Using an incremented value in a SELECT WHERE query MYSQL - php

Question

Let me start off that I have only been coding for the past few months. I know I've probably got a ton of mistakes or bad practices everywhere. I like constructive criticism, so please let me know what i can do better, along with how to address my current issue.
This code's purpose is to create a table of part numbers, and their associated location column data (storage type, Rack number, Shelf number) based on previously entered information. I've got the entry form working perfectly. I type in a number of parts I want to search for, and it posts that number back to itself. I'm then presented with that number of text input fields to put in part numbers.
//this form is to submit the number of parts you're looking for,
//and posts back to itself
<form action=View2.php method="post">
<input type="text" name="num">
<button type="submit">Number of Parts</button>
</form>
//This form takes the posted number, and creates that many text fields,
//populated with the number part you are entering.
<form action="List.php" method="post">
<?php while ($i<=$num){
echo "<input type='text' name='part$i' value='part$i'><br><br>";$i++;}?><input type="hidden" name="num" value="<?php $num?>">
<button type="submit">Submit</button>
</form>
My problem comes with running a mysqli_query to populate the table. I'm stuck as to where to go from here. I know that i need to take each part number that gets posted, and use it as the criteria in a SELECT WHERE search, so i made this While loop:
<?php
echo "<table border='1'>
<tr>
<th>Part Number</th>
<th>Location</th>
<th>Rack</th>
<th>Shelf</th>
</tr>";
while($i<=$num){
$x=$_POST["part$i"];
$result = ($con,"SELECT * FROM parts WHERE pn ='$x'");
$row = ($result);
echo "<tr>";
echo "<td>" . $x . "</td>";
echo "<td>" . $row['rcb'] . "</td>";
echo "<td>" . $row['ra'] . "</td>";
echo "<td>" . $row['sh'] . "</td>";
echo "</tr>";
$i++;
}
echo "</table>";?>
The page crashes at this point, but if i comment out the $result line, i'll get the table with the part number fields populated with the values from the previous page.
Anyone have any idea what i'm doing wrong, or how i can do it better?

Answer 1

This line doesn't do anything good :
$result = ($con,"SELECT * FROM parts WHERE pn ='$x'");
You need to actually query the DB.
$mysqli = new mysqli("localhost", "my_user", "my_password", "...");
...
$result = $mysqli->query("SELECT * FROM parts WHERE pn ='$x'");
You should use prepared statements so your code isn't open to sql injections though...