how to check for a linked string inside an array? - php

Question

I have an array, let us say, $breadcrumb = array("home" , "groups", "Create content", "some other element" "so on"); I want to check if it contains a string "Create content" and then unset the string, but my problem is that "Create content" is a link (anchored) and not just a plain string, I tried in_array(), but not successful. How do I look for it, to make it more clear?
Here is my code:
<?php
function phptemplate_breadcrumb($breadcrumb) {
if (!empty($breadcrumb)) {
if(in_array("Create content",$breadcrumb)){
foreach($breadcrumb as $key => $value){
if("Create content" == strip_tags($value)){
unset($breadcrumb[$key]);
}
}
}
}
return '<div class="breadcrumb">'. implode(' › ', $breadcrumb) .'</div>';
}
Note: I know it can be done anyway if I ommit in_array() check but I don't want to loop through the array unecessarily, if the 'Create content' is not in the array.
Edit: actual array is:
array(
[0]=>home
[1]=> groups
[2]=> my group
[3]=> Create content
)
here 'Create content' may occupy any position.
Note: all elements are links (anchored).

Answer 1

If your real array is something like
array(
[0]=> home
[1]=> groups
[2]=> my group
[3]=> Create content
)
then you can try to use preg-grep so as to return all items that match your regExp pattern:
$content_links = preg_grep("/[YOUR REGEXP HERE]/", $breadcrumb);
// if you have matching items
if (0 < sizeof($content_links)) {
// do some stuff - do `foreach` loop or use `array_diff`
}
UPD:
Or even you can use PREG_GREP_INVERT as third parameter and get all items that doens't match RegExp pattern.