JSON url field is not correctly displaying - php

Question

So this is where to view my json file: http://alyssayango.x10.mx/
this is my php file for that:
<?php
include('connectdb.php');
$sql = "SELECT * FROM tblmovies ORDER BY _id";
$result = mysql_query($sql);
if($result === FALSE) {
die(mysql_error()); // TODO: better error handling
}
$set = array();
while($row1 = mysql_fetch_assoc($result)) {
$set[] = $row1;
}
echo json_encode($set);
and the output is:
[{"_id":"3","movie_name":"Despicable Me 2","movie_cinema_number":"CINEMA 1","movie_length":"1hr. 40mins.","movie_type":"GP","movie_schedules":"12:10 PM | 02:25 PM | 04:40 PM","movie_image_url":"http:\/\/i39.tinypic.com\/szizo4.jpg"},{"_id":"4","movie_name":"White House Down","movie_cinema_number":"CINEMA 2","movie_length":"2 hrs. 10 mins.","movie_type":"PG-13","movie_schedules":"12:30 PM | 03:20 PM | 06:10 PM","movie_image_url":"http:\/\/i39.tinypic.com\/vp9n9j.jpg"},{"_id":"5","movie_name":"My Lady Boss","movie_cinema_number":"CINEMA 3","movie_length":"1hr. 50 mins.","movie_type":"PG-13","movie_schedules":"01:00 PM | 03:30 PM | 06:00 PM","movie_image_url":"http:\/\/i44.tinypic.com\/2qlv08z.jpg"},{"_id":"6","movie_name":"Four Sisters And A Wedding","movie_cinema_number":"CINEMA 4","movie_length":"2 hrs. 5 mins. ","movie_type":"PG-13","movie_schedules":"12:30 PM | 03:10 PM | 05:50 PM","movie_image_url":"http:\/\/i44.tinypic.com\/9iv0d1.jpg"}]
what seems to be wrong that I do in here? URL is displayed as: http:\ /\ /i44.tinypic.com\ /9iv0d1.jpg where it should be http://i44.tinypic.com/9iv0d1.jpg

Answer 1

The JSON format is often used for serializing and transmitting structured data over a network connection. It is used primarily to transmit data between a server and web application, serving as an alternative to XML.
If you create an API that should be:
$array = array("title" => "TEST", "username" => "test"); // Creating a array
echo json_encode($array); // Printing json
Client want to request and get response:
$json = file_get_contents('http://www.example.com/test/films.json'); // Your url
$array = json_decode($json); // Your first array its here!
More: http://en.wikipedia.org/wiki/JSON
Warning: You can't edit or tidy your json response! It is good!

Answer 2

The problem does not exists, actually.
What you're doing wrong is that you're using a piece of your JSON string without decoding it beforehand. Just use json_decode(..) if you're within PHP or the equivalent javascript function to decode JSON.
Once you did that, you'll have an object / an array which contains the data in the correct form.