Update a span when a select dropdown is made using ajax - php

Question

I am attempting to code the following script using jquery / ajax / php.
What happens is the php pulls all the records from the database and puts them into a select dropdown. When I select an item from the dropdown ajax pulls the price from the database and adds it into the span called priceeach1 . Well thats what its supposed to do, but my jquery is useless :-S .
The stockID comes from the select box value.
<script type="text/javascript" charset="utf-8">
$(document).ready(function(){
$('#stock1').on('change', function (){
var newValue1 = $.getJSON('select2.php', {stockID: $(this).val()}, function(data){
var options = '';
for (var x = 0; x < data.length; x++) {
options += data[x]['priceeach'];
}
$('#priceeach1').text( options);
});
});
});
</script>
The HTML :
Price Each : £<span id="priceeach1"></span>
The select2.php :
<?php include 'connectmysqli.php'; ?>
<?php
$id = $_GET['stockID'];
$sql = 'SELECT * FROM stock WHERE stockID = ' . (int)$id;
$result = $db->query($sql);
$json = array();
while ($row = $result->fetch_assoc()) {
$json[] = array(
'priceeach' => $row['priceeach'],
);
}
echo json_encode($json);
?>
EDIT >> Ok I have now updated the code with the latest edits, this now WORKS.....apart from an odd problem......If I select the first or last item in the list no price is displayed, anything in between appears just fine..........

Answer 1

Try this,
var options = [];
for (var x = 0; x < data.length; x++) {
options = data[x]['priceeach'];
}
$('#priceeach1').text(options.join(','));

Answer 2

It should be like this you have to store price in the array options[] instead of option and then join them by any separator
<script type="text/javascript" charset="utf-8">
$(document).ready(function(){
$('#stock').on('change', function (){
var newValue1 = $.getJSON('select2.php', {stockID: $(this).val()}, function(data){
var options = '';
for (var x = 0; x < data.length; x++) {
options[x] = data[x]['priceeach'];
}
$('#priceeach1').text(options.join(','));
});
});
});
</script>

Answer 3

You have to parse your JSON data to actual JSON Object before iterating it.
<script type="text/javascript" charset="utf-8">
$(document).ready(function(){
$('#stock').on('change', function (){
var newValue1 = $.getJSON('select2.php', {stockID: $(this).val()}, function(data){
var jsonParsed = JSON.parse(data);
var options = '';
for (var x = 0; x < jsonParsed.length; x++) {
options[] = jsonParsed[x]['priceeach'];
}
$('#priceeach1').text(options.join(','));
});
});
});
</script>

Answer 4

Try to use this snipt:
for (var x = 0; x < data.length; x++) {
options += data[x]['priceeach'];
}
$('#priceeach1').text( options);