I have a radiobutton list in yii php,but I don't know how to access the value from this it doesn't contain any name or identity
<?php
echo $form->radioButtonList($model,'priority',
array('C'=>'CRITICAL','H'=>'HIGH','L'=>'LOW')
array('separator'=>''));
?>
Please help me to sort out this. thanks
you need to do this to see the value
<?php echo $form->error($model, 'priority'); ?>
For your help
When you use the form builder in Yii it sets the names and ids in a certain way. Lets say your $model is an instance of User, in this case your html name attribute would be User[priority] and can be accessed as $_POST['User']['priority']. The html id attribute doesn't use arrays so it is User_priority. So one of the radio buttons would look like this:
<input type='radio' name='User[priority]' id='User_priority' value='C'> CRITICAL
You can always look at the html source code generated to see this.
Related
I have a text box which extracts the content of dropdownlist.Now whenever i extract the content i too need to edit it ana save it into the database.How can i do????
Here is my code:
<?php
require'conn.php';
$select_query="Select dynamictext from tbl_content where type=1";
$select_query_run =mysql_query($select_query);
echo'Dynamictext:';
echo "<select name='dynamic text' id='names' >";
while ($select_query_array= mysql_fetch_array($select_query_run) )
{
$value=$select_query_array["dynamictext"];
echo "<option value='$value' >".htmlspecialchars($select_query_array["dynamictext"])."</option>";
}
echo "</select>";
?>
Based on the clarification I got above from #krisha above, I'm going to take a stab at answering this. You'll want to refer to my comment above, for a definition of (Option A) and (Option B), as I defined them.
Let's assume you've got (Option A) working and that (as far as the select HTML element is concerned), it is functional.
Let's also assume that you know to do the following:
Place the select tag inside of a form tag.
Set the form tag's action and method values.
Place a <input type="submit" value="Submit"> inside of the form tag.
If none of the above made sense, see here.
Once you've done everything above, that will result in the value of the HTML drop-down being available to PHP after the user clicks the Submit button and the page refreshes. How the value of the drop-down is passed through the submit process will depend on the method value you pass to the form tag. I'll assume you use method="get" (which will result in the value of the drop-down appearing in the URL after the refresh). If you want more info on get versus post, see here.
Once the refresh occurs, you use PHP's $_GET[""] to retrieve the value of the HTML drop-down. In your case, you would use $_GET["dynamic text"] (since the name of your select is dynamic text). You could set this value to a variable, like so:
$value_of_select = $_GET["dynamic text"];
At this point, you have the value the user selected from the HTML drop-down. Now, push it to the database. It looks like you already understand how to pass queries to a database. The only difference in this case is that you want to do an insert or an update, not a select.
I have an input box in index.php which takes some user input and queries a database using that input field as an attribute. This input is stored in $arrInput[0].
I also have a link to inspect.php which, when clicked, takes me to inspect.php but I need to pass $resultArr[0] to inspect.php so that I can use that variable to continue doing other things within inspect.php. How can I achieve this? \
Currently this is what I have:
/* inspect.php */
// Create a table with some rows. Then create this
// column which has the inspect link
echo "<td> <a href='inspect.php?id=<?php echo $resultArr[0]; ?>'>Inspect</a>
</td>";
...
But I don't know how to access $resultArr[0] within inspect.php. I was told $_GET[] would help, but I'm not sure how and googling the subject hasn't been much help.
Can anyone please help?
Thank you
echo "<td><a href='inspect.php?id=".$resultArr[0]."'>Inspect</a></td>";
I think you are using wrong syntax. Please check above code. You can the access 'id' key inside $_GET.
Not that hard. use $_GET['id'].
I want to use a JQuery "check all" function in a form like this:
http://jetlogs.org/jquery/jquery_select_all.html
My problem is I am generating my form from a php script, and I don't know exactly how many checkboxes I will have in advance.
I use the "array" naming convention to be able to get all the selected checkbox values in my $_POST data...
so my checkboxes are like that:
<input type="checkbox" name="items[]" value="<?php echo $id ?>">
but this JQuery declaration does not work:
$("input[#name=items[]]").each(function()
{
this.checked = checked_status;
});
probably because the "[]" at the end of my "items" messes up the JQuery declaration... I tried to write #name=items[] like that: "#name=items[]", and to put some anti-slash before the [ and ] so they're not considered as special characters but it didnt work...
If someone knows a solution and is willing to share it'd be great!! :)
Escape internal brackets with \\(no space) - it should fix the problem.
This selector works for me:
$('input[name=items\\[\\]]')
Try using
$('input[name="items[]"]')
No need for # and use ". Note that the selector outside quotes are '. Otherwise you might cause parse error.
First of all, your name attribute should be used to set +1 elements with the same name. It's practically the same as the id attribute and should be unique per element excepted for references, but that is not the case for you.
Try using the class attribute, it's made for the things you want to do!
another thing is that in your code, you can only set your checkboxes to 'checked', but never to uncheck, this code will set your checkboxes to checked true or false, according to what it gets as attribute from the clicked element.
you can do something like this:
set your check all checkbox with an id
<input type="checkbox" id="checkAll">
Then set on all checkboxes that should be checked/unchecked a class
<input type="checkbox" class="checked">
And the you can do something like this in jQuery
$("#checkAll").click( function(){
var checkedValue = $(this).attr("checked");
$("input.checked").attr("checked", checkedValue); });
this will change all checkboxes with class checked to the same checked attribute as the one with id checkAll
$("input[name='smsid[]']")
This code works fine for me...
I have web page in PHP which displays all records in a table. I want to add check boxes against all rows and user can check a check box to select a row and then submit the page. When the page is submitted I want to enumerate all check boxes and check whether they are checked or not, How can I do this?
You'll create your checkboxes like this:
<input name="rows[]" value="uniqueIdForThisRow" type="checkbox" />
<input name="rows[]" value="anotherId" type="checkbox" />
Then you can loop through them like this:
<?php
// $_POST['rows'] contains the values of all checked checkboxes, like:
// array('uniqueIdForThisRow', 'anotherId', ...)
foreach ($_POST['rows'] as $row) {
if ($row == 'uniqueIdForThisRow') {
// do something
}
}
?>
PHP docs on dealing with forms, see especially Example #3.
Creating the form
You can generate the HTML as follows:
<form [action, method etc]>
<table>
<?php
foreach($dataSet as $dataRow) :
?>
<tr>
<td>
<input type="checkbox" name="dataRow[]" value="<?=$dataRow['id']?>"/>
</td>
[Additional details about datarow here]
<tr>
<?php
endforeach;
?>
</table>
</form>
AFTER POST
look into $_POST['dataRow'] : this will be an array with values the IDS of your $dataRow, so using array_values on $_POST['dataRow'] will give you all the ids of the selected rows:
<?php
$checkedRows = array_values($_POST['dataRow']);
foreach($checkedRows as $row) {
// Do whatever you want to do with the selected row
}
You don’t have to check all checkboxes if they have been checked. Because only successful controls are send to the server. And a checkbox is only successful when it’s checked:
Checkboxes (and radio buttons) are on/off switches that may be toggled by the user. A switch is "on" when the control element's checked attribute is set. When a form is submitted, only "on" checkbox controls can become successful.
So you just have to look what checkboxes you get in the request at all. And if you want to use <select multiple>, take a look at How do I get all the results from a select multiple HTML tag? in the PHP FAQ.
if i were you... i wouldn't fight with altering html table structure.
you can handle that with Javascript frameworks like JQuery which is very effective solution for you. you deal only a few lines of JS code and you don't need exaggerate the html output (i guess it's probably long enough). about jquery there is a good source named visual jquery if you have never used that.
here is the way how to do that.
you dont need to edit inside the loop. you just only put an id to your table tag.
then add new column to your table with checkboxes inside.
then you can get the values of checkboxes & serialize them in to a hidden input. or you can handle selected rows with ajax easy. i think JS framework will work better.
normally i've added many links to post but it says it's not allowed for new users.
I have a database which holds the residents of each house in a certain street. I have a 'house view' php web page which can display an individual house and residents when given the house number using 'post'. I also have a 'street view' web page which gives a list of houses. What I want to know is if you can have links on the street view which will link to the house view and post the house number at the same time without setting up a form for each?
Regards
If you want to pass the data using POST instead of GET, you can do it using a combination of PHP and JavaScript, like this:
function formSubmit(house_number)
{
document.forms[0].house_number.value = house_number;
document.forms[0].submit();
}
Then in PHP you loop through the house-numbers, and create links to the JavaScript function, like this:
<form action="house.php" method="POST">
<input type="hidden" name="house_number" value="-1">
<?php
foreach ($houses as $id => name)
{
echo "$name\n";
}
?>
</form>
That way you just have one form whose hidden variable(s) get modified according to which link you click on. Then JavaScript submits the form.
I assume that each house is stored in its own table and has an 'id' field, e.g house id. So when you loop through the houses and display them, you could do something like this:
<a href="house.php?id=<?php echo $house_id;?>">
<?php echo $house_name;?>
</a>
Then in house.php, you would get the house id using $_GET['id'], validate it using is_numeric() and then display its info.
You cannot make POST HTTP Requests by some_script
Just open your house.php, find in it where you have $house = $_POST['houseVar'] and change it to:
isset($_POST['houseVar']) ? $house = $_POST['houseVar'] : $house = $_GET['houseVar']
And in the streeview.php make links like that:
Or something else. I just don't know your files and what inside it.
This is an old thread but just in case anyone does come across i think the most direct solution is to use CSS to make a traditional form look like an anchor-link.
#ben is correct you can use php and javascript to send a post with a link, but lets ask what the js does -- essentially it creates a form with style='display:none' sets an input/text line with value='something' and then submits it.
however you can skip all this by making a form. setting style='display:none' on the input/text lines (not the form itself as above) and then using CSS to make the button look like a normal link.
here is an example is i use:
in PHP Class,
public function styleButton($style,$text){
$html_str = "<form id='view_form' action='".$_SERVER['REQUEST_URI']."' method='post' >";
$html_str .= "<input style='display:none;' name='list_style' type='text' value='".$style."' >";
$html_str .= "<input id='view_button' type='submit' value='".$text."' >";
$html_str .= "</form>";
return $html_str;
}
Then in the CSS id="view_form" set "display:inline;"
and in the CSS id="view_button" set to something like: "background:none;border:none;color:#fff;cursor:pointer"
I would just use a value in the querystring to pass the required information to the next page.
We should make everything easier for everyone because you can simply combine JS to PHP
Combining PHP and JS is pretty easy.
$house_number = HOUSE_NUMBER;
echo "<script type='text/javascript'>document.forms[0].house_number.value = $house_number; document.forms[0].submit();</script>";
Or a somewhat safer way
$house_number = HOUSE_NUMBER;
echo "<script type='text/javascript'>document.forms[0].house_number.value = " . $house_number . "; document.forms[0].submit();</script>";
This post was helpful for my project hence I thought of sharing my experience as well.
The essential thing to note is that the POST request is possible only with a form.
I had a similar requirement as I was trying to render a page with ejs. I needed to render a navigation with a list of items that would essentially be hyperlinks and when user selects any one of them, the server responds with appropriate information.
so I basically created each of the navigation items as a form using a loop as follows:
<ul>
begin loop...
<li>
<form action="/" method="post">
<input type="hidden" name="country" value="India"/>
<button type="submit" name="button">India</button>
</form>
</li>
end loop.
</ul>
what it did is to create a form with hidden input with a value assigned same as the text on the button.
So the end user will see only text from the button and when clicked, will send a post request to the server.
Note that the value parameter of the input box and the Button text are exactly same and were values passed using ejs that I have not shown in this example above to keep the code simple.
here is a screen shot of the navigation...
enter image description here