I'm making an aplication with phonegap and I'm stuck trying to send JSON data from the PHP on the server to JavaScript on the device. I want to do something like:
var JSON = '{ "Table" : ' + "http://www.hel.net/LoadDB.php=?table=exhibitions" + '}';
the php works fine and returns somethig like:
"[{"id":"1","name":"Art for everyone","image":null,"name2":"June 29, 2013: 11:00am.","description":"With reservation\r\nFree entrance","description2":null}]"
I want that result in a javascript variable to work later with:
var obj = eval ("(" + JSON + ")");
document.getElementById("rName").innerHTML=obj.Table[1].name;
document.getElementById("lname").innerHTML=obj.Table[1].name2;
What I want to do is something like:
var JSON = '{ "Table" : ' + "http://www.hel.net/LoadDB.php=?table=exhibitions" + '}';
var obj = eval ("(" + JSON + ")");
document.getElementById("rName").innerHTML=obj.Table[1].name;
document.getElementById("lname").innerHTML=obj.Table[1].name2;
How can I make the first line work? is it possible to make the first line work?
PS. I do not have much experience with JSON arrays.
Ok I tried ajax and works, I used:
console.log("before");
var jqxhr = $.ajax( "http://www.hel.com/LoadDB.php?table=exhibitions" )
.done(function(data) { console.log(data); })
.fail(function() { console.log("error"); })
.always(function() { console.log("complete"); });
console.log("after");
more info in:
api.jquery.com
I think all you need is var obj = <?php echo $myjsonencodedvar; ?>
or
var obj = <?php echo json_encode($myarray_or_object); ?>
Since I said "I think..." I decided to test it out. I found the following dump() function here on SO.
$arr=array(1,'biscuit'=>'gravy',3,4,5);
$json=json_encode($arr);
?>
<script>
j=<?php echo $json; ?>;
document.write(dump(j));
function dump(obj) {
var out = '';
for (var i in obj) {
out += i + ": " + obj[i] + "\n";
}
return out;
}
</script>
output:
0: 1 biscuit: gravy 1: 3 2: 4 3: 5
Try this:
PHP: (json.php)
<?php
header("Content-Type: text/json");
//the data format your question mentioned
$data = array("Table"=>array(array("id"=>"1","name"=>"Art for everyone","image"=>null,"name2"=>"June 29, 2013","description"=>"With reservation\r\nFree entrance","description2"=>null)));
echo json_encode($data);
?>
Front-end:
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script>
<script>
$.get("json.php",function(json){
alert(json.Table[0].name);
});
</script>
</body>
</html>
Hope this is helpful for you.
using JSONP (no callbacks), and on the client side use $.getJSON() it will parse it from json string to js object.
Related
I have a device which export data in XML format.
And I would like to display this data on my webpage + refresh every second by ajax.
So my PHP file is:
<?php
$xml=simplexml_load_file("http://admin:pass#192.168.0.109/st0.xml") or die("Error: Cannot create object");
echo json_encode($xml);
exit();
this will display:
{"out0":"1","out1":"1","out2":"1","out3":"1","out4":"1","out5":"1","out6":"1","di0":"up","di1":"up","di2":"up","di3":"up","ia0":"473","ia1":"166","ia2":"359","ia3":"187","ia4":"4326","ia5":"1832","ia6":"36","ia7":"198","ia8":"6","ia9":"234","ia10":"-600","ia11":"246","ia12":"-600","ia13":"0","ia14":"0","ia15":"65952","ia16":"0","ia17":"854000","ia18":"1000","ia19":"192","freq":"5008","duty":"500","pwm":"0","sec0":"27","sec1":"17","sec2":"20","sec3":"1","sec4":"1481894628"}
So now I know how to display whole data and refresh, but I do not now how to put every data in separete div, ex. to display only interesting part:
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function(){
setInterval(function() {
$("#load_results").load("get_xml.php");
}, 1000);
});
</script>
</head>
<body>
<div id = "load_results"></div>
</body>
</html>
You have 2 situations:
Either you know the format of the JSON and you can build a DOM
structure using jQuery (for example) in the exact format you want
with the exact data you have.
For that you will have to access the object properties of the JSON object so for instance:
$("#load_results").load("get_xml.php");
becomes:
$.get( "get_xml.php", function( data ) { // retrieves the JSON from that file using AJAX
var parsedJSON = JSON.parse(data); // we convert the JSON string into a Javascript object
var formattedString = 'Our OUT0 is ' + parsedJSON.out0 + '<br>'; // we access the data in the Javascript object as for all Javascript objects, see http://www.w3schools.com/js/js_objects.asp
formattedString = formattedString + 'Our ia12 is ' + parsedJSON.ia12; // and so on
$('#load_results').html(formattedString);
});
Either you don't know the format or
you don't care at all. In this case the situation is simpler, you
can use a JSON prettifying tool for JavaScript such as the one
implemented here: http://jsfiddle.net/unLSJ/ (by someone else than me, cheers to him).
For the option 2 this would be the library:
// Library
window.jsonPrettifier = {
replacer: function(match, pIndent, pKey, pVal, pEnd) {
var key = '<span class=json-key>';
var val = '<span class=json-value>';
var str = '<span class=json-string>';
var r = pIndent || '';
if (pKey)
r = r + key + pKey.replace(/[": ]/g, '') + '</span>: ';
if (pVal)
r = r + (pVal[0] == '"' ? str : val) + pVal + '</span>';
return r + (pEnd || '');
},
prettyPrint: function(obj) {
var jsonLine = /^( *)("[\w]+": )?("[^"]*"|[\w.+-]*)?([,[{])?$/mg;
return JSON.stringify(obj, null, 3)
.replace(/&/g, '&').replace(/\\"/g, '"')
.replace(/</g, '<').replace(/>/g, '>')
.replace(jsonLine, library.json.replacer);
}
};
After you added this library somewhere inside your code, you can replace
$("#load_results").load("get_xml.php");
with
$.get( "get_xml.php", function( data ) { // retrieves the JSON from that file using AJAX
var parsedJSON = JSON.parse(data);
$('#load_results').html(window.jsonPrettifier.prettyPrint(parsedJSON));
});
and you will obtain a pretty printed JSON.
Hi friends can anyone me for this plz. im new to this chapter..i am trying to get JSON format value from PHP but while im running i got this output "SyntaxError: JSON.parse: unexpected characte".. i think i had done mistake in php conversion ...plz help me friends
my .html file
<html>
<head>
<script src="http://code.jquery.com/jquery-1.8.3.min.js"></script>
<title>Display Page</title>
</head>
<body>
<button type='button' id='getdata'>GetData.</button>
<button type='button' id='get'>sample</button>
<script type='text/javascript'>
$('#get').click(function() {
alert("laksjdflk");
});
$(document).ready(function() {
$('#getdata').click(function() {
$.ajax({
url:'neww.php' ,
dataType:'json' ,
success:function(output_string) {
alert(output_string);
},
error:function(xhr,ajaxOptions,thrownError){
alert(xhr.statusText);
alert(thrownError);
}
});
});
});
</script>
</body>
</html>
generatephp.php
<?php
mysql_connect("localhost","root","");
mysql_select_db("androidlogin");
$sql=mysql_query("SELECT* FROM trysave");
$temp="";
$i=0;
while($row=mysql_fetch_assoc($sql)){
$temp=$row['stringss'];
$temp.=$row['integerr'];
$array[i]=$temp;
i++;
}
echo json_encode($array);// this will print the output in json
?>
This may because of Undefined array variable notice you have to define array in case no records found
Also you missed a $ before variable i which gives error(treated as CONSTANT, and which is undefined in your code), i should be $i like,
$array=array();// define here to prevent from "Notice"
while($row=mysql_fetch_assoc($sql))
{
$temp=$row['stringss'];
$temp.=$row['integerr'];
$array[$i]=$temp;// use $ before i
$i++;// use $ before i
}
echo json_encode($array);// this will print the output in json
One more thing you have mentioned PHP file name as generatephp.php and you are using url:'neww.php' , in $.ajax(), you have to check your code once.
Obvious problems (cough MySQL_*) aside, your PHP file should specify in the response headers that the output will be of type JSON. The output defaults to text/html and Javascript cannot parse it as a valid JSON object.
You can do it like this
<?php
header('Content-type: application/json');
// Rest of the code remains intact
i wold use something different ...
php:
<?php
mysql_connect("localhost","root","");
$sql=mysql_query("SELECT stringss, integerr FROM androidlogin.trysave");
$temp=array();
$i=0;
while($row=mysql_fetch_assoc($sql)){
$temp[] = $row;
}
echo json_encode($temp);// this will print the output in json
?>
//you do not need the $i variable since you will get in java str.length = that $i
<script type='text/javascript'>
$('#get').click(function() {
alert("laksjdflk");
});
$(document).ready(function() {
$('#getdata').click(
function() {
jQuery.getJSON( "neww.php") //no get vars
.done(function(a) {
//console.clear();
console.log(a);
show_data(a);
})
.fail(function(a) {
console.log( "error" );
});
});
});
function show_data(a){
for(var i=0; i<a.length; i++)
var stringss = a[i].stringss;
var integerr = a[i].integerr;
var nuber_temp = i;
//do stuff with them ...
}
</script>
if problem persists ... try http://php.net/manual/ro/function.urlencode.php
I am new to AJAX using jquery. I have a json response as below:
[{"customer_name":"Customer A"},{"customer_name":"Customer B"},{"customer_name":"Customer C"}]
And my ajax file is :
function(result){
$('#resdiv').html(result);
console.log(result);
var json_obj = $.parseJSON(result);//parse JSON
alert(json_obj);
var output="<ul>";
for (var i in json_obj)
{
output+="<li>" + json_obj[i].customer_name + "</li>";
}
output+="</ul>";
$('#resdiv1').html(output);
}
Though I can view the JSON response in div id resdiv, the div id resdiv1 is empty ! Also alert(json_obj); does not alerts anything ! Whats wrong with the file ?
NB: I am learning from Zuch Tutorial
You dont need to parse the json again.Simply do a iteration and try like this
var json = [{"customer_name":"Customer A"},{"customer_name":"Customer B"},{"customer_name":"Customer C"}];
var output="<ul>";
$.each(json,function(key,val){
output+="<li>" + val.customer_name + "</li>";
});
output+="</ul>";
console.log(output);
See DEMO
check this out
// Need to parse if string.
var result = '[{"customer_name":"Customer A"},{"customer_name":"Customer B"},{"customer_name":"Customer C"}]';
var json_obj = $.parseJSON(result);//parse JSON
// No need to parse
var json_obj = [{"customer_name":"Customer A"},{"customer_name":"Customer B"},{"customer_name":"Customer C"}];
Also check this
// if undefined, you don't have resdiv1 div or you have call function before your div render.
alert($('#resdiv1').html());
Can you try this
function(result){
$('#resdiv').html(result);
console.log(result);
var json_obj = $.parseJSON(result);
//parse JSON alert(json_obj);
var output="<ul>";
$.each(json_obj,function(key,val){
output+="<li>" + val.customer_name + "</li>";
console.log(key+":::"+val);
});
output+="</ul>";
$('#resdiv1').html(output);
}
I want to execute any JavaScript function that is part of a JSON using eval() but obviously I can't do it right, and can't figure out where exactly is the mistake/s. I'm using two very simple files, just for trying - the first is index.php and is at it is:
<!DOCTYPE html>
<html>
<head>
<title>Simple form sending and receiving a JSON object to/from PHP</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var data =
{
"sales": [
{ "firstname" : "John", "lastname" : "Brown" },
{ "firstname" : "Marc", "lastname" : "Johnson" }
] // end of sales array
}
var dataString = JSON.stringify(data);
$.post('simpleformSubmi.php', { data: dataString}, showResult, "text");
});
function showResult(res)
{
var data = eval('(' + res + ')');
$("#fullresponse").html("Full response: " +data);
}
</script>
<div id="fullresponse"></div>
</head>
<body>
and the second one is simpleformSubmi.php :
<?php
$logFile = 'logFile';
$res = json_decode(stripslashes($_POST['data']), true);
$arr = "function(){alert('Hi')}";
echo json_encode($res);
echo json_encode($arr);
So what I expected was after executing echo json_encode($arr); to get and alert but instead I get a mistake, and in Firebug the console shows error "missing ) in parenthetica". So the question is - how to send a valid JS function this way and to execute it properly?
Thanks
Leron
Why you are json_encodeing $arr. You may just return it as a string echo $arr and eval('(' + res + ')()') in the JavaScript (notice the () in the JS to execute the function). You may need to remove echo json_encode($res) just to get this to work for now.
You can't. A JSON object cannot contain functions, only values.
You will have to setup some sort of webservice that actually prints JavaScript, which you in turn can call through a <script src="/your/endpoint"></script> declaration client side.
You can send the js function as data.
$data = array("something"=>"12345");
$js = "alert('hi!')";
$data["autoexec"] = $js;
echo json_encode($data);
Then on the clientside do something like eval(data["autoexec"]);
so lets say this is my jquery portion of the code:
$.ajaxSetup ({
cache: false
});
load() functions
var loadUrl = "load.php";
$("#load_basic").click(function(){
$("#result").load(loadUrl + "?language=php&version=5");
});
});
and this is "load.php"
<?php $_GET['language'] .= "cool"; $_GET['version']+=2; ?>
How do I return the processed language and version vars back to my #result div?
Sorry if I'm doing this wrong. Pretty comfortable in php and jquery, but ajax sort of confuses me and I haven't found any tutorials that really clicked.
I know I can echo these vars out, and that will return the contents of load.php into my div.. but that seems clunky, and I doubt that's the way people actually do it..
JQuery
$("#load_basic").click(function(){
$.get(loadUrl + "?language=php&version=5", function(data){
var obj = eval(data)
$("#result").html(obj.language + " " + obj.version)
});
});
PHP
<?php $_GET['language'] .= "cool"; $_GET['version']+=2;
echo "{\"language\" : \"".$_GET['language']."\",\"version\" : \"".$_GET['version']."\"" ?>
not tested and not bullet-proof, but the concept is here. Return somthing in your PHP that you can read back (i choose JSON)
" What If I'm echoing out two or three vars in php, and I want them to be seperated and echoed out to different divs.. "
I'm ASP and not PHP but I think the prinicple is the same.
I have this is my requesting page:
<script type="text/javascript">
$(document).ready(function(){
$("#list").change(onSelectChange);
});
function onSelectChange(){
var selected = $("#list option:selected").val();
var bob = $("#list option:selected").text();
if (selected.length > 0) {
$.post("twopart.asp", { thing: selected, bob: bob }, function(data) {
var dataraw= data;
var dataarray = (dataraw).split("~~~");
var outone= dataarray["0"];
var outtwo= dataarray["1"];
var outthree= dataarray["2"];
$("#output1").html(outone);
$("#output2").html(outtwo);
$("#output3").html(outthree);
});
}
}
</script>
and this is in my processing page:
response.write bunch of stuff and ~~~
response.write bunch of stuff and ~~~
response.write more stuff
Sorry is the formatting is off- still learning how to do it.
Anyway, the "echoing page" echos its content with the three tildes stuck in there. Then I parse the return on the tildes and write different places.
Hope this is helpful.
The JSON answer by Grooveek is probably better.
try
$.ajax({
url:YOUR_URL,
dataType:'json',
type:'POST',
data:'&var1=value1&var2=value2',
beforeSend:function(){
//
},
success:function(response){
//complete
$('#container').html(response.result + ' ' + response.other);
}
});
in your php
$var1 = $_POST['var1'];
//your proccess
$result = array(
'result' => 'ok',
'other' => 'value'
);
echo json_encode($result);