Use array as table in MySql JOIN - php

Question

I would like to use data from an array to add a column and make a join on a MySql table.
Let's say, on one hand, we have an array ($relevance):
$relevance = array(
array('product_id' => 1, 'relevance' => 2),
array('product_id' => 2, 'relevance' => 5),
array('product_id' => 3, 'relevance' => 1),
);
And on the other hand, we have this table (products):
product_id | product_name
--------------------------
1 | Product 1
2 | Product 2
3 | Product 3
Now, I want to select data from the products table and joining them with $relevance based on their product_id in order to get something like this:
product_id | product_name | relevance
---------------------------------------
1 | Product 1 | 2
2 | Product 2 | 5
3 | Product 3 | 1
In other words, how can I make a SELECT with LEFT JOIN using data from both the MySql database and an array which would "mean" something like this:
SELECT `p`.*, `{{$relevance}}`.* FROM `products` AS `p`
LEFT JOIN `{{$relevance}}`
ON p.product_id = {{$relevance}}.product_id

Answer 1

pure sql solution, not efficient though for big recordsets:
$relevances = array()
foreach ($relevance as $v){
$relevances[] = "SELECT {$v['product_id']} as product_id, {$v['relevance']} as relevance"
}
$sql = implode(' UNION ', $relevances);
$sql = "SELECT p.product_id, p.product_name, r.relevance
FROM products p
JOIN ($sql) r ON p.product_id=r.product_id";

Answer 2

Well, you can make another table relevance and then you could just use JOIN. Or you can use loop to get those data. Something like
$relevance = array(
array(1, 'relevance' => 2),
array(2, 'relevance' => 5),
array(3, 'relevance' => 1),
);
$q = mysql_query("SELECT * FROM products")
while($r = mysql_fetch_assoc($q))
{
$productRelevance = $relevance[$r['prod_id']-1];
}
Hoewever this code may fail if you delete some product and those ids wouldn' be in order, e.g.: 1,2,5,6,7,10. I recommend you to use another table.