Can't display data from my database - php

Question

I am trying to allow users to select restrictions from my database by using 3 drop down boxes. I have set them up and I have connected to my database. However, once the user hits the submit button, I can't get data to be displayed in a table. Here is my code:
<?php
require_once 'connection.php';
?>
<form action="stats.php" method ="post">
<input type="hidden" name="submitted" value="true" />
<fieldset>
<legend>
Specify Date, Month, and County
</legend>
<p>
<label for="year">
Please select a year
</label>
<select name= 'year'>
<?php
$query = "select distinct year from unemployed";
$result = $conn->query($query);
while($row = $result->fetch_object()) {
echo "<option value='".$row->year."'>".$row->year."</option>";
}
?>
</select>
</p>
<p>
<label for="month">
Please select a month
<label>
<select name= 'month'>
<?php
$query = "select distinct month from unemployed";
$result = $conn->query($query);
while($row = $result->fetch_object()) {
echo "<option value='".$row->month."'>".$row->month."</option>";
}
?>
</select>
</p>
<p>
<label for="location">
Please specify a location
</label>
<select name='select'>
<?php
$query = "select * from unemployed";
$result = $conn->query($query);
while ($finfo = $result->fetch_field()) {
echo "<option value='".$finfo->name."'>".$finfo->name."</option>";
}
?>
</select>
</p>
<input type ="submit" />
</fieldset>
</form>
<?php
if (isset($_POST['submitted'])) {
include('connection.php');
$gYear = $_POST["year"];
$gMonth = $_POST["month"];
$gSelect = $_POST["select"];
$query = "select $gSelect from unemployed where year='$gYear' and month='$gMonth'";
$result = $conn->query($query) or die('error getting data');
echo"<table>";
echo "<tr><th>Year</th><th>Time</th><th>$gSelect</th></tr>";
while ($row = $result->fetch_object()){
echo "<tr><td>";
echo $row['Year'];
echo "</td><td>";
echo $row['Month'];
echo "</td><td>";
echo $row['$gSelect'];
echo "</td></tr>";
}
echo "</table";
} // end of main if statement
?>
I can't get the data to be displayed in a table at all. I have tried multiple ways, but I am still getting errors. To ensure that I am connected to my database, I used var_dump($row) to make sure, and that worked okay. So that is not the problem. Does anyone have any idea what is wrong with my code?

Answer 1

When you retrieve the data from your result set you're fetching it as an object:
while ($row = $result->fetch_object()){
But when you come to display it, you refer to it as an array:
echo "<tr><td>";
echo $row['Year']; // array syntax.
You should be using object syntax:
echo "<tr><td>";
echo $row->Year; // object syntax.
If you check your error logs you should see a lot of messages to this effect.