I would like to display an image using PHP. Here is what I have tried, but it does not work.
<!DOCTYPE html>
<html>
<head>
<title>Title</title>
</head>
<body>
<div class="container">
<?php
$img_name = echo $row['img_name']; //I get it from the database
img_block($img_name); //Display the image here.
//Function to display image
function img_block(img_src) {
// e.g. img_src = cat.jpg;
$img_input = "images/" . img_src;
$set_img = '<img class="media-object-ph" src="'.$img_input.'" width="380" height="290" alt="...">';
return $set_img;
}
?>
</div>
</body>
</html>
Thank you in advance.
Too long for a comment... You have a number of errors:
$img_name = echo $row['img_name'];
should be:
$img_name = $row['img_name'];
You are calling your function but not doing anything with the return value, you need to echo it:
img_block($img_name);
should be:
echo img_block($img_name);
Finally you have not put the required $ on the img_src variable in your function; it's definition should be:
function img_block($img_src) {
// e.g. img_src = cat.jpg;
$img_input = "images/" . $img_src;
$set_img = '<img class="media-object-ph" src="'.$img_input.'" width="380" height="290" alt="...">';
return $set_img;
}
If you make all these changes, and (e.g.) $row['img_name'] = 'image1.jpg', your code will output:
<img class="media-object-ph" src="images/image1.jpg" width="380" height="290" alt="...">
Demo on 3v4l.org
This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 6 years ago.
i tries to run this code and i got a http 500 error so i comment out line by line and i saw that the problem arise when i try to assign the values to the variable's i even tried to assign just a simple string and i got error can anyone help me
require 'connect_to_database.php';
$user_id = $_REQUEST['user_id'];
$select_query = "SELECT * FROM users WHERE user_id = " . $user_id;
$result = mysql_query($select_query);
if ($result) {
$row = mysql_fetch_array($result);
$first_name = hello;
$last_name = $row['last_name'];
$bio = $row['bio'];
$email = $row['email'];
$faebook_url = $row['facebook_url'];
$twitter_url = $row['twitter_handle'];
$user_image = "../../images/missing_user.png;"
} else {
die("Error locating user with ID {$user_id}");
}
?>
<html lang="en">
<head>
<meta charset="utf-8" />
<title></title>
<link href="../../css/phpMM.css" rel="stylesheet" type="text/css">
</head>
<body>
<div id="header"><h1>The Missing Manual</h1></div>
<div id="example">User profile</div>
<div id="content">
<div class="user_profile">
<h1><?php echo "{$first_name} {$last_name}"; ?></h1>
<p><?php echo $bio; ?></p>
<p class="contact_info">Get in touch <?php echo $first_name; ?>:</p>
<ul>
<li>...by emailing them at <a href="<?php echo $email; ?>">
<?php echo $email; ?></a></li>
<li>...by <a href="<?php echo $faebook_url; ?>">
checking them out on facebook</a></li>
<li>...by <a href="<?php echo $twitter_url; ?>">
following them on twitter</a></li>
</ul>
</div>
</div>
<div id="footer"></div>
</body>
</html>
The line user_image= the url needs to fixed. You left the trailing edge of a comment line in it and you cannot put an address like ../../xxxxx without the whole thing in quotes. So
$user_image = "../../images/missing_user.png";
I want to show a picture in my code but for some reason I get a big white almost blank page with a broken link img. I want to show the image and along with any other information.
I also want to resize the image(so it doesnt cover the whole page).
The code:
<?php
session_start()
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="initial-scale=1.0" />
<link rel="stylesheet" href="css/style.css" />
</head>
<div id="Container">
<div id="header">
<h1>Welcome!</h1>
</div>
<div id="navigation">
<?php
include_once "navigation.php";
?>
</div>
<div id="Content">
<?php
if (isset($_GET['search'])) {
$Name = $_GET['search'];
mysql_connect("localhost","root","") or die ("Could not connect to the server!");
mysql_select_db("pictures") or die ("That database could not be found!");
$query = mysql_query("SELECT * FROM picture WHERE Name='$Name'") or die ("The query could not be completed, please try again later!");
if (mysql_num_rows($wepquery) !=1) {
die ("That name could not be found!");
}
while ($row = mysql_fetch_array($query, MYSQL_ASSOC, 0)) {
$dbName = $row['Name'];
$dbCreator = $row['Creator'];
$dbDescription = $row['Description'];
$imageData = $row['Image'];
}
header("Content-type: image/jpeg");
if($Name != $dbName) {
die ("There has been a fatal error. Please try again.");
}
?>
<h2><?php echo $Name; ?></h2>
<br />
<table>
<tr><td>Creator: <?php echo $dbCreator;?></td></tr>
<tr><td>Description:<br /><?php echo $dbDescription;?></td></tr>
<tr><td>Picture:<br /><?php echo $imageData;?></td></tr>
</table>
<?php
} else die ("You need to specify a submission!");
?>
</div>
</div>
</html>
The database:
id, Name, Creator, Description, Image_name, Image(mediumblob).
The last two fields as you can see is dedicated to pictures. Yes I know about PDO and MySQLi, but I just want to finish this code first. Any help?
Images need to either be served by URL or the blob needs to be converted to a data URI like so:
<table>
<tr><td>Creator: <?php echo $dbCreator;?></td></tr>
<tr><td>Description:<br /><?php echo $dbDescription;?></td></tr>
<tr><td>Picture:<br /><?php echo "<img src='data:image/jpeg;base64," . base64_encode( $imageData ) . "' />"; ?></td></tr>
</table>
if you want image you need to enclose it with image tags. assume if your $imageData contains the location of the image then you can do the following.
<img src='<?php echo $imageData;?>' ... />
if your $imageData contains actual binary data of an image you need to create a separate call to a php script to return the imageData. and make the call to be the src attribute of an img tag.
is your path exactly pointing toward the image? have checked "../../" ? another question, is your image really inside an image tag? there must be something like this:
<img src="<?php echo $imagePath; ? />
Can someone help me connect some code??
What I want is a code that does this: If a picture exist then print it, else don't print anything.
(This code is used to find the pichure)
and I need help to conect the if statment to the one in the other code
<?php
$pathToFileOnDisk = 'inventory_images/' . $id . '.jpg';
if(file_exists($pathToFileOnDisk) && is_readable($pathToFileOnDisk)) {
<img src="inventory_images/' . $id . '.jpg" alt="' . $name . '" width="100%" height="260" border="1" />
}
else {
// NO IMG
}
?>
AND
<?php
session_start();
error_reporting(E_ALL);
ini_set('display_errors', '1');
?>
<?php
// Run a select query to get my letest 6 items
// Connect to the MySQL database
include "storescripts/connect_to_mysql.php";
$dynamicList = "";
$sql = mysql_query("SELECT * FROM content ORDER BY id DESC LIMIT 6");
$productCount = mysql_num_rows($sql); // count the output amount
if ($productCount > 0) {
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$name = $row["name"];
$content = $row["content"];
$date_added = strftime("%d %b, %Y", strtotime($row["date_added"]));
$dynamicList .= '<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td>
<div id="left">
<img src="inventory_images/' . $id . '.jpg" alt="' . $name . '" width="100%" height="260" border="1" /> <-- !!THIS IS WHAT I WANNA REPLACE!!
</div> <!-- End Left-->
</td>
<div id="right">
<td width="630px" valign="top"><h2><a id="overskrift" href="product.php?id=' . $id . '">' . $name . '</a></h2>
<p><b>
Skrevet den ' . $date_added . '<br />
' . $content . '</b></p>
</td>
</div>
</tr>
</table><br />';
}
} else {
$dynamicList = "Ingen inlegg enda..";
}
mysql_close();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link rel="stylesheet" href="style/style.css" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper">
<header>
<?php include_once("template_header.php");?>
</header> <!-- End Header -->
<div id="banner"></div>
<div class="content test clearfix">
<?php echo $dynamicList; ?>
</div> <!-- End Content -->
<footer>
<?php include_once("template_footer.php");?>
</footer> <!-- End Footer -->
</div> <!-- End Wrapper -->
</body>
Use the file_exists() and is_readable() functions.
The first will tell if the file exists, and the second will tell if you have permissions to read the file, before actually doing it. Similarly, there's also the is_writable() function, which tells you if you have permissions to write to a file.
Simply use this:-
<?php
$filename = 'some_name';
if (file_exists($filename)) {
echo "File exists";
} else {
echo "File does not exist";
}
?>
The file_exists and is_readable functions are perfect for this purpose.
For example:
<?php
$pathToFileOnDisk = '/full/system/path/to/image.jpg';
if(file_exists($pathToFileOnDisk) && is_readable($pathToFileOnDisk)) {
// The file exists and can be read
}
else {
// The file doesn't exist (or does exist, but PHP can't read it).
// Perhaps output a placeholder image here.
}
?>
Incidentally, I'd recommend a quick glance at all of the filesystem functions, as the time spent on this now will pay dividends in the future.
I wish to set the title of my webpage to Ultan.me - Whatever the post title. I want it to display the post title. The posts are submitted to a MySQL database and the title row is called "title". Any help is appreciated with this small question.
Update:
Here is the page itself now but it doesn't display the title. Should I open the php document and connect to my database somewhere different to it's current locations?
The Code (The only necessary piece is the beginning):
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?echo $title;?></title>
<link rel="stylesheet" href="css/styles.css" type="text/css" />
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script type="text/javascript"
src="js/jquery.labelify.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$(":text").labelify();
});
</script>
<style>
a {text-decoration:none}
</style>
</head>
<body>
<div id="main">
<!-- Menu Start -->
<div id="menu">
<ul>
<li>home</li>
<li>about me</li>
<li>archives</li>
<li>contact</li>
<li>gallery</li>
</ul>
</div>
<!-- Menu End -->
<img src="images/banner.png" />
<div id="content">
<div id="posts">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$date = date("l F d Y", $row['timestamp']);
$title = stripslashes($row['title']);
$entry = stripslashes($row['entry']);
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $row[category]");
$category = mysql_fetch_array($get_categories);
?>
<p><?php echo "<p id='post-title'><strong>" . $title . "</strong></p>"; ?><br /><br />
<div id="entry"><?php echo $entry; ?>
</div><br /><br />
<p id="date">Posted in <?php echo $category['category_name']; ?> on <?php echo $date; ?></p>
</p>
<h2 id="share-title">Share This Post</h2>
<div id="social-share">
<li id="link-right"><a href="http://twitter.com/home?status=
I just read <?php echo $title; ?> at http://ultan.me/post.php?id=<?php echo $id; ?>"><center>Twitter</center></a></li>
<li id="link-left"><center>Digg</center></li>
<br>
<li id="link-right"><center>Facebook</center></li>
<li id="link-left"><a href="http://www.google.com/buzz/post?url=http://ultan.me/post.php?id=<?php echo $id; ?>
"><center>Google Buzz</center></a></li>
<div class="clr"></div>
</div>
<h2 id="comments-title">Comments</h2>
<div id="comment-list">
<?php
}
$commenttimestamp = strtotime("now");
$sql = "SELECT * FROM php_blog_comments WHERE entry='$id' ORDER BY timestamp";
$result = mysql_query ($sql) or print ("Can't select comments from table php_blog_comments.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$timestamp = date("l F d Y", $row['timestamp']);
printf("<div class='comment-ind'><p id='comments'><a id='username' href=\"%s\">%s</a> %s</p>", stripslashes($row['url']), stripslashes($row['name']), $timestamp);
print("<p class='comments'>" . stripslashes($row['comment']) . "</p><div class='clr'><br></div></div>");
}
?>
<div class="clr"></div>
<form id="commentform" method="post" action="process.php">
<p><input type="hidden" name="entry" id="entry" value="<?php echo $id; ?>" />
<input type="hidden" name="timestamp" id="timestamp" value="<?php echo $commenttimestamp; ?>">
<input type="text" name="name" id="name" title="Name (required)" /><br />
<input type="text" name="email" id="email" title="Mail (will not be published) (required)" /><br />
<input type="text" name="url" id="url" title="Website" value="http://" /><br />
<br />
<textarea title="Your Comment Goes Here" name="comment" id="comment"></textarea></p>
<p><input type="submit" name="submit_comment" id="submit_comment" value="Add Comment" /></p>
</form>
</div>
<div id="pages">
<?php
$total_results = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS num FROM php_blog"));
$total_pages = ceil($total_results['num'] / $blog_postnumber);
if ($page > 1) {
$prev = ($page - 1);
echo "<< Newer ";
}
for($i = 1; $i <= $total_pages; $i++) {
if ($page == $i) {
echo "$i ";
}
else {
echo "$i ";
}
}
if ($page < $total_pages) {
$next = ($page + 1);
echo "Older >>";
}
?>
</div>
</div>
</div>
<!-- Sidebar Start -->
<div class="sidebar">
<!-- Item 1 -->
<div id="side-item">
<h2>
<a href="http://www.dailybooth.com/UltanCasey">
<img src="images/db-icon.jpg">Dailybooth
</a></h2>
<div id="side-item-content">
<center>
<img src="http://dailybooth.com/UltanCasey/latest/medium.jpg" />
</center>
</div>
</div>
<!-- Item 2 -->
<div id="side-item">
<h2><img src="images/connect.jpg" />Connect</h2>
</div>
<div id="side-item-content">
<div class="tweet-title"><p>Latest Tweet:</p></div>
<div id="tweet">
<?php
function getTwitterStatus($userid){
$url = "http://twitter.com/statuses/user_timeline/$userid.xml?count=1";
function auto_link_twitter ($text)
{
// properly formatted URLs
$urls = "/(((http[s]?:\/\/)|(www\.))?(([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+(\.[a-z]{2,2})?)\/?[a-z0-9._\/~#&=;%+?-]+[a-z0-9\/#=?]{1,1})/is";
$text = preg_replace($urls, " <a href='$1'>$1</a>", $text);
// URLs without protocols
$text = preg_replace("/href=\"www/", "href=\"http://www", $text);
// Twitter usernames
$twitter = "/#([A-Za-z0-9_]+)/is";
$text = preg_replace ($twitter, " <a href='http://twitter.com/$1'>#$1</a>", $text);
// Twitter hashtags
$hashtag = "/#([A-Aa-z0-9_-]+)/is";
$text = preg_replace ($hashtag, " <a href='http://hashtags.org/$1'>#$1</a>", $text);
return $text;
}
$xml = simplexml_load_file($url) or die("could not connect");
foreach($xml->status as $status){
$text = $status->text;
}
echo auto_link_twitter ($text);
}
getTwitterStatus("UltanKC");
?>
</div>
<br>
<ul>
<li id="social">YouTube</li>
<li id="social">Twitter</li>
<li id="social">LastFM</li>
<li id="social">Email</li>
</ul>
</div>
<!-- Item 2 End-->
<div id="side-item">
<h2><img src="images/archive.jpg" />Archives</h2>
</div>
<div id="archive-side">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
$result = mysql_query("SELECT FROM_UNIXTIME(timestamp, '%Y') AS get_year, COUNT(*) AS entries FROM php_blog GROUP BY get_year");
while ($row = mysql_fetch_array($result)) {
$get_year = $row['get_year'];
$entries = $row['entries'];
echo "<li id='tag'>Entries from " . $get_year . " (" . $entries . ")<br /></li>";
}
$result1 = mysql_query("SELECT * FROM php_blog_categories ORDER BY category_name ASC");
while($row = mysql_fetch_array($result1)) {
$result2 = mysql_query("SELECT COUNT(`id`) AS entries FROM php_blog WHERE category = $row[category_id]");
$num_entries = mysql_fetch_array($result2);
echo '<li id="tag">' . $row['category_name'] . ' (' . $num_entries['entries'] . ')</li>';
}
?>
</div>
</div>
<div class="clr" />
</div>
<!-- Sidebar End -->
<div id="footer">
<p> © Ultan Casey 2010</p>
<p style="margin-top: -18px; float:right">Home | About Me | Email Me</p>
</div>
</div>
</div>
</body>
</html>
?>
Here's the method I use (for similar things, not just title):
<?
ob_start (); // Buffer output
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title><!--TITLE--></title>
</head>
<body>
<?
$pageTitle = 'Title of Page'; // Call this in your pages' files to define the page title
?>
</body>
</html>
<?
$pageContents = ob_get_contents (); // Get all the page's HTML into a string
ob_end_clean (); // Wipe the buffer
// Replace <!--TITLE--> with $pageTitle variable contents, and print the HTML
echo str_replace ('<!--TITLE-->', $pageTitle, $pageContents);
?>
PHP usually works be executing any bits of code and printing all output directly to the browser. If you say "echo 'Some text here.';", that string will get sent the browser and is emptied from memory.
What output buffering does is say "Print all output to a buffer. Hold onto it. Don't send ANYTHING to the browser until I tell you to."
So what this does is it buffers all your pages' HTML into the buffer, then at the very end, after the tag, it uses ob_get_contents () to get the contents of the buffer (which is usually all your page's HTML source code which would have been sent the browser already) and puts that into a string.
ob_end_clean () empties the buffer and frees some memory. We don't need the source code anymore because we just stored it in $pageContents.
Then, lastly, I do a simple find & replace on your page's source code ($pageContents) for any instances of '' and replace them to whatever the $pageTitle variable was set to. Of course, it will then replace <title><!--TITLE--></title> with Your Page's Title. After that, I echo the $pageContents, just like the browser would have.
It effectively holds onto output so you can manipulate it before sending it to the browser.
Hopefully my comments are clear enough.
Look up ob_start () in the php manual ( http://php.net/ob_start ) if you want to know exactly how that works (and you should) :)
You parse the field from the database as usual.
Then let's say you put it in a variable called $title, you just
<html>
<head>
<title>Ultan.me - <?php echo htmlspecialchars($title);?></title>
</head>
EDIT:
I see your problem. You have to set $title BEFORE using it. That is, you should query the database before <title>...
header.php has the title tag set to <title>%TITLE%</title>; the "%" are important since hardly anyone types %TITLE% so u can use that for str_replace() later. then, you use output buffer like so
<?php
ob_start();
include("header.php");
$buffer=ob_get_contents();
ob_end_clean();
$buffer=str_replace("%TITLE%","NEW TITLE",$buffer);
echo $buffer;
?>
For more reference, click PHP - how to change title of the page AFTER including header.php?
What about using something like:
<?php
$page_title = "Your page tile";
include("navigation.php"); // if required
echo("<title>$page_title</title>");
?>
Move the data retrieval at the top of the script, and after that use:
<title>Ultan.me - <?php echo htmlspecialchars($title, ENT_QUOTES, 'UTF-8'); ?></title>
You need to set the value of $title before echoing it.
Also, you should really sanitize any data before using it in queries as this is a security risk
create a new page php and add this code:
<?php
function ch_title($title){
$output = ob_get_contents();
if ( ob_get_length() > 0) { ob_end_clean(); }
$patterns = array("/<title>(.*?)<\/title>/");
$replacements = array("<title>$title</title>");
$output = preg_replace($patterns, $replacements,$output);
echo $output;
}
?>
in <head> add code: <?php require 'page.php' ?> and on each page you call the function ch_title('my title');
The problem is that $title is being referenced on line 5 before it's being assigned on line 58. Rearranging your code isn't easy, because the data is both retrieved and output at the same time. Just to test, how does something like this work?
Because you're only retrieving one row, you don't need to use a while loop, but I left it with hopes that it'll make it easier for you to relate to your current code. All I've done is removed the actual output from your data retrieval, and added variables for category and category name which are then referred to as usual later on. Also, I haven't tested this. :)
It'll be tricky to rearrange your code to make this work, but I'll try :)
So, put this at the top of your code:
<?php require_once('mysql.php'); ?>
The top of the file should look like:
<?php require_once('mysql.php'); ?>
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?php echo htmlspecialchars($title); ?> </title>
Then, create a file called mysql.php in the same directory that the file which contains the code you quoted is in.
Put this is mysql.php:
<?php
mysql_connect ('localhost', 'root', 'root');
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
$res = mysql_fetch_assoc($result);
$date = date("l F d Y", $res['timestamp']);
$title = $res['title'];
$entry = $res['entry'];
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $res['category']");
$category = mysql_fetch_array($get_categories);
?>
Well, hope that helped :)
I know this is an old post but having read this I think this solution is much simpler (though technically it solves the problem with Javascript not PHP).
<html>
<head>
<title>Ultan.me - Unset</title>
<script type="text/javascript">
function setTitle( text ) {
document.title = text;
}
</script>
<!-- other head info -->
</head>
<?php
// Make the call to the DB to get the title text. See OP post for example
$title_text = "Ultan.me - DB Title";
// Use body onload to set the title of the page
print "<body onload=\"setTitle( '$title_text' )\" >";
// Rest of your code here
print "<p>Either use php to print stuff</p>";
?>
<p>or just drop in and out of php</p>
<?php
// close the html page
print "</body></html>";
?>
Simply add $title variable before require function
<?php
$title = "Your title goes here";
require("header.php");
?>
header.php
<title><?php echo $title; ?></title>
<?php echo APP_TITLE?> - <?php echo $page_title;?>
this should work fine for you
if you want to current script filename as your title tag
include the function in your project
function setTitle($requestUri)
{
$explodeRequestUri = explode("/", $requestUri);
$currentFileName = end($explodeRequestUri);
$withoutExt = preg_replace('/\\.[^.\\s]{3,4}$/', '', $currentFileName);
$explodeCurrentFileName = explode("-", $withoutExt);
foreach ($explodeCurrentFileName as $curFileValue)
{
$fileArrayName[] = ucfirst($curFileValue);
}
echo implode(" ", $fileArrayName);
}
and in your html include the function script
and replace your title tag with this
<title>Your Project Name -
<?php setTitle($_SERVER['REQUEST_URI']); ?>
</title>
it works on php7 and above but i dont have any idea about php 5.*
Hope it helps