Joining Multiple Rows From Within - php

The Problem
I have four tables I need to pull info from, two are just simple joins.
My query is returning nothing. Basically, there are forms I need to make sure I tied to my patient from one table, and the next table, to allow me to pull the form name so it's the correct form.
What I have
select person.first, person.last, treatmentPlan.created, treatmentPlan.updated, treatmentPlan.provider_id, intake.created, intake.updated, assesment.created, assesment.updated, discharge.created, discharge.updated
from form_patient_tie intake
LEFT OUTER JOIN form_patient_tie treatmentPlan ON intake.patient_id = treatmentPlan.patient_id
LEFT OUTER JOIN form_patient_tie assesment ON intake.patient_id = assesment.patient_id
LEFT OUTER JOIN form_patient_tie discharge ON intake.patient_id = discharge.patient_id
JOIN form as intakeForm ON intakeForm.form_id = intake.form_id
LEFT OUTER JOIN form treatmentPlanForm ON treatmentPlan.form_id = treatmentPlanForm.form_id
LEFT OUTER JOIN form assesmentForm on assesment.form_id = assesmentForm.form_id
LEFT OUTER JOIN form dischargeForm on discharge.form_id = dischargeForm.form_id
JOIN patient ON intake.patient_id = patient.patient_id
JOIN person on patient.person_id = person.person_id
WHERE (treatmentPlanForm.form_name LIKE "%Counseling Treatment Plan%" OR treatmentPlanForm.form_name IS NULL)
AND (intakeForm.form_name LIKE "%Counseling Intake%" OR intakeForm.form_name IS NULL)
AND (assesmentForm.form_name LIKE "%Counseling Assesment Review%" OR assesmentForm.form_name IS NULL)
AND (dischargeForm.form_name LIKE "%Counseling Discharge%" OR dischargeForm.form_name IS NULL)
It returns nothing even though I know there is a patient with Intake, Review, and Assessment done, but no discharge. If they have all 4, it works right, but if they are missing one, it doesn't.
It should look like
John Doe 2013-01-13 2013-01-15 2013-02-13 etc. It's definitely allowed for them to be null as not every person will have one filled out.

It looks to me as though your join to the "form" table (intakeForm alias) should also be a LEFT JOIN. Otherwise if there is not a match on the intake form, the entire query will return nothing.

Related

MYSQL PHP select the opposite of a query

I have two tables.
One table has everything I need including a cardId(PK)
The other name is a user type table. This table stores the userId and the cardId(FK).
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM USERCARDS uc
INNER JOIN CARDINDEX ci ON uc.cardId = ci.cardId
WHERE uc.userId = 'USER_ID'
So for this query, it will display the cardId, year, name, and number from the CARDINDEX. It will only display the cards that the user has saved in USERCARDS.
I want to do the opposite. If a user is looking at, lets just say, 5 cards, but the CARDINDEX has 50 cards, this query will display the information for the five cards. However, for a new query, I would want to show the remaining 45 cards. Basically, they cant add a card they already are following.
I tried to have uc.cardId != ci.cardId but that didn't work. Im kind of lost.
You can phrase this as a LEFT JOIN:
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM CARDINDEX ci LEFT JOIN
USERCARDS uc
ON uc.cardId = ci.cardId AND
uc.userId = 'USER_ID'
WHERE uc.cardID IS NULL;
Alternatively, you could write this using `NOT EXISTS:
SELECT ci.cardId, ci.year, ci.name, ci.number
FROM CARDINDEX ci
WHERE NOT EXISTS (SELECT 1
FROM USERCARDS uc
WHERE uc.cardId = ci.cardId AND
uc.userId = 'USER_ID'
);

SQL - select column inside different table if not null

I am trying to make a "recipe" system inside a game. The player can own a company and craft items in there.
I currently fetch the recipes per company type but I don't know how to write the query in a way that I can also fetch the item names and images if the item_id is not empty.
This is working:
SELECT a.recipe_id,
a.item1_id,
a.item1_uses,
a.item2_id,
a.item2_uses,
a.item3_id,
a.item3_uses,
a.item4_id,
a.item4_uses,
a.item5_id,
a.item5_uses,
a.newitem_id,
a.newitem_uses,
a.craft_description,
a.craft_button
FROM
company_recipes AS a,
company_types AS b
WHERE
a.type_id = b.type_id
AND
b.type_id = '".$type."';
"
A recipe can contain for example two items needed to craft something new, but it could also be 5. So if it's only 2, I only want to fetch the img, name of these 2 and the rest can be skipped.
I have a different table store_items that contains the img and name of the item. I was thinking something along the lines of an IF ELSE or CASE WHEN inside the query, but I'm not sure how I'd do that.
Something like: SELECT c.img, c.name FROM store_items AS c IF a.item1_id is not NULL.
I feel like I'm close to the solution, but missing the last step.
Thanks for the tips #jarlh, I've changed the code and came to this result. If you have any more tips to do it better I'm happy to listen. (I'm still a junior and thought myself by trial and error, so I might not have the best solutions at times... Which is why tips are highly appreciated).
SELECT cr.recipe_id,
cr.item1_id,
cr.item1_uses,
si1.name,
si1.img,
cr.item2_id,
cr.item2_uses,
si2.name,
si2.img,
cr.item3_id,
cr.item3_uses,
si3.name,
si3.img,
cr.item4_id,
cr.item4_uses,
si4.name,
si4.img,
cr.item5_id,
cr.item5_uses,
si5.name,
si5.img,
cr.newitem_id,
cr.newitem_uses,
si_new.name,
si_new.img,
cr.craft_description,
cr.craft_button
FROM
company_recipes AS cr
INNER JOIN company_types AS ct ON cr.type_id = ct.type_id
LEFT JOIN store_items AS si1 ON cr.item1_id = si1.item_id
LEFT JOIN store_items AS si2 ON cr.item2_id = si2.item_id
LEFT JOIN store_items AS si3 ON cr.item3_id = si3.item_id
LEFT JOIN store_items AS si4 ON cr.item4_id = si4.item_id
LEFT JOIN store_items AS si5 ON cr.item5_id = si5.item_id
LEFT JOIN store_items AS si_new ON cr.newitem_id = si_new.item_id
WHERE
ct.type_id = '".$type."';
I'm basically fetching everything now and handle the NULLs in the php code now.
Without seeing more info its had to see what you are trying achieve but you could start by using the the users inpute of the game to determine what data is first required before futher filtering. Try this:
Declare #Value int
set #Value = #User_input --- uses what ever the game user will
SELECT
a.recipe_id,
a.item1_id,
a.item1_uses,
a.item2_id,
a.item2_uses,
a.item3_id,
a.item3_uses,
a.item4_id,
a.item4_uses,
a.item5_id,
a.item5_uses,
a.newitem_id,
a.newitem_uses,
a.craft_description,
a.craft_button
--- you can insert more columns but i stopped here as i dont know what data you have in the other tables.
FROM
company_recipes a
INNER JOIN company_types b ON a.type_id = b.type_id
INNER JOIN store_items c ON c.type_id = b.type_id
WHERE
b.type_id = #Value; --- '".$type."';

Assistance with MySQL left outer join and differentiating query results from same key

I am trying to learn about SQL joins and trying to apply them to an application I am building. I am doing a query to find a "game record" on a schedule based on a specific game id. But on this game record; for the "h_team" and the "v_team"; only the ids of the teams are on the game record. And so what I want to do is join the "teams" table and look up the two different team_names of the "h_team" and "v_team". I have it also pull in a "division name" as well using a join since only the division id is stored on the game record. I have gotten this all to work fine; except I do not know how to get the results separately for the "team_name" for h_team and v_team. Basically the key for each one is just "team_name"; I will paste in my code and then explain further:
$array_game_id6=32;
$sql = "SELECT * FROM playoff_schedule LEFT OUTER JOIN teams on playoff_schedule.h_team = teams.team_id || playoff_schedule.v_team = teams.team_id LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id WHERE tom_game_id=$array_game_id6";
foreach ($dbh->query($sql) as $resultsg39)
{
$h_team=$resultsg39[h_team];
$v_team=$resultsg39[v_team];
$po_div_id=$resultsg39[po_div_id];
$round=$resultsg39[round];
$game_id=$resultsg39[game_id];
$date=$resultsg39[date];
$timestamp=$resultsg39[timestamp];
$h_score=$resultsg39[h_score];
$v_score=$resultsg39[v_score];
$tom_game_id=$resultsg39[tom_game_id];
$h_name=$resultsg39[team_name];
$div_name=$resultsg39[playoff_name];
}
the problem comes in when i am trying to get the results of the query and store them all in the different variables…
the last two "$h_name" and "$div_name" are being pulled from the JOINs all the prior ones are on the game record itself…
what I want to do is store both the names from "v_team" and "h_team" in the respective variables $h_name and $v_name;
I have it storing the $h_name no problem; but i do not know how to make it store both $h_name and $v_name separately as they are both values in the column "team_name" from "teams" table. So I just need to somehow make it so when i get my results it can tell the difference between the two different "team_names" and I can store them in the two different variables…
If this is not clear please let me know.
Thanks!
***** UPDATE 10:49pm EST 2/5/2015
have made some progress on this but my query is not working; I think it is a problem with the aliases and such are not right; here is my non-working query as it is right now:
$sth = $dbh->prepare("SELECT home_team.team_name as home_team_name, visiting_team.team_name as visiting_team_name,
h_team, v_team, po_div_id, round, game_id, date, timestamp, h_score, v_score, tom_game_id, playoff_name FROM playoff_schedule
LEFT OUTER JOIN teams as home_team on playoff_schedule.h_team = teams.team_id
LEFT OUTER JOIN teams as visiting_team on playoff_schedule.v_team = teams.team_id
LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6");
$sth->execute();
$article_list = $sth->fetchAll(PDO::FETCH_ASSOC);
foreach ($article_list as $row => $link) {
$h_team=$link['h_team'];
$v_team=$link['v_team'];
$po_div_id=$link['po_div_id'];
$round=$link['round'];
}
if anyone can spot a problem with my new query I would really appreciate it!
I think what you are trying to do is:
select home_team.team_name as home_team_name,
visiting_team.team_name as visiting_team_name
from playoff_schedule
join team as home_team on playoff_schedule.h_team = teams.team_id
join team as visiting_team on playoff_schedule.v_team = teams.team_id
You can join to the same table as many times as you want to. In this case, it makes sense, because you really are trying to get two different bits of information.
Based on your last edit, the following query appears to work:
SELECT home_team.team_name AS home_team_name,
visiting_team.team_name AS visiting_team_name,
h_team,
v_team,
playoff_schedule.po_div_id,
round,
game_id,
date,
timestamp,
h_score,
v_score,
tom_game_id,
playoff_name
FROM playoff_schedule
LEFT OUTER JOIN teams AS home_team
ON playoff_schedule.h_team = home_team.team_id
LEFT OUTER JOIN teams AS visiting_team
ON playoff_schedule.v_team = visiting_team.team_id
LEFT OUTER JOIN playoff_divisions
ON playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6
You can check the query and the schema at: SQLFiddle
A couple of thing that might be happening:
Is the query itself running?
What happens if you run the query in a mySQL client?
Are there any PHP errors in your log?
Could you post the schema itself?
Is $array_game_id6 actually an array of values? In that case, you need to use "in" as opposed to "=" in your where clause.
With regard to your updated query, I think the main thing you are missing is using the aliases in your JOIN conditions. You should keep your table aliases consistent throughout your query. Also, IMO its better to keep table aliases short so they are easier to read:
So applying those things to your query:
SELECT h.team_name as h_team_name, v.team_name as v_team_name, s.h_team, s.v_team, s.po_div_id, s.round, s.game_id, s.date, s.timestamp, s.h_score, s.v_score, s.tom_game_id, s.playoff_name
FROM playoff_schedule s
LEFT OUTER JOIN teams h ON (
s.h_team = h.team_id
)
LEFT OUTER JOIN teams as v ON (
s.v_team = v.team_id
)
LEFT OUTER JOIN playoff_divisions d ON (
s.po_div_id = d.po_div_id
)
WHERE s.tom_game_id = ?
Now I'm not 100% sure of your schema so I may have referenced some of the columns to the wrong table but you should be able to sort that out.

Mysql Complex Join Query Issue

I have 5 mysql tables as described below.
clinics table
id
name
d_location_subscription table
id
clinic_id
t_id //t_id will contain a foreign key of d_cities, d_states or d_countries table
type "country" "state" "city"
d_countries table
id
name
code
d_states table
id
d_country_id
name
code
d_city table
id
d_state_id
name
code
d_location_subscription table is used to record clinic's subscription for a location(it may be a city, state or country). I'm expecting to get all subscribed cities for a specific
clinic using d_location_subscription table.
For example, if clinic A is subscribed to Texas state, I should be able to get all city ids for clinic A.
I created following sql query, it looks ugly but generate a close result what i want to achieve.
select
`d`.`id` AS `clinic_id`,
if((`dct`.`id` is not null),`dct`.`id`,if((`dct1`.`id` is not null),`dct1`.`id`,`dct2`.`id`)) AS `d_city_id`
from ((((((((
`d_location_subscriptions` `dls`
join `clinics` `d`
on((`d`.`id` = `dls`.`clinic_id`)))
left join `d_countries` `dc`
on(((`dc`.`id` = `dls`.`t_id`) and (`dls`.`type` = 'country'))))
left join `d_states` `ds`
on((`ds`.`d_country_id` = `dc`.`id`)))
left join `d_cities` `dct2`
on((`dct2`.`d_state_id` = `ds`.`id`)))
left join `d_states` `ds1`
on(((`ds1`.`id` = `dls`.`t_id`) and (`dls`.`type` = 'state'))))
left join `d_cities` `dct`
on((`dct`.`d_state_id` = `ds1`.`id`)))
left join `d_cities` `dct1`
on(((`dct1`.`id` = `dls`.`t_id`) and (`dls`.`type` = 'city'))))
)
when there is record with type "country" in d_location_subscription table, I receive following result. total number of records returned are equal to the number of d_states table records.
How should I get rid of those Null values by changing above query?
And please advice me if this is the correct way to acheive similar functionality. Thanks in advance :)
The quickest, dirtiest way to achieve what you want is just to append this where condition to your query:
WHERE d_city_id is not null
but you might prefer to rework your query and decide where you really need LEFT joins and not INNER joins
the IF() computed column is in essence what STT LCU was trying to offer, but you can't use that directly in the where for some reason.
I've rewritten your query, but with different aliases to better follow the origination of the tables / relationships to get the data. In the end, I've added a where to test for ANY ONE of the "ID" values as NOT NULL. If they are ALL Null, the record should be excluded..
select
d.id AS clinic_id,
if(CityViaState.id is not null, CityViaState.id,
if( ByCity.id is not null, ByCity.id, CityViaCountry.id )) AS d_city_id
from
d_location_subscriptions dls
join clinics d
ON dls.clinic_id = d.id
left join d_countries ByCountry
ON dls.t_id = ByCountry.id
and dls.type = 'country'
left join d_states StateViaCountry
ON ByCountry.id = StateViaCountry.d_country_id
left join d_cities CityViaCountry
ON StateViaCountry.id = CityViaCountry.d_state_id
left join d_states ByState
ON dls.t_id = ByState.id
and dls.type = 'state'
left join d_cities CityViaState
ON ByState.id = CityViaState.d_state_id
left join d_cities ByCity
ON dls.t_id = ByCity.id
and dls.type = 'city'
where
CityViaState.id is not null
OR ByCity.id is not null
OR CityViaCountry.id is not null

SQL Advice - selecting multiple rows from a table as an innerJoin

I've been working on a project that until now has only needed to find 1 row from the joined table. But now I need to grab multiple rows..
So as it stand my sql works something like:
Select rows for each company for this particular project which alone would find company details (name, id, telephone.. blah).
Then I join a table that contains form data submitted for each company (multiple forms - so multiple records)
Until now i have been specifying one formid to look for in the join, but now i need to specify multiple ones.
If I use WHERE form_id = 1 OR form_id = 2 OR form_id = 3 ... I get a result of only the first form match that is found per company..
If I mix up the query so it looks for the forms 1st and returns multiple records for each company with different form data - that works in this sense..
But I am then looping through this array in a view and creating a table row per record (previously each row was a new company) but using the latter would cause multiple records to show for the same company.
Any way I can do this? I tried group by with the latter method but this results in only 1 record again.
SELECT DISTINCT p.project_company_has_user_id, p.project_company_has_user_project_id, p.project_company_has_user_user_id, c.company_id, c.company_hall_no, c.company_company_name, c.company_type, c.company_country, c.company_stand_number, c.company_image_file_1, p2.project_id, p2.project_name, u.user_id, u.user_username, o.orders_id, o2.order_detail_id, o2.order_detail_product_id, f2.form_question_has_answer_id, f2.form_question_has_answer_request, f2.form_question_has_answer_form_id, f2.form_question_has_answer_user_id
FROM project_company_has_user p
INNER JOIN company c ON p.project_company_has_user_company_id = c.company_id
INNER JOIN project p2 ON p.project_company_has_user_project_id = p2.project_id
INNER JOIN user u ON p.project_company_has_user_user_id = u.user_id
INNER JOIN form f ON p.project_company_has_user_project_id = f.form_project_id
LEFT JOIN orders o ON p.project_company_has_user_user_id = o.orders_user_id
LEFT JOIN order_detail o2 ON ((o2.order_detail_orders_id = o.orders_id AND (o2.order_detail_product_id = 65 OR o2.order_detail_product_id = 68 OR o2.order_detail_product_id = 64)))
LEFT JOIN form_question_has_answer f2 ON ((f2.form_question_has_answer_form_id = 297 AND f2.form_question_has_answer_user_id = p.project_company_has_user_user_id))
WHERE (f.form_template_name = "custom" AND p.project_company_has_user_garbage_collection = 0 AND p.project_company_has_user_project_id = 48) AND (LCASE(c.company_country) LIKE "%uk%" OR LCASE(c.company_country) LIKE "%uk%") ORDER BY company_company_name asc
you need another field in order_detail as o2 . this field is row_index(position),etc for positioning record
LEFT JOIN order_detail o2 ON (o2.row_index=1 AND (o2.order_detail_orders_id = o.orders_id AND (o2.order_detail_product_id = 65 OR o2.order_detail_product_id = 68 OR o2.order_detail_product_id = 64)))
Personally I would use an Outer Join for the table of which elements you need to list all matches. Should you them need to clean up that data you can build the logic into the Join Condition (as step 2). Depending on the volume of data you are handling and whether or not you need to reuse it later in the same proc, you may want to post that primary dataset into a temp table and use that as source (primary) for your later logic.
Hope that helps. If you need the code, let me know, but it is pretty straight forward.
Regards
Mac

Categories