saving MySQL query to two arrays - php

Question

I'm sure this is simple for someone else, but it escapes me.
I have a function that generates a .csv file based on a query input from an internal website.
The problem is, for speed purposes, I want to run 1 query to save to two different arrays. One of which I can pass to a function, the other to use for printing a table.
I've tried to pass the same $result var to the function. It seems to strip the data once sent through function? I need some help.
code for function:
function save_to_csv($result1, $filename, $attachment = false, $headers = true) {
if($attachment) {
// send response headers to the browser
header( 'Content-Type: text/csv' );
header( 'Content-Disposition: attachment;filename='.$filename);
$fp = fopen('php://output', 'w');
} else {
$fp = fopen($filename, 'w');
}
$result1 = mysql_query($query1) or die( mysql_error() );
if($headers) {
// output header row (if at least one row exists)
$row = mysql_fetch_assoc($result1);
if($row) {
fputcsv($fp, array_keys($row));
// reset pointer back to beginning
mysql_data_seek($result1, 0);
}
}
while($row = mysql_fetch_assoc($result1)) {
fputcsv($fp, $row);
}
fclose($fp);
}
I've tried setting second array like so
$csv_result = array();
also tried
$csv_result = $result = mysql_query($query);
I'm assuming it's something here, but I just cant see it.

Answer 1

There's nothing in this code that demonstrates why you need two separate arrays. After the line where you set $result1, you can simply do the following for the exact same effect:
$row = mysql_fetch_assoc($result1);
if ($row) {
if ($headers) {
fputcsv($fp, array_keys($row));
}
fputcsv($fp, $row);
}
The variable $row hasn't been modified, and is still equal to the data retrieved from $query1. There's really no need to make a duplicate array unless one of them is going to be modified. However, if you want to make a copy of the data at any point, you can just use:
$new_copy = $row;