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My php is not responding correctly here is my HTML code
<html>
<body>
<form name="myform" method="post" action="lol.php">
<input type="text" name="man" value="">
<input type="submit" name="submit" value= "post">
</form>
</body>
</html>
Here is my PHP code
<?php
if ($_POST['man']= null )
{print ('has no value');}
else {print ($_POST['man']);
}
?>
use == operator for comparison instead of = because the second one is for assignment.
if ($_POST['man']== null )
{
print ('has no value');}
else {
print ($_POST['man']);
}
See PHP Comparison Operators
Change
if ($_POST['man']= null )
to
if ($_POST['man'] == null )
You are receiving any error?
Try:
if (isset($_POST['man'])) {
echo $_POST['man'];
}
else {
echo 'Nothing';
}
And to confirm everything is working use this:
var_dump($_POST);
The you will see the values on $_POST
At First, you should use isset instead of =, second and very important: = is an assignment, but what you want is an comparison, so use == and compare against an empty string
Related
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How to print all even numbers between two input values typed by user. please write code hint only in php.
I can give you a hint. Lookup the modulo operator. With it you can do something like this:
<?php
if (($number % 2) === 1)
{
echo "$number is odd.";
}
if (($number % 2) === 0)
{
echo "$number is even." ;
}
?>
Also. Have a look at how you ask questions on stack overflow. Or they will prevent you from asking questions in the future if you don't adhere to those rules.
use this code, for user input i have created a form.
<html>
<body>
<form method="post">
<input type="number" name="num1">
<input type="number" name="num2">
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
<?php
if(isset($_POST['submit'])){
$num1 = $_POST['num1'];
$num2 = $_POST['num2'];
// while loop that will print number
while($num1 <= $num2){
// here is the condition to check the EVEN number
if($num1%2!==0){
echo $num1."<br>";
}
// increasing the loope counter by 1
$num1++;
}
}
?>
i hope now your problem has been solved..
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I'm writing a php program that will convert user input to a string and count the times each character is used, eventually for each word. Does anyone know how to convert the post data to a string? I was looking at implode and count_chars, but implode isn't converting to string like expected. I'm not sure how to show the error that it is encountering to give more information. I'm running it and writing it in phpFiddle. I'm not sure how to run it elsewhere. Please give info on what could be wrong with implode, how to show errors in phpFiddle, or run this in a browser without phpFiddle.
<?php
echo $_POST['value'];
$post_string = implode($_POST);
foreach (count_chars($post_string, 1) as $i => $val) {
echo "there were $val instances of \"", chr($i) , "\" in the string. \n";
}
?>
<form method="post" action="">
<input type="text" name="value">
<input type="submit">
</form>
This might be what you are looking for....
implode("", $_POST)
Imploding PHP Arrays usually requires two arguments, delimiter, and array.
To convert the $_POST array into a string, you should be able to implode it using;
implode('', $_POST);
I hope this is what you are looking for.
<?php
if (isset ($_POST['value'])) {
echo $_POST['value'] . "<br>";
}
$post_string = implode("", $_POST);
foreach (count_chars($post_string, 1) as $i => $val) {
echo "There were $val instances of \"", chr($i) , "\" in the string. <br>";
}
?>
<form method="post" action="">
<input type="text" name="value">
<input type="submit">
</form>
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my question is how to make button disabled?
I have two buttons on/off,i had already stored as off in table..when the users wants him to update the table,the webpage will display as the disabled button of off button.
If you are fetching data using query you can achieve this as like
<input type='button' value='button' <?php if($data === "off"){echo "disabled";}/>
Try the code:
<?php
$db_value = true or false; // put your database retrieved value here
if($db_value == true ):
echo '<button type="button" name ="myButton" disabled>OFF</button>';
else:
echo '<button type="button" name ="myButton">ON</button>';
endif;
?>
'Try something like this:
<?php
$x=1; //says "on" is 1 and "off" is 0 in your database value.here you can check your database value and apply condition accordingly
if($x==1) {
$disabled="disabled=true";
} else {
$disabled="";
}
echo '<input type="button" name="button" value="button" '.$disabled.'>';
?>
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This is my HTML Code
<input type="checkbox" value="fotoğraf" name="materyal[]"> Fotoğraf
<input type="checkbox" value="resim" name="materyal[]">Resim
<input type="checkbox" value="çizelge" name="materyal[]">Çizelge
<input type="checkbox" value="katlanabilir harita" name="materyal[]"> Katlanabilir Harita
There are checkbox and i'll take values with $_POST['materyal'] and then i want to write screen values with comma if values more than one. if checkbox values empty i don't write anything screen.
if (isset($_POST['materyal']) && !empty($_POST['materyal'])) {
$materyal = $_POST['materyal'];
echo "İçerdiği extra materyaller ; ";
foreach ($materyal as $materyallist) {
foreach ($materyallist as $yenimateryal){
array_push($sonmateryal, $yenimateryal);
}
}
echo implode(", ", $sonmateryal);
}
This is my code. when i want to use implode in if contiditon, I take mistake.
How can i do
It seems like you just want to show the contents?
$sonmateryal = array();
if (isset($_POST['materyal']) && !empty($_POST['materyal'])) {
echo "İçerdiği extra materyaller ; ";
foreach ($_POST['materyal'] as $materyallist) {
foreach ($materyallist as $yenimateryal) {
$sonmateryal[] = $yenimateryal;
}
}
}
echo implode(", ", $sonmateryal);
update according to given HTML
if (!empty($_POST['materyal'])) {
echo "İçerdiği extra materyaller ; ".htmlentities(implode(',', $_POST['materyal']));
}
Since you're posting the inputs as simple array's this will implode the results with a comma if the post-ed value isn't empty..
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I have a special form I have been making that uses some cusotm post types in wordpress. At one point I need to echo a variable $i into an if statement.
There is some validation stuff at the top that will look like this and the code in the loop is below. Pretty much I have been trying to get the majorCause1Error to be majorCause $i Error if you know what I mean, so all up it will be like 1-13
Edit: Sorry If it is hard to see what I am asking, I am finding it really hard to word my problem.
So there is a loop running around the li tags and it echos $i into the name etc so it becomes majorCause1 then next one majorCause2 and the next one magjorCause3 etc etc
Under the labels there is an if statement that is like - if($majorCause1Error !='') { do something } - I want this to be like if($majorCause1Error !=''){} and then the next one be like if($majorCause2Error !=''){} and then if($majorCause3Error !=''){}
Does this make more sense?
Here is a link to the site http://www.foresightaus.com.au/form/
if(trim($_POST['majorCause1']) === '') {
$majorCause1Error = "Please enter a major cause.";
$hasError = true;
} else {
$majorCause1 = trim($_POST['majorCause1']);
}
if(trim($_POST['majorCause2']) === '') {
$majorCause2Error = "Please enter a major cause.";
$hasError = true;
} else {
$majorCause2 = trim($_POST['majorCause2']);
}
<li class="fill-in">
<label for="majorCause<?php echo($i); ?>"><?php echo($j); ?>. State one major cause:</label>
<input type="text" name="majorCause<?php echo($i); ?>" id="majorCause<?php echo($i); ?>" value=""/>
<?php if($majorCause1Error != '') { ?>
<span class="error"><?=$majorCause1Error;?></span>
<?php } ?>
</li>
You probably want to be using an array but what you are referencing is called a variable variable and is supported by PHP!
Something like this should do it
${"majorCause{$i}Error"}