All products being displayed instead of only one - php

i edited my code as below but the issue is that each time i click on the edit link, all of the products are being displayed instead of only the one beside which i clicked the edit link.
note: Sorry for posting another question relating to my other one. I could not add any more comments.
<?php
include_once("db_connect.php");
if(isset($_POST['update']))
{
$prod_id = $_POST['prod_id'];
$prod_name=$_POST['prod_name'];
$prod_brand=$_POST['prod_brand'];
$prod_price=$_POST['prod_price'];
// checking empty field
if(empty($prod_price))
{
//if name field is empty
if(empty($prod_price))
{
echo "<font color='red'>Price field is empty.</font><br/>";
}
}
else
{
//updating the table
//$result=mysql_query("UPDATE tblretprod SET prod_price='$prod_price' WHERE prod_id=$prod_id");
$result=mysql_query("UPDATE tblretprod SET prod_price='".$prod_price."' WHERE prod_id='".$prod_id."';");
//redirectig to the display page. In our case, it is index.php
header("Location: update.php");
}
}
?>
<?php
$prod_id = $_GET['prod_id'];
$result=mysql_query("SELECT a.prod_name, a.prod_brand, b.prod_price FROM tblproduct a, tblretprod b where a.prod_id = b.prod_id") or die(mysql_error());
?>
<html>
<title>Edit Product</title>
<body>
Home
<br/><br/>
<form name="edit" method="post" action="updprod.php">
<table border="0">
<?php
while($res=mysql_fetch_array($result))
{
$prod_name = $res['prod_name'];
$prod_brand = $res['prod_brand'];
$prod_price = $res['prod_price'];
?>
<tr>
<td>Product Name</td>
<td>
<input type="text" disabled="disabled" name="prod_name" value = "<?php echo $prod_name;?>"> </td>
</tr>
<tr>
<td>Brand</td>
<td>
<input type="text" disabled="disabled" name="prod_brand" value = "<?php echo $prod_brand;?>"> </td>
</tr>
<tr>
<td>Product Price</td>
<td>
<input type="text" name="prod_price" value = "<?php echo $prod_price;?>">
<input type="hidden" name="prod_id" value = "<?php echo $_GET['prod_id'];?>">
</td>
</tr>
<?php } ?>
<tr>
<td><input type="submit" name="update" value="Update"></td>
</tr>
</table>
</form>
</body>
</html>

Add in your select query in WHERE clause:
AND a.prod_id = ".$prod_id."
query:
"SELECT
a.prod_name,
a.prod_brand,
b.prod_price
FROM
tblproduct a, tblretprod b
where
a.prod_id = b.prod_id
AND a.prod_id = ".intval($prod_id).""
To make the query safer against SQL Injection i've added intval function like Kickstart well pointed out.

Related

database field data not appearing in form textbox in PHP

i have this code in PHP and a database sql.. the situation is .. if i type the 1, 2 or 3 (productID) .. the textbox will be populated and field with database values.. but when i run the program.. fortunately it has no errors.. but when i type the id or 1 and click the submit button.. it doesnt get the neccessary values.. sorry for this im a complete newbie and im practicing PHP for a while now.. any help will do.. thank you..
<?php
session_start();
include_once 'dbconnect.php';
if(!isset($_SESSION['user'])){
header("Location: index.php");
}
$res = mysql_query("SELECT * FROM users WHERE user_id=".$_SESSION['user']);
$userRow = mysql_fetch_array($res);
?>
<?php
require('dbconnect.php');
$id = (isset($_REQUEST['productID']));
$result = mysql_query("SELECT * FROM tblstore WHERE productID = '$id'");
$sql = mysql_fetch_array($result);
if(!$result){
die("Error: Data not found");
} else {
$brandname = $sql['brandname'];
$price = $sql['price'];
$stocks = $sql['stocks'];
}
?>
<html>
<body>
<p>
hi' <?php echo $userRow['username']; ?> Sign Out
</p>
<form method="post">
<table align="center">
<tr>
<td>Search Apparel:</td>
<td><input type="text" name="search" name="productID" /></td>
</tr>
<tr>
<td>Brandname:</td>
<td><input type="text" name="brandname" value="<?php echo $brandname; ?>"/ </td>
</tr>
<tr>
<td>Price:</td>
<td><input type="text" name="price" value="<?php echo $price; ?>"/></td>
</tr>
<tr>
<td>Stocks:</td>
<td><input type="text" name="stocks" value="<?php echo $stocks; ?>"/></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="Search" /></td>
</tr>
</table>
</form>
</body>
</html>
your getting the id incorrectly, you have:
<?php
$_REQUEST['productID']=8; //for testing
$id = (isset($_REQUEST['productID']));
if you check it you will find the output is true\false as returned by isset
var_dump($id); //true
what you should use is:
<?php
if(isset($_REQUEST['productID'])){ //maybe also check its a number and or valid range
$id=$_REQUEST['productID'];
}

Can you update in a div tag

I have a little question about something. I have some forms, where I send the input to a MySQL database. I get the return from the database, out in some div tags. Here I have 2 buttons. Button number 1 can delete the row, and button number 2 should have a function, where I can update a specific row, if I want to change the content of the row. But can I update a div tag? I can see on the net, that a lot of people use tables to do that.
<html>
<head>
<link rel="stylesheet" type="text/css" href="css/arrangeTables.css">
</head>
<body>
<?php
include 'connection.php';
if(isset($_POST['addto'])){
// Insert to database
$date = $_POST['date'];
$day = $_POST['day'];
$fromtime = $_POST['fromtime'];
$totime = $_POST['totime'];
$sql = "INSERT INTO addWorkTime(date, day, fromtime, totime) VALUES('$date', '$day', '$fromtime', '$totime')";
$result = mysql_query($sql, $dbhandle) or die(mysql_error($dbhandle));
// Update of the row
if(isset($_POST['update'])){
$hidden = mysql_real_escape_string($_POST['hidden']);
$UpdateQuery = "UPDATE addWorkTime
SET date='$_POST[date]',
day='$_POST[day]',
fromtime='$_POST[fromtime]',
totime='$_POST[totime]'
WHERE p_id='$_POST[hidden]'";
$update = mysql_query($UpdateQuery, $dbhandle) or die(mysql_error($dbhandle));
if($update) {
echo "Succes";
} else {
echo "Der er en fejl";
}
}; // brace for if(isset($_POST['update']))
if($result){
echo "Insert successful.";
}
}; // brace for if(isset($_POST['addto']))
if(isset($_POST['delete'])){
$hidden = mysql_real_escape_string($_POST['hidden']);
$DeleteQuery = "DELETE FROM addWorkTime WHERE p_id=$hidden";
$delete = mysql_query($DeleteQuery, $dbhandle) or die(mysql_error($dbhandle));
if($delete){
echo "Delete successful";
}
}
//Return records from database
$result = mysql_query("SELECT p_id, date, day, fromtime, totime FROM addWorkTime");
?>
<form method="post">
<h3>Add your worktime to database</h3><br>
Date:
<input type="date" name="date"><br><br>
Day
<select name="day">
<option value="Mandag">Mandag</option>
<option value="Tirsdag">Tirsdag</option>
<option value="Onsdag">Onsdag</option>
<option value="Torsdag">Torsdag</option>
<option value="Fredag">Fredag</option>
<option value="Lørdag">Lørdag</option>
<option value="Søndag">Søndag</option>
</select>
From time:
<input type="time" name="fromtime">
To time:
<input type="time" name="totime">
<input type="submit" name="addto" value="submit"><br><br>
<!-- Return from the database -->
<h3>Return from database:</h3><br>
<!-- headers -->
<table>
<tr>
<th class="column0">Primary Key</th>
<th class="column1">Date</th>
<th class="column2">Day</th>
<th class="column3">From</th>
<th class="column4">To</th>
</tr>
</table>
</form>
<!--loop through through the database -->
<?php while($row = mysql_fetch_array($result)): ?>
<form method="post">
<table>
<tr>
<td class="resultcolumn0"><?php echo $row{'p_id'};?></td>
<td class="resultcolumn1"><?php echo $row{'date'};?><br></td>
<td class="resultcolumn2"><?php echo $row{'day'};?></td>
<td class="resultcolumn3"><?php echo $row{'fromtime'};?></td>
<td class="resultcolumn4"><?php echo $row{'totime'};?></td>
<td><input type="hidden" name="hidden" value="<?php echo $row{'p_id'}?>"><?php echo $row{'p_id'}?></td>
<td><input type="submit" name="update" value="Update"></td>
<td><input type="submit" name="delete" value="Delete"></td>
</tr>
</table>
</form>
<?php endwhile; ?>
</body>
</html>
If you want to update your cell table like your recording, you can do a tricky way like this code snippet:
function change1() {
var inp1 = document.getElementById('myTable').rows[1].cells[0];
inp1.innerHTML = "<input type='text' name='inp1'>";
var inp2 = document.getElementById('myTable').rows[1].cells[1];
inp2.innerHTML = "<input type='text' name='inp2'>";
}
function change2() {
var inp1 = document.getElementById('myTable').rows[2].cells[0];
inp1.innerHTML = "<input type='text' name='inp1'>";
var inp2 = document.getElementById('myTable').rows[2].cells[1];
inp2.innerHTML = "<input type='text' name='inp2'>";
}
table, td {
border: 1px solid black;
}
<table id="myTable">
<tr>
<td>column 1</td>
<td>column 2</td>
<td>action</td>
</tr>
<tr>
<td>Row2 cell1</td>
<td>Row2 cell2</td>
<td>
<button onclick="change1()">Update</button>
</td>
</tr>
<tr>
<td>Row3 cell1</td>
<td>Row3 cell2</td>
<td>
<button onclick="change2()">Update</button>
</td>
</tr>
</table>
<button onclick="alert('whatever function to save the edit')">Save</button>
you can improve that to give <form> tag to your <table> tag and save that using another Save button. Or you can use if conditional to your update button for change to textfield and post it to your database.
<form method="post" action='function_to_update_or_delete.php'>
<table>
<tr>
<td class="resultcolumn0"><?php echo $row{'p_id'};?></td>
<td class="resultcolumn1"><?php echo $row{'date'};?><br></td>
<td class="resultcolumn2"><?php echo $row{'day'};?></td>
<td class="resultcolumn3"><?php echo $row{'fromtime'};?></td>
<td class="resultcolumn4"><?php echo $row{'totime'};?></td>
<td><input type="hidden" name="hidden" value="<?php echo $row{'p_id'}?>"><?php echo $row{'p_id'}?></td>
<td><button onclick="<?php echo change($some_information_to_your_cell)?>">Update</button></td>
<td><input type="submit" name="delete" value="Delete"></td>
</tr>
</table>
</form>
And, please try to make a function dynamically each row, don't hardcode it like function change1(), function change2(), function change3(), etc
Hope this will help you out. :)

Php form update in update the form

I am running while loop and fetch 3 records from database. and then update it on same page. Every record have submit button. But after edit when i submit the form it catchs the values of last record only and update other rows with the last record values. Please if somebody help me out i'll be very thankful. Remember it catches the exact (id) but the other parameters are only of last row.
<form method="post" action="">
<table width="700" border="1">
<tr><th><?php echo $_SESSION['teamtwo']; ?></th></tr>
<tr>
<th>Player Name</th>
<th>Runs</th>
<th>Edit</th>
<th>Save</th>
</tr>
<?php
$team = new DBConnection();
$condition = "WHERE teamname = '".$_SESSION['teamtwo']."' and datecreated = CURDATE()";
$sel_player = $team->SelectRecord(array("*"),"`match`","$condition");
//$sel_player = mysql_query("SELECT * FROM `match` WHERE teamname = '$team1' and datecreated = CURDATE()") or die(mysql_error());
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
<?php
} ?>
</table>
</form>
<?php } ?>
</div>
</div>
</body>
</html>
<?php
if(isset($_POST['team'])){
$runs = $_POST['runs'];
$balls = $_POST['ball'];
$object = new DBConnection();
$arr_Field=array("runs_bat","ball_bat","player_status","how_out","opposite_bowl","opposite_player","sr","overs","bowl_ball","runs_ball","extra","madien");
$arr_Values=array("$runs","$balls","$status","$how_out","$opposite_bowler","$opposite_player","$sr","$over","$bowls","$score","$extra","$madien");
$condition = "WHERE id = '".$_REQUEST['player']."'";
//echo $_REQUEST['player'];
//echo $runs.$balls;
$object->UpdateRecord("`match`",$arr_Field,$arr_Values,"$condition") or die(mysql_error());
//header("Location:extra.php?update");
}
the problem is you are having one form and when you submit the form it will submit the last rows values because you are having same name for all 3 rows inside 1 form.
Solution:-
Create form element inside the while loop and close it inside the while loop itself . Like this you will have 3 forms each for 3 rows.
Code Example:-
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<form>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
</form>
<?php
} ?>
1.
you need to make input array in while because name attribute is overwriting in loop
<td><input type="text" name="player_name[<?php echo $get_player['id']?>]" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs[<?php echo $get_player['id']?>]" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
2.
you have all text boxes mean if press submit button of one row, then also you will get all textboxes as php side so make hidden variable in form to get which button clicked
//write javascript in your page
<script>
function setPlayerId(id) {
document.getElementById('playerid').value=id;
}
</script>
//take hidden field into form
<input type='hidden' name='playerid' value='0'>
//write down onlick button event
<input type="submit" value="Save" name="team" onClick="setPlayerId('<?php <?php echo $get_player['id']?>?>')"/>
3.
Now in php you will get that as below
echo $_POST['player_name'][$_POST['playerid']];
// same way you can do your insert or update.
this code must work
<form method="post" action="">
<table width="700" border="1">
<tr><th><?php echo $_SESSION['teamtwo']; ?></th></tr>
<tr>
<th>Player Name</th>
<th>Runs</th>
<th>Edit</th>
<th>Save</th>
</tr>
<?php
$team = new DBConnection();
$condition = "WHERE teamname = '".$_SESSION['teamtwo']."' and datecreated = CURDATE()";
$sel_player = $team->SelectRecord(array("*"),"`match`","$condition");
//$sel_player = mysql_query("SELECT * FROM `match` WHERE teamname = '$team1' and datecreated = CURDATE()") or die(mysql_error());
while($get_player = mysql_fetch_array($sel_player))
{
$totalruns = $get_player['runs_bat'];
$totalballs = $get_player['ball_bat'];
#$strike = $totalruns / $totalballs * 100;
?>
<tr>
<td><input type="text" name="player_name" value="<?php echo $get_player['player_name']; ?>" disabled="disabled" /></td>
<td><input type="text" name="runs<?=$get_player['id']?>" value="<?php echo $get_player['runs_bat']; ?>" size="1" /></td>
// you didnt write this i added
<input type="text" name="ball<?=$get_player['id']?>" value="<?php echo $get_player['ball_bat']; ?>" size="1" />
<td><button>Edit</button></td>
<td><input type="submit" value="Save" name="team" /></td>
</tr>
<?php
} ?>
</table>
</form>
<?php } ?>
</div>
</div>
</body>
</html>
<?php
if(isset($_POST['team'])){
$runsname = 'runs'.$_GET['player'];
$ballsname = 'ball'.$_GET['player'];
$runs = $_POST[$runsname];
$balls = $_POST[$ballsname];
$object = new DBConnection();
$arr_Field=array("runs_bat","ball_bat","player_status","how_out","opposite_bowl","opposite_player","sr","overs","bowl_ball","runs_ball","extra","madien");
$arr_Values=array("$runs","$balls","$status","$how_out","$opposite_bowler","$opposite_player","$sr","$over","$bowls","$score","$extra","$madien");
$condition = "WHERE id = '".$_REQUEST['player']."'";
//echo $_REQUEST['player'];
//echo $runs.$balls;
$object->UpdateRecord("`match`",$arr_Field,$arr_Values,"$condition") or die(mysql_error());
//header("Location:extra.php?update");
}

php $_get variable gone after submitting form

my problem goes like this:
my home page has tables with rows pulled from the database (while loops)
each row has a - cell in which he can add an event to that specific row
in order to do that i send the row id as a $_GET variable from the home page table
and in the "add event" page i store it as a variable
but when i submit my addevent form without filling it properly (as i coded) it simply refreshes the form only without the row id in the url therefor also the query i do in the beginning of the page for pulling the row data can no longer execute and that pops a PHP error
for the id variable which i sign it the $_GET and the query (mysql fetch array).
also of course all the data which i display in the form from that query is gone.
any suggestions on how to approach this ? thanks in advance, Regards.
EDIT:** kill the new guy! -Sorry i guess
home page where i send the id :
$sql = "SELECT * FROM alarms WHERE alarmstatus = 'OFF' and starttime='::' ORDER BY clientid ASC";
$query = mysql_query($sql);
echo "<table cellpadding='1px' border='1px' bordercolor='#0066FF' cellspacing='0'>
<form action='hpage.php' method='get'>";
while($fetch = mysql_fetch_array($query)) {
echo "<tr>
<td>
".$fetch['clientid']."</td>
<td>".$fetch['controller']."</td>
<td>".$fetch['typeid']."</td>
<td style='color: red'>".$fetch['alarmstatus']."</td>
<td>".$fetch['starttime']."</td>
<td>".$fetch['endtime']."</td>
<td><a href='includes/editalarm.php?id=".$fetch['id']."'>Edit</a></td>
<td><a href='includes/addevent.php?id=".$fetch['id']."'>Add event</a></td>
<td><a href='includes/deletealarm.php?id=".$fetch['id']."'>Delete</a></td>
</tr>";
}
the add event where i get the variable and make the query:
$alarmid = $_GET['id'];
$sql = "SELECT * FROM alarms WHERE id=".$alarmid;
$query = mysql_query($sql);
$fetch = mysql_fetch_array($query);
?>
the form:
<table cellpadding="2px" cellspacing="0" >
<form action="addevent.php" method="post">
<tr>
<td>סניף:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="client" value="<?php echo $fetch['clientid']; ?>" /></td>
</tr>
<tr>
<td>בקר:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="controller" value="<?php echo $fetch['controller']; ?>" /></td>
</tr>
<tr>
<td>אזעקה:</td>
<td><input style="width:200px; background-color: #d6d6d6;" readonly name="controller" value="<?php echo $fetch['typeid']; ?>" /></td>
</tr>
<tr>
<td>מוקדן:</td>
<td>
<?php
$sql = "SELECT * FROM users WHERE privilege = '2'";
$query = mysql_query($sql);
echo "<select name='user' style='width:207px;'>";
echo "<option>..</option>";
while ($fetch2 = mysql_fetch_array($query)){
echo "<option>".$fetch2['username']."</option>";
}
echo "</select>";
?>
</td>
</tr>
<tr>
<td>איש קשר:</td>
<td><input type="text" name="contact" /></td>
</tr>
<tr>
<td>הודעה:</td>
<td><input type="text" style="width:200px; height:100px" name="message" /></td>
</tr>
<tr>
<td>תשובה:</td>
<td><input type="text" style="width:200px; height:100px" name="answer" /></td>
</tr>
<tr>
<td>שעה:</td>
<td>
<select name="eventhour">
<option value ="default"></option>
<?php
for($i = 0; $i<60; $i++){
$value = $i;
if($i<=9){
$value= "0".$i;
}
echo "<option>".$value."</option>";
}
?>
</select>
<select name="eventminute">
<option value ="default"></option>
<?php
for($i = 0; $i<24; $i++){
$value = $i;
if($i<=9){
$value= "0".$i;
}
echo "<option>".$value."</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td>
<input type="submit" name="save" value="שמור" />
<input type="submit" name="cancell" value="בטל" />
</td>
<td></td>
</tr>
</form>
Your form action is POST. If you change that to GET then you will have the form as $_GET.

multiple update array query gone wrong :(

hey guys im having trouble with an array. all i need is for the query to update 2 columns on the table based on the records id
The table has a column called OffID and it looks for any record that has not yet been authorised. to mark it authorised the user will select a check box for either authorise or deny and then press the submit button. however at the moment i have 9 records which show in the table each with there own unique id but when submit is selected it will only update one. any help in showing where ive gone wrong would be grateful and cheers in advance :)
ok i edited the code but it is only now setting the first record. so if there are 8 records and i choose accept for the first record and deny for the second record both the accept and deny are set to the first record in the database my new code is below
<?php
$path = $_SERVER['DOCUMENT_ROOT'];
$path .= "/Apollo/dbc.php";
include_once($path);
$rs_results = mysql_query("SELECT * FROM off WHERE IsItAuthorised='0' and isitsick='0' ORDER BY DayOff");
?>
<html>
<head>
<title>Administration Main Page</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<?php
if (isset($_POST['submit'])) {
//Assign each array to a variable
$id = $_POST['id'];
$approve = $_POST['approve'];
$deny = $_POST['deny'];
$limit = count($rs_results);
$values = array(); // initialize an empty array to hold the values
for($k=0;$k<$limit;$k++){
$msg[] = "$limit New KPI's Added";
$query = "UPDATE off SET Authorised = '$approve[$k]', Deny = '$deny[$k]' WHERE OffID = '$id[$k]'";
}
$Event = "INSERT INTO events (UserName, Event ) VALUES ('$_SESSION[user_name]', 'Entered New KPI' )";
echo $query;
if (!mysql_query($query,$link)){
die('Error: ' . mysql_error());
} else {
mysql_query($Event);
echo "<div class=\"msg\">" . $msg[0] . "</div>";
}
}
?>
</head>
<body>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td width="14%" valign="top"><?php
?>
</td>
<td width="74%" valign="top" style="padding: 10px;">
<p><?php
if(!empty($msg)) {
echo $msg[0];
}
?></p>
<p>
<?php
$cond = '';
$sql = "select * from off ";
$rs_total = mysql_query($sql) or die(mysql_error());
$total = mysql_num_rows($rs_total);
?>
<p>
<form name "searchform" action="/Apollo/Admin/HolidayRequests.php" method="post">
<table width="100%" border="0" align="center" cellpadding="2" cellspacing="0">
<tr class="mytables">
<td width="4%"><font color="white"><strong>ID</font></strong></td>
<td width="4%"> <font color="white"><strong>Staff Member</font></strong></td>
<td width="10%"><font color="white"><strong>Day Off</font></strong></div></td>
<td width="10%"><font color="white"><strong>Is It Authorized</font></strong></div></td>
<td width="15%"> </td>
</tr>
<tr>
<td> </td>
<td width="10%"> </td>
<td width="17%"><div align="center"></div></td>
<td> </td>
</tr>
<?php while ($rrows = mysql_fetch_array($rs_results)) {?>
<tr>
<td><input name="id[]" id="id[]" size="4" value="<?php echo $rrows['OffID'];?>" /></td>
<td><?php echo $rrows['StaffMember']; ?></td>
<td><?php echo date('d/m/Y', strtotime($rrows['DayOff']));?></div></td>
<td> <span id="approve<?php echo $rrows['id']; ?>">
<?php if(!$rrows['IsItAuthorised']) { echo "Pending"; } else {echo "Authorized"; }?>
</span> </td>
<td>
<input type="checkbox" name="approve[]" id="approve[]" value="1"> Approve
<input type="checkbox" name="deny[]" id="deny[]" value="1"> Deny
</td>
</tr>
<?php } ?>
</table>
<input name="submit" type="submit" id="submit" value="Submit">
</form>
</p>
<?php
?>
<p> </p>
<p> </p>
<p> </p>
<p> </p></td>
<td width="12%"> </td>
</tr>
</table>
</body>
</html>
isn't it because your $id etc isn't passes an array:
$id = $_POST['id'];
$approve = $_POST['approve'];
$deny = $_POST['deny'];
You're using $_POST['id'] but nowhere in your <form/> do I see any <input name="id[]"/> which could provide the data

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