How to add a </tr><tr> automatically after every 2 <td> - php

i am retrieving results from MySQL with PHP based on user search
i want to add a automatically after every 2 s in the result
<?php
include_once("config.php");
isset( $_REQUEST['name'] ) ? $name=$_REQUEST['name'] : $name='';
$name = mysql_real_escape_string( $name );
if (strlen($name) >= 4) {
$sql = "select * from places where speciality like '%$name%'";
$rs = mysql_query( $sql ) or die('Database Error: ' . mysql_error
$num = mysql_num_rows( $rs );
if($num >= 1 ){
echo "<table id='result-table'><tr>";
while($row = mysql_fetch_array( $rs )){
echo "<td>row[cname]</td>"; //here i want to add </tr><tr> after 2 <td>s
}
}else{
echo "no records found</table>";
}
}
?>

Used $i = 1; if ($i % 2 == 0) and $i++;
<?php
include_once ("config.php");
isset ($_REQUEST['name']) ? $name = $_REQUEST['name'] : $name = '';
$name = mysql_real_escape_string($name);
if (strlen($name) >= 4) {
$sql = "select * from places where speciality like '%$name%'";
$rs = mysql_query($sql) or die('Database Error: '.mysql_error $num = mysql_num_rows($rs);
if ($num >= 1) {
$i = 1;
echo "<table id='result-table'><tr>";
while ($row = mysql_fetch_array($rs)) {
echo "<td>row[cname]</td>"; //here i want to add </tr><tr> after 2 <td>s
if ($i % 2 == 0)
echo "</tr><tr>";
$i++;
}
}
else {
echo "no records found</table>";
}
}
?>

echo "<table id='result-table'><tr>";
$currentCount = -1;
while($row = mysql_fetch_array($rs))
{
echo "<td>row[cname]</td>";
$currentCount = ($currentCount + 1) % 2;
if($currentCount == 1)
{
echo '</tr><tr>';
}
}

I suggest not putting them into a table at all; instead simply put them into <div> elements, with float:left and width:50% styles.
If you must put them into a table, and you want to do it the way you asked, you can use PHP's modulo operator (%) to divide the current record number by 2 and get the remainder. If it's 1, then add the <tr> tag:
if(++$rowNum % 2) {print "</tr><tr>";}

Related

How to display only 5 records per page from my mysql database table through pagination?

I want to display five record per page through pagination (mysql,php,html,css) until all the records are displayed, navigation to pages must be like, Page: 1 2 3 4 5 6 7 7 8... Last.
HERE IS MY CODE TO VIEW ALL THE RECORDS FROM emp_master table.
I am new to PHP so please write an easily understandable code for pagination. I have seen few examples but they are not working.
<?php
$con=mysqli_connect("localhost","user","password","dataplus");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM emp_master");
echo "<table border='1'>";
$i = 0;
while($row = $result->fetch_assoc())
{
if ($i == 0) {
$i++;
echo "<tr>";
foreach ($row as $key => $value) {
echo "<th>" . $key . "</th>";
}
echo "</tr>";
}
echo "<tr>";
foreach ($row as $value) {
echo "<td>" . $value . "</td>";
}
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
I want to display five record per page through pagination untill all the records are displayed, navigation to pages must be like, Page: 1 2 3 4 5 6 7 7 8... Last.
This code below is not working:
$dbhost="localhost";
$dbuser="10053";
$dbpass="n6867242";
$database="0368";
$rec_limit = 10;
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('1005368');
/* Get total number of records */
$sql = "SELECT count(emp_id) FROM emp_master ";
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
$row = mysql_fetch_array($retval, MYSQL_NUM );
$rec_count = $row[0];
if( isset($_GET{'page'} ) ) {
$page = $_GET{'page'} + 1;
$offset = $rec_limit * $page ;
}else {
$page = 0;
$offset = 0;
}
$left_rec = $rec_count - ($page * $rec_limit);
$sql = "SELECT emp_id, emp_name, e_mail ".
"FROM emp_master ".
"LIMIT $offset, $rec_limit";
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
echo "EMP ID :{$row['emp_id']} <br> ".
"EMP NAME : {$row['emp_name']} <br> ".
"EMP MAIL : {$row['e_mail']} <br> ".
"--------------------------------<br>";
}
if( $page > 0 ) {
$last = $page - 2;
echo "Last 10 Records |";
echo "Next 10 Records";
}else if( $page == 0 ) {
echo "Next 10 Records";
}else if( $left_rec < $rec_limit ) {
$last = $page - 2;
echo "Last 10 Records";
}
mysql_close($conn);
If you want just PHP MySQL code, I usually use something like the following.
$page=max(intval($_GET['page']),1); // assuming there is a parameter 'page'
$itemsperpage = 5;
$total=100; // total results if you know it already otherwise use another query
$totalpages = max(ceil($total/$itemsperpage),1);
$query = "SELECT * FROM emp_master LIMIT ".(($page-1)*$itemsperpage).",".$itemsperpage; // this will return 5 items based on the page
You can use a library called dataTables that will auto paginate the data and you can easily customize it to suit your needs with the look and how many records to show per page. It also has a search field which enables users to search your data without any extra code.
All you have to do is include a couple of cdn's and the following code and everything works fine
$(document).ready(function(){
$('#myTable').DataTable();
});
Some examples here
you just should remove spaces in href and also make $page = $page + 1 when page is 0
if( $page > 0 ) {
$last = $page - 2;
echo "Last 10 Records |";
echo "Next 10 Records";
}else if( $page == 0 ) {
$page = $page + 1;
echo "Next 10 Records";
}else if( $left_rec < $rec_limit ) {
$last = $page - 2;
echo "Last 10 Records";
}
Link is here for demo, click here to experience the result
Here is the code working for me, just change your db name, username and password
and get pagination done. You can change $rec_limit value to your desired no. of records per page.
<?php
$host="localhost";
$username="68";
$password="67242";
$database="68";
$rec_limit = 5;
$conn = mysql_connect($localhost,$username,$password);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('10');
/* Get total number of records */
$sql = "SELECT count(emp_id) FROM emp_master ";
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
$row = mysql_fetch_array($retval, MYSQL_NUM );
$rec_count = $row[0];
if( isset($_GET{'page'} ) ) {
$page = $_GET{'page'} + 1;
$offset = $rec_limit * $page ;
}else {
$page = 0;
$offset = 0;
}
$left_rec = $rec_count - ($page * $rec_limit);
$sql = "SELECT eid,ename, email, quali, gender, contactno, birthdate, joiningdate,CURDATE(), TIMESTAMPDIFF( YEAR, birthdate, CURDATE( ) ) AS age ".
"FROM emp_master ".
"LIMIT $offset, $rec_limit";
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not get data: ' . mysql_error());
}
echo "<table border='1'>";
$i = 0;
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
if ($i == 0) {
$i++;
echo "<tr>";
foreach ($row as $key => $value) {
echo "<th>" . $key . "</th>";
}
echo "</tr>";
}
echo "<tr>";
foreach ($row as $value) {
echo "<td>" . $value . "</td>";
}
echo "</tr>";
}
echo "</table>";
if( $page > 0 ) {
$last = $page - 2;
echo "Last 5 Records | ";
echo "Next 5 Records";
}else if( $page == 0 ) {
$page = $page + 0;
echo "Next 5 Records";
}else if( $left_rec < $rec_limit ) {
$last = $page - 2;
echo "Last 5 Records";
}
mysql_close($conn);
php?>
IF your are using mysqli the code is below
$conn=mysqli_connect("localhost","root","","ui");
$start=0;
$limit=5;
$t=mysqli_query($conn,"select * from form_table");
$total=mysqli_num_rows($t);
if(isset($_GET['id']))
{
$id=$_GET['id'] ;
$start=($id-1)*$limit;
}
else
{
$id=1;
}
$page=ceil($total/$limit);
$query=mysqli_query($conn,"select * from form_table limit $start, $limit");
?>
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script s src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"> </script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"> </script>
</head>
<body>
<div class="container">
<h2>Table</h2>
<table class="table table-bordered">
<thead>
<tr>
<th>Id</th>
<th>Name</th>
<th>Gender</th>
<th>Hobbies</th>
<th>Course</th>
</tr>
</thead>
<tbody>
<?php
while($ft=mysqli_fetch_array($query))
{?>
<tr>
<td><?= $ft['0']?></td>
<td><?= $ft['1']?></td>
<td><?= $ft['2']?></td>
<td><?= $ft['3']?></td>
<td><?= $ft['4']?></td>
</tr>
<?php
}
?>
</tbody>
</table>
<ul class="pagination">
<?php if($id > 1) {?> <li>Previous</li><?php }?>
<?php
for($i=1;$i <= $page;$i++){
?>
<li><?php echo $i;?></li>
<?php
}
?>
<?php if($id!=$page)
{?>
i Give you an example of my project of pagination. Just you have to put your values in the code
$sql="SELECT * FROM tblname LIMIT $next,5";
$results = mysqli_query($conn,$sql);
}
else if (isset($_POST['prev']))
{
$prev1=$_POST['prev'];
$next=$_POST['prev'];
$prev=$prev1;
$sql="SELECT * FROM tablename LIMIT $prev,5";
$prev=$prev1;
$results = mysqli_query($conn,"SELECT * FROM tablename LIMIT $prev,10");
if($prev==0)
{
$prev = 0;
}
else
{
$prev=$next-10;
}
}
else
{
$next=0;
$prev=0;
$results = mysqli_query($conn,"SELECT * FROM tablename LIMIT $next,10");
}

Check if FK order is numbered correctly

I have some absences, and each absence has an FK to an employee, which I wanna display in a generated HTML table. However, if I delete an employee the order changes from 0, 1, 2 to 1, 2 (for example if the second employee got deleted).
This messed up my code, because I need the FK to check where I have to insert the leave (in which <tr>). Here I count the employees:
$result = mysql_query("select count(1) FROM employee");
$row = mysql_fetch_array($result);
$count_user = $row[0];
Later in my code I make a query in a loop. The loop runs as many times as there are users. And heres the problem: if an employee gets deleted it will not reach the other one ($i goes 0 and then 1 if there are 2 users, but if one is deleted the FK is 3, so it would need to go one further).
to
$result = mysql_query("select start, end, type_FK, employee_FK FROM absences where employee_FK = $i");
while ($row = mysql_fetch_assoc($result)) {
$array_absences[] = $row;
}
Has anyone an Idea that is not based on the FK order?
Also this topic needs a better title so feel free to edit it.
<html>
<head>
<title>Absence System</title>
</head>
<body>
<?php
$con = mysql_connect("localhost", "root", "");
if (!$con) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("absence_system", $con);
$result = mysql_query("select count(1) FROM employee");
$row = mysql_fetch_array($result);
$count_user = $row[0];
$result = mysql_query("select count(1) FROM absences");
$row = mysql_fetch_array($result);
$count_absences = $row[0];
$result = mysql_query("select name, surename, employee_ID FROM employee");
while ($row = mysql_fetch_assoc($result)) {
$array_user[] = $row;
}
for($i = 0; $i < $count_user; $i++){
echo '<table = border = 1px>';
echo '</tr>';
$result = mysql_query("select start, end, type_FK, employee_FK FROM absences where employee_FK = $i");
while ($row = mysql_fetch_assoc($result)) {
$array_absences[] = $row;
}
$count = count($array_absences);
echo $count;
print_r($array_absences);
for($j = 0; $j < 32; $j++){
$true = 0;
if($j == 0){
echo '<td>';
echo $array_user[$i]['name'], " ", $array_user[$i]['surename'] ;
echo '</td>';
}
for($k = 0; $k < $count; $k++)
{
$array_absences[$k]['start'] = substr($array_absences[$k]['start'], -2);
$array_absences[$k]['end'] = substr($array_absences[$k]['end'], -2);
$array_absences[$k]['start'] = ereg_replace("^0", "", $array_absences[$k]['start']);
$array_absences[$k]['end'] = ereg_replace("^0", "", $array_absences[$k]['end']);
if($j == $array_absences[$k]['start'] && $array_absences[$k]['employee_FK'] == $i){
$true = 1;
echo '<td>';
echo $array_absences[$k]['type_FK'];
echo '</td>';
}
}
if($j != 0 && $true == 0){
echo '<td>';
echo "$j";
echo '</td>';
}
}
echo '</tr>';
echo '</table>';
}
?>
</body>
</html>
If employee_ID corresponds to employee_FK, then you should not iterate over $count_user, but rather over $array_user - then your select would looke like this:
$result = mysql_query("select start, end, type_FK, employee_FK FROM absences where employee_FK = {$array_user[$i]['employee_ID']}");
while $i will still represent sequence number, because
$count_user == count($array_user)

PHP - If variable's character is number then do something

I created a PHP page that show names from a table, there is some names is too long, I want to make if $name is 12 characters then replace what after 12 characters with ...
this is my code
$query= mysql_query("SELECT * FROM `table`")or die(mysql_error());
while($arr = mysql_fetch_array($query)){
$num = mysql_num_rows($query);
$name= $arr['name'];
echo '</br>';
echo $name;
}
How can I do it?
Try:
$name = (strlen($arr['name']) > 12) ? substr($arr['name'],0,12) . "..." : $arr['name'];
This is a conditional assignment. If $arr['name'] is greater than 12 characters, then it truncates it to 12 characters and adds "...". Otherwise, it uses the full name.
if (strlen($name) > 12)
$name = substr($name, 0, 12) . '...';
https://php.net/strlen
https://php.net/substr
You can do something like this:
if( strlen($arr['name']) > 12)
{
substr($arr['name'],0,12)."...";
}
So, your code will look like:
$query= mysql_query("SELECT * FROM `table`")or die(mysql_error());
while($arr = mysql_fetch_array($query)){
$num = mysql_num_rows($query);
$name= $arr['name'];
echo '</br>';
if(strlen($name) > 12)
{
substr($name,0,12) . "...";
}
}
You can do it like this:-
<?php
$mystring = "this is a test string to check that";
if( strlen($mystring) >= 12)
{
$result= substr($mystring,0,12);
$result .='...';
}
echo $result;
?>

Trouble pulling data out of an sql table

I have a html form tat my user can use to search through a table in my MYSQL database.
By default if you just hit go it will display the entire table, however I would like them to be able select certain fields and my php form to search via the fields that are filled in.
I seem to be unable to find a way of doing this without writing a seperate query for all 11 inputs in the different combinations they could be entered in, which comes out at a total of 76 queries..
If anyone has a way to simplify this I would love any advice.
I have tried just running a query with the AND operator but that doesnt work as some variables can be left empty and that will return no result, not sure if that is what is upposed to happen, but that is what is happening.
my html and php:
http://jsbin.com/oquwid/1/edit
PHP
$sql = "SELECT * FROM ".$tbl_name."
WHERE fname='".$fname."'
and lname='".$lname."'
and city='".$city."'
and phone='".$pohne."'
and interest_inet='".$internet."'
and interest_tv='".$television."'
and interest_voice='".$voice."'
and submission_ip='".$ip."'
and inquiry_handled='".$handled."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
echo $row;
}
echo "</table>";
You could append parts to the query depending on which are filled in:
if(!empty($fname) || !empty($lname) || !empty($city) || etc.etc.) {
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryParts = array();
if($fname != "") {
$queryParts[] = " fname='$fname'";
}
if($lname != "") {
$queryParts[] = " lname='$lname'";
}
etc.etc.
$sql .= implode(" AND ", $queryParts);
// do query, etc.
}
else {
// Don't do query if no parameters are specified
}
You also need to make sure that you escape all of your query parameters before you use them or risk having someone ravage your data.
The following uses loops to avoid duplicate code:
$fieldIsSpecified = false;
$queryFields = array('fname' => $fname, 'lname' => $lname, 'city' => $city, etc...);
foreach($queryFields as $column => $value) {
if(!empty($value){
$fieldIsSpecified = true;
break;
}
}
if($fieldIsSpecified) {
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryParts = array();
foreach($queryFields as $column => $value) {
if(!empty($value)) {
$queryParts[] = " $column = '$value'";
}
}
$sql .= implode(" AND ", $queryParts);
// do query, etc.
}
else {
// Don't do query if no parameters are specified
}
The reason you're query isn't working if a value is not filled in, is probably because the query results in this (given first name is empty)
SELECT * FROM $tbl_name WHERE fname=''
And there probably isn't a user having no first name.
Further, you considered adding a flag per requested info, and on base of that either add or remove the needed part to the select part of the query ?
For example,
$sql = "SELECT * FROM $tbl_name WHERE ";
$queryChanged = false;
if (isset($fname)){
if (!empty($fname)){
$sql .= "fname='$fname' ";
$queryChanged=true;
}
}
if (isset($lname)){
if (!empty($lname)){
$sql .= ($queryChanged) ? " AND lname='$lname'" : "lname='$lname'";
$queryChanged = true;
}
}
... //Continue the logic
I'd recommend you to read this post about select * as well as this about user input and how to handle it
this is how i am going to have to do it
php:`
//if just lname is set
if(empty($start_date) && empty($end_date) && empty($fname) && isset($lname) && empty($city) &&
empty($internet) && empty($television) && empty($voice) && empty($phone) && empty($ip) &&
empty($handled) && empty($not_handled)){
$sql = "SELECT * FROM ".$tbl_name."
WHERE lname='".$lname."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
}
echo "</table>";
exit();
}
//if just city is selected
if(empty($start_date) && empty($end_date) && empty($fname) && empty($lname) && isset($city) &&
empty($internet) && empty($television) && empty($voice) && empty($phone) && empty($ip) &&
empty($handled) && empty($not_handled)){
$sql = "SELECT * FROM ".$tbl_name."
WHERE city='".$city."'";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
}
echo "</table>";
exit();
}
And etc... i am going to have to repeat this process until i cover all, 76 i believe, possibilites. thnkfully its just a lot of copy paste. thanks for the help everyone
First don't use MYSQL_*. Use PDO
Second, with your code, your are requiring all fields to be filled.
If you don't wanna do that then go this way:
You can use WHERE 1=1 , but it's not recommended !!!!!
$sql = "SELECT * FROM ".$tbl_name." WHERE confirm = '0' ";
$sql .= "AND fname = ".$fname."";
$sql .= "AND lname = ".$lname."";
$sql .= "AND city = ".$city."";
$sql .= "AND phone = ".$pohne."";
$sql .= "ORDER BY date DESC";
$result = mysql_query($sql);
echo "<table border='1'>";
echo "<tr>";
$i = 0;
while ($i < mysql_num_fields($result))
{
$meta = mysql_fetch_field($result, $i);
echo "<th>".$meta->name."</th>";
$i++;
}
while ($row = mysql_fetch_row($result))
{
echo '<tr>';
foreach($row as $item)
{
echo "<td>".$item."</td>";
}
echo '</tr>';
echo $row;
}
echo "</table>";

Why does my query result repeat 3 times?

the code i have below basically behaves as a friend search engine where you can add someone if you don't have them on you account. So i am trying to do the following: If exists it should just display the friend and if not then it should say add friend.
I got it to work but the tail end of the query (please see this comment "//Problem code - when i use this echo below this where it repeats 3 times") is giving me trouble where it repeats Add 3 times.
<?php
$num_rows1 = mysql_num_rows($result);
if ($result == "") {
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if ($rows == 0) {
print("<div id=norequests>No results for <strong>$q
</strong></div>");
}
elseif ($rows > 0) {
while ($row = mysql_fetch_array($query))
{
$person = htmlspecialchars($row['full_name']);
$linksys = htmlspecialchars($row['name']);
$pid = htmlspecialchars($row['system_id']);
}
print("");
}
}
else{
echo '<div id="error">No results.</div>';
}
$sql = "SELECT `Friend_id` from `friends_container`
WHERE `System_id` = '$sid'";
$result = mysql_query($sql);
$query = mysql_query($sql) or die("Error: " . mysql_error());
if ($result == "") {
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if ($rows == 0) {
print("");
}
elseif ($rows > 0)
{
while ($row = mysql_fetch_array($query))
{
$existing = htmlspecialchars($row['Friend_id']);
if ($existing == $pid) {
echo("<img src=$linksys />$person - Already Existing");
}
else
//Problem code - when i use this echo below this where it repeats 3 times
{
echo("Add $person");
}
}
?>
You must have 3 images stored for each account.
Your query will always result in a multiple result. what you should do is use php to convert it to something which will result in a better option or say convert the result in an array for convenience.

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