How to get group from user in SonataUserBundle? - php

Question

I'm using symfony 2.2.3 and sonata admin in dev-master.
I would like a custom field to show users from a specific group.
I've not found how to make the relation with Sonata User entity and Sonata Group entity.
The doctrine schema create 3 tables : fos_user_user, fos_user_group and the relation table fos_user_user_group.
I've a form with a field like that in my Admin class :
->add('coach', 'entity', array(
'class' => 'ApplicationSonataUserBundle:User',
'empty_value' => 'Choisissez un coach',
'property' => 'username',
'query_builder' => function(\Application\Sonata\UserBundle\Entity\UserRepository $er) {
return $er->getCoachs();
},
))
And my function getCoachs() in UserRepository:
public function getCoachs()
{
$em = $this->getEntityManager();
$qb = $em->createQueryBuilder(array('u', 'g'))
->select('u.username, g.id')
->from('ApplicationSonataUserBundle:User', 'u')
->innerJoin('ApplicationSonataUserBundle:Group', 'g', 'WITH','g.id = u.group_id')
->where('g.id = :id')
->setParameter('id', 1);
return $qb;
}
I know that the query doesn't work because the innerJoin isn't correct.
My user entity and group entity just extends BaseUser and GroupUser with an id.
Someone know the right query ?
Thank you.
EDIT :
Ok i've found the solution for the query :
public function getCoachs()
{
$em = $this->getEntityManager();
$qb = $em->createQueryBuilder('u')
->select('u.username')
->from('ApplicationSonataUserBundle:User', 'u')
->innerJoin('u.groups', 'g')
->where('g = :id')
->setParameter('id', 1);
return $qb;
}
However, i've this error :
Expected argument of type "object or array", "string" given
I don't understand because I return my function getCoachs() which return a query builder...
No idea ?

Answer 1

Ok I've found the solution !
My query is :
public function getCoachs()
{
$em = $this->getEntityManager();
$qb = $em->createQueryBuilder('u')
->select('u') // and not u.username
->from('ApplicationSonataUserBundle:User', 'u')
->innerJoin('u.groups', 'g')
->where('g = :id')
->setParameter('id', 1);
return $qb;
}
In fact, I returned values of a specific column (username) but you have to return the object User.