I have a variable with a score and I'm having php change the color of a div element based on this variable. This if statement is always resolving to True. Anyone see the flaw?
<style>
.poster{
background-color:<?php
if($voteRating > 80.0){
echo "#2ecc71;";
}
else{
echo "#f1c42c;";
}
?>
}
.year{
color:;
}
</style>
Personally, I would create two CSS classes and echo an appropriate class name on the element instead.
if($voteRating < 80)
{
echo "<div class='one-class'>";
}
else
{
echo "<div class='another-class'>";
}
Or, considering this is more of front-end thing, maybe use ajax to determine the $voteRating and then change the style with javascript. Just some alternatives.
Nothing wrong with code. Try echoing $voteRanking to see if it gives more then 80.0
try something like this:-
<style>
.poster{
background-color:<?php echo ($voteRating > ceil(80.0)) ? "#2ecc71;" : "#f1c42c;"; ?>
}
.year{
color:;
}
</style>
You should create different classes for each color and then use javascript or php conditions to set the class upon page rendering or any other event triggering. This way its easy to debug issues with your code.
for example
<style>
.posterhigh{
background: #2ecc71;
}
.posterlow {
background: #f1c42c;
}
</style>
Related
I have created a skin switcher and it is working great, but the code is messy.
I save a cookie and then for some defined css classes, I append '-userDelectedColourFromTheCookie' to the end of the css class to apply it on the page.
So far, I am adding a short php line to the end of every instance of these classes in the html code and as I have said, it is working.
I would prefer to run the php code just once across the whole page and update all occurrences of an array containing the required classes to append the class as above.
I have this at the top of my page:
<?php
$classList = array("theme-1","theme-2","theme-3","theme-4","theme-5","theme-6","theme-7","theme-8","theme-9","theme-10","theme-hover","theme-heading","theme-drop-content","theme-container","theme-banner-text");
if ((isset($_COOKIE["Theme"])) && in_array($_COOKIE["Theme"], array("Blue","Red","Grey","Ochre","Mauve"))) echo $classList."-".strtolower($_COOKIE["Theme"]);
?>
<!DOCTYPE html>
... etc
I am defining an array of css classes, then reading the user colour from the cookie and appending it to the css class.
As and example, the default class might be 'theme-3' but of the user selects the blue skin, then this class becomes 'theme-3-blue' and so on.
But it's not working.
Any help would be appreciated.
Don't mess with the element class lists. Use CSS files to apply the colours you want.
Start with a basic CSS design file:
p {
margin-left:10px
font-size: 12pt;
}
h1 {
font-size: 24pt;
}
div {
margin: 10px;
padding 20px;
}
Then create CSS colour files with different colour selections:
blue.css
p {
color:blue;
}
h1 {
color: darkblue;
background-color: lightblue;
}
red.css
p {
color:red;
}
h1 {
color: maroon;
background-color: pink;
}
default.css
p {
color:black;
}
h1 {
color:white;
background-color:black;
}
Then load the colour theme you want
<?php
if (isset($_COOKIE['theme'] && in_array($_COOKIE['theme'], ['red','blue'])) {
$themeCSS = '<link rel="stylesheet" href="'.$_COOKIE['theme'].'.css">';
} else {
$themeCSS = '<link rel="stylesheet" href="default.css">';
}
Then echo $themeCSS in your <head> just like any other <head> element
** I've used standard HTML elements here to illustrate, but any CSS selectors should work.
I believe you want to change the class names inside the $classList variable by appending the selected color theme from the cookies.
You may use the array_map function to modify all elements of your $classList array.
$classList = array("theme-1","theme-2","theme-3","theme-4","theme-5","theme-6","theme-7","theme-8","theme-9","theme-10","theme-hover","theme-heading","theme-drop-content","theme-container","theme-banner-text");
$themeColor = $_COOKIE["Theme"]; // blue
$classList = array_map(function($val) use ($themeColor) { return $val.'-'.$themeColor; }, $classList);
Once you use the array_map function, all elements of the $classList array will be appended with the "-blue".
You can execute and see the output here
http://sandbox.onlinephpfunctions.com/code/6051282e00be1eb7bb7e6a086de20bbcfe9bcc9f
Several good ways to do it. It's a little more complicated with the array of classes but you should be able to adjust this if you need it (not sure why the syntax highlighting is wonky).
Use output buffering and replace at the end:
<?php
ob_start();
?>
<html>
<head></head>
<body>
<div class="theme-1"></div>
</body>
</html>
<?php
$themes = array("Blue","Red","Grey","Ochre","Mauve");
if ((isset($_COOKIE["Theme"])) && in_array($_COOKIE["Theme"], $themes)) {
echo preg_replace('/class="(theme-[^"]+)"/', 'class="$1-' . $_COOKIE['Theme'] . '"', ob_get_clean());
}
With the array of classes, just do it the same way with output buffering but replace like so:
$replace = array_map(function($v) { return "{$v}-{$_COOKIE['Theme']}"; }, $classList);
echo str_replace($classList, $replace, ob_get_clean());
im having a problem and i can't seem to put an image icon on my delete and edit button i've put a div class and styled it in my css but still the image doesn't show.what might be wrong here?
HTML
<?php
$this->table->set_heading("Name","Nationality","Contact Number","Number of Guest","Date of Arrival","Time","Pickup Location","Package","Other Request","Delete Record","Edit Record");
$qry = $this->db->like('name',$search_key)->order_by('date')->get('booking');
if ($qry->num_rows > 0) {
foreach ($qry->result() as $row) {
$this->table->add_row(anchor('site/print_records/'.$row->id, $row->name, 'target="_blank"'),$row->nationality,$row->contactnum,$row->number_of_guest,$row->date,$row->time,$row->pickup,$row->package,$row->request,anchor('site/delete/'.$row->id, "<div class='deleteico'></div>),anchor('site/update/'.$row->id, "<div class='editico'></div>));
}
}
else{
echo "No records found!";
}
echo $this->table->generate();
?>
CSS
#deleteico{
background-image: url('../pictures/delete_icon.png');
}
#editico{
background-image: url('../pictures/edit_icon.png');
}
You are using class in your code and are applying the css to an id selector.
If you want to use classes, change your css to the following:
.deleteico{
background-image: url('../pictures/delete_icon.png');
}
.editico{
background-image: url('../pictures/edit_icon.png');
}
# is used to select IDs, and . is used for classes.
Note: and as #skip405 has mentioned as well, you will need to set a width and height in your css or the div will be 0x0 big and thus not show anything.
Try adding a space inside your brakets:
you need to add width and height of the background-image to the #deleteico and #editico ids. Then add to them and change it to id from class in your code.
For instance,
<div id='deleteico'> </div>
<div id='editico'> </div>
Hope this helps.
I have several sites on the same hosting package. They’re all in different directories. ( i.e. “htdocs/site1”). I want to be able to have them all share one CSS file.
I was wondering if there is a way to change the color of certain elements based on which directory the site is in.
Ideally I would like to be able to define what directory the page is in and what color to use for each directory. Then in my CSS do something like:
.button { color: <?php echo $color ?> ;}
to each element that gets a color change.
Is this possible and if so, how do I go about setting this up?
thank you
You could add different classes to your body tag depending on the directory:
<body class="<?php echo $dir; ?>">
where the $dir variable is given a different value (let's say $dir = 'site1',...) for each directory...
... And then have something like:
.site1 #button { /*styles*/ }
.site2 #button { /*styles*/ }
.site3 #button { /*styles*/ }
in your CSS file.
You could add a CSS class to the body tag of the HTML document to determine the site. In PHP you would have to find a way to write the correct site into to the document. Do you use some kind of global template?
Just to give you an idea:
PHP:
<?php
// some code
// some logic to determine which site you are on - let's say ...
$site = 'SITE1';
?><body class="<?php echo $site; ?>"><?php
// more code
?>
CSS:
body.SITE1 #button { color: #ff0000; }
body.SITE2 #button { color: #0000ff; }
body.SITE2 #button { color: #123456; }
You could dynamically generate the css file using php, where you'd have
<?php
switch ($_SERVER['SERVER_NAME']) {
case 'www.site1.com':
$color = '#ff0000';
break;
case 'www.site2.com':
$color = '...';
break;
...
default:
$color = '...';
?>
.someclass { color : <?php echo $color ?>; }
This is somewhat inefficient, however. You'd be building a css file just to change a single color each time. Better way is to simply embed the color change in the page's header as an in-line style. That way you don't have to mess with making your server parse CSS files as if they were PHP scripts, and you can put the site-specific css overrides into that inline style in the site's header.
Honestly, I would suggest you add a class to your html tag:
<html class="site1">
And within your CSS, define your css:
.site1 * .button1{ background:#f00;}
.site2 * .button1{ background:#f0f;}
.site3 * .button1{ background:#ff0;}
You can find some more information on this subject here for a PHP approach.
I have a standard html page so:
<html>
<head>..
.
..
and so on
and i have a php script linked to that html page with:
if blablabla {
change background color;
}
does anyone know how to change the background color of my page if the conditions in the if statement are met?
I hope i made this clear, if not, please say which bit is unclear.
Thanks for any help in advance
put your <body> tag inside the if else
if blablabla {
echo '<body style="background-color:white">';
}
else {
echo '<body style="background-color:orange">';
}
It's not necessarily great practice, but it should get the job done:
if ( your_conditional ) {
$styleBlock = sprintf('
<style type="text/css">
body {
background-color:%s
}
</style>
', $yourColor);
echo $styleBlock;
}
One good (?) thing about this is that with this technique, you can put your if statement anywhere - it'll act on the body tag regardless of where you put it.
One caution: if you have additional style rules for the body tag's background color farther down your page, those will take precedence over the one from your if statement.
here is code that i whant to change background of body
<body bgcolor="<?php echo $name2; ?>">
Currently I'm doing something like this:
<?php
if ($x == 0)
$image = 'background-position: 0px -7px';
else
$image = 'background-position: 0px -14px';
?>
<a class="asdf" style="<?php echo $image; ?>"></a>
Is this the recommended way to change an image based on a variable in HTML/PHP? Is there any way to refactor this?
Try something like this:
<?php
$positionClass = ($x == 0) ? 'position1' : 'position2';
?>
<style type="text/css">
.position1 { background-position: 0px -7px; }
.position2 { background-position: 0px -14px; }
</style>
<a class="asdf <?php echo $positionClass;?>"></a>
PHP will set which class should be used, and then echo the corresponding class in your HTML. The CSS will be applied with the desired positioning attributes.
If it's part of the style, use css and classes. If it's part of the content, you should be using an img element.
You're code is weird? At the end of the if-statement the position would end up begin -7 or -14px... the first is just nonsense...
thus this code might be 'neat'-er but thats just personal:
<a class="asdf" style="background-position: 0px -<?php echo (($x==0)?'7':'14') ?>px;"></a>
Again, some might argue that this inline tenerary operator might be unreadable, but it does the same thing...
I would probably set a class instead, and change the class via PHP. This way, you are still maintaining style in your CSS, but can choose it with PHP.