Random Picture From Database MYSQL - php

Hi trying to grab 7 random photos from my database where type='img'
Some code
<?php
$ilosc= 7;
$Query='SELECT * FROM tentego_img WHERE type = 'img' ORDER BY RAND() LIMIT '.$ilosc;
$QueryResult=mysql_query($Query);
while($Kol=mysql_fetch_array($QueryResult)){
echo('<td style="border: 0px"><img src="/upload/'.$Kol['src'].'" alt="'.$Kol['title'].'" title="'.$Kol['title'].'" width="120px" height="120px" /></td> ');
}
?>
So should catch 7 randoms photos where type= img, but have no idea whats wrong with code
when query looks like `
$Query='SELECT * FROM tentego_img ORDER BY RAND() LIMIT '.$ilosc;`
works fine but i need to show just photos where type=img
Help Please
Cheers

Use different characters:
$Query="SELECT * FROM tentego_img " .
"WHERE type='img' ORDER BY RAND() LIMIT ".$ilosc;
or escape the single quotes:
$Query='SELECT * FROM tentego_img ' .
'WHERE type=\'img\' ORDER BY RAND() LIMIT '.$ilosc;

You must escape your ' characters or use " around the string
$Query = "SELECT * FROM tentego_img WHERE type = 'img' ".
"ORDER BY RAND() LIMIT ".$ilosc;

Related

CodeIgniter get table count rows

I am new in CodeIgniter, I want to count all rows from database table but i use limit in query and i want all count without use limit how can i do ?
my code is below :
$sql = " SELECT intGlCode,fkCategoryGlCode,'C' as acctyp,varEmail,varContactNo as phone,CONCAT(varFirstName,' ',varLastName) as name,dtCreateDate,chrStatus,varMessage as message
FROM " . DB_PREFIX . "Customer WHERE varEmail='$userEmail'
UNION
SELECT intGlCode,'' as fkCategoryGlCode,'P' as acctyp,varEmail,varPhoneNo as phone,varName as name,dtCreateDate,chrStatus,txtDescription as message FROM
" . DB_PREFIX . "Power WHERE varEmail='$userEmail' ORDER BY intGlCode DESC
LIMIT $start, $per_page ";
$query = $this->db->query($sql)
i use limit for pagination but i want to get all record from table.
You can add new column in both above and below UNION queries. It will be like below.
select (select count(*) from your_query), your_columns from query_above_union
UNION
select (select count(*) from your_query), your_columns from query_below_union
your_query = your full actual query your are using currently.
Although I am not sure about Codeigniter. But sure about SQl.
* If you count all records with all data including limit, than you can use this code. please check it. I hope it will works for you.*
$countsql = " SELECT intGlCode,fkCategoryGlCode,'C' as acctyp,varEmail,varContactNo as phone,CONCAT(varFirstName,' ',varLastName) as name,dtCreateDate,chrStatus,varMessage as message
FROM " . DB_PREFIX . "Customer WHERE varEmail='$userEmail'
UNION
SELECT intGlCode,'' as fkCategoryGlCode,'P' as acctyp,varEmail,varPhoneNo as phone,varName as name,dtCreateDate,chrStatus,txtDescription as message FROM
" . DB_PREFIX . "Power WHERE varEmail='$userEmail' ORDER BY intGlCode DESC";
$sql = $countsql. " LIMIT $start, $per_page";
$totalRecords = $this->db->query($countsql);
$result["total_rows"] = $totalRecords->num_rows();
$query = $this->db->query($sql);
$result["list"] = $query->result_array();

MySQL syntax error in string built by PHP

I have some code which generates a MySQL query string called $query:
$query = "select * from Surveys where surveylayoutid='$surveyid' and customerid='" . $_SESSION['login_customerid'] . "' and (";
$clue = $_POST['postcode'];
$onwhat="Postcode";
$query .= $onwhat . " like '%$clue%') order by id desc";
$result = mysql_query($query, $connection) or die(mysql_error());
This returns something like:
select * from Surveys where surveylayoutid='12' and customerid='1' and (Postcode like '%dn%') order by id desc
which works fine. I've then altered the code because I want to search on more fields so it now reads:
$remap = array("Postcode", "Street", "HouseNum", "District", "Town");
$query = "select * from Surveys where surveylayoutid='$surveyid' and customerid='" . $_SESSION['login_customerid'] . "' and (";
for ($i=0; $i<=4; $i++) {
if ($_POST[strtolower($remap[$i])]!="") {
$clue = $_POST[strtolower($remap[$i])];
$query .= $remap[$i] . " like '%$clue%') order by id desc";
break;
}
}
This also returns:
select * from Surveys where surveylayoutid='12' and customerid='1' and (Postcode like '%dn%') order by id desc
which on the face of it is identical but it generates this error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like '%dn%' order by id desc' at line 1
In both cases $query contains the same "text" but for some reason isn't treated as a valid MySQL query in the updated code, can anyone tell me why?
One possible problem could be the interpretation of the content here.
If you use:
$query .= $remap[$i] . " like '%$clue%') order by id desc";
All that is inside "" gets to be interpreted. Thus there could be unwanted side effects that you don't see at first glance and can explain what is happening. To avoid this it would have to be changed to:
$query .= $remap[$i] . ' like ' . "'" . '%' . $clue . '%' . "') order by id desc";
Even though more clunky in terms of how big it is, it makes sure that $lue and also the % are not interpreted as all in between ' ' is not interpreted.
See if this help you solve your problem?
$remap = array(
"Postcode",
"Street",
"HouseNum",
"District",
"Town"
);
for ($i = 0; $i <= 4; $i++)
{
if ($_POST[strtolower($remap[$i]) ] != "")
{
$query = "select * from Surveys where surveylayoutid='12' and customerid='1' and (";
$clue = $_POST[strtolower($remap[$i]) ];
$query.= $remap[$i] . " like '%$clue%') order by id desc";
$query_done[] = $query;
unset($query);
$result = mysql_query($query_done[$i], $connection) or die(mysql_error());
// Display your result here
}
}
I tried changing your code abit, and it seems the result is something like this
select * from Surveys where surveylayoutid='12' and customerid='1' and (Postcode like '%Postcode%') order by id descselect * from Surveys where surveylayoutid='12' and customerid='1' and (Street like '%Street%') order by id descselect * from Surveys where surveylayoutid='12' and customerid='1' and (HouseNum like '%HouseNum%') order by id descselect * from Surveys where surveylayoutid='12' and customerid='1' and (District like '%District%') order by id descselect * from Surveys where surveylayoutid='12' and customerid='1' and (Town like '%Town%') order by id desc

Why is this PHP / mySQL query giving me an error?

I am generating the first part of the query like this:
while ($all_products = $db->fetch_array($all_prods))
{
$filter_string .= 'AND product_id !=';
$filter_string .= $all_products['item_id'];
$filter_string .= ' ';
}
and then the second part like this:
$sql_more_items = $db->query("SELECT * FROM db_products
WHERE owner_id='" . $user_id . "' AND active=1 '" . $filter_string . "'
ORDER BY RAND() LIMIT 10");
However it's giving me a mySQL syntax error and the $filter_string part strangely adds ' twice before and after the string, so it runs like this:
WHERE user_id='12345' AND active=1 'AND product_id !=0001 AND product_id !=0002 ' ORDER BY RAND ...
What am I doing wrong?
$filter_string adds ' because you put it there. :P
Try with just the double quotes around $filter_string:
$sql_more_items = $db->query("SELECT * FROM db_products WHERE owner_id='" . $user_id . "' AND active=1 " . $filter_string . "ORDER BY RAND() LIMIT 10");
$sql_more_items = $db->query("SELECT * FROM db_products
WHERE owner_id='" . $user_id . "' AND active=1 '" . $filter_string . "'
ORDER BY RAND() LIMIT 10");
Check the way you're performing a string concatenation (putting together strings). It seems like there's a copy/paste error as you're using '" instead of just a "
I would use whitespace (and a good code editor) to your advantage by reformatting your code to look like this:
$queryString = "SELECT * FROM db_products WHERE owner_id='$user_id'"
." AND active=1 " //Note these
. $filter_string //are separated
. "ORDER BY RAND() LIMIT 10 "; //into individual lines
$sql_more_items = $db->query($queryString);
This style helps you keep track of whether you're using " or ' for your strings and also helps you debug things more easily than putting it into one giant hard to read string.
That's probably because of the part
`"' AND active=1 '"`
^.... This ' here

jQuery and php. mysql error

My code loads with the following text on top of it:
"Problem with SQL: SELECT * FROM table WHERE id < ORDER BY id DESC LIMIT 5"
Could someone help me find a solution?
Thanks
//jQuery
var value = '3';
$.post("load.php", {number: value} ,function(data){
$('p').append(data);
});
$('p').load('load.php');
//PHP load.php
//I have the escape inside $db.
$random = $_POST['number'];
$db->query('SELECT * FROM table WHERE id <' . '$random' . 'ORDER BY id DESC LIMIT 1');
$result = $db->get();
foreach ($result as $key => $value){
echo $value['user'];
};
//Output
Problem with SQL: SELECT * FROM table WHERE id < ORDER BY id DESC LIMIT 5
$value['user']
Try changing it to this one:
$db->query("SELECT * FROM table WHERE id < " . $random . " ORDER BY id DESC LIMIT 1");
Better use double instead of single quotes.
The reason this is not working is because single quotes does not allow PHP to expand the variable value.
So instead of this:
$db->query('SELECT * FROM table WHERE id <' . '$random' . 'ORDER BY id DESC LIMIT 1');
You might do this:
$db->query('SELECT * FROM table WHERE id <' . $random . ' ORDER BY id DESC LIMIT 1');
Just remove the quotes in $random and you'll be well.

Select name from database by first character only

I want to be able to find all the names in a database by its first character. For example:
$sql="SELECT name LEFT(".$_GET['abc'].",1) from `users` ORDER BY `id` LIMIT 20";
$res=mysql_query($sql) or die(mysql_error());
And output:
Letter: C
Names: Craig, Chris, Chad, etc.
I feel as if it's simple and for some reason I can't find it on Google. I also don't want to use LIKE, as I need it to be only the first character.
use this :
SELECT name FROM `users` WHERE name LIKE 'c%'
% is the "joker" in SQL... with most DBMS
You query need to be changed a bit:
$first_letter = substr($_GET['abc'], 0, 1);
$sql="SELECT name from `users` WHERE LEFT(name ,1) = '" . $first_letter . "' ORDER BY `id` LIMIT 20";
// OR SUBSTR variant
$sql="SELECT name from `users` WHERE SUBSTR(name, 1, 1) = '" . $first_letter . "' ORDER BY `id` LIMIT 20";
$res=mysql_query($sql) or die(mysql_error());

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