PHP Error When Submited - php

Question

Im trying to display 2 rows from my database but i want it to be that when i click the 1st row radiobuttons the 1st row updates.. this is not happening ... when i click the 1st row the second row updated .. check it yourself live please ---> http://albsocial.us/seria.php
<?php
include("connect.php");
$query = "SELECT * FROM test ORDER BY `id` DESC LIMIT 2";
$result = mysql_query($query);
echo "<h2>Seria A</h2><hr/>";
while($row = mysql_fetch_array($result)){
$id = $row['id'];
$home = $row['home'];
$away = $row['away'];
$win = $row['win'];
$draw = $row['draw'];
$lose = $row['lose'];
echo $home, " - ", $away,"<br/>";
echo "<form action='' method='post'>
<input type='hidden' name='id' value='".$row['id']."'>
<input type='radio' name='select' value='1'>1
<input type='radio' name='select' value='X'>X
<input type='radio' name='select' value='2'>2
<input type='submit' name='submit' value='Submit'/>
</form>
";
echo $home, " -> ", $win;
echo "<br/>Barazim -> ", $draw,"<br/>";
echo $away, " -> ", $lose,"<hr/>";
}
$id = isset($_POST['id']) && is_numeric($_POST['id']) ? $_POST['id']:false;
if (isset($_POST) && $_POST['select'] == 1){
$select = $_POST['select'];
$select = $win + $select;
mysql_query("UPDATE test SET win='$select' WHERE id='$id'");
header('Location: ../seria.php');
}else if (isset($_POST) && $_POST['select'] == 'X'){
$select = $_POST['select'];
$select = '1';
$select = $draw + $select;
mysql_query("UPDATE test SET draw='$select' WHERE id='$id'");
header('Location: ../seria.php');
}else if (isset($_POST) && $_POST['select'] == 2){
$select = $_POST['select'];
$select = '1';
$select = $lose + $select;
mysql_query("UPDATE test SET lose='$select' WHERE id='$id'");
header('Location: ../seria.php');
}
?>

Answer 1

the problem is with your button name. you should give each of your button name, a different name from each other so that the server will know which form is being submitted. you could try to give your button name based on id like this :
<input type='submit' name='submit<?php echo $id; ?>' value='Submit'/>
then you could do the conditional statement to see which button is clicked like this :
if ( isset( $_POST['submit$id'] ) ) { }

Answer 2

Your while loop will always leave $id set to the id of the last row in your dataset.
You'll need some way of submitting an id for each row in your form. Then, get that value when you retrieve POST variables.
If you structure things properly, you won't need to do a header redirect.
Also, I suggest moving the isset($_POST) test to it's own if statement, just so none of that code gets executed if nothing has been posted.
Here's how I would rework it:
<?php
include("connect.php");
// if data is submitted, update database
if (!empty($_POST)) {
$id = isset($_POST['id']) && is_numeric($_POST['id']) ? $_POST['id'] : false;
$select = isset($_POST['select'])&&in_array($_POST['select'],array('win','lose','draw')) ? $_POST['select'] : false;
if ($id && $select) {
$sql="UPDATE `test` SET `$select`=`$select`+1 WHERE `id`='$id';";
mysql_query($sql) or die(mysql_error());
}
}
// get data from database
$query = "SELECT * FROM test ORDER BY `id` DESC LIMIT 2";
$result = mysql_query($query) or die(mysql_error());
// output
?><h2>Seria A</h2><hr/><?php
while($row = mysql_fetch_assoc($result)){
?><p><?=$row['home']?> - <?=$row['away']?></p>
<form action="" method="post">
<input type="hidden" name="id" value="<?=$row['id']?>">
<input type="radio" name="select" value="win">1
<input type="radio" name="select" value="draw">X
<input type="radio" name="select" value="lose">2
<input type="submit" name="submit" value="Submit">
</form>
<p><?=$row['home']?> -> <?=$row['win']?></p>
<p>Barazim -> <?=$row['draw']?></p>
<p><?=$row['away']?> -> <?=$row['lose']?></p><?php
}
?>
Incidentally, how are you handling "home" vs "away" games?