Passing PHP select elements into a url - php

Question

Ok so I have a simple php select script and I have the code below to define variables.
$result = mysqli_query($con,"SELECT * FROM practice_sheets WHERE student_name='$_SESSION[SESS_FIRST_NAME] $_SESSION[SESS_LAST_NAME]'");
$numrows = mysqli_num_rows($result);
$id = $row['id'];
$total_min = $row['total_min'];
$due_date = $row['due_date'];
I then have:
echo "<td> <a href='account/practiceSheets?id='$id'> <i class='icon-eye-open'> </i> </a> </td>";
and this is supposed to pass the variables from the php select script into the url when the <a> is clicked.
All I end up with is the account/practiceSheets?id= with no actual id. I'm sure this is something stupidly simple and I do apologize as I am new to PHP and also didn't know what to call this to get a useable result in search engines! My full code is below if it helps.
<?php
$con = mysqli_connect("50.63.106.47", "usd309bands", "MacBook1!", "usd309bands");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con, "SELECT * FROM practice_sheets
WHERE student_name='$_SESSION[SESS_FIRST_NAME] $_SESSION[SESS_LAST_NAME]'");
$numrows = mysqli_num_rows($result);
$id = $row['id'];
$total_min = $row['total_min'];
$due_date = $row['due_date'];
if ($numrows == 0) {
echo "<div class='alert alert-danger'>";
echo "No Entries, See your instructor for details.";
echo "</div>";
} else {
echo "<table class='mws-table table-striped table-hover'>";
echo "<thead align='center'>";
echo "<tr>";
echo "<th>Sheet Number</th>";
echo "<th>Total Minutes</th>";
echo "<th>Due Date</th>";
echo "<th>View</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody align='center'>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['total_min'] . "</td>";
echo "<td>" . $row['due_date'] . "</td>";
echo "<td> <a href='account/practiceSheets?id='$id'> <i class='icon-eye-open'> </i> </a> </td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
mysqli_close($con);
}
?>

Answer 1

$result = mysqli_query($con,"SELECT * FROM practice_sheets
WHERE student_name='$_SESSION[SESS_FIRST_NAME] $_SESSION[SESS_LAST_NAME]'");
$numrows = mysqli_num_rows($result);
$id = $row['id'];
Can't see the where the $row is coming from.
I think you've forgotten to fetch the MySQL response into an associated array.
(You could use mysqli_fetch_assoc() to acomplish that)
Here's a quick example:
$result = mysqli_query($con,"SELECT * FROM practice_sheets WHERE student_name='$_SESSION[SESS_FIRST_NAME] $_SESSION[SESS_LAST_NAME]'");
$allRows = mysqli_fetch_assoc($result);
foreach($allRows as $row) {
echo $row['id'].'<br/>';
}
This one should list all ID's from the database request.

Answer 2

This sql query is probably not going to return anything unless names are stored in your table like this
firstlast
"SELECT * FROM practice_sheets WHERE student_name='$_SESSION[SESS_FIRST_NAME] $_SESSION[SESS_LAST_NAME]'"
you probably want something like this
$_SESSION[SESS_FIRST_NAME] . " " . $_SESSION[SESS_LAST_NAME]
to return a name like
first last

Answer 3

I changed
echo "<td> <a href='account/practiceSheets?id='$id'> <i class='icon-eye-open'></i></a></td>"
to this:
echo "<td> <a href='account/practiceSheets?id=" . $row["id"] . "'> <i class='icon-eye-open'> </i> </a> </td>";
and got the desired results!