There is some stupid mistake with what i am doing, but for some reason i cannot push another key value to an array of arrays...
Here is what i am trying to do:
$result = mysqli_query($conn, $query) or die("Sql Error: " . mysqli_error($conn)); $creatives = array();
while($row = mysqli_fetch_assoc($result)) {
$elements[$row["id"]] = array("min_load_size" => $row["min_load_size"],
"avg_load_size" => $row["avg_load_size"], "max_load_size" => $row["max_load_size"]);
}
After this i am making another call to a differend database and i want to add to each of the arrays another key/value pair. And the code looks like that:
while($row = mysqli_fetch_assoc($result)) {
$arr = $elements[$row["id"]];
$arr["technical_attribute_id"] = $row["technical_attribute_id"];
}
after that i print out my elements array and there is no "technical_attribute_id" in any of the underlying arrays. there is no doubt that the id's match the keys in the regard.
Thanks
You should use references:
$arr = &$elements[$row["id"]];
Without the & that statement will just make a copy of $elements[$row['id']] once it executes the next code line.
Alternatively, you could type the whole thing out:
$elements[$row["id"]]["technical_attribute_id"] = $row["technical_attribute_id"];
Related
Hi I need to add some value-key pair to an array which is the output of mysql query. Below is the code,
$query = "select TITLE,DESCRIPTION from TABLE where ID='1234'";
$result = mysqli_query($conn, $query);
$numrows = mysqli_num_rows($result);
if($numrows>0)
{
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
$myArray[] = $row;
}
}
echo json_encode($myArray);
Giving me the result like
[{"TITLE":"Special","DESCRIPTION":"This is DESCRIPTION."}]
Now I need to to add an another key-value pair to generate the json output like,
[{"TITLE":"Special","DESCRIPTION":"This is DESCRIPTION.","URL":"imgname.jpg"}]
So I added the code
$myArray["URL"]="imgname.jpg";
echo json_encode($myArray);
But giving me the output like,
{"0":{"TITLE":"Chef Special","DESCRIPTION":"Grilled Salmon and crab."},"URL":"imgname.jpg"}
Is there anything wrong with above code.
check your data with
var_dump($myArray);
and you will find, that it is a 2-dimensional array. you'd have to add your data with
$myArray[0]["URL"] = "imgname.jpg";
If you have to add after encoding it, reverse with:
$a = json_decode($myArray,true)
add a new pair of key, value with $a['URL'] = "imgname.jpg" and then encode again.
I am basically trying to fetch results from a SQL database and load that into a multidimensional array so i can use them later on in the page.
while($row = mysqli_fetch_array($result))
{
$send = array
(
array($row['Name'],$row['Email'],$row['Mobile'])
);
$count = $count + 1;
}
That is what i am using to get the results which if i print within the while loop it will echo all the results. However when putting it into the array it loads each result into the array as the first result. My initial plan was to use a counting variable to set where in the array the result was set to with this adding by one each time. I am not certain how to specify where to add the result i thought something along the lines of
$send = array[$count]
(
array.....
so i could then refer to the results as 0 to count length but i am not sure how to make this work. Or ,which i presume, if there is a much easier and better way of going about it. I am also not sure if this is necessary as surely the results seem to be in an array when gathered from the SQL database but i am unsure if this array is populated with each while loop or stored and can be accessed at any point
If any one can give me an example of something similar or point me at some documentation much appreciated
Try this:
$count = 0;
while ($row = mysqli_fetch_array($result)) {
$send[$count] = array($row['Name'], $row['Email'], $row['Mobile']);
$count++;
}
I have a better way for you. You could also use the id for your index, if you have one:
while ($row = mysqli_fetch_array($result)) {
$send[$row['id']] = array(
"Name" => $row['Name'],
"Email" => $row['Email'],
"Mobile" => $row['Mobile']
);
}
You can use:
$count = 0;
while($row = mysqli_fetch_array($result))
{
$send[$count] = $row;
$count ++;
}
Also you might want to use the table id as an array index, so you can access the records by ID later. In that case you can do:
while($row = mysqli_fetch_array($result))
{
$send[$row['id']] = $row;
}
You're declaring your array inside your loop. So it will reset it every time.
$send = array();
while($row = mysqli_fetch_array($result))
{
$send[] = array($row['Name'],$row['Email'],$row['Mobile']);
}
I'm a bit new to multidimensional arrays, and would like to see if I'm doing it right. preferably, I'd like to name the arrays within the main array for ease of use.
$unique_array = array(
username=>array(),
user_id=>array(),
weeknumber=>array()
);
and then I have a while loop which checks some database results:
while($row = mysql_fetch_array($query)) //yes, I know mysql is deprecated
{
$unique_array[] = username=>$row['username'], user_id=>$row['user_id'], week number=>['weeknumber'];
}
I'm not sure if I am placing the values in the array from within the while loop correctly, or if it needs to be done some other way. I couldn't find any resources I could easily understand on SO or elsewhere to deal with query results within a named array within a multidimensional array.
EDIT FOLLOW UP QUESTION: I also need to check the array for duplicate values, because there will be multiple values that are exactly the same, but I only want one of them.
Any help is appreciated!
EDIT SOLUTION:
By modifying the answer I was able to create code to fit my needs.
Array initialization:
$unique_array = array(
'username'=>array(),
'user_id'=>array(),
'weeknumber'=>array()
);
Building the array from within a while loop:
while($row = mysql_fetch_array($query))
{
$unique_array[] = array('username'=>$row['username'], 'user_id'=>$row['user_id'], 'weeknumber'=>$row['weeknumber']);
}
And finally, I need to make sure the array values are unique (there are duplicates entries as a result of database and query limitations), after the while loop I have:
print_r(multi_unique($unique_array));
Is the top level an associative array or a numeric array?
If it is an associative array, it should have structure like this:
$unique_array = array(
'username'=>array('John','Mike',...),
'user_id'=>array(1,2,3,...),
'week_number'=>array(1,2,3,...)
);
Or if it is a numeric array, it should have structure like this:
$unique_array = array(
array('username'=>'John', 'user_id'=>1, 'week_number'=>1),
array('username'=>'Mike', 'user_id'=>2, 'week_number'=>2),
array('username'=>'Sam', 'user_id'=>3, 'week_number'=>3),
...
)
for the first type use the code below:
while ($row = mysql_fetch_assoc($query)) {
$unique_array['username'][] = $row['username'],
$unique_array['user_id'][] = $row['user_id'],
$unique_array['week_number'][] = $row['week_number'],
}
for the second type, it is something like your code. But there are some syntax problems:
while($row = mysql_fetch_array($query)) //yes, I know mysql is deprecated
{
$unique_array[] = array('username'=>$row['username'], 'user_id'=>$row['user_id'], 'week_number'=>$row['weeknumber']);
}
I am trying to add array data from mysql. But only the last row details are getting added. I tried array_push also but did not work. Can any one help
$sql="SELECT * FROM server_details";
$result=mysqli_query($dbC, $sql);
while ($row = mysqli_fetch_array($result))
{
$services=array(
$row['server_name'] => array($row['server_add'] => $row['port'])
);
}
By not creating a new array in every iteration of the loop :
$sql = "SELECT * FROM server_details";
$result = mysqli_query($dbC, $sql);
$services = array();
while ($row = mysqli_fetch_array($result)) {
$services[$row['server_name']] = array($row['server_add'] => $row['port']);
}
Perhaps you're looking for this:
$services[ $row['server_name'] ] = array($row['server_add'] => $row['port']);
In the end you'll get in your $services variable an associative array, indexed by server_name column values.
If they're not unique, you should do this instead...
$services[ $row['server_name'] ][] = array($row['server_add'] => $row['port']);
This way you'll still get the same associative array, but its values will be indexed arrays; thus you won't lose any information for records with the same server_name.
I have a little problem that I don't understand. I have a db that has an owner and type (and more off course). I want to get a list of all the type values that has owner equal to the current user, but I get only two result
$sql = "SELECT type FROM cars WHERE owner='".mysql_real_escape_string($_SESSION['username'])."' AND selling='0' ORDER BY id DESC ";
$result = mysql_query($sql,$con);
print_r(mysql_fetch_array($result));
prints out:
Array ( [0] => 18 [type] => 18 )
and
$sql = "SELECT type FROM cars WHERE owner='".mysql_real_escape_string($_SESSION['username'])."' AND selling='0' ";
prints out:
Array ( [0] => 16 [type] => 16 )
And the result should be something like 19, 19, 18, 17, 16 in an array. Thats all the types that has me as set as owner.
I have got this working now:
for ($x = 0; $x < mysql_num_rows($result); $x++){
$row = mysql_fetch_assoc($result);
echo $row['type'];
}
Here I print out all the values correctly, but I need to create an array with all the values. I though I could use array_push, but there most be a better way of doing it. I thought I would get all the type values with a simple mysql query.
Very often this is done in a while loop:
$types = array();
while(($row = mysql_fetch_assoc($result))) {
$types[] = $row['type'];
}
Have a look at the examples in the documentation.
The mysql_fetch_* methods will always get the next element of the result set:
Returns an array of strings that corresponds to the fetched row, or FALSE if there are no more rows.
That is why the while loops works. If there aren't any rows anymore $row will be false and the while loop exists.
It only seems that mysql_fetch_array gets more than one row, because by default it gets the result as normal and as associative value:
By using MYSQL_BOTH (default), you'll get an array with both associative and number indices.
Your example shows it best, you get the same value 18 and you can access it via $v[0] or $v['type'].
THE CORRECT WAY ************************ THE CORRECT WAY
while($rows[] = mysqli_fetch_assoc($result));
array_pop($rows); // pop the last row off, which is an empty row
You do need to iterate through...
$typeArray = array();
$query = "select * from whatever";
$result = mysql_query($query);
if ($result) {
while ($record = mysql_fetch_array($results)) $typeArray[] = $record['type'];
}
while($row = mysql_fetch_assoc($result)) {
echo $row['type'];
}
You could also make life easier using a wrapper, e.g. with ADODb:
$myarray=$db->GetCol("SELECT type FROM cars ".
"WHERE owner=? and selling=0",
array($_SESSION['username']));
A good wrapper will do all your escaping for you too, making things easier to read.
$type_array = array();
while($row = mysql_fetch_assoc($result)) {
$type_array[] = $row['type'];
}
You may want to go look at the SQL Injection article on Wikipedia. Look under the "Hexadecimal Conversion" part to find a small function to do your SQL commands and return an array with the information in it.
https://en.wikipedia.org/wiki/SQL_injection
I wrote the dosql() function because I got tired of having my SQL commands executing all over the place, forgetting to check for errors, and being able to log all of my commands to a log file for later viewing if need be. The routine is free for whoever wants to use it for whatever purpose. I actually have expanded on the function a bit because I wanted it to do more but this basic function is a good starting point for getting the output back from an SQL call.