Displaying data from 3 arrays with correct format - php

Question

Hello and thanks in advance to anyone that can answer my question. I'm still a bit green in terms of PHP but I will try to explain what I want and what my problem is.
I have 3 arrays with MySQL query's results:
$resultsTextPageID (with pageID value [int(10)])
$resultsTextPageName (with pageName value [text])
$resultsTextIntro (with pageIntro value [text])
I would like the final output to be
<b>[pageName goes here]</b><br />
[pageIntro goes here]<br /><br />
Like this:
[pageName]
[pageIntro]
[pageName]
[pageIntro]
I tried the following code:
//ECHO PAGEID PART
while ($pageID = mysql_fetch_assoc($resultsTextPageID))
{
echo '<b><a href="page.php?id='.$pageID['pageID'].'">';
//ECHO PAGENAME PART
while ($pageName = mysql_fetch_assoc($resultsTextPageName))
{
echo $pageName['pageName'].'</a></b><br />';
//ECHO PAGEINTRO PART
while ($intro = mysql_fetch_assoc($resultsTextIntro))
{
echo $intro['pageIntro'].'<br /><br />';
}
}
}
But the output I get is:
[pageName]
[pageIntro]
[pageIntro]
[pageName]
I think the problem is on the way I structured the while loops, but for the life of me, I can't figure out how to fix it.
Can someone help me? Again, thanks in advance! :D
EDIT 1:
Here is the query code:
//Prepare and set search query string
$q = preg_replace("/[^a-zA-Z0-9 !?.:]+/", " ", $_GET['q']);
//RETRIEVE KEYWORDS
//seperate multiple keywords into array
$keywords = explode(" ", $q);
//Clean empty arrays so they don’t get every row as result
$keywords = array_diff($keywords, array(""));
//MySQL QUERY
$searchTextPageID = "SELECT pageID FROM pages WHERE pageIntro LIKE '%".$keywords[$i]."%' OR pageText LIKE '%".$keywords[$i]."%'";
$searchTextPageName = "SELECT pageName FROM pages WHERE pageIntro LIKE '%".$keywords[$i]."%' OR pageText LIKE '%".$keywords[$i]."%'";
$searchTextIntro = "SELECT pageIntro FROM pages WHERE pageIntro LIKE '%".$keywords[$i]."%' OR pageText LIKE '%".$keywords[$i]."%'";

Answer 1

Essentilally you should be collecting all 3 pieces of info at one time, if these are all in the same table, the job is quite easy.
$qry = "select pageID, pageName, pageIntro from <your table name>";
// now loop thru results
while ($page = mysql_fetch_assoc($qry))
{
echo '<b><a href="page.php?id='.$page['pageID'].'">';
echo $page['pageName'].'</a></b><p>';
echo $page['pageIntro'].'<br /></p>';
}
If the data is spread over more than one table you will have to do a JOIN in your sql.

Answer 2

Your code doesn´t make much sense since you iterate over every entry of $resultsTextPageID but already in the first entry you iterate over all $resultsTextPageName. Therefore the second time you enter the body of resultsTextPageID-loop there is no more to fetch from $resultsTextPageName. This happens the exact same way to the second/third while-loop.
Assuming you have only one title and only one page intro you can change your code to
while ($pageID = mysql_fetch_assoc($resultsTextPageID))
{
/* get only ONE entry */
$pageName = mysql_fetch_assoc($resultsTextPageName);
$intro = mysql_fetch_assoc($resultsTextIntro);
echo '<b><a href="page.php?id='.$pageID['pageID'].'">';
echo $pageName['pageName'].'</a></b><br />';
echo $intro['pageIntro'].'<br /><br />';
}
But that is in no way nice code.
You should take a look at mysql JOIN commands to arrange your data correctly in the database select. Then your output code would be much easier.
EDIT because you added mysql-code:
you are selecting 3 times from the same db under the same condition, only to retrieve different columns, change it to
$searchTextPageID = "SELECT pageIDm, pageName, pageIntro FROM pages WHERE pageIntro LIKE '%".$keywords[$i]."%' OR pageText LIKE '%".$keywords[$i]."%'";