php inserting to database fail - php

Question

I have following message box error, says Failed. these are my codes:
<?php
require('admin/connectdb.php');
if (isset($_POST['Sub']))
{
//get data from reservation form
$cutomername=$_POST['aname'];
$gender=$_POST['sex'];
$phoneno=$_POST['tel'];
$email=$_POST['email'];
$age=$_POST['age'];
$computerpart=$_POST['partcomp'];
$option1=$_POST['option1'];
$notes=$_POST['Notes'];
$query="INSERT INTO `assignmentwebprog`.`reservation` (`cumstomername`, `gender`, `phoneno`, `email`, `age`, `typeofcomputerpart`, `option`, `notes`)
VALUES ('$cutomername', '$gender', '$phoneno', '$email', '$age', '$computerpart', '$option1', '$notes')";
$qresult = mysql_query($query);
if ($qresult){
echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
}
else
{
echo "<script type='text/javascript'>alert('failed!')</script>";
}
}
?>
up there is inserting value to phpmyadmin & every time i load/input then click enter then the page shows message box "failed"
these are my database:
<?php
$host="localhost"; // Host name
$username="root"; // username
$username="root"; // username
$db_name="assignmentwebprog"; //database name
$tbl_name="reservation";
// Replace database connect functions depending on database you are using.
mysql_connect("$host", "$username", "$password");
mysql_select_db("$db_name");
?>
currently my database is phpmyadmin, is there something missing with my code?

Answer 1

Check to see if the field in the database cumstomername is spelt correctly.
It should probably be customername
Passing the paramter
$cutomername=$_POST['aname'];
SQL
$query="INSERT INTO `assignmentwebprog`.`reservation` (`cumstomername`, `gender`, `phoneno`, `email`, `age`, `typeofcomputerpart`, `option`, `notes`)
VALUES ('$cutomername', '$gender', '$phoneno', '$email', '$age', '$computerpart', '$option1', '$notes')";

Answer 2

Change this line and try:
$qresult = mysql_query($query) or die(mysql_error());

Answer 3

check this :
$query="INSERT INTO reservation (cumstomername, gender, phoneno, email, age, typeofcomputerpart, option, notes)
VALUES ('$cutomername', '$gender', '$phoneno', '$email', '$age', '$computerpart', '$option1', '$notes')";
$qresult = mysql_query($query) or die(mysql_error());

Answer 4

You might have missing something in the $query which is mandatory for the table insertion.
First echo the query on the page. // echo $query ;
Then RUN the query in phpmyadmin and you will get the reason why it is not inserting in the table. See the error there.