json_encode : values showing null - php

<?php
require_once (realpath(dirname(__FILE__) . '/../includes/database.php'));
class User {
public $email;
public $password;
public function find_email($email, $password) {
global $database;
$pswd = substr(md5($password), 0, 25);
$results_array = self::find_by_sql("SELECT * FROM tbl_users where email_id='".$email."' AND password='".$pswd."'");
return !empty($results_array)? array_shift($results_array) : false;
}
public static function find_by_sql($sql){
global $database;
$results = $database -> query($sql);
$object_array = array();
while($row = $database -> fetch_array($results)){
$object_array[] = self::instantiate($row);
}
return $object_array;
}
public static function instantiate($row) {
$event = new self;
foreach($row as $attribute => $value) {
if($event -> has_attribute($attribute)) {
$event -> $attribute = $value;
}
}
return $event;
}
private function has_attribute($attribute) {
$object_vars = get_object_vars($this);
return array_key_exists($attribute, $object_vars);
}
}
if (isset($_GET['email']) && isset($_GET['password'])) {
$result = new User();
$result->find_email($_GET['email'], $_GET['password']);
echo json_encode($result);
}
?>
This is the login.php which is supposed to print out the json for the required user, but whenever I try to get the json, this is getting returned.
{"email":null,"password":null}
Any help would be appreciated. Thanks.

You don't do anything with the result of find_email. Your class doesn't update it's own properties when find_email is called. Instead, it returns a new instance of the class with the email and password properties set, so you need to capture the return value and encode that.
Change to:
$result = new User();
$user = $result->find_email($_GET['email'], $_GET['password']);
echo json_encode($user);
Side note: have a look at SOLID and Dependency Injection. DI would be preferred over having a global $Database.

Related

How to dynamically display user name from the database after log in?

I need to dynamically display user name from logged in user in my OOP PHP project. I can display it when I type right id from the database but it shows error when I try to define property $user_id in my function find_by_id. I need help on how to define $user_id variable. Here is my code:
index.php
<?php $user = User::find_by_id($user_id); ?>
<h1>Hello, <?php echo $user->username; ?></h1>
user.php
<?php
class User
{
protected static $db_table = "users";
public $id;
public $username;
public $password;
public $first_name;
public $last_name;
private function has_the_attribute($the_attribute)
{
$object_properties = get_object_vars($this);
return array_key_exists($the_attribute, $object_properties);
}
public static function instantation($the_record)
{
$the_object = new self;
foreach ($the_record as $the_attribute => $value) {
if ($the_object->has_the_attribute($the_attribute)) {
$the_object->$the_attribute = $value;
}
}
return $the_object;
}
public static function find_this_query($sql)
{
global $database;
$result_set = $database->query($sql);
$the_object_array = [];
while ($row = mysqli_fetch_array($result_set)) {
$the_object_array[] = self::instantation($row);
}
return $the_object_array;
}
public static function find_all()
{
return self::find_this_query("SELECT * FROM " . static::$db_table . " ");
}
public static function find_by_id($user_id)
{
global $database;
$the_result_array = self::find_this_query("SELECT * FROM " . self::$db_table . " WHERE id = $user_id");
return !empty($the_result_array) ? array_shift($the_result_array) : false;
}
public static function verify_user($username, $password)
{
global $database;
$username = $database->escape_string($username);
$password = $database->escape_string($password);
$sql = "SELECT * FROM " . self::$db_table . " WHERE ";
$sql .= "username = '{$username}' ";
$sql .= "AND password = '{$password}'";
$the_result_array = self::find_this_query($sql);
return !empty($the_result_array) ? array_shift($the_result_array) : false;
}
}
$user = new User();
session.php
<?php
class Session
{
private $signed_in = false;
public $user_id;
public $message;
public function __construct()
{
session_start();
$this->check_the_login();
$this->check_message();
}
public function login($user)
{
if ($user) {
$this->user_id = $_SESSION['user_id'] = $user->id;
$this->signed_in = true;
}
}
public function logout()
{
unset($_SESSION['user_id']);
unset($this->user_id);
$this->signed_in = false;
}
private function check_the_login()
{
if (isset($_SESSION['user_id'])) {
$this->user_id = $_SESSION['user_id'];
$this->signed_in = true;
} else {
unset($this->user_id);
$this->signed_in = false;
}
}
public function is_signed_in()
{
return $this->signed_in;
}
public function message($msg="")
{
if (!empty($msg)) {
$_SESSION['message'] = $msg;
} else {
return $this->message;
}
}
public function check_message()
{
if (isset($_SESSION['message'])) {
$this->message = $_SESSION['message'];
unset($_SESSION['message']);
} else {
$this->message = "";
}
}
}
$session = new Session();
For the sake of marking this as accepted, what you need to do is actually pass the user ID of the and not just an uninitialised variable, if your instance you are storing it in the session so I presume it would be:
<?php $user = User::find_by_id($_SESSION['user_id']); ?>
Note: To make your templating cleaner, you can use the shorthand syntax for echo:
<h1>Hello, <?= $user->username; ?></h1>
Another thing to note is that you have built a Session class, however you are still for some reason accessing the data through $_SESSION which doesn't make sense, make some setters / getters for it. Finally, sessions are something that you'll be using a lot therefore it would be worth making that class static.
Reading Material
echo

How to get everything outside the database with foreach and class

I have a problem. I want some data out my database.
I have two page's a categorie.php here I want that he shows everything out the database. And I have a second page. Here are my classes. I have trying a foreach on the categorie.php but if I do that, than shows he 1 thing out the database 4 times the same and not the another data.
Below you can see my code.
I hope that you can help me.
Thank you.
This is my categorie.php
<?php
require_once '../app/functions/second.php';
require_once '../app/db/dbpassword.php';
require_once 'include/head.php';
if (isset($_GET['categorie']) && !empty($_GET['categorie'])) {
$id = $_GET['categorie'];
$dbh = new PDO("mysql:host=$host; dbname=$dbname;", $usernamedb,
$passworddb);
$cate = new Categorie($dbh);
$cate->loadCate($id);
// $page->loadId($id);
$categorie = $cate->getCategorie();
$titel = ucwords($categorie);
?>
<h2 class="center_h2"><?= $titel ?></h2>
<?php foreach ($cate as $key) {
$titelart = $cate->getTitel();
$beschrijving = $cate->getBeschrijving();
$plaatje = $cate->getImage();
$id = $cate->getId();
var_dump($titelart);
} ?>
<?php
} else {
echo "Dit bericht is verwijderd of is verplaats.";
}
require_once 'include/footer.php';
?>
This is my class page
<?php
class Categorie {
protected $dbh;
public function __construct($new_dbh){
$this->dbh = $new_dbh;
}
public function loadCate($cate){
$query = $this->dbh->prepare('SELECT * FROM schilderijen WHERE categorie=?');
$query->execute(array($cate));
while ($row = $query->fetch(PDO::FETCH_OBJ)) {
$this->id = $row->id;
$this->categorie = $row->categorie;
$this->titel = $row->titel;
$this->beschrijving = $row->beschrijving;
$this->plaatje = $row->plaatje;
}
}
public function getId(){
return $this->id;
}
public function getCategorie(){
return $this->categorie;
}
public function getTitel(){
return $this->titel;
}
public function getBeschrijving(){
return $this->beschrijving;
}
public function getImage(){
return $this->plaatje;
}
}
?>
Ok so you have a problem with the use of your class. In the while after your SQL request, you apply the value the instance variable like $this->id = $row->id; but this variable will be rewrite with the next row value.
Use a static function for your SQL request and return an array of Categorie like that :
class Categorie {
protected $id, $categorie, $title, $beschrijving, $plaatje;
public function __construct($id, $categorie, $title, $beschrijving, $plaatje){
$this->id = $id;
$this->categorie = $categorie;
$this->title = $title;
$this->beschrijving = $beschrijving;
$this->plaatje = $plaatje;
}
public static function loadCate($dbh, $cate){
$query = $dbh->prepare('SELECT * FROM schilderijen WHERE categorie=?');
$query->execute(array($cate));
$res = array();
while ($row = $query->fetch(PDO::FETCH_OBJ)) {
$res[] = new Categorie($row->id, $row->categorie, $row->titel, $row->beschrijving, $row->plaatje);
}
return $res;
}
public function getId(){
return $this->id;
}
public function getCategorie(){
return $this->categorie;
}
public function getTitle(){
return $this->title;
}
public function getBeschrijving(){
return $this->beschrijving;
}
public function getImage(){
return $this->plaatje;
}
}
And you can use it like that:
$categories = Categorie::loadCate($dbh, $id);
foreach($categories as $categorie){
var_dump($categorie->getTitle());
}

PHP OOP undefined > method stdClass

I'm new in OOP and I have 2 classes.
class db{
private $_database;
public function __construct(){
try{
$this->_database = new PDO('mysql:host='.'localhost'.';dbname='.'lala','root','');
}catch(PDOExeption $e){
die($e->getMessage());
}
}
public function query(){
$query = $this->_database->query('SELECT * FROM users');
$query->setFetchMode(PDO::FETCH_OBJ);
$query->execute();
$row = $query->fetchAll();
return $row;
}
}
first class is database.
class users{
public $id, $name, $password, $mail;
private $_databaseUSERS, $_result;
public function __construct(){
$this->_databaseUSERS = new db();
}
public function nameAndpass(){
echo "Name: {$this->name}, Password: {$this->password}".'<br>'.'<br>'.'<br>'.'<br>';
}
public function get(){
$this->_result = $this->_databaseUSERS->query();
$object_array = array();
foreach ($this->_result as $key => $value) {
$object_array[] = self::blabla($value);
}
return $object_array;
}
public function blabla($record){
foreach($record as $attribute => $value){
$this->$attribute = $value;
}
return $record;
}
}
and second class is users.
$users = new users();
$users->get();
echo $users->nameAndpass();
echo $users->mail.'<br>'
this is working and output is:
Name: Johny, Password: 123456
Johny#mail.com
$users = new users();
$user = $users->get();
foreach ($user as $userss) {
echo $userss->name.'<br>';
}
this is also working and output is:
Jack
Billy
Johny
$users = new users();
$user = $users->get();
foreach ($user as $userss) {
echo $userss->nameAndpass().'<br>';
}
this is not working and ouput is: Fatal error: Call to undefined
method stdClass::nameAndpass() in
C:\Users\Irakli\Desktop\Work\xamp\htdocs\index.php
How can I fix this error?

PHP OOP unable to edit class properties

New to PHP and especially OOP.
I have a class User.php which I am using in login.php.
$vars = $user->login($email, $pass)
At the moment I am calling the login method as the above, eventually I am going to call an if statment to validate, etc.
At the moment however, I am trying to connect to the DB, pull some information out and add that information to the properties in my class. I can pull the information out (verified by var_dumps of the objects in method login() (vardump of $results), yet for some reason with my current code I cannot update my class properties.
Here is my code
User.php
<?php
class User {
public $id, $password, $first_name, $last_name;
private $user_level;
protected static $db_fields = array('id', 'first_name', 'last_name', 'pass');
protected static $table_name="users";
public function login($email, $pass) {
global $database;
$sql = "SELECT user_id, first_name, last_name, user_level FROM users WHERE (email='$email' AND pass=SHA1('$pass')) AND active IS NULL LIMIT 1";
$results = self::find_by_sql($sql);
if (!empty($results)) {
$this->setuservars($results);
return array_shift($results);
} else {
return false;
}
// return !empty($results) ? array_shift($results) : false;
}
private function setuservars($uservariables) {
$this->id = $uservariables->id;
$this->first_name = $uservariables->first_name;
$this->last_name = $uservariables->last_name;
$this->user_level = $uservariables->user_level;
}
public static function find_by_sql($sql="") {
global $database;
$results_array = $database->query($sql);
$object_array = array();
while ($row = $results_array->fetch_assoc()) {
$object_array[] = self::instantiate($row);
}
return $object_array;
}
public function mysqli_array_escape($arg1){
global $database;
foreach ($arg1 as $key => $value) {
$arg1[$key] = $database->real_escape_string($value);
}
return $arg1;
}
private static function instantiate($record) {
// Could check that $record exists and is an array
$object = new self;
foreach($record as $attribute=>$value){
if($object->has_attribute($attribute)) {
$object->$attribute = $value;
}
}
return $object;
}
private function has_attribute($attribute) {
return array_key_exists($attribute, $this->attributes());
}
protected function attributes() {
// return an array of attribute names and their values
$attributes = array();
foreach(self::$db_fields as $field) {
if(property_exists($this, $field)) {
$attributes[$field] = $this->$field;
}
}
return $attributes;
}
}
$user = new User();
?>
and here is my login.php (I have edited the if statement with to verify the user logged in successfully, i have replaced with "if (1 == 1) {" statement just to help with debugging code.
if (isset($_POST['submitted'])) {
$postdata = $user->mysqli_array_escape($_POST);
//var_dump($user->results);
if (((!isset($_POST['email'])) || ($_POST['email']) == '') || (!isset($_POST['pass']) || ($_POST['pass']) == '') ) {
//error handling eventually
} else {
$email = $_POST['email'];
$pass = $_POST['pass'];
$vars = $user->login($email, $pass);
echo $vars->first_name;
if (1 == 1) {
echo "you have successfully logged in";
var_dump($user->id);
} else {
echo "not logged in";
}
}
}
Oh and the current error I am receiving is "An error occurred in script 'F:\internet\www\htdocs\blissoop\classes\User.php' on line 26: Trying to get property of non-object
Date/Time: 4-13-2012 05:01:09"
I have resolved this issue with help from this question
here was the code that helped : Get value from Multidimentional Array containing an Object.
I have +1'd the answer which helped.
foreach ($array as $item) {
$userId = $item->user_id;
//do something with the userId for this item
}
I had to loop through the array to be able to get the object's properties.

PHP5 variable scope and class construction

I'm having problems with accessing variables from my classes...
class getuser {
public function __construct($id) {
$userquery = "SELECT * FROM users WHERE id = ".$id."";
$userresult = mysql_query($userquery);
$this->user = array();
$idx = 0;
while($user = mysql_fetch_object($userresult)){
$this->user[$idx] = $user;
++$idx;
}
}
}
I'm setting this class in a global 'classes' file, and later on I pass through a user id into the following script:
$u = new getuser($userid);
foreach($u->user as $user){
echo $user->username;
}
I'm hoping that this will give me the name of the user but it's not, where am I going wrong?!
Thanks
please define your users member as public in your class like this
class getuser {
public $user = null;
//...
}
in order to access a class property, you have to declare it public or implement getters and setters (second solution is preferable)
class A {
public $foo;
//class methods
}
$a = new A();
$a->foo = 'whatever';
with getters and setters, one per property
class B {
private $foo2;
public function getFoo2() {
return $this->foo2;
}
public function setFoo2($value) {
$this->foo2 = $value;
}
}
$b = new B();
$b->setFoo2('whatever');
echo $b->getFoo2();
in your example:
class getuser {
private $user;
public function __construct($id) {
$userquery = "SELECT * FROM users WHERE id = ".$id."";
$userresult = mysql_query($userquery);
$this->user = array();
$idx = 0;
while($user = mysql_fetch_object($userresult)){
$this->user[$idx] = $user;
++$idx;
}
}
/* returns the property value */
public function getUser() {
return $this->user;
}
/* sets the property value */
public function setUser($value) {
$this->user = $value;
}
}
$u = new getuser($userid);
$users_list = $u->getUser();
foreach($users_list as $user) {
echo $user->username;
}

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