i have a simple website which is written by php code. i have a detect button on my page and given below code is writen for this function but my problem is i need a popup window when the detect link is clicked. i have tired to set a code in my created code but i am not able .kindly please help me solve this problem.
<?php
/*echo "permessi".$permessi;
echo "<br>id".$id_nome;*/
if($action=='canc'){?>
<h1>are you sure want to delect the course?</h1>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post" name="canc1" style="float: left; margin-left:25px;">
<input type="hidden" name="idcorsocanc" value="<?=$canc_id?>">
<input type="hidden" name="action" value="">
<input type="submit" name="ok" value="Si,cancella" class="puls_invia">
</form>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post" name="canc2" style="float: left; margin-left:25px;">
<input type="hidden" name="action" value="">
<input type="submit" name="ok" value="NO" class="puls_invia">
</form>
<?php
}
Try this
<script>
function open_win()
{
window.open("URL HERE")
}
</script>
<input type="button" value="Open Window" onclick="open_win()">
Related
I have an HTML input and button:
<form action="validate.php" method="post">
<!-- THE CODE INSERT -->
<div id="code">
<form>
<label></label>
<input id="input" name="InputText" type="text"/>
</form>
</div>
<!-- THE BUTTON ITSELF -->
<input type="button" id="button" name="myButton"><b>Search Archive</b>
</form>
in my validate.php file I have this switch statement:
<?php
switch ($_POST["InputText"])
{
case "someval":
http_header("someaddress.com");
die();
break;
}
?>
the problem is that when I click the button it doesn't do anything. I did this with JS and it worked but it should be noted that I'm really new to web development so if anyone can explain to me what I did wrong and specifically why that would be great. Thanks!
You have a form inside of a form, that won't work. Also, you need to include an <input type="submit" value="submit" /> before you close your form. This is what submits the information from the form to your action="file.php".
A form would typically look like this:
file.html
<form action="validate.php" method="POST">
<input type="text" name="username" placeholder="Enter your username" />
<input type="submit" name="submit" value="Submit" />
</form>
Then you'd do something like this:
validate.php
<?php
echo "Your username is" . $_POST['username'];
The $_POST['username'] is the data gathered from the name="username" input from the HTML. If you write die($_POST); you'll get all the data that is sent through the form.
When you are using type='button' you have to perform the submit by yourself.
So, you can do that using javascript or change to type='submit'.
Example:
<input type="button" id="button" name="myButton"><b>Search Archive</b>
To
<input type="submit" id="button" name="myButton" value="Search Archive" />
you can try this
<form action="/validate.php" method="post">
<!-- THE CODE INSERT -->
<div id="code">
<label></label>
<input id="input" name="InputText" type="text"/>
</div>
<!-- THE BUTTON ITSELF -->
<button type="submit" id="button" name="myButton">Search Archive</button>
</form>
in the div id ="code" you used form tag that's why its not work...delete it will work and button type must be submit
<?php
echo $_POST['textvalue'];
echo $_post['radiovalue'];
?>
<div id="hidethis">
<form method="POST" action="">
<label>Tekst Value</label>
<input type="text" name="textvalue">
<label>Radio Value</label>
<input type="radio" name="radiovalue" value="autogivevalue">
<input type="submit" id="submit" name="submit" value="submit">
</div>
http://jsfiddle.net/Bjk89/2/ here is it with the jQuery.
What i try to do is to hide the <div id="hidethis"> when it's clicking submit.
I know i can make another page where i can recieve the values without the <form> section, but i want to put both in one page, make the <div id="hidethis"> hidden after submit.
So i'll be able to get echo $_POST['textvalue']; and echo $_post['radiovalue']; as results
RESULT MUST BE LIKE
A Text // This is the value you input into Tekst Value
autogivevalue // This is the value from the radio button
----- INVISIBLE -----
<form is hidden because we set it in jQuery so>
</form>
Try this. No need to use jQuery here.
<?php
if($_POST) {
echo $_POST['textvalue'];
echo $_post['radiovalue'];
} else {
?>
<form method="POST" action="">
<label>Tekst Value</label>
<input type="text" name="textvalue">
<label>Radio Value</label>
<input type="radio" name="radiovalue" value="autogivevalue">
<input type="submit" id="submit" name="submit" value="submit">
</form>
<?php
}
?>
Try adding '#' in your jquery code. Your version does not have # next to submit. Also your form is missing a closing tag here and in your JSFiddle code.
Try this:
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(document).ready(function () {
$('#submit').click(function () {
$('form').submit();
$('#hidethis').hide();
});
});
</script>
<form method='post' id="hidethis" name='form'>
<input type="text" name="textvalue">
<input type="radio" name="radiovalue" value="1">
<input type="button" id="submit" name="submit" value="submit">
</form>
Problem: How to make an HTML Form call different php pages from the action based on what button is pushed?
The code below is the solution I have now, but I figure there must be a better way to do this then creating multiple forms on the page?
<html>
<body>
<form name="entry_form" action="entry_update_script.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="entry_id" value="">
<input type="hidden" name="entry_item_id" value="">
Truck/Railcar/Barge#:<input type="text" name="pro_number" value=""><br>
BOL #:<input type="text" name="bol" value=""><br>
<input type="submit" name="entry_submit" value="Add New Entry!">
</form>
<form name="entry_form_add" action="entry_view.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="entry_id" value="">
<input type="submit" name="submit" value="Add New Item!">
</form>
</body>
</html>
<html>
<body>
<script type="text/javascript">
function submitAction(act) {
document.sample.action = act;
document.sample.submit();
}
</script>
<form name ="sample" action="default.php">
<input type="button" value = "blah1" onClick="submitAction('phpPage1.php')">
<input type="button" value = "blah2" onClick="submitAction('phpPage2.php')">
</form>
</body>
</html>
you might choose the page to go from a dispatcher, it's an extensible and robust solution:
your form
<form action="dispatcher.php" method="POST">
<input type="radio" name="myOption" value="register" />
<input type="radio" name="myOption" value="login" />
</form>
dispatcher.php
$actions = array ('register', 'login');
// validate possible actions
if (in_array($_POST['myOption']), $actions)) {
include ($_POST['myOption'] . '.php');
}
Hi having a problem with this code even if i clicked on cancel it will still proceed to use the action of my form even though the CANCEL button is not part of the form, Would appreciate any help.
Here is the code.
<form method="post" action="input_enroll.php" >
<div id="overlay1">
<div>
<h1> Enter Educational Level Entry</h1>
<input type="text" name="level" >
<input type="submit" value="Proceed To Enroll" '>
</form>
<input type="submit" value="Cancel" onclick='overlay()'>
</div>
</div>
EDIT: Any suggestions what would be a better idea? I'm thinking putting the cancel outside the div.
You are having form started, then divs started, then form closed..start form after divs..
as your markup is not correct, browsers will change it as thier parser suggest,
In chrome </form> tag is postponed after </div>s..
<div id="overlay1">
<div>
<form method="post" action="input_enroll.php" >
<h1> Enter Educational Level Entry</h1>
<input type="text" name="level" />
<input type="submit" value="Proceed To Enroll" />
</form>
<input type="submit" value="Cancel" onclick='overlay()' />
</div>
</div>
<form action="here.php" method="POST">
<input type="text" name="text">
<div id="one">
<input type="hidden" name="aaa" value="one">
<input type="submit" value="Send">
</div>
<div id="two">
<input type="hidden" name="aaa" value="two">
<input type="submit" value="Send">
</div>
</form>
Now if i click on Send of div ONE or div TWO i have always in $_POST['aaa'] = 'two';
Is possible make one form with two submit with different values?
If i click on div one submit i would like reveice $_POST['aaa'] = 'one' and if i click on div two submit i would like receive $_POST['aaa'] = 'two'.
How can i make it?
I can use for this PHP and jQuery.
EDIT:
I dont want create two form - i dont want showing two many times <input type="text" name="text">
EDIT: maybe i can instead button submit ? but how?
It seems that what you actually want to do is have a value in each of the buttons, see this, for example:
<form action="demo_form.asp" method="get">
Choose your favorite subject:
<button name="subject" type="submit" value="fav_HTML">HTML</button>
<button name="subject" type="submit" value="fav_CSS">CSS</button>
</form>
You'd need two different forms:
<div id="one">
<form ...>
<input type="hidden" name="aaa" value="one">
<input type="submit" value="Send">
</form>
</div>
<div id="two">
<form ...>
<input ...>
<input ...>
</form>
</div>
Standard practice is that when two fields have the exact same name, to use only the LAST value encountered in the form and submit that.
PHP does have a special-case notation (name="aaa[]") to allow submitting multiple values with the same name, but that wouldn't help you here, as that'd submit ALL of the aaa values, not just the one closest to the submit button.
HTML form:
<form ...>
<input type="text" name="textfield">
<div id="one">
<input type="hidden" name="one_data" value="aaa" />
<input type="submit" name="submit_one" value="Submit" />
</div>
<div id="two">
<input type="hidden" name="two_data" value="bbb" />
<input type="submit" name="submit_two" value="Submit" />
</div>
</form>
server-side:
if (isset($_POST['submit_two'])) {
$data = $_POST['two_data'];
} else if (isset($_POST['submit_one'])) {
$data = $_POST['one_data'];
} else {
die("Invalid submission");
}
Instead of showing two submit button, you can show a radio list with two options and one submit button.
Try this:
in html-
<input id="PreviousButton" value="Previous" type="submit" />
<input id="NextButton" value="Next" type="submit" />
<input id="Button" name="btnSubmit" type="hidden" />
in jOuery-
$("#PreviousButton").click(function () {
$("#Button").val("Previous");
});
$("#NextButton").click(function () {
$("#Button").val("Next");
});
then you can see in the form results - what "Button" contains.