Hello there i have a php file with the included:
The image shows properly when i access the PHP file, however when I try to show it in the HTML template, it shows as the little img with a crack in it, so basically saying "image not found"
<img src="http://konvictgaming.com/status.php?channel=blindsniper47">
is what i'm using to display it in the HTML template, however it just doesn't seem to want to show, I've tried searching with next to no results for my specific issue, although I'm certain I've probably searched the wrong title
adding code from the OP below
$clientId = ''; // Register your application and get a client ID at http://www.twitch.tv/settings?section=applications
$online = 'online.png'; // Set online image here
$offline = 'offline.png'; // Set offline image here
$json_array = json_decode(file_get_contents('https://api.twitch.tv/kraken/streams/'.strtolower($channelName).'?client_id='.$clientId), true);
if ($json_array['stream'] != NULL) {
$channelTitle = $json_array['stream']['channel']['display_name'];
$streamTitle = $json_array['stream']['channel']['status'];
$currentGame = $json_array['stream']['channel']['game'];
echo "<img src='$online' />";
} else {
echo "<img src='$offline' />";
}
The url is not an image, it is a webpage with the following content
<img src='offline.png' alt='Offline' />
Webpages cannot be displayed as images. You will need to edit the page to only transmit the actual image, with the correct http-headers.
You can probably find some help on this by googling for "php dynamic image".
Specify in the HTTP header that it's a PNG (or whatever) image!
(By default they are interpreted as text/html)
in your status.php file, where you output the markup of <img src=... change it to read as follows
$image = file_get_contents("offline.png");
header("Content-Type: image/png");
echo $image;
Which will send an actual image for the request instead of sending markup. markup is not valid src for an img tag.
UPDATE your code modified below.
$clientId = ''; // Register your application and get a client ID at http://www.twitch.tv/settings?section=applications
$online = 'online.png'; // Set online image here
$offline = 'offline.png'; // Set offline image here
$json_array = json_decode(file_get_contents('https://api.twitch.tv/kraken/streams/'.strtolower($channelName).'?client_id='.$clientId), true);
header("Content-Type: image/png");
$image = null;
if ($json_array['stream'] != NULL) {
$channelTitle = $json_array['stream']['channel']['display_name'];
$streamTitle = $json_array['stream']['channel']['status'];
$currentGame = $json_array['stream']['channel']['game'];
$image = file_get_contents($online);
} else {
$image = file_get_contents($offline);
}
echo $image;
I suppose you change the picture dynmaclly on this page.
Easiest way with least changes will just be using an iframe:
<iframe src="http://konvictgaming.com/status.php?channel=blindsniper47"> </iframe>
Related
after no one answered at this question Php Rss feed use img in CDATA -> content:encoded i try to do something else solving this problem...
how can i load an image from a given url directly into my homepage?
<?php
$url = "...";
$image = file_get_contents("$url");
echo $image;
?>
*i don't want to save the image anywhere... just load the image from the url and show it in my own homepage.
Try this code,work fine on my machine.
<?php
$image = 'http://www.google.com/doodle4google/images/d4g_logo_global.jpg';
$imageData = base64_encode(file_get_contents($image));
echo '<img src="data:image/jpeg;base64,'.$imageData.'">';
?>
You are almost there. When you download the contents of the file you need to encode it to base64 if you do not plan to store it on server.
<?php
$url = '...';
$image = base64_encode(file_get_contents($url));
?>
Then you can display it:
<img src="data:image/x-icon;base64,<?= $image ?>">
I created a php page that print the barcode. Just to view it before i print it on an A4. Still in testing phase. The codes are as below.
<?php
include('include/conn.php');
include('include/Barcode39.php');
$sql="select * from barcode where b_status = 'NOT-PRINTED'";
$result=mysqli_query($conn,$sql);
echo mysqli_num_rows($result);
$i=0;
while($row=mysqli_fetch_assoc($result)){
$acc_no = $row["b_acc_no_code"];
$bc = new Barcode39($row["b_acc_no_code"]);
echo $bc->draw();
$bc->draw($acc_no.$i.".jpg");
echo '<br /><br />';
$i++;
}
?>
Without the while loop, it can be printed, but only one barcode. How to make it generate, for example in the database have 5 values, it will print 5 barcode in the same page. Thanks in advance
Try to use another bar code source. Because It is generate only one bar code per page. Can't able to create multiple bar code per page.
I know this is an older post but comes up in searches so is probably worth replying to.
I have successfully used the Barcode39 to display multiple barcodes. The trick is to get base64 data from the class and then display the barcodes in separate HTML tags.
The quickest way to do this is to add a $base64 parameter to the draw() method:
public function draw($filename = null, $base64 = false) {
Then, near the end of the draw() method, modify to buffer the imagegif() call and return the output in base64:
// check if writing image
if ($filename) {
imagegif($img, $filename);
}
// NEW: Return base 64 for the barcode image
else if ($base64) {
ob_start();
imagegif($img);
$image_data = ob_get_clean();
imagedestroy($img);
return base64_encode($image_data);
}
// display image
else {
header("Content-type: image/gif");
imagegif($img);
}
Finally, to display multiples from the calling procedure, construct the image HTML in the loop and display:
// assuming everything else has been set up, end with this...
$base64 = $barcode->draw('', true); // Note the second param is set for base64
$html = '';
for ($i = 0; $i < $numBarcodes; $i++) {
$html .= '<img src="data:image/gif;base64,'.$base64.'">';
}
die('<html><body>' . $html . '</body></html>');
I hope this helps anyone else facing this challenge.
i am trying to get a Minecraft player's skin via PHP, and it all works, until the user enteres an invalid username, techniclly, if that happenes the script should replace the not found image with an alternative image, but for some reason it doesn't.
full script:
<?php
//initial settings
header("Content-type: image/png");
//declere values
$name = $_GET['n'];
//get the image from Minecraft main servers
$src = imagecreatefrompng("http://s3.amazonaws.com/MinecraftSkins/{$name}.png");
//if not found, use an alternative image
if(!$src){
$src = imagecreatefrompng("http://s3.amazonaws.com/MinecraftSkins/char.png");
}
//display the skin
imagepng($src);
?>
Any help will be appriciated, thank you.
try
<?php
//initial settings
header("Content-type: image/png");
//declere values
$name = $_GET['n'];
//get the image from Minecraft main servers
if(file_exists("http://s3.amazonaws.com/MinecraftSkins/{$name}.png")) {
$src = imagecreatefrompng("http://s3.amazonaws.com/MinecraftSkins/{$name}.png");
//if not found, use an alternative image
else {
$src = imagecreatefrompng("http://s3.amazonaws.com/MinecraftSkins/char.png");
}
//display the skin
imagepng($src);
?>
I'm trying to get the twitter profile picture actual link.
I know I can get the profile picture through the following link:
$test = "http://api.twitter.com/1/users/profile_image?screen_name=".$nickname."&size=original"
but when I want to get the file contents of this url, it doesn't work, cause above mentioned link is redirected to the actual link of the profile picture. So this doesn't work:
file_get_contents($test);
How can I get the actual link of the profile picture and then with the size original?
Try this it might help you.
<?php
function getTwitterProfileImage($username) {
$size = '_bigger';
$api_call = 'http://twitter.com/users/show/'.$username.'.json';
$results = json_decode(file_get_contents($api_call));
return str_replace('_normal', $size, $results->profile_image_url);
}
$img = getTwitterProfileImage('thetutlage');
echo '<img src="'.$img.'"/>';
?>
Try this is up+direct,
<img class="img-rounded" src="<?php
$size = '';
echo str_replace('_normal', $size,$tweet->user->profile_image_url)
?>"
height="250px" width="400px" />
I have a code download image from link http://www.bitrepository.com/download-image.html
When start is link format: <img src='test[1].jpg'>
But when download this link is link become <img src='test3%5B1%5D.jpg'>
How to fix it?
code here
<?php
include_once 'class.get.image.php';
// initialize the class
$image = new GetImage;
$image->source = 'http://test.com/test[1].jpg';
$image->save_to = 'images/'; // with trailing slash at the end
$get = $image->download('gd'); // using GD
if($get)
{
echo 'The image has been saved.';
}
?>
Try this.
On this line
$image->source = 'http://test.com/test[1].jpg';
Changed to
$image->source = htmlspecialchars_decode('http://test.com/test[1].jpg');
Look up urldecode in php to change the encoded values back to brackets