Well, I'm trying to do something very simple but turns out it's pretty complicated.
I have this string which is -
post/6
And for example and I want to replace it with -
post/view/6
so I tried to replace it using the following pattern -
/post/[1-9-a-z]/
And the replacement pattern -
view/$0
But for some reason, the string that's returned is this string -
/view/post/6
Maybe you guys know the solution for this?
I greatly appreciate your help.
You could simply use str_replace() no regex is required:
echo str_replace('post/', 'post/view/', $str);
you can use
Search Pattern
~post/([1-9-a-z])~
with Replacement Pattern
post/view/$1
This is expected result
$0 represents the complete string that has been matched i.e post/6 in your case
You can use lookaround
preg_replace('/(?<=post)(?=\/[\da-z])/',"/view",$txt);
OR
preg_replace('/(post)(\/[\da-z])/',"$1/view$2",$txt);
Related
I need a regular expression for select some text like #__james_name in PHP
I tried with :
(^#__[a-z]*)*
But I did not succeed.
help please
UPDATE
I tried with :
\#__([a-z]*)_([a-z]*)
How to using this in preg_match ?
Your grouping is a bit wrong, try
^#_(_[a-z]+)*
see it here on Regexr.
^ is the anchor to the start of the string, you don't want to repeat that. I replaced also the * with a + inside the group, so it requires at least one letter.
Now the string has to start with "#_" and then there can be 0 or more parts starting with an underscore followed by one or more (lowercase) letters.
This regex will match:
#_
#__a
#__a_b
#__a_b_ccccc_d_efadsfaksdjh
preg_match('/(^#__[a-z_]*)/', '#__james_name', $matches);
Do like this
$str=preg_replace('/^#__([\w]+)/', '$1', $str);
I have a string, such as "https://itunes.apple.com/us/album/artpop/id687591810?ign-mpt=uo%3D4" from which I want to extract just 687591810.
My regex skills are not great, but I can use /id\d{4,12} to at least get the right block (it gives me /id687591810). I'm wondering if there's a way using preg_match to search for the pattern but then return just the bit I want in one go?
Use the capturing group:
$url = "https://itunes.apple.com/us/album/artpop/id687591810?ign-mpt=uo%3D4";
preg_match('#/id(\d{4,12})#', $url, $output);
echo($output[1]);
output:
687591810
I'm trying to replace 0-1. with 0-1.<br> how do i do that?
update:
Sorry for my vague question. You guys misunderstood me. '0-1.' is the pattern i want to replace, which means the pattern should be like `"/(\d)+(-)*(\d)*\./"` and the string may be '1.' '0-1.' or something that expression could represent
You can use a standard PHP function:
str_replace('0-1.', '0-1.<br>', $yourString);
How about:
preg_replace("/(\d+(?:-\d+)?\.)/", "$1<br>", $string);
You can use preg_replace like this:
preg_replace("/(0-1\.)/", "$1<br>", $string);
or, as you know the substitution already:
preg_replace("/0-1\./", "0-1.<br>", $string);
In PHP is there an equivalent to preg_match that does not require the use of regex? There is str_replace() for preg_replace. Is there something for preg_match.
*update * I am only looking to replace a known string with another. Using regex just seems like overkill.
I have the string "This is a [test1], and not a [test2]" and I want to match them with "[test1]" and "[test2]".
If you mean find a string within another string without using regex, you can use strpos
if (strpos('hello today', 'hello') !== false) {
// string found
}
Since I am not sure what result you are looking for I can't say if this is exactly what you are looking for.
You can use strpos to see if an occurrence of one string is in another.
To answer your question there is some function of PHP without regex
Do not use preg_match() if you only
want to check if one string is
contained in another string. Use
strpos() or strstr() instead as they
will be faster.
But they can not replace preg_match completely at all
First, str_replace() is not replacement for preg_replace(). Function str_replace() replaces all occurrences of the search string with the replacement string, preg_replace() replaces content selected by regular expressions (that's not same thing).
A lot of things require regex (and that's good) so you can't simply replace it with single PHP function.
Most developers use preg_match because they want to use the matches (the third parameter which will get set by the function).
I can not think of a function that will return or set the same information, as done with matches.
If however, you are using preg_match without regex then you might not care as much about the matches.
If you are using preg_match to see if there is a "match" and just that then I'd suggest using strpos instead, since it is much more efficient at seeing if one string is found in another.
Here is the subject:
http://www.mysite.com/files/get/937IPiztQG/the-blah-blah-text-i-dont-need.mov
What I need using regex is only the bit before the last / (including that last / too)
The 937IPiztQG string may change; it will contain a-z A-Z 0-9 - _
Here's what I tried:
$code = strstr($url, '/http:\/\/www\.mysite\.com\/files\/get\/([A-Za-z0-9]+)./');
EDIT: I need to use regex because I don't actually know the URL. I have string like this...
a song
more text
oh and here goes some more blah blah
I need it to read that string and cut off filename part of the URLs.
You really don't need a regexp here. Here is a simple solution:
echo basename(dirname('http://www.mysite.com/files/get/937IPiztQG/the-blah-blah-text-i-dont-need.mov'));
// echoes "937IPiztQG"
Also, I'd like to quote Jamie Zawinski:
"Some people, when confronted with a problem, think 'I know, I'll use regular expressions.' Now they have two problems."
This seems far too simple to use regex. Use something similar to strrpos to look for the last occurrence of the '/' character, and then use substr to trim the string.
/http:\/\/www.mysite.com\/files\/get\/([^/]+)\/
How about something like this? Which should capture anything that's not a /, 1 or more times before a /.
The greediness of regexp will assure this works fine ^.*/
The strstr() function does not use a regular expression for any of its arguments it's the wrong function for regex replacement.
Are you thinking of preg_replace()?
But a function like basename() would be more appropriate.
Try this
$ok=preg_match('#mysite\.com/files/get/([^/]*)#i',$url,$m);
if($ok) $code=$m[1];
Then give a good read to these pages
http://www.php.net/preg_match
preg_replace
Note
the use of "#" as a delimiter to avoid getting trapped into escaping too many "/"
the "i" flag making match insensitive
(allowing more liberal spellings of the MySite.com domain name)
the $m array of captured results