I have ran into a problem.
I want to replace only the part in parenthesis, but the problem is if the value in parenthesis is 1 or something else in the same part ([x(xxx:x:x)xx];), it will end up replacing that also, which I need the x(value) at the end of each part.
[0(267:0:0)x1];[1(257:0:0)x1];[2(256:0:0)x1];[3(258:0:0)x1];[4(261:0:0)x1]; [5(262:0:0)x64];[6(320:0:0)x10];[7(17:0:0)x32];[8(295:0:0)x2];[9(35:0:0)x2];[10(44:1:1)x6];[11(0:0:0)x1];[12(0:0:0)x1];[13(0:0:0)x1];[14(0:0:0)x1];[15(0:0:0)x1];[16(0:0:0)x1];[17(0:0:0)x1];[18(0:0:0)x1];[19(0:0:0)x1];[20(0:0:0)x1];[21(0:0:0)x1];[22(0:0:0)x1];[23(0:0:0)x1];[24(0:0:0)x1];[25(0:0:0)x1];[26(0:0:0)x1];[27(0:0:0)x1];[28(0:0:0)x1];[29(0:0:0)x1];[30(0:0:0)x1];[31(0:0:0)x1];[32(0:0:0)x1];[33(0:0:0)x1];[34(0:0:0)x1];[35(0:0:0)x1];[103(0:0:0)x1];[102(0:0:0)x1];[101(0:0:0)x1];[100(0:0:0)x1];
I cannot get this working. If I try to replace a 1 value in the part in parenthesis, it ends up changing all of the 1's on the printed part.
Also keep in mind that the zero's in the parenthesis won't always be 0's.
Here's what I tried:
$items = $row['inventory'];
$test = str_replace('267', '<img href="../assets/images/items/iron_sword.png">', $items);
echo $items;
I only tried one line of code to see how it would work.
I'm trying to replace the part in parenthesis with an image (for example, the first one is [0(267:0:0)x1];. I want to replace (267:0:0) with an image...
If you want to replace all (*:*:*) pattern with the same image, you cant try preg_replace:
$str = "[0(267:0:0)x1];[1(257:0:0)x1];[2(256:0:0)x1];[3(258:0:0)x1];[4(261:0:0)x1];";
$res = preg_replace("/\(\d+\:\d+\:\d+\)/",'<img href="../assets/images/items/iron_sword.png">', $str);
You can see the result here: http://codepad.org/UIjGKv6n
If you want to replace different item with different image, then you need an translate map like this:
$from = array(
'(267:0:0)',
'(257:0:0)',
...
);
$to = array(
'<img href="../assets/images/items/iron_sword.png">',
'<img href="../assets/images/items/other.png">',
...
);
$res = str_replace($from, $to, $str);
And if you have other requirements, you can just modify the code as you need.
Related
So I need to re-write some old code that I found on a library.
$text = preg_replace("/(<\/?)(\w+)([^>]*>)/e",
"'\\1'.strtolower('\\2').'\\3'", $text);
$text = preg_replace("/<br[ \/]*>\s*/","\n",$text);
$text = preg_replace("/(^[\r\n]*|[\r\n]+)[\s\t]*[\r\n]+/", "\n",
$text);
And for the first one I have tried like this:
$text = preg_replace_callback(
"/(<\/?)(\w+)([^>]*>)/",
function($subs) {
return strtolower($subs[0]);
},
$text);
I'm a bit confused b/c I don't understand this part: "'\\1'.strtolower('\\2').'\\3'" so I'm not sure what should I replace it with.
As far as I understand the first line looks for tags, and makes them lowercase in case I have data like
<B>FOO</B>
Can you guys help me out here with a clarification, and If my code is done properly?
The $subs is an array that contains the whole value in the first item and captured texts in the subsequent items. So, Group 1 is in $subs[1], Group 2 value is in $subs[2], etc. The $subs[0] contains the whole match value, and you applied strtolower to it, but the original code left the Group 3 value (captured with ([^>]*>) that may also contain uppercase letters) intact.
Use
$text = preg_replace_callback("~(</?)(\w+)([^>]*>)~", function($subs) {
return $subs[1] . strtolower($subs[2]) . $subs[3];
}, $text);
See the PHP demo.
I have URL of file which looks like this
movieImages/1`updateCategory.PNG
it should look like this
updateCategory.PNG
you can use like this, simple
$string = 'movieImages/1`updateCategory.PNG';
$ser = 'movieImages/1`';
$trimmed = str_replace($ser, '', $string);
echo $trimmed;
output will be updateCategory.PNG
Find the position of unwanted character and then pick up the substring after that position.
$str="movieImages/1`updateCategory.PNG";
$unwanted="`";
echo substr($str,strpos($str,$unwanted)+1);
Output
updateCategory.PNG
Fiddle
That is if the string can vary in structure and size. If the first part will always remain same you can simply remove the unwanted stuff using str_replace.
echo str_replace('movieImages/1`','',$str);
I have following issue:
I import WKT dynamicaly from DB into WKT Wicket Javascript library. I must do some substitutions to fit the WKT correctly. Since mysql fetches WKT AsText(SHAPE) i recive several arrays e.g. POLYGON((xxxx)),POLYGON((yyyy)) and so on.
First, I had to remove all "POLYGON" doing
$str = preg_replace('/^POLYGON/', '', $WKT[1]);
and add MULTIPOLYGON before <?php
tag in the wicket. It works.
Second, I must add comma between polygons, preicisely between "))((" brackets:
$str2 = str_replace(array('((', '))'), array('((', ')),'), $str);
It works but last comma remains what "slightly" deforms my multipolygon:
MULTIPOLYGON((xxx)),((yyy)),((zzz)),
How can I remove last comma?
I would be thankful for every regex or some other solution which can solve my problem.
In any string, you can remove the last X if you are sure that no X follows. So, you can use a negative lookahead: (,)(?!.*,), as seen here and replace it with empty string.
$result = preg_replace('/(,)(?!.*,)/', '', $str)
This doesn't look at the context though, it will just remove the last comma of any string, no matter where it is.
Thank you both - your answers were right and very helpful.
The problem was not string replacement. It was more the data fetching from DB.
Mysqli_fetch_array and mysqli_fetch_assoc return stringstringsring or arrayarrayarray for 3 rows fetched. That is why all commas were replaced.
I changed to mysqli_fetch_all ,then did minor replacements for each row (as array) and implode each one as variable. After i merged them into single variable, then I could apply your solutions. It is not sofisticated solution, but if it is packed into function it'll be fine.
($WKT = mysqli_fetch_all($result)) {
$str = preg_replace('/POLYGON/', '', $WKT[0]);
$str1 = preg_replace('/POLYGON/', '', $WKT[1]);
$str2 = preg_replace('/POLYGON/', '', $WKT[2]);
$str3 = implode($str);
$str4 = implode($str1);
$str5 = implode($str2);
$str6 = $str3 . $str4 . $str5;
$str7 = preg_replace('/\)\)/', ')),', $str6);
$str8 = rtrim($str7, ",");
echo $str8;
}
I am trying to use a License PHP System…
I will like to show the status of their license to the users.
The license Server gives me this:
name=Service_Name;nextduedate=2013-02-25;status=Active
I need to have separated the data like this:
$name = “Service_Name”;
$nextduedate = “2013-02-25”;
$status = “Active”;
I have 2 days tring to resolve this problem with preg_match_all but i cant :(
This is basically a query string if you replace ; with &. You can try parse_str() like this:
$string = 'name=Service_Name;nextduedate=2013-02-25;status=Active';
parse_str(str_replace(';', '&', $string));
echo $name; // Service_Name
echo $nextduedate; // 2013-02-25
echo $status; // Active
This can rather simply be solved without regex. The use of explode() will help you.
$str = "name=Service_Name;nextduedate=2013-02-25;status=Active";
$split = explode(";", $str);
$structure = array();
foreach ($split as $element) {
$element = explode("=", $element);
$$element[0] = $element[1];
}
var_dump($name);
Though I urge you to use an array instead. Far more readable than inventing variables that didn't exist and are not explicitly declared.
It sounds like you just want to break the text down into separate lines along the semicolons, add a dollar sign at the front and then add spaces and quotes. I'm not sure you can do that in one step with a regular expression (or at least I don't want to think about what that regular expression would look like), but you can do it over multiple steps.
Use preg_split() to split the string into an array along the
semicolons.
Loop over the array.
Use str_replace to replace each '=' with ' = "'.
Use string concatenation to add a $ to the front and a "; to the end of each string.
That should work, assuming your data doesn't include quotes, equal signs, semicolons, etc. within the data. If it does, you'll have to figure out the parsing rules for that.
Hopefully, this is an easy one. I have an array with lines that contain output from a CSV file. What I need to do is simply remove any commas that appear between double-quotes.
I'm stumbling through regular expressions and having trouble. Here's my sad-looking code:
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '(?<=\")/\,/(?=\")'; //this doesn't work
$revised_input = preg_replace ( $pattern , '' , $csv_input);
echo $revised_input;
//would like revised input to echo: "herp","derp,"hey get rid of these commas man",1234
?>
Thanks VERY much, everyone.
Original Answer
You can use str_getcsv() for this as it is purposely designed for process CSV strings:
$out = array();
$array = str_getcsv($csv_input);
foreach($array as $item) {
$out[] = str_replace(',', '', $item);
}
$out is now an array of elements without any commas in them, which you can then just implode as the quotes will no longer be required once the commas are removed:
$revised_input = implode(',', $out);
Update for comments
If the quotes are important to you then you can just add them back in like so:
$revised_input = '"' . implode('","', $out) . '"';
Another option is to use one of the str_putcsv() (not a standard PHP function) implementations floating about out there on the web such as this one.
This is a very naive approach that will work only if 'valid' commas are those that are between quotes with nothing else but maybe whitespace between.
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '/([^"])\,([^"])/'; //this doesn't work
$revised_input = preg_replace ( $pattern , "$1$2" , $csv_input);
echo $revised_input;
//ouput for this is: "herp","derp","hey get rid of these commas man",1234
It should def be tested more but it works in this case.
Cases where it might not work is where you don't have quotes in the string.
one,two,three,four -> onetwothreefour
EDIT : Corrected the issues with deleting spaces and neighboring letters.
Well, I haven't been lazy and written a small function to do exactly what you need:
function clean_csv_commas($csv){
$len = strlen($csv);
$inside_block = FALSE;
$out='';
for($i=0;$i<$len;$i++){
if($csv[$i]=='"'){
if($inside_block){
$inside_block=FALSE;
}else{
$inside_block=TRUE;
}
}
if($csv[$i]==',' && $inside_block){
// do nothing
}else{
$out.=$csv[$i];
}
}
return $out;
}
You might be coming at this from the wrong angle.
Instead of removing the commas from the text (presumably so you can then split the string on the commas to get the separate elements), how about writing something that works on the quotes?
Once you've found an opening quote, you can check the rest of the string; anything before the next quote is part of this element. You can add some checking here to look for escaped quotes, too, so things like:
"this is a \"quote\""
will still be read properly.
Not exactly an answer you've been looking for - But I've used it for cleaning commas in numbers in CSV.
$csv = preg_replace('%\"([^\"]*)(,)([^\"]*)\"%i','$1$3',$csv);
"3,120", 123, 345, 567 ==> 3120, 123, 345, 567