i an new to php . please help me how to remember text input in PHP forms after go back to form ?
i have an rgister page and want to save text input in database , but if a text input existing in database go back to register page but remember text input .
please help me !
Save the data in your session.
Call
session_start();
in the form.php and your target.php. In target.php parse all your $_POST/$_GET Parameters and store them in the session.
$_SESSION['user_name'] = check_for_valid_name($_POST['user_name']);
in form.php just set input default to your session Variable:
<input name='user_name' value='<?= $_SESSION['user_name'] ?>' />
edit: In form.php you can also use:
value='<?php isset($_SESSION['user_name'])?(echo $_SESSION['user_name']):(echo "") ?>'
to get rid of warnings/notices of uknown index/variable.
Use PHP session
<?php
session_start();
$_SESSION['name'] = "YourSession";
// ...
?>
You can store the details in a session variable. You'll have to learn working with sessions though.
define your input field something like this.this will retain values after submission
<input id="user_firstname" type="text" name="user_firstname" value=<?= $_POST['user_firstmane'] ?> >
<form action="action.php" method="post">
<input type="text" name="inmputname" value="<?php echo $_POST['inmputname']?>">
<input type="submit">
</form>
Hope it will help you
Just try this one,
<?php
$name = NULL;
if(isset($_POST['submit'])){
$name=$_POST['inputname'];
}
?>
And in your form,
<form action="action.php" method="post">
<input type="text" name="inputname" value="<?php echo $name;?>">
<input type="submit">
</form>
Related
I have a problem of getting the value of an input element. Thanks in advance for help! This is the sample code:
<form action="#" method="POST">
<input name="X" value="3" />
<?php
//question: how can I put the value of input in a variable
//$_POST['X']; isn't applicable since I am in the same form.
?>
</form>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST">
<input name="X" value="3" />
<input type="submit" value="Submit">
</form>
<?php
if(isset($_POST['X']) == true){
echo $_POST['X'];
}
?>
First of all submitting a form on its own page is a bad practice because whenever you reload the page the form will submit everytime.
Best approach is that you set the action attribute of form to another file or link.
fileOne.php (where your form is located):
<form action="anotherfile.php" method="POST">
<input name="X" value="3" />
<button type="submit" name="submitForm">Submit</button>
</form>
Then in anotherfile.php you will do this:
$check = $_POST["submitForm"];
If(isset($check))
{
$myInputValue = $_POST["X"];
header("Location: fileOne.php/?val".$myInputValue);
}
Then in fileOne.php you can get the variable and its value which is sent via link in the browser like this:
$getInputValue = $_GET["val"];
Now you can echo out the $getInputValue variable wherever you want.
If the the information is not sensitive this is the best approach you got. But if it is, try saving that value in the session and retrieving in the file where you want. I hope it helps. Typed code via app so it might throw an error. But i think this code will work fine. Good luck!
I have a script that users can submit certain data, and after a submit they can "review" the output and go back to previous page or submit to it again and there is my proble, the submitted page: How can I submit it again to write it to a file?
form.html
<form method="post" action="vaihe2.php">
<input name="laskuttaja" type="text" value="Nimi" size="25">
<input name="submit" type="submit" value="Lähetä" />
</form>
vaihe2.php
<?
$laskuttaja = $_POST['laskuttaja'];
$data = '<B>'.$laskuttaja.'</b>';
echo $data;
?>
So how can I post that $data to next page(vaihe3.php) with submit and let the script write it to a file. I know how php write file works but the post to third page is not working.
If you wat to go back, the secret is in the value of the input.
<input name="laskuttaja" type="text" value="<?php echo(isset($_POST['laskuttaja'])?$_POST['laskuttaja']:"Nimi";?>" size="25"/>
To 'save' data to the next page use $_SESSIONs. They're simple to use. Just remember everywhere you use them, you must have session_start(); on LINE 1! Can't stress that enough!
$_SESSION['data']=$data;
on your third page:
echo$_SESSION['data'];
More on sessions here.
In vaihe2.php
<form method="post" action="vaihe3.php">
<?
$laskuttaja = $_POST['laskuttaja'];
$data = '<B>'.$laskuttaja.'</b>';
echo $data;
echo "<input name=\"laskuttaja\" type=\"hidden\" value=\"".$laskuttaja."\" size=\"25\">";
?>
<input name="submit" type="submit" value="anything" />
</form>
Here you are passing laskuttaja as hidden field and on post will be available to you in third page.
Now data flow as per your requirement. User fills data in form.html -> reviews on vaihe2 and confirms -> gets written in vaihe3.
Could you post the form conditionally back to itself until validated by checkbox? the action would change to "vaihe3.php" ?
<form method="post" action="<?php if ($_POST["valid"]==1) {echo 'vaihe3.php';} ?>">
<input name="laskuttaja" type="text" value="<?php if ($_POST['laskuttaja']!=='') {echo '$_POST[laskuttaja]'} else {echo 'Nimi';} ?>" size="25">
<?php if (isset ($_POST['laskuttaja') && $_POST['laskuttaja']!=="") {
echo 'Please Confirm your answers: <input name="valid" type="checkbox" value="1" />'; } ?>
<input name="submit" type="submit" value="Lähetä" />
</form>
Otherwise, the mention above about CURL would be another option. Or - since your using PHP anyways, you could write the values of form submission to a session array and make them available to all pages until you empty the array.
My question is how do I call input value of user selected which has show by php code from another php.
Normal simple way we get the input this way
$calendar_id_val = $_GET['calendar_id'];
and now it is not working:
For example Show.php, I have one form which show the values from Database and show the result with php variable with While Loop.
<input name="calendar_id" value="<?php echo $calendar_id;?>">
and when user is submit that form I will carry these user selected value and perform insert.php
While you are doing echo in the input use echo $calendar_id_val
You should use form like,
<form action="insert.php" method="get">
<input type="text" name="calendar_id" value="<?php echo $calendar_id;?>"/>
<input type="submit" name="submit_id" value="Insert"/>
</form>
Insert.php
echo $calendar_id_val = $_GET['calendar_id'];
Does this answer your question?
<form action="insert.php" method="GET">
<input name="calendar_id" value="<?php echo $calendar_id;?>">
</form>
If you want to redirect the user back to show.php, add this to the end of your insert.php script
header('Location: show.php');
exit();
I suggest $_POST var like this:
<form action="insert.php" method="POST">
<input type="text" name="calendar_id" value="<?php echo $calendar_id;?>" />
<input type="submit" name="submit" value="Submit" />
</form>
insert.php file:
echo $calendar_id = $_POST['calendar_id'];
I have a webpage that uses php and has a bunch of input fields in which a user enters some data and I turn the input into an SQL statement to query some database. I successfully parse the input fields and put the SQL statement together but when they click the "submit" button, all the input fields get cleared. How can I make it so these input fields don't get erase every time the user clicks "submit"?
Store them in local variables like
<?php
$name = '';
$last = '';
if(isset($_POST['post_me'])) {
$name = $_POST['post_me'];
$last = $_POST['last'];
//Process further
}
?>
<form method="post">
<input type="text" name="name" value="<?php echo $name; ?>" />
<input type="text" name="last" value="<?php echo $last; ?>" />
<input type="submit" name="post_me" />
</form>
Something like this should work.
<?
if(!isset($_POST['stackoverflow'])){
$txt = "";
} else {
$txt = $_POST['stackoverflow'];
}
?>
<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<form action="" method="post">
<input type="text" name="stackoverflow" value="<?= $txt ?>">
</form>
</body>
</html>
You need to check if the POST values (assuming you're using POST) are already set when the page loads (because they have already been submitted). If they are set, echo their contents into the value attributes of the form fields, or set checked=checked etc. depending on the field types.
This has always worked for me:
<input type="text" name="somename" value="<?php echo htmlspecialchars($_POST['somename']); ?>">
The key is to store the post values in session and display it using value tag.
Example:
HTML:
<form action="index.php" method="post">
<input type="text" name="name" placeholder="First Name"
value="<?php
if (isset($_SESSION['name'])) {
echo $_SESSION['name'];
}?>" >
<input type="submit" name="submit">
</form>
PHP:
session_start();
if (isset($_POST['submit'])) {
$name=$_POST['name']);
$_SESSION['name']=$name;
}
<?php
if(isset($_POST['submit'])) {
$decimal = $_POST['decimal'];
?>
<form action="" method="post">
<input type="number" name="decimal" required value="<?php echo (isset($decimal)) ? $decimal: ''?>">
</form>
Just use your $_POST['decimal'] into your input value
Have you used sessions and Cookies in PHP??
You can store the values in session on form submit before updating in Database for a user, then check if there is a session for user and value is set for field output the value else output null.
You just have to make sure the HTML input value has a php echo statement of the appropriate php variable for that field.
Simplest answer
`<form method="post" onsubmit="return false">`
coding your input with PHP is dangerous even if with htmlentities - hope this helps
In index.php, I have created a form and in the action attribute of the form tag I have specified "page2.php".
page2.php is also a form, (which continues on from index.php) and in the action attribute of the form tage I have specified "page3.php". I can retrieve what the user entered into the "location" text box, in the form on index.php and display it in page2.php through the method
<?php echo $_GET["location"]; ?>
but, I now also want to display the user location in page3.php, but when I use the above method it does not work. It give me the error: "Undefined index: location". I take it is because page3.php can not access the fields from index.php, but how do I get this to work?
Thanks in advance
You will need to store the value of $_GET["location"]; in a hidden field on page2.php within the form that gets submitted to page3.php.
Update Example
page2.php
<form action="page3.php">
<input type="hidden" value="<?php print $_GET['location']; ?>" name="location_from_page2" />
page3.php
$location = $_GET["location_from_page2"];
What you're doing here is printing out the contents of location into the value of a hidden field and then you're reading this hidden field in page3.php
This is one way to do it but you might want to consider looking into the php sessions.
Try using session variables
$_SESSION['location'] = $_GET['location'];
You can use hidden fields to achieve this.
page2.php:
<form id="myform" action="/page3.php" method="get">
<fieldset>
<label>x</label> <input type="text" name="something" value=""><br><br>
<input type="hidden" name="location" value="<?php echo $_GET['location']; ?>">
<input type="submit" name="submit" value="submit">
</fieldset>
</form>
You need to include the values in your form on the 2nd page.
Like: <input type="hidden" name="location" value="<?= $_GET["location"]; ?>">
or append the variable to your action in the form.
Otherwise you could just use Sessions - which would probably be easiest.