I had this construction error when trying to creating a new DateTime object using a timestamp:
Exception: DateTime::_construct(): Failed to parse time string (1372622987) at position 8 (8): Unexpected character in DateTime->_construct()
The object creation code is:
$start_date = new DateTime( "#{$dbResult->db_timestamp}" );
Where $dbResult->db_timestamp is a valid unix timestamp taken from a database. The timestamp in question was:
1372622987
I would understand this error for invalid formats being passed, but this is a genuine timestamp.
The reason this is very strange: I since ran a script to create a new DateTime object with the timestamp passed in as a hard coded value, and it reported no errors.
This seems to have been a one off, but I need an explanation if there is one, as I can't afford for this to happen again.
You should use setTimestamp instead, if you hardcode it:
$start_date = new DateTime();
$start_date->setTimestamp(1372622987);
in your case
$start_date = new DateTime();
$start_date->setTimestamp($dbResult->db_timestamp);
Use the createFromFormat method:
$start_date = DateTime::createFromFormat("U", $dbResult->db_timestamp);
UPDATE
I now recommend the use of Carbon
change your code to this
$start_date = new DateTime( "#" . $dbResult->db_timestamp );
and it will work fine
This worked for me.
/**
* return date in specific format, given a timestamp.
*
* #param timestamp $datetime
* #return string
*/
public static function showDateString($timestamp)
{
if ($timestamp !== NULL) {
$date = new DateTime();
$date->setTimestamp(intval($timestamp));
return $date->format("d-m-Y");
}
return '';
}
$start_date = new DateTime();
$start_date->setTimestamp($dbResult->db_timestamp);
Related
There's something ugly about this way of producing 2 date strings a year apart
$obj_now = new DateTime();
$obj_year_ago = new DateTime();
$obj_year_ago->modify( '- 1 year');
$string_now = $obj_now->format('Y-m-d') ;
$string_year_ago = $obj_year_ago->format('Y-m-d') ;
It works but seems a clunky to me (and therefore probably inefficient).
To frame the question; if I have to produce dates based on a reference date (these are used in different ways in different forms). Do I need one object to each date or can I perform calculations to produce my strings from one DateTime object?
The difficulty I see is if I use $obj_now->modify()` it's no longer 'now'
Modify changes the DateTime object, but not the format method. Here's how you can do the following:
$curDate = new DateTime('Now');
$dates = [];
for($i=0;$i<3;$i++){
$dates[] = $curDate->format('Y-m-d');
$curDate->modify('-1 year');
}
var_dump($dates);
//array(3) { [0]=> string(10) "2021-11-04" [1]=> string(10) "2020-11-04" [2]=> string(10) "2019-11-04" }
If you don't want the modify to change the original object, you can use DateTimeImmutable. To get the same result as above, the code for DateTimeImmutable is like this:
$date = new DateTimeImmutable('Now');
$dates = [];
for($i=0;$i<3;$i++){
$curDate = $date->modify('-'.$i.' year');
$dates[] = $curDate->format('Y-m-d');
}
var_dump($dates);
For more information see DateTimeImmutable vs DateTime
Obviously, after modify() the datetime has changed and it's no longer 'now'.
But you can do your job using just one object simply changing your instructions order:
$obj = new DateTime();
$string_now = $obj->format('Y-m-d');
$obj->modify('- 1 year');
$string_year_ago = $obj->format('Y-m-d');
Edit: As mentioned by the user IMSoP (Thank you!) the date object parameter gets modified. Therefore I changed the function to use a copy of the object to prevent this.
I would prefere to use a function for it.
First of all you can, but not have to declare an date object. Second, the object you declared before the function calls doesn't get modified only to get the information you need.
<?php
/**
* #param DateTime $dt_date
* #param String $s_format
* #param String $s_modifier
* #return String
*/
function dateGetFormatedStringModified($dt_date, $s_format, $s_modifier = ''){
$dt_temp = clone $dt_date;
if(!empty($s_modifier)){
$dt_temp->modify($s_modifier);
}
return $dt_temp->format($s_format);
}
$string_year_ago = dateGetFormatedStringModified(new DateTime(), 'Y-m-d', '- 1 year');
$string_now = dateGetFormatedStringModified(new DateTime(), 'Y-m-d');
echo $string_now; // 2021-11-04
echo $string_year_ago; // 2020-11-04
?>
Different approach would be DateTimeImmutable. This prevents the date getting changed if modify is used.
$date = new DateTimeImmutable();
$date_last_year = $date->modify('-1 year');
echo $date->format('Y-m-d');
echo $date_last_year->format('Y-m-d');
You also can combine modify with format within one line
$date = new DateTimeImmutable();
echo $date->format('Y-m-d');
echo $date->modify('-1 year')->format('Y-m-d');
I am pulling DateTime timestamp result from another table which is set as:
When dumping specific value of $post->getUploadTime() I get:
"2602585961"
It's in string format.
In my entity I have modified the setter to:
public function setStartTime($startTime)
{
$date = new \DateTime($startTime);
$this->startTime = $date->getTimestamp();
return $this;
}
And my code:
$newEntityObject->setStartTime(intval($post->getUploadTime()));
I am using intval() to transform string to integer (timestamp) so I can insert it in db but I get an error:
DateTime::__construct(): Failed to parse time string (2602585961) at position 8 (6): Unexpected character"
It's an error with or without the intval().
I can not figure out what is wrong?
I know there are a lot of posts about the issue. I tried them, but the problem still remains.
Try :
$date = new \DateTime();
$date->setTimestamp($startTime);
$this->startTime = $date->getTimestamp();
But since you are trying to assign a timestamp to your startTime property and you are already passing a timestamp to your function you can just assign whatever timestamp you are passing:
$this->startTime = $startTime;
You have a timestamp, and you are trying to make it a DateTime and get timestamp from the new datetime object.
The DateTime constructor only accept specific date and time format.
Also, the given value refer to the year 2052. So it's possible that you have another issue before.
You don't need to convert to a number. Because you need a string argument that starts with #
You need use #. Read Documentation.
<?php
$a = "#2602585961";
function setStartTime($startTime)
{
$date = new \DateTime($startTime);
$b = $date->getTimestamp();
return $b;
}
echo setStartTime($a);
https://www.php.net/manual/ru/datetime.formats.compound.php
In your code:
$newEntityObject->setStartTime("#" . $post->getUploadTime());
What is the "cleanest" way to add a date and a time string in PHP?
Albeit having read that DateTime::add expects a DateInterval, I tried
$date = new \DateTime('17.03.2016');
$time = new \DateTime('20:20');
$result = $date->add($time);
Which was no good and returned nothing to $result.
To make a DateInterval from '20:20', I only found very complex solutions...
Maybe I should use timestamps?
$date = strtotime($datestring);
$timeObj = new \DateTime($timestring);
// quirk to only get time in seconds from string date
$time = $timeObj->format('H') * 3600 + $timeObj->format('i') * 60 + $timeObj->format('s');
$datetime = $date+$time;
$result = new \DateTime;
$result->setTimestamp($datetime);
In my case, this returns the desired result, with the correct timezone offset. But what do you think, is this robust? Is there a better way?
If you want to add 20 hours and 20 minutes to a DateTime:
$date = new \DateTime('17.03.2016');
$date->add($new \DateInterval('PT20H20M'));
You do not need to get the result of add(), calling add() on a DateTime object will change it. The return value of add() is the DateTime object itself so you can chain methods.
See DateInterval::__construct to see how to set the intervals.
DateTime (and DateTimeImmutable) has a modify method which you could leverage to modify the time by adding 20 hours and 20 minutes.
Updated
I've included examples for both DateTime and DateTimeImmutable as per the comment made, you don't need to assign the outcome of modify to a variable because it mutates the original object. Whereas DateTimeImmutable creates a new instance and doesn't mutate the original object.
DateTime
<?php
$start = new DateTimeImmutable('2018-10-23 00:00:00');
echo $start->modify('+20 hours +20 minutes')->format('Y-m-d H:i:s');
// 2018-10-23 20:20:00
Using DateTime: https://3v4l.org/6eon8
DateTimeImmutable
<?php
$start = new DateTimeImmutable('2018-10-23 00:00:00');
$datetime = $start->modify('+20 hours +20 minutes');
var_dump($start->format('Y-m-d H:i:s'));
var_dump($datetime->format('Y-m-d H:i:s'));
Output
string(19) "2018-10-23 00:00:00"
string(19) "2018-10-23 20:20:00"
Using DateTimeImmutable: https://3v4l.org/oRehh
I'm using the PHP DateTime class to generate a date for a custom licensing system. While I'm debugging it, I've noted that the date time are always wrong, it will be 5-dec-2018 but now we are in November, and this date will be the same also for the expiration_date.
How i can fix this issue? I need to add 30 days to the start date of the trial period.
Here is the code.
class Activator {
private $uuid;
private $keygen;
private $licence_code;
public static function generateLicence($uuid) {
if (!file_exists(ABSPATH.'/DataStorage/.licence')) {
$start_date = new DateTime();
$time_zone = $start_date->setTimezone(new DateTimeZone('Europe/Rome'));
$trial_date = $start_date->add(new DateInterval('P30D'));
$end_date = $trial_date->format('d-M-Y');
$machine_uuid = bin2hex($uuid);
$licence_code = base64_encode($machine_uuid);
$licence_file = array(
'uuid' => $machine_uuid,
'activation_date' => $time_zone->format('d-M-Y'),
#'trial_version' => true,
#'expire_date' => $end_date,
#'licence_code' => $licence_code
);
$w = file_put_contents(ABSPATH.'/DataStorage/.licence', json_encode($licence_file));
echo $w;
}
}
This is the expected behavior, as you add() to the date (by doing $start_date->add(...) - this modifies the original object $start_date.
You can solve this a few different ways, although the easiest way is just to create a new instance entirely with the 30 days added directly in the construct. You can also set the timezone as the second parameter of new DateTime().
$timezone = new DateTimeZone('Europe/Rome');
$start_date = new DateTime("now", $timezone);
$trial_date = new DateTime("+30 days", $timezone);
PHP.net on new DateTime()
PHP.net on DateTime::add()
See this live demo.
I'm trying to figure out how to accept a date/time from a form, which is consequently in the user's timezone, and change it to UTC before inserting it into the database. For some reason, no amount of searching has netted me an answer.
My form will POST whatever date is selected by the user to my code, so I expect to be able to do something like this. Note: the $userDate may be relative to any number of timezones based on user's location
$userDate = $_POST['user_date'] // 2014-05-15 16:37:23
I anticipate using Date().getTimezoneOffset() on my form to also submit the users UTC offset (as detailed here).
$userOffset = $_POST['user_offset']
Then before inserting the date into my database, I would like to convert it to UTC -- but I am stumped on how to do that with PHP (I'm actually using Laravel so if you know of a way using Carbon, that would be even easier, but I couldn't find it in their docs).
I've been half tempted to manually parse the offset and convert it to number of seconds and add or subtract it to strtotime() output of the $userDate and then convert it back into a date format using date() -- but there has to be a better way!
What am I missing here? Does PHP have a function I just don't know about that lets me do something like:
$userDate = '2014-05-15 16:37:23';
$userOffset = '+04:00';
$utcDate = date_apply_offset($userDate, $userOffset);
echo $utcDate; // Outputs: 2014-05-15 20:37:23
Or am I making this harder than it has to be?
EDIT
Based on the solution provided by #vascowhite, I went with the following (added into question to improve answers for those seeking guidance)
I ended up using a function from moment.js since I was already using it to convert UTC to user's timezone on display.
HTML:
<input id="user_offset" type="hidden" name="user_offset" value="">
Javascript:
var offset = moment().format('ZZ');
$('#user_offset').val(offset);
PHP (in a custom date class):
class MyDate {
/**
* Convert Date to UTC
*
* #param string $date Any date parsable with strtotime()
* #param string $offset UTC offset of date
*/
public static function toUTC($date, $offset = '+0:00')
{
if ($timestamp = strtotime($date) && ! empty($offset) )
{
$newDate = date('Y-m-d H:i:s', $timestamp);
$newDate = new \DateTime($date . ' ' . $offset);
$newDate->setTimezone(new DateTimeZone('UTC'));
$date = $newDate->format('Y-m-d H:i:s');
}
return $date;
}
}
// To convert
$userDate = trim($_POST['user_offset']);
$userOffset = trim($_POST['user_date']);
$utc = MyDate::toUTC($userDate, $userOffset)
That class method isn't perfect, and in the event something goes wrong, it just returns the date back -- when really it should throw an exception.
This is a simple task with the DateTime classes:-
$userDate = '2014-05-15 16:37:23';
$userOffset = '+04:00';
$date = new \DateTime($userDate . ' ' . $userOffset);
var_dump($date);
$date->setTimezone(new \DateTimeZone('UTC'));
var_dump($date);
You can then format the date as you wish for output eg:-
echo $date->format('Y-m-d H:i:s');
or:-
$utcDate = $date->format('Y-m-d H:i:s');
echo $utcDate; // Outputs: 2014-05-15 20:37:23
See it working.
If you are doing any work with dates and times in PHP it is worth taking the time to become familiar with these extremely useful classes.
For all sorts of date/time manipulations you can make use of moment.php
For your example all what is needed are two lines of code:
$m = new \Moment\Moment('2014-05-15 16:37:23', '+0400');
echo $m->setTimezone('UTC')->format(); // 2014-05-15T12:37:23+0000
There is much more which helps to deal with date/time issues: https://github.com/fightbulc/moment.php
Cheers