Issue with AJAX "load more" button: disappears once clicked - php

EDIT: thanks everyone for your help. It still doesn't work though.
This script works fine if i change the table to an ordered list. (tr = ol and td = li) That's why i really think the issue comes from the append part of the code. Any ideas?
Everything seems to work fine except for the "load more" button that disappears after it's been clicked. The new posts load but the users cannot click on the button again to load more posts. I've looked on SO but couldn't find a fix for my issue.
If I remove this line:
$("#more"+ID).remove();
then the button does show up but the gif image keeps on loading forever and the button is not clickable...
Here's the index.php code:
<table id="update_list" >
<tbody>
<?php
$result=query("SELECT * FROM postlist ORDER BY postid DESC LIMIT 9");
foreach ($result as $row)
{
$postid=$row['postid'];
$post=$row['post'];
?>
<tr id="<?php echo $postid ?>">
<td>
<?php echo $post; ?>
</td>
</tr>
<?php } ?>
</tbody>
</table>
<div id="more<?php echo $postid; ?>" class="morebox">
more
</div>
</div>
</body>
<script type="text/javascript">
$(function() {
$('.more').live("click",function()
{
var ID = $(this).attr("id");
if(ID)
{
$("#more"+ID).html('<img src="/loading.gif" />');
$.ajax({
type: "POST",
url: "loadmore.php",
data: "lastpost="+ ID,
cache: false,
success: function(html){
$("#update_list >tbody").append(html);
$("#more"+ID).remove();
}
});
}
else
{
$(".morebox").html('The End');
}
return false;
});
});
</script>
</html>
Here is the loadmore php page:
<?php
include("includes/config.php");
if(isset($_POST['lastpost']))
{
$lastpost=$_POST['lastpost'];
$result=query("SELECT * from postlist WHERE postid < '$lastpost' ORDER BY postid DESC
LIMIT 5");
foreach ($result as $row){
$postid=$row['postid'];
$post=$row['post'];
?>
<tr id="<?php echo update$postid ?>">
<td>
<?php echo $post; ?>
</td>
</tr>
<?php } ?>
<div id="more<?php echo $postid; ?>" class="morebox">
more
</div>
<?php }?>
Any tips on what i'm doing wrong here ?
Thanks !

Try this:
$(function() {
$('.more').live("click",function()
{
var ID = $(this).attr("id");
if(ID)
{
$("#more"+ID).find("a").hide().insertAfter('<img src="/loading.gif" />'); //hide a link and insert image after it
$.ajax({
type: "POST",
url: "loadmore.php",
data: "lastpost="+ ID,
cache: false,
success: function(html){
$("#update_list >tbody").append(html);
$("#more"+ID).find("img").remove(); // remove img
$("#more"+ID).find("a").show(); //and show link
}
});
}
else
{
$(".morebox").html('The End');
}
return false;
});
});

You are removing the load more button after button clicked
$("#update_list >tbody").append(html);
//$("#more"+ID).remove(); remove this line

Related

how to built ajax tabs in wordpress?

I try to display the departments in my website as tabs, when click one tab it will display the data related to this department according to department_id.
I try this code Execute php function only when clicked (wordpress) but I need the tabs number to be dynamic.
<div class="tabs">
<ul>
<?php
$arr1=array(2,3,5,10,22,25,27,28,29,30);
$arr2=array("dep1","dep2","dep3","dep4",
"dep5","dep6","dep7","dep8","dep9","dep10");
for($i=0;$i<10;$i++){?>
<li><a href="#tab" id="<?php echo $arr1[$i]; ?>"><?php echo
$arr2[$i];?>
</a></li>
<?php } ?>
</ul>
</div>
<div id="tab" class="section">
</div>
functions.php:
<?php
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id=$_GET[id];
/** Here I print data according to $dept_id **/
die();
}
?>
script.js:
jQuery(document).ready(function() {
jQuery('.tabs a').click(function(e) {
e.preventDefault();
var tab_id = jQuery(this).attr('id');
console.log(tab_id);
jQuery.ajax({
type: "GET",
url: "wp-admin/admin-ajax.php",
dataType: 'html',
data: ({ action: 'tabsfunction', id: tab_id}),
success: function(data){
jQuery('#tab').html(data);
},
error: function(data)
{
alert("Error!");
return false;
} });}); });
it dose not work, it displays data only for one tab.
console.log(tab_id) ----> it display the id for the first tab clicked
and did not change when click another tab.
You need to echo the output from the tabsfunction and also add the die() at end of the function like below :
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id=$_GET[id];
/** Here display data according to $dept_id **/
echo 'output';
die();
}
Hope it helps.
can you please correct your tab list code.
<div class="tabs">
<ul>
<?php
$arr1 = array(2,3,5,10,22,25,27,28,29,30);
$arr2 = array("dep1","dep2","dep3","dep4","dep5","dep6","dep7","dep8","dep9","dep10");
for($i=0;$i<10;$i++)
{
?>
<li><?php echo $arr2[$i];?></li>
<?php
}
?>
</ul>
</div>
<?php for($i=0;$i<10;$i++)
{
?>
<div id="tab<?php echo $arr1[$i]; ?>" class="section">
</div>
<?php
}
?>
Also return proper response on ajax request.
<?php
add_action('wp_ajax_tabsfunction', 'tabsfunction');
add_action('wp_ajax_nopriv_tabsfunction', 'tabsfunction');
function tabsfunction() {
$dept_id = $_GET[id];
echo $dept_id; // this just dispay requsted id as tab content here you can add your logic for dynamic content based on id
die();
}
?>
And your script js look like this
jQuery(document).ready(function() {
jQuery('.tabs a').click(function(e) {
e.preventDefault();
var tab_id = jQuery(this).attr('id');
console.log(tab_id);
jQuery.ajax({
type: "GET",
url: "wp-admin/admin-ajax.php",
dataType: 'html',
data: ({ action: 'tabsfunction', id: tab_id}),
success: function(data){
jQuery('#tab'+tab_id).html(data);
},
error: function(data)
{
alert("Error!");
return false;
} });}); });

How to get the output using ajax when the Double outputs displayed one for PHP Echo and another for Ajax request?

I successfully fetch the data from the database. The problem is that, I want to display the results using Ajax request. The results/Output which displayed twice, I mean the *first output which displayed through Ajax (#the bottom of index.php), and the Second output displayed through PHP ECHO (**#**the bottom of the page). What can I do to get a single output through Ajax without adding another file and without refreshing the page?
index.php
<head>
<script src="https://code.jquery.com/jquery-3.1.1.js"></script>
<script type="text/javascript" src="javas.js"></script>
</head>
<body>
<div id="table_content"></div>
<?php
include ("db.php");
error_reporting(~E_NOTICE);
function ShowForm($AnswerCommentId) {
echo '<form id="myForm">';
echo '<input id="user" name="user" />';
echo '<textarea id="text" name="text"></textarea>';
echo sprintf('<input id="ParentId" name="ParentId" type="hidden" value="%s"/>', ($AnswerCommentId));
echo '<button type="button" OnClick=SendComment()>Comment</button>';
echo '</form>';
}
$query="SELECT * FROM `comm` ORDER BY id ASC";
$result = mysqli_query($conn,$query);
if (isset($_REQUEST['AnswerId'])) $AnswerId = $_REQUEST['AnswerId'];
else $AnswerId = 0;
$i=0;
while ($mytablerow = mysqli_fetch_row($result)){ $mytable[$i] = $mytablerow; $i++; }
function tree($treeArray, $level, $pid = 0) {
global $AnswerId;
foreach($treeArray as $item){
if ($item[1] == $pid){
echo sprintf('<div class="CommentWithReplyDiv" style="margin-left:%spx;">',$level*60);
echo sprintf('<p>%s</p>', $item[2]);
echo sprintf('<div>%s</div>', $item[3]);
if ($level<=2) echo sprintf('Reply', $item[0]);
if ($AnswerId == $item[0]) echo sprintf('<div id="InnerDiv">%s</div>', ShowForm($AnswerId));
echo '</div><br/>';
tree($treeArray, $level+1, $item[0]); // Recursion
}
}
}
tree($mytable,0,0);
?>
Comment
<div id="MainAnswerForm" style="display:none;width:40%; margin:0 auto;"><?php ShowForm(0); ?></div>
<div id="AfterMainAnswerForm"></div>
<script>
$(document).ready(function(){
$("#Link").click(function () {
$("#InnerDiv").remove();
$("#MainAnswerForm").slideToggle("normal");
return false;
});
});
</script>
</body>
Page.php
<?php
include ("db.php");
$user = $_POST['user'];
$text = $_POST['text'];
$ParentId = $_POST['ParentId'];
$action = $_POST['action'];
if ($action=="add") $query= mysqli_query($conn,"INSERT into `comm` VALUES (NULL,'{$ParentId}','{$user}','{$text}',NOW())");
?>
Javas.js
function show_messages(){
$.ajax({
url: "index.php",
cache: false,
success: function(html){
$("#table_content").html(html);
}
});
}
function AnswerComment (id){
$.ajax({
type: "POST",
url: "index.php",
data: "AnswerId="+id,
success: function(html){
$("#table_content").html(html);
}
});
}
function SendComment (){
var user1 = $("#user").val();
var text1 = $("#text").val();
var ParentId1 = $("#ParentId").val() + "";
$.ajax({
type: "POST",
url: "page.php",
data: "user="+user1+"&text="+text1+"&ParentId="+ParentId1+"&action=add",
success: function(html){
show_messages();
}
});
return false;
}
OK I think its more simple than you think
while you're using .html() it should change all the content of your div but while you're using <div id="table_content"></div> then the <?php ?> your code will show both - one appended to the div and under it the one which echoed by php ... so instead of using
<div id="table_content"></div>
<?php ?>
just wrap the <?php ?> inside the div
<div id="table_content">
<?php ?>
</div>
Alternative way: by using jquery wrapAll() but while Id must be unique you'll need to .remove() the #table_content element first then wrap all your code inside a new #table_content div .. see the example below
$(document).ready(function(){
$('#table_content').remove();
$('.CommentWithReplyDiv').wrapAll('<div id="table_content"></div>');
});
#table_content{
margin : 50px;
background : red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="table_content"></div>
<div class="CommentWithReplyDiv">1</div>
<div class="CommentWithReplyDiv">2</div>
<div class="CommentWithReplyDiv">3</div>
<div class="CommentWithReplyDiv">4</div>

refresh an included page

I have a page index.php
Inside of it is a friendlist that updates the db with a button click without refreshing the page. Now I want that only the friendlist refreshs so its updated
<html>
<body>
<?php
include ("friendlist.php");
?>
</body>
</html>
friendlist.php:
<script>
function adduser() {
var data=$("#adduserform").serialize();
$.ajax({
type: "POST",
url: "addfriend.php",
data: data,
dataType: "html",
success: function(data)
{
//refresh myFriendlist or requser so its updated
}
});
}
</script>
<div id="myFriendlist" class="friendlist-content">
<?php if(!empty($request)) { ?>
<div id="req">
<h2 id="reqh">Anfragen</h2>
<?php foreach($request as $row) {
$row['userAname'] = (strlen($row['userAname']) > 5) ? substr($row['userAname'], 0, 5) . '...' : $row['userAname'];
?>
<div id="requser">
<a class="reqimg" style="padding:0px;" href="user.php?id=<?php echo ($row['id']);?>">
<img class="reqpb" src="./users/<?php echo ($row['userAid']); ?>/pb.jpg" alt="Bild nicht gefunden" onerror="this.src='./img/no_pb.png';"></img>
</a>
<a class="reqnm" style="padding:0px;" href="user.php?id=<?php echo ($row['userAid']);?>"><?php echo $row['userAname']; ?></a>
<img id="aimg" src="./img/accepticon.png">
<form id="adduserform" name="adduserform">
<input type="hidden" id="reqid" name="reqid" value="<?php echo $row['userAid'];?>" />
<input type="hidden" id="reqnm" name="reqnm" value="<?php echo $row['userAname'];?>" />
</form>
<img id="aimg" src="./img/dntaccepticon.png">
</div>
<?php
}
?>
</div>
<?php
}
?>
</div>
How can I do that?
You can refresh an external file using ajax. For example, if you had a div with the id "friendslist" you could refresh its contents this way:
$.ajax({
url: "friendlist.php"
}).done(function(response) {
$( '#friendslist' ).html( response );
});
The documentation for ajax is on the jQuery site here: http://api.jquery.com/jquery.ajax/.
If you can make "addfriend.php" to return the new complete list of users, so that would be:
<?php foreach($request as $row) {
$row['userAname'] = (strlen($row['userAname']) > 5) ? substr($row['userAname'], 0, 5) . '...' : $row['userAname'];
?>
you could use that response, which you will receive when you do the AJAX call, to refresh the friendlist, using the jquery HTML function (http://api.jquery.com/html/)
you can follow this code but not tested
first update your index.php
<html>
<body>
<div id="friendlist">
<?php
include ("friendlist.php");
?>
</div>
</body>
</html>
then update your addfriend.php as like
<?php
// your code here
// then include your frindlist.php content
include 'yourpath/frindlist.php'
?>
then update your javascript code like this
function adduser() {
var data=$("#adduserform").serialize();
$.ajax({
type: "POST",
url: "addfriend.php",
data: data,
dataType: "html",
success: function(data)
{
$('#friendlist').html(data);
}
});
}

ajax a href onclick get php variable and execute php file

Before I ask this question, I have already referred to the example of this question. However, it seems doesn't work. Without using ajax, I can get my post deleted but after implement ajax, the deleteAtc.php seems to be not working.
My delete page code (delete.php)
<h4>Select an Article to Delete:</h4>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span> Delete<br />
<script type="text/javascript">
$(function(){
$('#link').click(function(){
var id = <?php echo $article['article_id']; ?>;
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id"+id+,
sucess: function() {
$('#sucess').html(data);
}
})
return false;
});
});
</script>
<div id="success"></div><br />
<?php } ?>
While my deleteAtc.php code:
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
echo "Article deleted";
}
}
?>
What I'm trying to do here is to delete the record without redirect to deleteAtc.php, it will remove out the record and replace Article Deleted
May I know where did I go wrong in ajax side?
Please refer below for updated question
Based on the answer below, here is my updated code:
delete.php
<h4>Select an Article to Delete:</h4>
<div id="message"></div>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span>
Delete<br />
<?php } ?>
script
<script type="text/javascript">
$(function(){
$('.link').click(function(){
var elem = $(this);
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+elem.attr('data-artid'),
dataType:"json",
success: function(data) {
if(data.success){
elem.hide();
$('#message').html(data.message);
}
}
});
return false;
});
});
</script>
deleteAtc.php
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
//Also try to handle false conditions or failure
echo json_encode(array('success'=>TRUE,'message'=>"Article deleted"));
}
}
?>
Somehow, if I delete two record at a time, only the first record echo the result, the second result deleted doesn't echo out the result.
Am wondering, possible to add jquery animation to .show the success message and .hide the record deleted?
First of all IDs are not meant to be duplicated, use class selector instead. Also you could make use of custom data attributes to store the id of the article.
Try
<h4>Select an Article to Delete:</h4>
<div id="message"></div>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span>
Delete<br />
<?php } ?>
Script
<script type="text/javascript">
$(function(){
$('.link').click(function(){
var elem = $(this);
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+elem.attr('data-artid'),
dataType:"json",
success: function(data) {
if(data.success){
elem.hide();
$('#message').html(data.message);
}
}
});
return false;
});
});
</script>
And in server side
<?php
session_start();
include_once('../includes/connection.php');
if (isset($_SESSION['logged_in'])) {
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query = $pdo->prepare('DELETE FROM articles WHERE article_id = ?');
$query->bindValue(1, $id);
$query->execute();
//Also try to handle false conditions or failure
echo json_encode(array('success'=>TRUE,'message'=>"Article deleted"));
}
}
?>
The above script won't work you have to change like below. You are repeating the same identifier function again and again. Keep the jquery script out of foreach loop. You have to add the class property with the article id.
<h4>Select an Article to Delete:</h4>
<?php foreach ($articles as $article) { ?>
<span><?php echo $article['article_title']; ?></span> <a href="#" id="link" class='<?php echo $article['article_id']; ?>' >Delete</a><br />
<div id="success"></div><br />
<?php } ?>
<script type="text/javascript">
$(function(){
$('#link').click(function(){
var id = $(this).prop('class');
$.ajax({
type: "GET",
url: "deleteAtc.php",
data: "id="+id,
sucess: function() {
$('#sucess').html(data);
}
})
return false;
});
});
</script>
You create several links with id="link". ID must be unique.
You have to write
id="link<? echo $article['article_id']; ?>"
as well as
$('#link<? echo $article["article_id"]; ?>').click(function() {...})
<script language="javascript">
$(document).ready(function() {
$(".delbutton").click(function(){
var element = $(this);
var del_id = element.attr("id");
var info = 'id=' + del_id;
if(confirm("Sure you want to delete this record? There is NO undo!"))
{
$.ajax({
type: "GET",
url: "products/delete_record.php",
data: info,
cache: false,
success: function(){
setTimeout(function() {
location.reload('');
}, 1000);
}
});
$(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
.animate({ opacity: "hide" }, "slow");
}
return false;
//location.reload();
});
});
</script>

Get the data that is being loaded by jquery in PHP CodeIgniter

I have this dropdown menu using form_helper in CodeIgniter:
<?php if($materialType): ?>
<?php
$material_options = array();
foreach($materialType as $rows){
$material_options[$rows->id] = $rows->category;
}
echo form_dropdown('materialType',$material_options,'','id="materialType"');
?>
<?php endif; ?>
<div id="materials"></div>
The code above is inside a <form> tag and I have this script:
<script type="text/javascript">
var base_url = "<?php echo base_url(); ?>";
</script>
<script>
$(document).ready(function(){
$(document).on('change','#materialType',function(){
loadthis();
});
function loadthis(){
var ID = $('#materialType').val();
var dataString = 'id='+ ID ;
$.ajax({
type: "POST",
url: base_url + "index.php/admin/get_material",
data: dataString,
cache: false,
success: function(data)
{
$('#materials').html(data);
}
});
}
loadthis();
});
</script>
And here is the code that is being loaded:
<div id="materials">
<?php if($materials): ?>
<table>
<th>Name</th>
<th>Description</th>
<?php foreach($materials as $row): ?>
<tr>
<td><?php echo $row->mname; ?></td>
<td><?php echo $row->mdesc; ?></td>
<td>
<button class="try" value="<?php echo $row->id; ?>">Add</button>
</td>
</tr>
<?php endforeach; ?>
</table>
<?php else: ?>
<div class="alert alert-error" style="width:300px;">No Resource Available!</div>
<?php endif; ?>
$(document).on('click','.try',function(){
alert($(this).val());
return false;
});
And what i want is if the Add button is being click I can get the ID,mname and store it until the form is submitted.
How can I do that using .data() in jquery? or Any ideas on how to store it until the form is being submit.
I didn't thoroughly look at your code, but I noticed when you print your table rows in a loop you have the id="try" assigned to all of the rows. the html id-attribute is a unique identifier so the JS that is alerting the value will only return the value of the first id it will find (at least that's what i think). Try to use a class instread of an id and then use this in your js.
$(document).on('click','.try',function(){
alert($(this).val());
return false;
});

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