Get element by index, [n] - php

Question

I'm using PHPQuery to read some content from HTML, I'm unable to get the element by it's index using the square bracket notation.
See this simple example:
$html = '<div><table id="theTable"><tr><td>FIRST TD</td><td>SECOND TD</td><td>THIRD TD</td></tr></table></div>';
$pq = phpQuery::newDocumentHTML($html);
$table = $pq->find('#theTable');
$tds = $table->find('td');
echo "GETTING BY INDEX:\n\n";
echo '$tds[1] = ' . $tds[1];
echo "\n\n\n";
echo "GETTING IN FOREACH:\n\n";
foreach($tds as $key => $td){
echo '$tds[' . $key . '] = ' . pq($td) . "\n";
}
The output of this is:
GETTING BY INDEX:
$tds[1] =
GETTING IN FOREACH:
$tds[0] = FIRST TD
$tds[1] = SECOND TD
$tds[2] = THIRD TD
I would have expected that I can get the contents of $tds[1] using square brackets, but seems not. How can I get it by index?

Answer 1

Try a var_dump($tds), it'll tell you whats exactly inside the tds. Maybe those keys are actually strings and you should use:
echo "GETTING BY INDEX:\n\n";
echo '$tds['1'] = ' . $tds['1'];
Edit: Also, on your foreach you're using pq(), maybe you should use this
echo "GETTING BY INDEX:\n\n";
echo '$tds[1] = ' . pq($tds[1]);

Answer 2

Found the answer just after posting the question. Instead of square brackets you need to use eq(n):
echo '$tds[1] = ' . $tds->eq(1);

Answer 3

Try the following:
echo '$tds[1] = ' . $tds['1'];