My target: create dynamic variables like
$counterMon00 = 0;
$counterMon01 = 0;
$counterThu23 = 0;
My code until now:
$array_days = ["Mon","Tue","Wed","Thu","Fri"];
for ($i = 0; $i < sizeof($array_days); $i++)
{
$weekDay = (String) $array_days[$i];
for($ii = 7; $ii < 10; $ii++)
{
"counter".${$weekDay}.${$ii} = 0;
}
}
Can You help my with this line
"counter".${$weekDay}.${$ii} = 0;
I tried different solution but nothing worked ...
You need to have the variable set as a single string before using it.
$var = "counter".$weekDay.$ii;
$$var = 0;
${"counter".$weekDay.$ii} = 0;
Try using variable variables:
$varName = "counter".${$weekDay}.${$ii};
$$varName = 0;//Note the $$
You also may want to look into building an array rather than the above as this would be easier (in my opinion at least). Something like an array mapping weekdays to counts i.e.
$arr["Mon"][3] = 0;
You want an array! That's exactly what they're for. Variable variables are a bad idea in 99% of all cases.
$counter = [];
$days = ["Mon","Tue","Wed","Thu","Fri"];
foreach ($days as $day) {
foreach (range(7, 9) as $i) {
$counter[$day][$i] = 0;
}
}
$array_days = array("Mon","Tue","Wed","Thu","Fri");
for ($i = 0; $i < count($array_days); $i++)
{
$weekDay = (String) $array_days[$i];
for($ii = 7; $ii < 10; $ii++)
{
$var="counter".$weekDay.$ii;
$$var;
}
}
Please try the following you make a mistake in the array declaration also
<?php
$array_days = array("Mon","Tue","Wed","Thu","Fri");
for ($i = 0; $i < sizeof($array_days); $i++)
{
$weekDay = (String) $array_days[$i];
for($ii = 7; $ii < 10; $ii++)
{
$var = "counter".$weekDay.(String)$ii;
$$var = 0;
}
}
?>
Try This
$array_days = ["Mon","Tue","Wed","Thu","Fri"];
for ($i = 0; $i < sizeof($array_days); $i++)
{
// $weekDay = $array_days[$i];
for($ii = 0; $ii < 5; $ii++)
{
//echo "counter".${$weekDay}.${$ii} = 0;
$a = "counter".$array_days[$i].$i.$ii;
$$a = 0;
}
}
Related
Is it possible to add or concatenate something into a variable name in a PHP variable? For example:
for($g = 7; $g <= 10; $g++){
for($i = 0; $i <= 4; $i++){
$counter = $g - 7;
if($i != $counter){
continue;
} else {
$grade.[$g] = $grades[$i];
}
}
}
I want this to happen:
$grade7 = 0
$grade8 = 1
$grade9 = 2
$grade10 = 3
Concatenates the $g with grade and make this value a variable by adding a $ sign at the starting line...
The example given below:
for($g = 7; $g <= 10; $g++){
for($i = 0; $i <= 4; $i++){
$counter = $g - 7;
if($i != $counter){
continue;
} else {
${"grade".$g} = $grades[$i];
}
}
}
echo $grade7; // 0
echo $grade8; // 1
echo $grade9; // 2
echo $grade10;// 3
One solution would be to create the variables dynamically:
for ($g = 7; $g <= 10; $g++) {
for ($i = 0; $i <= 4; $i++) {
$counter = $g - 7;
if ($i == $counter) {
${'grade' . $g} = $grades[$i];
}
}
}
You should use ARRAY instead of your method. :)
Try to look at variable named like "$$".
EDIT: Maybe something like
var $array = array();
for($g=7; $g<=10; $g++)
{
for($i=0; $i<=4; $i++)
{
$counter = $g - 7;
if($i != $counter) continue;
else $array[$grade.[$g]] = $grades[$i];
}
}
$data = new Array();
for($g = 7; $g <= 10; $g++){
for($i = 0; $i <= 4; $i++){
$counter = $g - 7;
if($i != $counter){
continue;
} else {
$data[$grade.[$g]] = $grades[$i]);
}
}
}
PHP NOOB, i have been working on this code all day, but cant find any good way to fix it.
here is my code:
$priv = explode(',', '0,1,1');
$m = 'me';
for($i = 0; $i <= 2; $i++)
{
if($priv[$i] == '0')
{
$m.$i = 20;
}
else
{
$m.$i = 10;
}
}
Am trying to join $m.$i together and set it to 20 or 10, but i end up having me20 or me10 instead of me1 = 20 or me1 = 10 when i echo $m.$i which is legit, is there anyways to make this work?
$m.$i = 20;
This will assign $i = 20 and then concatenate it with $m and hence you will see me20.
What you need is $m . $i .= 20; instead. which will concatenate them altogether.
Fixed:
<?php
$priv = explode(',', '0,1,1');
$m = 'me';
for($i = 0; $i <= 2; $i++)
{
if($priv[$i] == '0')
{
echo $m . $i .= 20;
}
else
{
echo $m.$i .= 10;
}
}
?>
EDIT:
The above answer was a total misunderstanding, I realised you intended to create the variables:
for($i = 0; $i <= 2; $i++)
{
if($priv[$i] == '0')
{
${$m.$i} = 20;
echo $me0;
}
else
{
${$m.$i} = 10;
}
}
Assign it like so.
${$m.$i} = 20;
You are trying to dynamically create variables, so you have to do something like this:
$priv = explode(',', '0,1,1');
$m = 'me';
for($i = 0; $i <= 2; $i++)
{
if($priv[$i] == '0')
{
${$m.$i} = 20;
}
else
{
${$m.$i} = 10;
}
}
then try to priny $me0, $me1
i am facing a problem
can some one suggest me
for ($i = 1; $i <= 2; $i++) {
$r2 = 0;
for ($t = 1; $t <= 2; $t++) {
echo $r2;
$r2++
}
}
output is 0101;
can i get output 0123 ??? please
if
for ($i = 1; $i <= 3; $i++) {
$r2 = 0;
for ($t = 1; $t <= 3; $t++) {
echo $r2;
$r2++
}
}
output is 010101;
can output 012345678 ??? please
and if
for ($i = 1; $i <= 4; $i++) {
$r2 = 0;
for ($t = 1; $t <= 4; $t++) {
echo $r2;
$r2++
}
}
output is 01010101;
can output 0123456789101112131415 ??? please
i think you understand
thanks
In all of these cases you are initializing $r2=0; in the inner loop. It should be outside the loop.
$r2=0;
for($i=1;$i<=2;$i++){
for($t=1;$t<=2;$t++){
echo $r2;
$r2++
}
}
This would produce "1234".
why are you using two nested for loops ?
why not just use one:
for ($i=0; $i<=15; $i++) echo $i . " ";
Try this:
$r2 = 10;
for($t = 0; $t <= $r2; $t++){
echo $r2;
}
Oh wait.. I get it now, why you have the two nested loops, you want to essentially raise a number to the power of 2 in order to control the number of values output. In that case, what you want is simply this:
// this is the variable you need to change to affect the number of values outputed
$n = 2;
// Square $n
$m = $n * $n;
// Loop $m times
for ($i = 0; $i < $m; $i++) {
echo $i;
}
I have this code, but i want in second loop a decrease of $p value. The first internal loop must be repeated three times, the second, two times and the last, one time. I am trying $p-- but without success.
Any idea ? thanks
$p = 3;
for ($i = 0; $i < 3; $i++) {
for ($o = 0; $o < $p; $o++) {
echo "something";
$p--;
}
}
Move your $p-- to outside the inner for loop:
$p = 3;
for ($i = 0; $i < 3; $i++) {
for ($o = 0; $o < $p; $o++) {
echo "something";
}
$p--;
}
Or better, just depend on the value of $i:
for ($i = 0; $i < 3; $i++) {
for ($o = 0; $o < 3 - $i; $o++) {
echo "something";
}
}
Or if you don't actually use $i:
for ($i = 2; $i >= 0; $i--) {
for ($o = 0; $o < $i; $o++) {
echo "something";
}
}
It's quite simple.
for ($i = 2; $i >= 0; $i--)
{
}
Set the starting number at the upper limit number, and then go down until equal to 0, $i minus 1;
You need to decrement $p outside the first loop
I want to create somthing like 100 var's which their names will be:
$numbr_1 = 1;
$numbe_2 = 2;
$number_3 = 3;
...
I won't write 100 vars of course, but there is a way to do it with foor loop or somthing? I thought about this:
for ($i = 1; $i <= 100; $i++)
$number_{$i} = $i;
You're talking about variable variables, and they are incredibly stupid to use. For one, they make debugging next to impossible.
What you want is an array:
for ($i = 1; $i <= 100; $i++) {
$numbers[$i] = $i;
}
Something like this should work:
for($i = 1 ; $i <= 100 ; $i++){
$var_name = "number_$i";
$$var_name = $i;
}
for($i=1;$i<=100;$i++) {
$j="number$i";
$$j = $i;
}
Why don't you use an array?
$number = array();
for ($i = 0; $i < 100; $i++)
{
$number[] = $i;
}
for($i = 1 ; $i <= 100 ; $i++){
${'number_'.$i} = $i;
}
Possible solution is usage of array.
$number = array();
for ($i = 1; $i <= 100; $i++) {
$number[$i] = $i;
}