Just want to get some direction on how I'd accomplish this; I have a form
<form method="POST" action="myform.php">
<input name="selecttype" type="radio" value="send1only" checked><input name="selecttype" type="radio" value="send1and2">
<input type="submit" value="Next">
</form>
I have to post files for example, myform.php and myform2.php. I'm trying to accomplish something where if the 'send1only' is selected, the form posts to myform.php only. And if 'send1and2' is selected, the form posts to both myform.php and myform2.php.
How would I go about this? Basically I'm building a form with paypal so giving customer the option to process payment later (send1only) or now (send1and2), one post wouldn't be a file it'll be the paypal link and other would be to get info to me.
You can't post to two actions but you should be able to include the contents of myform2.php and there by perform the same processing conditionally
<?php
// contents of myform1.php
if (isset($_POST["selecttype"]) && $_POST["selecttype"] == "send1and2"){
// contents of myform2.php or
include "myform2.php";
}
?>
Related
I'm doing a Quiz project: The idea is to implement almost 25 questions in which each question occupies each HTML page with 4 radio buttons and a submit button and a reset button as well.On clicking the submit button it should take the user to the next page as well as submit the data to the server. How to achieve this dual behaviour?
I tried this:
<form action="cba.php" method="post">
<a href="abc.html">
<input type="submit" value="submit">
</a>
</form>
But this does only one purpose: Acting as a link without submitting the data.
If you just want to redirect the user after submitting the form, you can use :
header("Location: yourlink");
in the php script you called cba.php.
Otherwise, i'm not sure it is possible to redirect the user before sending him the php script page.
As mentioned, it would be a smoother experiance to handle this via ajax, but it can be acheived in just php by creating a redirect in the form processing code (as mentioned in comments and a current answer).
I believe your issue is with the fact that the same proccessing code (cba.php) will be called every step of the way, so you need a way for each quiz section to define the next section.
This can be done with a hidden field instead of the link code you tried:
<form action="cba.php" method="post">
<input type="hidden" name="next-page" value="abc.html">
<input type="submit" value="submit">
</form>
Then i cba.php, you redirect to the value contained in this hidden field:
//save the data from the form, then
header("Location: " . $_POST['next-page']);
I am looking for a bit of code to do the following:
A form containing a single text field and a submit button, must send the value of the text field to a landing page that automatically counts how many html tags that this page contains.
E.g. if the text field states stackoverflow.com, the landing page should say (H1 tags = 20) with many more parameters to come.
How is this done? I know how to make a form, but I do not know how to make it send its value to the landing page.
<form action="landingpage.php/" method="post">
The URL
<input type="text" name="cf_name">
<input type="submit" value="Submit">
</form>
This piece of code is a perfect answer to your question.
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET">
Type In Something: <input name="random-info" type="text" size="25">
<input type="submit" value="Submit">
</form> <br>
<?php
echo "You Typed: " . $_GET['random-info'];
?>
you get the method into the url, then you can use them on another page.
To access data from a form it depends on the method. Since your code shows a post message you simply access it in the php on the landing page by user $POST_['cf_name'].
To learn more you can check out:
http://w3schools.com/php/php_post.asp about the post method and http://w3schools.com/php/php_get.asp about the get method.
Also an invaluable source is php manual itself.
As far as counting the tags, not really sure what you are trying to achieve.
If you are counting the tags in the page you create, just make a variable and add to it each time you put that specific tag on the page.
Then you can put those values in a hidden field of the form to be passed into your landing page.
Hello I have a form working properly using
php echo $_SERVER['PHP_SELF']
The results are shown on same page as form.
I need to be able to send the form data and results to another page (eg results.php) when the user submits the form.
How is this achieved?
Just point the form action to results.php
<form action="results.php">
<!--Inputs-->
</form>
Or if you need to do a redirection store $_GET at $_SESSION['parameters'] .
Here are some attributes of form tag <form> you need to set them..
<form action="controller.php" method="post">
<!--form elements-->
<input type="submit" name="submit" value="Submit Form" />
</form>
Here when ever the submit button clicked, it will submit the form to its action i.e. controller.php by post method (i.e. form elements' value won't display in query string).
Later you can access their value on controller.php by $_REQUEST['element_name'] or $_POST['element_name'] or $_GET['element_name'] according to the form method type.
I have come across a situation I am not sure how to hndle. I am new to this, but I do understand the server side realm of php vs user side of the browser.. I just dont know how to accomplish what I want to do..
I have a form on a page where a user can enroll in a school course. They select the course type, location, date, and payment type.
On submit it goes to an outsourced shopping cart for payment, which uses PHP vars to populate the item description, price, ect.. along with our store id and other pertinent information.
I ALSO need to insert some of the PHP vars into the user database.
I tried having the form action go to another PHP page which process the DB entry then redirects to the cart, but when I get to the cart an error is generated saying the info was not submitted properly.. but the DB entry was successful.
I also tried using an include(dbentry.php) in the form action with the cart link.. this generates a server side error on loading the page.
At one point I successfully had it create a db entry (although it was blank) AND successfully redirect to the cart with all of the vars there, but a blank DB entry does me no good. I am assuming entry happened before the $POST vars were created... I also have changed so much I dont remember how I did it and cannot reproduce that..
My main question is:
How can I have a user fill out an HTML form, and when submitted perform the DB entry with the $POST vars while also directly passing the $POST vars to the cart page? Normally I would run the dbentry.php on the next page, but I have no access to scripting on the outsourced cart page...
You can try to use hidden textboxes to hold the values of the form! And this value can be accessed from different php pages
You will need to pass your variables from page1.php to page2.php to outsourced cart. I would do something like the following:
What the below code is doing:
Send original form data using POST to page2.php
Page2.php will then read the POST data (you can now do what you want with this data, whether it be store it into a database, etc.). A Javascript snippet will then submit the form to your checkout cart page (page3.php) with the necessary POST variables which are being stored as hidden fields within the form.
Page1.php
<form action="page2.php">
<input type="text" name="myfield1"/>
<input type="text" name="myfield2"/>
<input type="text" name="myfield3"/>
<input type="hidden" name="myfield4"/>
<input type="hidden" name="myfield5"/>
<input type="hidden" name="myfield6"/>
<input type="hidden" name="myfield7"/>
<input type="hidden" name="myfield8"/>
</form>
page2.php
<?php
if(isset($_POST['myfield1']))
{
$myfield1 = $_POST['myfield1'];
}
// do the above for all of the fields, use the data to query database with.
// Perform database operations here
?>
<form action='Page3.php' method='post' name='frm'>
<?php
foreach ($_POST as $a => $b) {
echo "<input type='hidden' name='".$a."' value='".$b."'>";
}
?>
</form>
<!-- Script to submit button -->
<script language="JavaScript">
document.frm.submit();
</script>
This is definately a novice question, but if you could be of any help i would be very grateful.
Basically, i'm building a database management page, and it of course includes a search function.
So, the search form looks something like this
<form name="name" function="search.php" method="get">
But, whenever i use it, i will of course get redirected to search.php. What i want is a way to display the results on the same page i did the search from (let's say index.php), without having to build an entire identical page around search.php
Thankful for answers.
Use a hidden field in the form that indicates that the form has been submitted.
In your form page (e.g. index.php)
<form name="name" action="index.php" method="post">
{OTHER_FORM_FIELDS}
<input type="hidden" name="doSearch" value="1">
</form>
So in your php code (could be in the index.php page or in a php script included)
<?php
if($_POST['doSearch']==1) {
//query database
//get results
} ?>
in your index.php page
<?php if($_POST['doSearch']) { //a search request was made display my search results ?>
HTML_CODE
<?php } ?>
Let the page submit to itself:
<form name="name" function="index.php" method="get">
In the handler for the page, check whether or not you have parameters and display either the input box or the results as appropriate.
You could even take it one step futher. You could use AJAX to insert the results directly into the page content when the submit button is pressed, rather than causing a page refresh.