checkbox" value="val1" name="cat1"></li>
<li>Category2 : <input type="checkbox" value="val2" name="cat1"></li>
<li>Category3 : <input type="checkbox" value="val3" name="cat1"></li>
<!-- while continues -->
<li>Category100 : <input type="checkbox" value="val100" name="cat1"></li>
</ul>
<input type="submit" value="submit" />
</form>
In account.php only the check boxes will be posted. As you've named them all the same though, only 1 will be posted, the last checkbox. If you want them to have the same name and come through as an array you need to add [] after the name, like this:
<input type="checkbox" value="val100" name="cat1[]">
Then in your account.php where they are submitted you can do this:
foreach($_POST['cat1'] as $val)
{
echo "$val<br>";
}
That will echo out the values of all the checked boxes.
First off, you have your options set up as if they were radio buttons all having the same name turning into 1 value out of the 3 possible. If you want them to be conventional checkboxes you have to give them separate names.
in your PHP you would check if the array_key_exists for the checkbox name in question, this is how I usually translate the checkbox fields in a form to be easier to use:
<?php
$checked = array(
'cat1' => array_key_exists('cat1', $_POST),
'cat2' => array_key_exists('cat2', $_POST),
'cat3' => array_key_exists('cat3', $_POST)
);
print_r($checked);
exit;
?>
change the name="cat1" to name="cat[1][]"
in your account.php page
foreach($_POST['cat'] as $category){
foreach($category as $value){
echo $value;
}
}
You can check it like that:
This code will check which categories are activated
assuming that your database returns categories from 0 to x
$i = 0;
while(true){
if ($_POST["cat".$i."]) {
//category activated
}
else {
//no category found -> loop ends
break;
}
$i++;
}
How can I use the conditional OR in a form with isset?
I have this but it does not work.
FORM HTML:
...
<input type="checkbox" name="carga1">
<input type="checkbox" name="carga2">
...
and the PHP
$cargas=array($_POST['carga1'],$_POST['carga2'],$_POST['carga3'],
$_POST['carga4'],$_POST['carga5'],$_POST['carga6'],
$_POST['carga7'],$_POST['carga8'],$_POST['carga9'],
$_POST['carga10'],$_POST['carga11'],$_POST['carga12'],
$_POST['carga13'],$_POST['carga14'],$_POST['carga15'],
$_POST['carga16'],$_POST['carga17'],$_POST['carga18']);
if(isset($cargas[0]) ││ isset ($cargas[1])){
$cargas[0]=5.62;
$cargas[1]=4.5;
echo "$cargas[0]<br>";
echo "$cargas[1]<br>";
}
i expect that this works but is not.
Only checked checkbox is posted to the server.You have to change your condition using pregmatch and work accordingly.
$postData = $_POST;
foreach ($postData as $key => $value) {
$match = preg_match('|cargas(\d+)|', $key, $matches);
if ($match) {
$index = $matches[1];
if($index == 0 || $index == 1){
// do your stuff which you would have done in case of $cargas[0] ,$cargas[1]
}
}
}
I think array is not Suitable way to do this try following
try this
<input type="checkbox" name="carga1">
<input type="checkbox" name="carga2">
.....................................
<input type="submit" name="submit">
<?php
if(isset($_POST['submit'])){
//
$category1=$_POST['carga1'];
$category2=$_POST['carga2'];
$category3=$_POST['carga3'];
if(isset($category1) ││ isset ($category2)){
$category1=5.62;
$category2=4.5;
echo "$category1<br>";
echo "$category2<br>";
}
}
?>
only the checked checkboxes get posted. so it needs slightly different appraoch.
You can acheive it like this-
put a hidden input with the same name as the checkbox that might not be checked. I think it works so that if the checkbox isn't checked, the hidden input is still successful and sent to the server but if the checkbox is checked it will override the hidden input before it. This way you don't have to keep track of which values in the posted data were expected to come from checkboxes.
<form>
<input type='hidden' id='testName' value='0' name='carga1'>
<input type='checkbox' id='testNameHidden' value='1' name='carga1'>
</form>
Before submitting the form , disabled the hidden field based on the checked condition.
<script>
if(document.getElementById("testName").checked){
document.getElementById('testNameHidden').disabled = true;
}
</script>
I personally think its the easiest approach for this.
ok, check boxes in html works as follows,
<input type="checkbox" name="carga1" value="1">
<input type="checkbox" name="carga2" value="123">
in php,
if the check box is in checked state during the submission, you will get
isset($_POST['carga1']) as true, else the form element would not be available in post data, hence false.
and in cheked state you will get value for
$_POST['carga1'] as 1 and
$_POST['carga2'] as 123
and if you want to group the check boxes in form you can use a single name for multiple check boxes and different values,
<input type="checkbox" name="carga[]" value="1">
<input type="checkbox" name="carga[]" value="2">
<input type="checkbox" name="carga[]" value="3">
<input type="checkbox" name="carga[]" value="4">
and in php you will get an array of selected values of the check boxes
$arr=$_POST['carga'];
and you can use foreach to iterate through the values,,,
I am simply trying to pass my checkbox values through a session variable for use if the user goes back at some point. After going to my first page and POSTING, I want these selections stored in a SESSION variable. I've had no luck so far in figuring this one out. My code is below.
Here is my html of my checkboxes. I have about 15 checkboxes with the same name as below. I take all those checkboxes and break them down in another script for insertion into a database.
<input type='checkbox' name='list[]' id='product' value='Product'></input>
Here I am setting my variable with the POST of the checkboxes.
$checkboxes = $_POST['list'];
$_SESSION['list'] = $checkboxes;
How can I pass these checkbox selections into and out of a session variable for selecting elements on a previous page?
Change:
<input type='checkbox' name='list[]' id='product' value='Product'></input>
To
<input type='checkbox' name='list[0]' id='product' value='Product'></input>
<input type='checkbox' name='list[1]' id='product' value='Product'></input>
etc.
And use foreach:
Okay so. We know that in $_SESSION['list'] we have only checked ones!
foreach ($_SESSION['list'] as $key => $value)
{
echo '<input type="checkbox" name="list['$key']" value="'.$value.'" checked="checked >';
}
Just thought I share my code / solution for storing the html form checkbox value in a session. My search did not get me to cover all scenarios that I needed.
My scenario includes that I pass a default state for checked or not checked.
HTML Form Code:
<input type="hidden" name="product[]" value = 0>
<input name="product[]" type="checkbox" value = 1 <?php echo (($productvalue == 1) ? 'checked' : '')?>>
PHP Form processing code:
$productvalue = ((isset($_POST['product'])) ? array_sum((array)$_POST['product']) : ((isset($_SESSION['productsession'])) ? $_SESSION['productsession'] : 0));
$_SESSION['productsession'] = $productvalue;
How to read if a checkbox is checked in PHP?
If your HTML page looks like this:
<input type="checkbox" name="test" value="value1">
After submitting the form you can check it with:
isset($_POST['test'])
or
if ($_POST['test'] == 'value1') ...
Zend Framework use a nice hack on checkboxes, which you can also do yourself:
Every checkbox generated is associated with a hidden field of the same name, placed just before the checkbox, and with a value of "0". Then if your checkbox as the value "1", you'll always get the '0' or '1' value in the resulting GET or POST
<input type="hidden" name="foo" value="0" />
<input type="checkbox" name="foo" value="1">
When using checkboxes as an array:
<input type="checkbox" name="food[]" value="Orange">
<input type="checkbox" name="food[]" value="Apple">
You should use in_array():
if(in_array('Orange', $_POST['food'])){
echo 'Orange was checked!';
}
Remember to check the array is set first, such as:
if(isset($_POST['food']) && in_array(...
Let your html for your checkbox will be like
<input type="checkbox" name="check1">
Then after submitting your form you need to check like
if (isset($_POST['check1'])) {
// Checkbox is selected
} else {
// Alternate code
}
Assuming that check1 should be your checkbox name.And if your form submitting method is GET then you need to check with $_GET variables like
if (isset($_GET['check1'])) {
// Checkbox is selected
}
$check_value = isset($_POST['my_checkbox_name']) ? 1 : 0;
I've been using this trick for several years and it works perfectly without any problem for checked/unchecked checkbox status while using with PHP and Database.
HTML Code: (for Add Page)
<input name="status" type="checkbox" value="1" checked>
Hint: remove checked if you want to show it as unchecked by default
HTML Code: (for Edit Page)
<input name="status" type="checkbox" value="1"
<?php if ($row['status'] == 1) { echo "checked='checked'"; } ?>>
PHP Code: (use for Add/Edit pages)
$status = $_POST['status'];
if ($status == 1) {
$status = 1;
} else {
$status = 0;
}
Hint: There will always be empty value unless user checked it. So, we already have PHP code to catch it else keep the value to 0. Then, simply use the $status variable for database.
To check if a checkbox is checked use empty()
When the form is submitted, the checkbox will ALWAYS be set, because ALL POST variables will be sent with the form.
Check if checkbox is checked with empty as followed:
//Check if checkbox is checked
if(!empty($_POST['checkbox'])){
#Checkbox selected code
} else {
#Checkbox not selected code
}
You can check the corresponding value as being set and non-empty in either the $_POST or $_GET array depending on your form's action.
i.e.: With a POST form using a name of "test" (i.e.: <input type="checkbox" name="test"> , you'd use:
if(isset($_POST['test']) {
// The checkbox was enabled...
}
You can do it with the short if:
$check_value = isset($_POST['my_checkbox_name']) ? 1 : 0;
or with the new PHP7 Null coalescing operator
$check_value = $_POST['my_checkbox_name'] ?? 0;
Learn about isset which is a built in "function" that can be used in if statements to tell if a variable has been used or set
Example:
if(isset($_POST["testvariabel"]))
{
echo "testvariabel has been set!";
}
Well, the above examples work only when you want to INSERT a value, not useful for UPDATE different values to different columns, so here is my little trick to update:
//EMPTY ALL VALUES TO 0
$queryMU ='UPDATE '.$db->dbprefix().'settings SET menu_news = 0, menu_gallery = 0, menu_events = 0, menu_contact = 0';
$stmtMU = $db->prepare($queryMU);
$stmtMU->execute();
if(!empty($_POST['check_menus'])) {
foreach($_POST['check_menus'] as $checkU) {
try {
//UPDATE only the values checked
$queryMU ='UPDATE '.$db->dbprefix().'settings SET '.$checkU.'= 1';
$stmtMU = $db->prepare($queryMU);
$stmtMU->execute();
} catch(PDOException $e) {
$msg = 'Error: ' . $e->getMessage();}
}
}
<input type="checkbox" value="menu_news" name="check_menus[]" />
<input type="checkbox" value="menu_gallery" name="check_menus[]" />
....
The secret is just update all VALUES first (in this case to 0), and since the will only send the checked values, that means everything you get should be set to 1, so everything you get set it to 1.
Example is PHP but applies for everything.
Have fun :)
$is_checked = isset($_POST['your_checkbox_name']) &&
$_POST['your_checkbox_name'] == 'on';
Short circuit evaluation will take care so that you don't access your_checkbox_name when it was not submitted.
A minimalistic boolean check with switch position retaining
<?php
$checked = ($_POST['foo'] == ' checked');
?>
<input type="checkbox" name="foo" value=" checked"<?=$_POST['foo']?>>
<?php
if (isset($_POST['add'])) {
$nama = $_POST['name'];
$subscribe = isset($_POST['subscribe']) ? $_POST['subscribe'] : "Not Checked";
echo "Name: {$nama} <br />";
echo "Subscribe: {$subscribe}";
echo "<hr />";
}
?>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<input type="text" name="name" /> <br />
<input type="checkbox" name="subscribe" value="news" /> News <br />
<input type="submit" name="add" value="Save" />
</form>
<form>
<input type="check" id=chk1 value="1">
<input type="check" id=chk2 value="1">
<input type="check" id=chk3 value="1">
</form>
when you check on chk2 you can see values as:
<?php
foreach($_POST as $key=>$value)
{
if(isset($key))
$$key=strip_tags($value);
}
insert into table (chk1,chk2,chk3) values ('','1','');
?>
in BS3 you can put
<?php
$checked="hola";
$exenta = $datosOrdenCompra[0]['exenta'];
var_dump($datosOrdenCompra[0]['exenta']);
if(isset($datosOrdenCompra[0]['exenta']) and $datosOrdenCompra[0]['exenta'] == 1){
$checked="on";
}else{
$checked="off";
}
?>
<input type="checkbox" id="exenta" name="exenta" <?php echo $checked;?> > <span class="label-text"> Exenta</span>
Please Note the usage of isset($datosOrdenCompra[0]['exenta'])
Wordpress have the checked() function.
Reference: https://developer.wordpress.org/reference/functions/checked/
checked( mixed $checked, mixed $current = true, bool $echo = true )
Description
Compares the first two arguments and if identical marks as checked
Parameters
$checked
(mixed) (Required) One of the values to compare
$current
(mixed) (Optional) (true) The other value to compare if not just true
Default value: true
$echo
(bool) (Optional) Whether to echo or just return the string
Default value: true
Return #Return
(string) html attribute or empty string
i have fixed it into a PHP form with a checkbox
$categories = get_terms( ['taxonomy' => 'product_cat', 'hide_empty' => false] );
foreach ($categories as $categorie) {
echo "<input type="checkbox" value="$categorie->term_taxonomy_id" name="catselected[]"> $categorie->slug";
}
This way i add it to the Woocommerce tabel.
wp_set_post_terms( $product_id, $_POST['catselected'], 'product_cat' );
filter_input(INPUT_POST, 'checkbox_name', FILTER_DEFAULT, FILTER_FORCE_ARRAY)
<?php
if(isset($_POST['nameCheckbox'])){
$_SESSION['fr_nameCheckbox'] = true;
}
?>
<input type="checkbox" name="nameCheckbox"
<?php
if(isset($_SESSION['fr_nameCheckbox'])){
echo 'checked';
unset($_SESSION['fr_nameCheckbox']);
}
?>
you should give name to your input .
then which box is clicked you will receive 'on' in your choose method
Array
(
[shch] => on
[foch] => on
[ins_id] => #
[ins_start] => شروع گفتگو
[ins_time] => ما معمولاً در چند دقیقه پاسخ میدهیم
[ins_sound] => https://.../media/sounds/ding-sound-effect_2.mp3
[ins_message] => سلام % به کمک نیاز دارید؟
[clickgen] =>
)
i have two checked box in my form name with 'shch' and 'foch'