if i have this table:
perma_table:
+-------+-------+
| A | B |
+-------+-------+
| a | 5 |
| c | 7 |
| a | 8 |
| b | 9 |
| a | 7 |
| c | 6 |
| a | 8 |
+-------+-------+
i want to make
inserted_table:
+-------+-------+-------+
| A | B | C |
+-------+-------+-------+
| a | 5 | 1 |
| a | 7 | 2 |
| a | 8 | 3 |
| a | 8 | 4 |
| b | 9 | 5 |
| c | 6 | 6 |
| c | 7 | 7 |
+-------+-------+-------+
how to do this?
im using code igniter (php), is this all of this method can be done by using query, without using CI active record/php function?
You can do it with a single query
CREATE TABLE inserted_table as
SELECT A,B,#num:=#num+1 AS C
FROM perma_table,(select #num:=0) temp
ORDER BY A,B;
If you want just a query to do it, its so simple:
Insert it normally, after inserted you can select
SELECT * FROM table ORDER BY A, B, C ASC
But if you want to keep this order, without at any select without order you can create a view or a new table like
CREATE VIEW inserted_table AS
SELECT A, B, #id = #id+1 AS C FROM perma_table
ORDER BY A,B;
OR a new table (no view)
CREATE TABLE inserted_table AS
SELECT A, B, #id = #id+1 AS C FROM perma_table
ORDER BY A,B;
With view you can insert any value on perma_table, the inserted_table will automaticaly generated, if you choose the second case, you heave to recreate the table averytime when you edit perma_table
Related
I have 1 master_table and 2 sub_tables. I want the join the 3 columns together (but the problem is the 2 sub_tables do not have any column that share the same value) and then SELECT * based on 2 different columns from the 2 sub_tables.
I've searched and tried many ways of coding, but couldn't find a solution.
SELECT *
FROM (master INNER JOIN sub_1 ON master.id=sub_1.id WHERE sub_1.column_1 = 'Y')
AND (master INNER JOIN sub_2 ON master.id=sub_2.id WHERE sub_2.column_2 = 'Y')
ORDER BY master.id
++++++++++++++++++++++++++++++++++++++++++++++++++
* Finally, solved. See the solution at the bottom of this post. *
++++++++++++++++++++++++++++++++++++++++++++++++++
===========
Edit: explain more about my data, problem and MySQL code
I have 3 tables stored in MySQL as follow
Master_table: regist
------------------------------------------
| reg_no | firstname | lastname | submit |
------------------------------------------
| 1 | first_A | last_A | N |
| 2 | first_B | last_B | A |
| 3 | first_C | last_C | P |
| 4 | first_D | last_D | P |
| 5 | first_E | last_E | A |
| 6 | first_F | last_F | N |
| 7 | first_G | last_G | N |
| 8 | first_H | last_H | A |
------------------------------------------
Sub_1: sub_A Sub_2: sub_P
------------------------------ ------------------------------
| reg_no | A_title | reply_A | | reg_no | P_title | reply_P |
------------------------------ ------------------------------
| 2 | 222 | Y | | 3 | 333 | N |
| 5 | 555 | N | | 4 | 444 | Y |
| 8 | 888 | Y | ------------------------------
------------------------------
I want to create a query that gives result like this
----------------------------------------------------------------------------------
| reg_no | firstname | lastname | submit | A_title | reply_A | P_title | reply_P |
----------------------------------------------------------------------------------
| 2 | first_B | last_B | A | 222 | Y | | |
| 8 | first_H | last_H | A | 888 | Y | | |
| 4 | first_D | last_D | P | | | 444 | Y |
----------------------------------------------------------------------------------
or
-----------------------------------------------------------
| reg_no | firstname | lastname | submit | title | reply |
-----------------------------------------------------------
| 2 | first_B | last_B | A | 222 | Y |
| 8 | first_H | last_H | A | 888 | Y |
| 4 | first_D | last_D | P | 444 | Y |
-----------------------------------------------------------
$sql = "SELECT *
FROM (regist INNER JOIN sub_A ON regist.reg_no = sub_A.reg_no WHERE sub_A.reply_A = 'Y')
AND (regist INNER JOIN sub_P ON regist.reg_no = sub_P.reg_no WHERE sub_P.reply_P = 'Y')
ORDER BY regist.reg_no";
Expected outcome:
ECHO personal data of all registrants who got reply as 'Y'
if($row['submit']=="A") $title = $row['A_title'];
elseif($row['submit']=="P") $title = $row['P_title'];
$result = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
echo $row['reg_no']." / ".$row['firstname']." ".$row['lastname']." / ".$title."<br>";
}
Problem: my SELECT code resulted in error. The code from #GMB and #Rogue didn't error, but echo give nothing.
If it is not possible to code a query as I want, I will just modify the column names (sub_1.reply_A and sub_2.reply_P) to be the same and change the input code in other webpages. However, it would be best if there is a way because I don't know whether the 'reply' columns were used somewhere else.
========================
Solution: a little modification from #Rogue code
SELECT *
FROM master
LEFT OUTER JOIN sub_1
ON master.id=sub_1.id
LEFT OUTER JOIN sub_2
ON master.id=sub_2.id
WHERE sub_1.column_1 = 'Y'
OR sub_2.column_2 = 'Y'
ORDER BY master.id
Do you just want simple JOINs between these 3 tables ?
SELECT m.*, s1.*, s2.*
FROM master m
INNER JOIN sub_1 s1 ON m.id=s1.id AND s1.column_1 = 'Y'
INNER JOIN sub_2 s2 ON m.id=s2.id AND s2.column_2 = 'Y'
ORDER BY m.id;
If you have master records that may not exist in both sub tables, you can switch to LEFT JOIN to avoid filtering them out.
Guidelines :
typical syntax is SELECT ... FROM table1 INNER JOIN table2 ON ... INNER JOIN table3 ON...
better put all conditions related to a JOINed table in the ON clause of the join rather than in the WHERE clause
avoid SELECT * : be specific about the columns you want to select
use table aliases to make the query easier to read
You're a little off syntactically:
SELECT *
FROM master
LEFT OUTER JOIN sub_1
ON master.id=sub_1.id
LEFT OUTER JOIN sub_2
ON master.id=sub_2.id
WHERE sub_1.column_1 = 'Y'
AND sub_2.column_2 = 'Y'
ORDER BY master.id
Personally I would recommend not using SELECT * and only grabbing the data you will need. As for determining what join to use, I like to link to CodingHorror's blog post in these times.
Edit: swapped INNER to LEFT OUTER, per OP's update
I have a MySQL table that looks like this:
id | id_item |
1 | T0001 |
2 | T0002 |
2 | T0003 |
3 | T0004 |
and I want to change it like this:
id | id_item |
1 | T0001,T0002 |
2 | T0001,T0003 |
2 | T0001,T0004 |
3 | T0002,T0003 |
4 | T0002,T0004 |
5 | T0003,T0004 |
and I want save in table item_2 like this:
id | id_item |
1 | T0001 |
2 | T0002 |
3 | T0001 |
4 | T0003 |
5 | T0001 |
6 | T0004 |
7 | T0002 |
8 | T0003 |
9 | T0002 |
10 | T0004 |
11 | T0003 |
12 | T0004 |
Does anyone know how to do this by using PHP or MySQL?
You can generate this output via the following query:
SELECT
CONCAT(t1.id_item, ',', t2.id_item) AS id_item
FROM yourTable t1
INNER JOIN yourTable t2
WHERE
t2.id > t1.id
ORDER BY
t1.id,
t2.id
If you wanted to insert this data, you can use the above select to do an INSERT INTO ... SELECT into a new table. I mention new table, because it probably would not make much sense to store CSV and non CSV data in the same column. Actually, I don't at all recommend storing CSV data in the first place. Instead, just generate it if you need it in your presentation layer using a query similar to what I have given above.
Demo here:
Rextester
I have a data like this :
car_id | price_id | transmission_id | group_id | image_id
=======|==========|=================|==========|=============
1. CAR A | $20/hour | Automatic | GROUP A | image_1.jpg
2. CAR B | $30/hour | Automatic | GROUP B | image_2.jpg
3. CAR C | $40/hour | Manual | GROUP C | image_3.jpg
4. CAR D | $20/hour | Manual | GROUP A | image_4.jpg
5. CAR E | $30/hour | Manual | GROUP B | image_5.jpg
6. CAR F | $40/hour | Automatic | GROUP D | image_6.jpg
So, the lists can be selected (choose) by "group_id" or "transmission_id".
User can tick and automatically generate result sort by :
Group A,B,C,D
Transmission Automatic,Manual
Group + Transmission
The result shown on the same page. Is it possible if I don't want to use MySQL?
I have three tables group_sentences, group_sentences_attributes and group_senteces_categories.
I have an attributes array which I am using in query with IN (after implode).
Then I have one category ID because they are stored recursively, so no need for an array.
I need to select one group number where is the biggest match for $attributesArray and of course category too.
Here is table group_sentences_attributes
+-----+-------+-----------+
| id | group | attribute |
+-----+-------+-----------+
| 1 | 1 | 3564 |
| 2 | 1 | 3687 |
| 3 | 1 | 3689 |
| 4 | 2 | 3687 |
| 5 | 2 | 3564 |
+-----+-------+-----------+
Here is group_sentences_category
+-----+-------+----------+
| id | group | category |
+-----+-------+----------+
| 1 | 1 | 1564 |
| 2 | 1 | 1221 |
| 3 | 1 | 1756 |
| 4 | 2 | 1358 |
| 5 | 2 | 1125 |
+-----+-------+----------+
Here is my query, but I am afraid that it won't do the job done.
SELECT group_categories.group
FROM group_categories, group_attributes
WHERE group_categories.category = '$category'
AND group_attributes.attribute IN ($attributesArray)
GROUP BY group_categories.group
ORDER BY count(group_attributes.attribute)
Any help would be appreciated, thanks.
First, the table in your query do not match the tables in the question. I am guessing they are simply missing the "sentence". Then, you have no join clause. Simple rule: Never use commas in the from clause.
group is a lousy name for a column, because it is a keyword in SQL. The following may be what you are looking for:
SELECT gc.groupid
FROM group_sentences_attributes sa JOIN
group_sentences_category sc
ON sa.groupid = sc.groupid
WHERE sc.category = '$category' AND
sa.attribute IN ($attributesArray)
GROUP BY sa.groupid
ORDER BY count(sa.attribute);
If you only want one row, then add LIMIT 1 to the end.
I have a big filter with many options and want to generate the query for sql automaticle and without many code.
GET:
searchvalue=abc
&title=abc
&description=abc
&category=1
&subcategory=2
&zip=7
&city=ke
&country=DE
SQL:
SELECT activity.* FROM activity,subcategory,city,country
WHERE activity.title LIKE '%abc%' OR activity.description LIKE '%abc%'
AND subcategory.SubID = 2
AND city.zip LIKE '%7%'
AND city.City LIKE '%ke%'
AND country.CShort= 'DE'
With this options, I have 1 row in my database.
The answer is this row many times, many many times.
I know that the sql duplicate a row, when a table is not used in a WHERE clausel - but why he do it now and how can I solve that?
Edit: I have a ER, but the database is in german (school project), maybe it help you to understand:
Thanks!
You are doing a cross product by selecting multiple tables. SQL will return every row from the one table combined with every row in the other table.
For example in a database with table a
|------|----------|
| idA | textA |
|------|----------|
| 1 | fooA |
| 2 | barA |
|------|----------|
and table b
|------|----------|
| idB | textB |
|------|----------|
| 1 | fooB |
| 2 | barB |
|------|----------|
when you do
SELECT * FROM a, b
you would get
|------|----------|------|----------|
| idA | textA | idB | textB |
|------|----------|------|----------|
| 1 | fooA | 1 | fooA |
| 1 | fooA | 2 | barA |
| 2 | barA | 1 | fooB |
| 2 | barA | 2 | barB |
|------|----------|------|----------|
To combine these rows logically you do a JOIN. That means you tell in your query which rows belong together. You can do so by JOIN clause or without JOIN clause directly in the WHERE clause.
Back to the example you would do
SELECT * FROM a, b
WHERE a.idA = b.idB
-- or
SELECT * FROM a
JOIN b ON a.idA = b.idB
you would get only 2 rows.
|------|----------|------|----------|
| idA | textA | idB | textB |
|------|----------|------|----------|
| 1 | fooA | 1 | fooA |
| 2 | barA | 2 | barB |
|------|----------|------|----------|
To answer your question:
You have to support JOIN/WHERE clauses to connect your tables activity, subcategory, city and country according to your database schema.
I don't know your table structures but for example clauses like this:
WHERE
...
AND city.country_id = country.id
AND activity.subcategory_id = subcategory.id
AND ...