I have some bar code numbers in an array. PHP seems to be rounding the barcodes which start with leading zeros. How do I stop this happening and keep the numbers as they were? Code I am using is below:
$array = array(5032227448124,5060028999989,5010121096504,5060028999996,5016254104864,5016402052788,8422248036986,0000003798720,0000003735503,0000003798713);
echo '<pre>';
print_r($array);
echo '</pre>';
This echos the following, as you can see the last four bar codes which feature leading zeros have been changed and had their leading zeros removed. These numbers are always 13 digits long and are padded with zeros.
Array
(
[0] => 5032227448124
[1] => 5060028999989
[2] => 5010121096504
[3] => 5060028999996
[4] => 5016254104864
[5] => 5016402052788
[6] => 8422248036986
[7] => 31
[8] => 1030979
[9] => 31
[10] => 1031004
)
You need to quote them as strings if they arent a number (integer, float, exponent).
The obvious, easy, and also likely wrong answer is to make them strings.
The better answer is to use printf()/sprintf() to pad with zeroes:
printf('%013d', 12345); // output: 0000000012345
MySQL also has a handy LPAD() function:
SELECT LPAD(12345, 13, 0) // output 0000000012345
Here's an easy way to convert your values to padded strings:
$array = array_map(function ($e){return str_pad($e, 13, "0", STR_PAD_LEFT);}, $array);
In the end I just needed to put double quotes around each barcode number e.g.
$array = array("5032227448124","5060028999989","5010121096504","5060028999996","5016254104864","5016402052788","8422248036986","0000003798720","0000003735503","0000003798713");
Related
I'm wanting to replace the first character of a string with a specific character depending on its value,
A = 0
B = 1
C = 2
Is there a way to do this based on rules? In total I will have 8 rules.
Ok, so I'm editing this to add more information as I don't think some people understand / want to help without the full picture...
My string will be any length between 5 and 10 characters
Capitals will not factor into this, it is not case sensitive
Currently there is no code, I'm not sure the best way to do this. I can write an if statement on a substring, but I know straight away that is inefficient.
Below is the before and after that I am expecting, I have kept these examples simple but all I am looking to do is replace the first character with a specific character depending on its value. For now, there are eight rules, but this could grow in the future
INPUT OUTPUT
ANDREW 1NDREW
BRIAN 2RIAN
BOBBY 2OBBY
CRAIG 3RAIG
DAVID 4AVID
DUNCAN 4UNCAN
EDDIE 5DDIE
FRANK 6RANK
GEOFF 7EOFF
GIANA 7IANA
HAYLEY 8AYLEY
So as you can see, pretty straight forward, but is there a simple way to specifically specify what a character should be replaced by?
Assuming all the rules are for single characters, like in the example, it would be easisest to code them in to a dictionary:
$rules = array('A' => 0, 'B' => 0 /* etc... */);
$str[0] = $rules[$str[0]];
I think this is what you want.
<?php
$input = array('ANDREW','BRIAN','BOBBY','CRAIG','DAVID','DUNCAN','EDDIE','FRANK','GEOFF','GIANA','HAYLEY');
$array = range('A','Z');
$array = array_flip(array_filter(array_merge(array(0), $array)));
$output = [];
foreach($input as $k=>$v){
$output[] = $array[$v[0]].substr($v, 1);
}
print_r($output);
?>
Output:
Array (
[0] => 1NDREW
[1] => 2RIAN
[2] => 2OBBY
[3] => 3RAIG
[4] => 4AVID
[5] => 4UNCAN
[6] => 5DDIE
[7] => 6RANK
[8] => 7EOFF
[9] => 7IANA
[10] => 8AYLEY
)
DEMO: https://3v4l.org/BHLPk
I am trying to parse a string that contain strings that are 9-11 characters long and are integers and starts with 08 or +62. How do I do this in PHP? Here's my regex thus far:
/^(\+?62|08)[0-9]{9,11}$/
so here's some sample string/integer I should be able to extract out of a long string
082298744807
087884962429
087783218768
0818809692
081224505277
+628129191929
+62812123929
It's unclear if you want to match numbers between 10-13 digits, or 9-11. In any case it's a simple fix (just count the initial two digits 08, or 62 as part of the total sum of digits. To implement this in php use preg_match_all:
$pat = "/^(?:\+?62|08)[0-9]{8,11}$/uim"; // note modfied range of digits
preg_match_all($pat, $str, $res);
print_r($res[0]);
Example:
http://ideone.com/GJYK7C
Result:
Array
(
[0] => 082298744807
[1] => 087884962429
[2] => 087783218768
[3] => 0818809692
[4] => 081224505277
[5] => +628129191929
[6] => +62812123929
[7] => +629490029944
)
I've been trying for the couple of days to split a string into letters and numbers. I've found various solutions but they do not work up to my expectations (some of them only separate letters from digits (not integers or float numbers/per say negative numbers).
Here's an example:
$input = '-4D-3A'; // edit: the TEXT part can have multiple chars, i.e. -4AB-3A-5SD
$result = preg_split('/(?<=\d)(?=[a-z])|(?<=[a-z])(?=\d)/i', $input);
print_r($result);
Result:
Array ( [0] => -4 [1] => D-3 [2] => A )
And I need it to be [0] => -4 [1] => D [2] => -3 [3] => A
I've tried doing several changes but no result so far, could you please help me if possible?
Thank you.
try this:
$input = '-4D-3A';
$result = preg_split('/(-?[0-9]+\.?[0-9]*)/i', $input, 0, PREG_SPLIT_DELIM_CAPTURE);
$result=array_filter($result);
print_r($result);
It will split by numbers BUT also capture the delimiter (number)
giving : Array ( [1] => -4 [4] => D [5] => -3 [8] => A )
I've patterened number as:
1. has optional negative sign (you may want to do + too)
2. followed by one or more digits
3. followed by an optional decimal point
4. followed by zero or more digits
Can anyone point out the solution to "-0." being valid number?
How about this regex? ([-]{,1}\d+|[a-zA-Z]+)
I tested it out on http://www.rubular.com/ seems to work as you want.
i'm working on a project that will need to have everything shown with barcodes, so I've generated 7 numbers for EAN8 algorithm and now have to get these 7 numbers seperately, right now i'm using for the generation
$codeint = mt_rand(1000000, 9999999);
and I need to get this 7 numbers each seperately so I can calculate the checksum for EAN8, how can i split this integer to 7 parts, for example
12345678 to
arr[0]=1
arr[1]=2
arr[2]=3
arr[3]=4
arr[4]=5
arr[5]=6
arr[6]=7
any help would be appreciated..
also I think that I'm becoming crazy :D because I already tried most of the solutions you gave me here before and something is not working like it should work, for example:
$codeint = mt_rand(1000000, 9999999);
echo $codeint."c</br>";
echo $codeint[1];
echo $codeint[2];
echo $codeint[3];
gives me :
9082573c
empty row
empty row
empty row
solved! $codeint = (string)(mt_rand(1000000, 9999999));
Try to use str_split() function:
$var = 1234567;
print_r(str_split($var));
Result:
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
)
There are two ways to do this, one of which is reasonably unique to PHP:
1) In PHP, you can treat an integer value as a string and then index into the individual digits:
$digits = "$codeint";
// access a digit using intval($digits[3])
2) However, the much more elegant way is to use actual integer division and a little knowledge about mathematical identities of digits, namely in a number 123, each place value is composed of ascending powers of 10, i.e.: 1 * 10^2 + 2 * 10^1 + 3 * 10^0.
Consequently, dividing by powers of 10 will permit you to access each digit in turn.
it's basic math you can divide them in loop by 10
12345678 is 8*10^1 + 7*10^2 + 6*10^3...
the other option is cast it to char array and then just get it as char
Edit
After #HamZa DzCyberDeV suggestion
$string = '12345678';
echo "<pre>"; print_r (str_split($string));
But in mind it comes like below but your suggestion is better one.
If you're getting string from your function then you can use below one
$string = '12345678';
$arr = explode(",", chunk_split($string, 1, ','));
$len = count($arr);
unset($arr[$len-1]);
echo "<pre>";
print_r($arr);
and output is
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
[7] => 8
)
okay what you can do is
Type cast to string with prefill 0
this is how it works
$sinteger = (string)$integer;
$arrsize = 0 ;
for (i=strlen($sinteger), i == 0 ; i--)
{
arr[$arrsize]=$sinteger[i];
$arrsize++;
}
And then what is left you can prefill with zip.
I am sure you can manage the order reverse or previous. but this is simple approach.
Greetings All
I am trying to get the values in the 4th column from the left for this url. I can get all the values but it skips the first one (e.g. 30 i think is the value on top right now )
My regex is
~<td align="center" class="row2">.*([\d,]+).*</td>~isU
NOTE: HTML PARSING IS NOT AN OPTION RIGHT NOW AS THIS IS PART OF A HUGE SYSTEM AND CANNOT
BE CHANGED
Thanking you
Imran
You could just use:
/([\d,]+)/
As the javascript function can be exploited as a "regex selection point"
If you want your regex to work you need to use non-greedy expression, i.e. change .* to .*?
Also your first align match attribute in the HTML is surrounded in '' quotation marks, not "" in the HTML, for some weird inconsistent reason. Try this:
|<td align=["\']center["\'] class="row2">.*?([\d,]+).*?</td>|is
Edit:
$a = file_get_contents('http://www.zajilnet.com/forum/index.php?showforum=31');
preg_match_all('|<td align=["\']center["\'] class="row2">.*?([\d,]+).*?</td>|is',$a,$m);
print_r($m[1]);
Result:
Array
(
[0] => 30
[1] => 16
[2] => 56
[3] => 14
[4] => 96
[5] => 4
[6] => 0
[7] => 17
[.... and more....]