While{ while{code}} not working wright - php

Question

I have noticed that if i have a while{ while{}} loop, not all the data in a MYSQL database is shown...
here is the PHP (this is a working code...)
<?php
$conn = mysql_connect("localhost","xfiddlec_user","public");
mysql_select_db("xfiddlec_max");
mysql_set_charset("UTF8", $conn);
?>
<script>
$(function()
{
var icons =
{
header: "ui-icon-circle-arrow-e",
activeHeader: "ui-icon-circle-arrow-s"
};
$( "#dam" ).accordion({
icons: icons,
heightStyle: "content",
collapsible: true
});
});
</script>
<?php
$construct ="SELECT * FROM Noutati";
$constructaug ="SELECT * from Noutati WHERE MONTH(DataIntroducere) = 8 AND YEAR(DataIntroducere) = YEAR(CURDATE())";
$run = mysql_query($construct) or die(mysql_error());
$runaug = mysql_query($constructaug) or die(mysql_error());
$foundnum = mysql_num_rows($run);
$foundnumaug = mysql_num_rows($runaug);
if ($foundnum==0)
{
echo "Nu avem noutăți!";
}
else
{
echo"<div id='dam'>";
while($runrows = mysql_fetch_assoc($runaug) )
{
echo"
<h3>August 2013</h3>
<div><br>";
while($runrows = mysql_fetch_assoc($runaug))
{
$Luna = $runrows ['Luna'];
$Ziua = $runrows ['Ziua'];
$Mesaj = $runrows ['Mesaj'];
echo "
<table class='noutatitabel'>
<tr>
<td class='faramargini'>
<div class='data'>
<div class='luna'>$Luna</div>
<div class='ziua'>$Ziua</div>
</div>
</td>
<td class='albastru'>$Mesaj
</td>
</tr>
</table><br>";
}
echo"
<br><hr><br></div>";
}
echo"</div>";
}
?>
The database contains 6 rows.
When the above code is executed, an accordion menu appears but only 2 rows of that database are shown (for the specific month - the 1-st row is not shown) and i just don't understand where is the problem. If i remove the first while loop, the query shows 3 rows. I also have a fiddle for this and can be found here.
Have I done something wrong? Have you ever encountered this? How can i solve this problem?
Thank you.

Answer 1

And why exactly do you have these two loops? They're both going through the same mysql result resource, so they're interfering with each other.
I think you want to do something like this:
if(mysql_num_rows($runaug) > 0 )
{
echo"
<h3>August 2013</h3>
<div><br>";
while($runrows = mysql_fetch_assoc($runaug))
{

Answer 2

you can't use the pointer from mysql_fetch_assoc($runaug) to run nested loops. because once the child loop finish iterating the parent loop will have gone past the end of the result as well. If you really just want to run two loops use
mysql_data_seek($rs,$offset);
you will have to keep a reference to the offset of the parent loop when you enter the child loop and then reset the pointer accordingly.

Answer 3

Change your code to use just one while:
else
{
echo"<div id='dam'>";
if($foundnumaug)
echo"<h3>August 2013</h3><div><br>";
while($runrows = mysql_fetch_assoc($runaug) )
{
$Luna = $runrows ['Luna'];
$Ziua = $runrows ['Ziua'];
$Mesaj = $runrows ['Mesaj'];
echo "
<table class='noutatitabel'>
<tr>
<td class='faramargini'>
<div class='data'>
<div class='luna'>$Luna</div>
<div class='ziua'>$Ziua</div>
</div>
</td>
<td class='albastru'>$Mesaj
</td>
</tr>
</table><br>";
}
echo"<br><hr><br></div>";
}
echo"</div>";
}
The reason of your problem is that the first while fetches first row and moves the internal data pointer to the next row, than the second while fetches all remaining rows.

Answer 4

First of all, you should use the improved mysql extension, mysqli
After that, I'm sure that you don't want to exact same loops, so revise them, most likely you are losing data there.

Answer 5

So if I understand correctly from the comments, the first WHILE is used to check if there are any results.
Then you need to change the first WHILE:
while($runrows = mysql_fetch_assoc($runaug) )
INTO
if ( mysql_num_rows($runaug) > 0 )
Otherwise the first WHILE will consume your first row. So you will never show the first row.