Reverse date order in script - php

Question

I have a recruitment script written in PHP that I am working with at present. On our registrations page there is a drop down for date of birth which you can see in action here:
http://www.v3recruitment.com/users/register.php
As you can see, the date starts at 1900, what I would like to do is reverse the date order. I think I have found the code thats generating the dates, but my PHP is not good enough to work out how to get it to show dates in a reverse order, here is that code:
function FetchYears($type){
$start = 1901;
$end = date("Y");
for($i=$start;$i<=$end;$i++){
$array[]['year'] = $i;
}
return $array;
}
The front end is using Smarty Templates and here is that code:
{section name="c" loop=$dob_years}
<option value="{$dob_years[c].year}" {get_value field=select selectvalue=$dob_years[c].year fieldname="dob_year"}>{$dob_years[c].year}</option>
{/section}
Can anyone please help me with this?

Answer 1

Either reverse loop or use array_reverse()
change return$array; to return array_reverse($array);
For smarty it's very simple you don't have to even create this function in PHP it can be done in smarty as well.
{foreach $dob_years as $entry)
<option value="{$entry.year}">{$entry.year}</option>
{/foreach}
Check HTML_SELECT_DATE in smarty or simply use just the code below doesn't require any additional php code.
{assign var=currentYear value=$smarty.now|date_format:"%Y"}
{assign var=fromYear value="2003"}
{section name=years start=$currentYear step=-1 loop=$fromYear}
{$smarty.section.years.index}
{/section

Answer 2

array_reverse does what it says on the tin.

Answer 3

Try like this
function FetchYears($type){
$start = date("Y");
$end = 1901;
for($i=$start;$i>=$end;$i--){
$array[]['year'] = $i;
}
return $array;
}
or simply use array_reverse while returning your array like
function FetchYears($type){
$start = 1901;
$end = date("Y");
for($i=$start;$i<=$end;$i++){
$array[]['year'] = $i;
}
return array_reverse($array);
}

Answer 4

function FetchYears($type){
$start = date("Y");
$end = 1901;
for($i=$start;$i>=$end;$i--){
$array[]['year'] = $i;
}
return $array;
}

Answer 5

for ($i = $end; $i >= $start; $i--) {
$array[]['year'] = $i;
}
Haven't tested it yet, should work :)

Answer 6

Probably the easiest way to do this would be to put the dates in UTC (integer) format.
$dates[$i] = $timestamp;
Then use the PHP sort function to sort the dates.
sort($dates,SORT_NUMERIC);
You can use rsort for the opposite.
rsort($dates,SORT_NUMERIC);
When you are finished, iterate through your array and covert back using the date() function.
echo (date('m-d-Y', $dates[$i]));