I created a login page that when user login redirect to a pictures.php,
pictures page should contains the images of the user , I already create upload page to upload image to file directory and when the user upload an image the image link is added to a new row in the database, I need to add the image link to an exist row of the user,I already created a session for user when logged in.
So I need to add the image link to an exist row of the user.
This is the code that insert the image to a file directory and save its link to a new row of the database.
<?php
$name = $_FILES["myfile"] ["name"];
$type = $_FILES["myfile"] ["type"];
$size = $_FILES["myfile"] ["size"];
$temp = $_FILES["myfile"] ["tmp_name"];
$name = $size.$size .$name ;
$error = $_FILES["myfile"] ["error"];
if ($error > 0){
die ("Error uploading image");
}else{
mysql_query("INSERT INTO userid (imageid) VALUES ('.$name')");
move_uploaded_file($temp,"uploaded/".$name);
echo "Upload Completed";
}
?>
And the upload form is
<html>
<form action="upload.php" method="POST" enctype="multipart/form-data">
<input type="file" name="myfile">
<input type="Submit" value="Upload">
</form>
</html>
So how to the image link to an exist row of the user.
Use mysql_query("UPDATE $table_name SET imageid='{$name}' WHERE userid=$userid")
Of course substituting variables and columns with correct values
Use UPDATE query instead of INSERT. INSERT will add new row but UPDATE will update your existing data.
You have to update the row if the row where you want to add image link is already exist. So use UPDATE Query. and debug wether table is updated or not.
check in table or use or die(); after the query
Related
I have a booking table which contain file_name and file_path, I need to upload a picture into the user row based on the noic, after I select a picture and click the upload button, it show upload success, but in the database doesn't have the picture and picture name.
$target = "upload/";
$target = $target . basename( $_FILES['file']['name']);
//This gets all the other information from the form
$file=basename( $_FILES['file']['name']);
$filename=$_POST['file_name'];
//Writes the file to the server
if(move_uploaded_file($_FILES['file']['tmp_name'], $target)) {
//Tells you if its all ok
echo "The file ". basename( $_FILES['file']['name']). " has been uploaded, and your information has been added to the directory";
// Connects to your Database
//Writes the information to the database
mysql_query("UPDATE INTO booking (file_path,file_name)
VALUES ('$file', '$filename') WHERE noic = '$_SESSION[noic]'") ;
} else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
<form enctype="multipart/form-data" action="userstatus.php" method="POST">
<p> File Name :
<input style="background:grey;" type="text" name="file_name" value="" >
</p>
<p>
<input type="file" name="file" >
</p>
<p>
<input type="submit" name="submit" value="Upload file" style="background:grey;">
</p>
</form>
Your MySQL query is incorrect, it should be UPDATE SET... MySQL Insert statement does not support the WHERE clause so your query will fail if you directly replace UPDATE with INSERT, make the following changes,
//Writes the information to the database
mysql_query("UPDATE booking SET file_path='$file',
file_name='$filename' WHERE noic = '$_SESSION[noic]'") ;
}
NOTE: PLEASE AVOID USING php mysql* class for database queries, it has been deprecated and should not be used, Switch to PDO or MySQLi. PDO reference - http://php.net/manual/en/book.pdo.php
Have you tried to run your query
UPDATE INTO booking (file_path,file_name) VALUES ('$file', '$filename') WHERE noic = '(replace here the noic you want)'
On phpMyAdmin or MySql Workbench??
Why don't you try to run the query like this:
UPDATE booking SET file_path = '$file', SET file_name= '$filename' WHERE noic = '$_SESSION[noic]'
Also check If you have set the 775 permission to the /upload folder..
Hope I help you!
$image = file_get_contents($_FILES['image']['tmp_name']);
$image = mysql_real_escape_string($image);
mysql_query("UPDATE ngc set pic='" . $image "' WHERE username='" . $_SESSION["username"] . "'");
<form method="post" action="" enctype="multipart/form-data">
Upload Image :<input type="file" name="image" id="file">
<br><input type="submit" name="submit" value="Update!" class="btnSubmit">
</form>
i want to upload image to database..
Read this very nice example here: http://www.mysqltutorial.org/php-mysql-blob/
Also see this image gallery example here: http://www.anyexample.com/programming/php/php_mysql_example__image_gallery_(blob_storage).xml
BLOBs are data types in MySql database which can help you store image files in database directly.
Although a better way would be to store the file on the disk and store the path of that variable in the database.
get the Content of the file and save in database;
$image = addslashes(file_get_contents($_FILES['image']['tmp_name']));
Mysql:
$sql = "INSERT INTO `product_images` (`id`, `image`) VALUES ('1', '{$image}')";
First of all if you want to save the entire image into the database , you must have the pic attribute type set to BLOB , here you have two options , either save the entire image into database , or save the name after uploading the images into a specified folder with a unique name each , so you can retrieve the images by name into this directory.
I am building a forum with php and MySQL and I want to append current time to each image that users upload for their profile. I used time() function on each image file uploaded and it worked for the image file but I have trouble inserting the new filename into the database. I wanted to give each image a unique name to prevent override.
OK here is what I did: I stored the current time as $time and the filename in a variable, $photo and I tried to insert that variable’s value using $photo .= $time into the database so it has the filename as I did with each uploaded image. However the original filename is inserted into the database in every attempt.
Any workarounds?
$image = $_FILES['photo']['name'];
$time = time();
$image .= $time;
delete the existing photo
delete(image_dir/$row['current_photo.jpg']);
//does not work, but i want something like that
if(move_uploaded_file($_FILES['photo']['tmp_name'], 'image_dir/$image') {
$query = "INSERT INTO profile (user_id, profile_photo) VALUES($id, $image)";
mysqli_query($dbc, $query);
if(mysqli_affected_rows($dbc) == 1) {
echo "added to the database!";
}else {
echo "failed to add photo to the database";
}
}else {
echo "failed to upload photo";
}
how can i give the uploaded image unique the name since the original image name gets inserted in the database in every try i make?
i know the code looks funny :). just want to show the logic.
If you need a unique id, you can use the uniqid function
$name=uniqid();
you may need to use
$filename=uniqid();
I am trying to create a script that has a basic file upload button and a form function. I am also trying to make a script that would be a file manager with all the input data from the form.
Form Layout:
Browse (Button) ----> When clicked prompts the user to upload only pdf files.
File Name (Form): ----> The user must put a file name
Brief Description (Form): ----> The user must put a brief description of their file
Upload (Button): ----> Once this button is hit the file is uploaded to my web server to a folder called 'files'.
File Browser Layout:
The file browser would be a table that would display all the files uploaded using the previous form. Each column in the table would show the size of the file, and show the information the uploader posted in 'File Name' and 'Brief Description'
My guess is I would need some sort of SQL database that the form information would be stored. Then I would need to make a file browser that displayed the stored information. I am not sure how to go about this task. I would really appreciate your help or ideas. Thank you for your time.
I've just wrote this without checking the errors.... here goes...
1) Create the form in upload.php
<form enctype="multipart/form-data" action="uploader.php" method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />
Choose a file to upload: <input name="uploadedfile" type="file" /><br />
description <textarea name="description" cols="15" rows="15"></textarea><br>
<input type="submit" value="Upload File" />
</form>
2) create mysql table
CREATE TABLE `uploads` (
`ID` INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,
`filename` TEXT NOT NULL ,
`description` TEXT NOT NULL
) ENGINE = INNODB;
3) create uploader.php and put your credentials in mysql to match the user / pass of mysql
// Where the file is going to be placed
$target_path = "uploads/";
/* Add the original filename to our target path.
Result is "uploads/filename.extension" */
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
// Make a MySQL Connection
mysql_connect("localhost", "admin", "1admin") or die(mysql_error());
mysql_select_db("uplodas") or die(mysql_error());
// Insert a row of information into the table "example"
mysql_query("INSERT INTO uplods
(ID, filename, description) VALUES("","'.$_FILES['uploadedfile']['name'].'", "'.mysql_real_escape_string($_POST['description']).'" ) ")
or die(mysql_error());
echo "File Uploaded!";
This will allow you to have a working upload script.
a simple file manager will be
// Make a MySQL Connection
mysql_connect("localhost", "admin", "1admin") or die(mysql_error());
mysql_select_db("uplodas") or die(mysql_error());
// Make a MySQL Connection
$query = "SELECT * FROM uploads";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result) or die(mysql_error());
echo $row['filename']. " - ". $row['description'] ." - DELETE | EDIT";
?>
use UPDATE and DELETE mysql queries to create your delete and edit buttons.
Hope this help!
Hi I am newish to php and I have created an update page for Content Management System. I have a file upload in this case a picture. I have other inputs that contain text and I can get them to populate my form and thats fine and works great because the user can see what has already been entered. But the file name for the photo can not have a value so if the user doesn't pick the picture from the directory again it will update minus the picture. What I think I need is a isset function that says if the file (picture) input is left blank don't update this field and use whatever what already in the database for it, that way if it was left blank when created it will still be, and if the user has changed it this time it will change; or if they want to leave it the same it won't leave their picture blank. Hope that makes sence.
Here is my coding currently for the Form:
<p>
Photo:
</p>
<input type="hidden" name="MAX_FILE_SIZE" value="350000">
<input type="file" name="photo"/>
Below is my php code for my update if the update button is pressed:
$con = mysql_connect("localhost","******","********");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("*******", $con);
// run this only, once the user has hit the "Update" button
if (isset($_POST['update'])) {
// assign form inputs
$name = $_POST['nameMember'];
$position = $_POST['bandMember'];
$pic = $_POST['photo'];
$about = $_POST['aboutMember'];
$bands = $_POST['otherBands'];
// add member to database
$result = mysql_query("UPDATE dbProfile SET nameMember='".$name."',bandMember='".$position."',photo='".$pic."',aboutMember='".$about."',otherBands='".$bands."' WHERE id='".$id."'");
mysql_close($con);
Header("Location: listMember.php");
exit;
}
else { // read member data from database
$result = mysql_query ("SELECT * FROM dbProfile WHERE id='".$id."'");
while($row = mysql_fetch_array($result))
{
$name = $row['nameMember'];
$position = $row['bandMember'];
$pic = $row['photo'];
$about = $row['aboutMember'];
$bands = $row['otherBands'];
}
}
mysql_close($con);
?>
If you could help I would be very please and greatful.
You have to use the $_FILES variable for uploaded files. For further information, see Handling file uploads in the PHP manual.
Try:
if(is_uploaded_file($_FILES['photo']['tmp_name']))
From the manual:
Returns TRUE if the file named by filename was uploaded via HTTP POST. This is useful to help ensure that a malicious user hasn't tried to trick the script into working on files upon which it should not be working--for instance, /etc/passwd.