incrementing a date in a loop - php

Question

I've done some reasearch but I did not find any issue. I try to increment a date in a loop in order to test if some files does exist. In fact I would like to make some user play each sevent days. When they played the file is created whith their IP and with the date. So we test in a loop if a file does exist with each date between this days. If it exist we return 1 else we return 0.
I met some trouble I do not really know how to increment a date in php using aloop
I tried something like that
**function afficheTirageAusort() {
//Initialisation des variables
$ip = $_SERVER["REMOTE_ADDR"];
$date_str = date('d-m-y');
$rep = "ip/";
if (!file_exists($rep)) {
fopen($rep, "w+");
}
$fichier = $ip . $date_str . '.txt';
$periode = 7;
$i = 0;
$date_jeu = 0;
//Test de l\'existence du fichier
while ($i <= $periode) {
list($d,$m,$Y)= explode('-',$date_str);
$date2 = Date('d-m-Y', mktime(0, 0, 0, $m, $d + 1, $Y));
$date = Date($date2, mktime(0, 0, 0, $m, $d + 1, $Y));
var_dump($date);
if (file_exists($rep . $ip . $date . '.txt')) {
$var = 0;
} else {
fopen($rep . $ip . $date . '.txt', 'w+');
$var = 1;
//break 1;
}
$i++;
};
return $var;
}
I'm a beginner in php.
anykind of help will be much appreciated.

Answer 1

You will want to use strtotime and continue to use the $date variables:
// Setup the dates
list($d, $m, $Y) = explode('-', $date_str);
$date2 = Date('d-m-Y', mktime(0, 0, 0, $m, $d, $Y));
$date = Date($date2, mktime(0, 0, 0, $m, $d, $Y));
//Test de l\'existence du fichier
while ($i <= $periode) {
$date = strtotime("+1 day", strtotime($date)); // 1 day past previous date
$date2 = strtotime("+1 day", strtotime($date)); // 1 Day past the $date var
echo date("Y-m-d", $date);
var_dump($date);
if (file_exists($rep . $ip . $date . '.txt')) {
$var = 0;
} else {
fopen($rep . $ip . $date . '.txt', 'w+');
$var = 1;
//break 1;
}
$i++;
};
return $var;

Answer 2

try something along these lines.
$todaysdate = date("Y-m-d H:i:s");
$tomorrowsdate = date("Y-m-d H:i:s", date()+86400);
essentially i just added 86400 seconds to the current date, and there are 86400 seconds in a day, so I just added 1 day.

Answer 3

Wouldn't it be easier for you to create date out of UNIX Timestamp and increment it? Like this:
$time = time() + (3600 * 24);
$date = date('d-m-Y', $time);