codeigniter view won't show up from passing javascript/ajax parameter - php

Question

I'm integrating codeigniter with phpgrid, and I'm having a trouble with passing the row values from phpgrid (in VIEW A) to another view (VIEW B) through javascript and codeigniter controllers
I have a virtual column like this in PHPGRID (VIEW A):
$col_formatter = <<<COLFORMATTER
function(cellvalue, options, rowObject, rowid){
var sessid = rowObject[0];
return '<input type="button" value="View" onclick="btnView('+sessid+')">';
}
COLFORMATTER;
and the javascript in VIEW A:
function btnView(sessid){
var dataRow = {
sessid:sessid,
};
$.ajax({
type:"POST",
url: "<?php echo base_url()."index.php/main/tes"; ?>",
data: dataRow,
success: function(msg){
}
});
return false;
}
in the Codeigniter CONTROLLERS:
public function tes(){
$data['sessid'] = $_POST['sessid'];
$this->load->view('view_b', $data);
}
I can't seem to load the view. I used Mozilla's Firebug to know the response, it's true that the response is the code of my view_b view, but how can I switch to that view?

Answer 1

//Your are using ajax for some operation and want to reload the view page the you can test these options:
1) take a div in current view page and assing ajax retrun message to that div
function btnView(sessid){
var dataRow = {
sessid:sessid,
};
$.ajax({
type:"POST",
url: "<?php echo base_url()."index.php/main/tes"; ?>",
data: dataRow,
success: function(msg){
$("#divid").html(msg);
}
});
return false;
}
//Or 2)just redirect to your view page again
function btnView(sessid){
var dataRow = {
sessid:sessid,
};
$.ajax({
type:"POST",
url: "<?php echo base_url()."index.php/main/tes"; ?>",
data: dataRow,
success: function(msg){
window.location.href=path to your view page;//<?php echo base_url()."index.php/controller/function"; ?>
}
});
return false;
}

Answer 2

If I understand correctly you want to go from VIEW A to VIEW B (meaning an actual change in the window location) and pass a value to VIEW B so it can generate some dynamic content. Well, AJAX is not the solution here since it will not trigger a change of page but instead will return the markup/text of the response as a string.
But there are still a number of ways you can achieve what you want, using Codeigniter the simpler way would be to use an argument for your controller method that you can send as part of the uri in a link:
HTML
View
Since you're using Javascript to generate the markup you would need something like this
return 'View';
*Note that you will now have a link instead of a button but you can use CSS to style it any way you want it.
You would now retrieve the value in your controller like this:
PHP
public function tes($sessid){
$data['sessid'] = $sessid;
$this->load->view('view_b', $data);
}
Pretty simple. A second option will be to use a form instead of your button to send the value using either GET or POST, forms do trigger a change in page whenever they are submitted:
HTML
<form action="http://example.com/index.php/main/tes" method="get">
<input type="submit" value="{ssid}" name="sessid" />
</form>
Again using javascript:
return '<form action="<?php echo site_url('main/tes')?>" method="get">'
+'<input type="submit" value="'+sessid+'" name="sessid" />'
+'</form>';
And to get the value in your controller:
PHP
public function tes(){
$data['sessid'] = $_GET['sessid']; //OR $_POST['sessid']
$this->load->view('view_b', $data);
}

Answer 3

Turns out that passing a variable from javascript to codeigniter controller is just:
function btnView(sessid){
window.location = "printvo/"+sessid;
}
I was using ajax because I don't know how to pass the variable, I always thought that passing variable is using brackets: window.location = "printvo("+sessid+")"; and that didn't work.