Query isn't getting executed - php

Question

Can some onw please explain what is wrong with this ... this worked completely fine with procedural php
function foo(){
$incomingtime = date('Y-m-d H:i:s', time());
$stmt = $db->stmt_init();
$id = "Abc123" ;
$u_id = 1;
$c_id = 1;
$query = "INSERT INTO table (indate, myid, uniqueid, commonid)
VALUES (?, ?, ?, ?)";
$stmt = $db->prepare($query);
$stmt->bind_param('ssii', $incomingtime, $id, $u_id, $c_id);
$stmt->execute();
printf("Affected rows (UPDATE): %d\n", $db->affected_rows); // Always return 1
$stmt->close();
}
But nothing goes in the database.
Datatype in mysql db for indate is datetime

Answer 1

There's several issues with this code.
$stmt_4 is used before it's defined.
$u_id and $c_id are both defined then not used.
Trying to execute $stmt without supplying parameters.
$db is not defined.
$id is not defined.
If you are trying to convert working code to a function make sure that either the function gets these passed in as an argument, they are marked as global or the function creates/ retrieves them.

Answer 2

Check changing:
$query = "INSERT INTO table (indate, myid, uniqueid, commonid)
VALUES (?, ?, ?, ?)";
$stmt = $db->prepare($query);
$stmt->bind_param('ssii', $incomingtime, $id, $u_id, $c_id);
$u_id = 1;
$c_id = 1;
$stmt->execute();
to:
$u_id = 1;
$c_id = 1;
$query = "INSERT INTO table (indate, myid, uniqueid, commonid)
VALUES (CURRENT_TIMESTAMP, ?, ?, ?)"
$stmt = $db->prepare($query);
$stmt->execute(array($id, $u_id, $c_id));
NOTE: I deleted the parameter ssii because it's not considered in the query. It only expects 4 parameters.