How to pass a parameter to ajax sucsses function - php

Question

I have a php function that get some xml information to be handled, but my problem is to pass a parameter to the function in addition to the data returned from the ajax :
$.ajax({
type: "POST",
url: 'proxy.php',
data:{country:'home'},
dataType: "xml",
success: function(data)
{
alert(data);
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert(XMLHttpRequest);
alert(textStatus);
alert(errorThrown);
alert(XMLHttpRequest.responseText);
}
});
I want to pass parameter with the data .
I know that I could do it like the following:
$.ajax({
type: "POST",
url: 'proxy.php',
data:{country:'home'},
dataType: "xml",
success: function do_it(parameter)
});
function do_it(parameter)
{
return function(data)
{
alert(parameter);
alert(data);
}
}
I do not want to use this way I want to pass the parameter as the first code is showing.
Is it possible?

Answer 1

You can use the context option to $.ajax. This will then be available as this in the callback.
$.ajax({
type: "POST",
url: 'proxy.php',
data:{country:'home'},
dataType: "xml",
context: parameter,
success: function(data)
{
alert(data);
alert(this);
},
error : function(XMLHttpRequest, textStatus, errorThrown) {
alert(XMLHttpRequest);
alert(textStatus);
alert(errorThrown);
alert(XMLHttpRequest.responseText);
}
});

Answer 2

If your parameter is not affected by the AJAX call, simply define it in the same scope as the call and then access it from the success function. For example:
var parameter = 'some value';
$.ajax({
type: 'post',
url: 'proxy.php',
data: {country: 'home'},
dataType: 'xml',
success: function (data) {
alert(parameter);
alert(data);
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
alert(XMLHttpRequest);
alert(textStatus);
alert(errorThrown);
alert(XMLHttpRequest.responseText);
}
});
This works because parameter is in an outer scope and thus accessible by the success function.