php function with 2 arguments - php

Question

I have a function with 2 arguments. Here it is
function listBoats($con,$table){
//get record set for all boats sort them by their "sort" number
$queryBoat = "SELECT * FROM " .$table. " WHERE `id` <> 'mainPage' ORDER BY `sort` LIMIT 0, 1000";
$result = mysqli_query($con,$queryBoat);
return $result;
}
here is how I'm calling it
$result = listBoats($con,"CSINSTOCK"); //run query to list all the boats in the CSINSTOCK table
I can't get it to work. But If I add the variable $table = "CSINSTOCK" inside the function it does work. Why wont the function pass the "CSINSTOCK" variable through?

Answer 1

I would suggest that you use PDO. Here is an example
EXAMPLE.
This is your dbc class (dbc.php)
<?php
class dbc {
public $dbserver = 'server';
public $dbusername = 'user';
public $dbpassword = 'pass';
public $dbname = 'db';
function openDb() {
try {
$db = new PDO('mysql:host=' . $this->dbserver . ';dbname=' . $this->dbname . ';charset=utf8', '' . $this->dbusername . '', '' . $this->dbpassword . '');
} catch (PDOException $e) {
die("error, please try again");
}
return $db;
}
function getAllData($qty) {
//prepared query to prevent SQL injections
$query = "select * from TABLE where qty = ?";
$stmt = $this->openDb()->prepare($query);
$stmt->bindValue(1, $qty, PDO::PARAM_INT);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $rows;
}
?>
your PHP page:
<?php
require "dbc.php";
$getList = $db->getAllData(25);
foreach ($getList as $key=> $row) {
echo $row['columnName'] .' key: '. $key;
}
If you have the access to your database you should be able to perform your required operations.